 In the following example the first Brocard point is presented, but the construction for the second Brocard point is very similar.As in the diagram above, form a circle through points A and B, tangent to edge BC of the triangle (the center of this circle is at the point where the perpendicular bisector of AB meets the line through point B that is perpendicular to BC).Symmetrically, form a circle through points B and C, tangent to edge AC, and a circle through points A and C, tangent to edge AB.