Write Python code to solve the task:
A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward. Examples of numerical palindromes are: 

2332
110011
54322345

For a given number ```num```, write a function which returns the number of numerical palindromes within each number. For this kata, single digit numbers will NOT be considered numerical palindromes. 

Return "Not valid" if the input is not an integer or is less than 0.

```
palindrome(5) => 0
palindrome(1221) => 2 
palindrome(141221001) => 5  
palindrome(1294) => 0
palindrome("1221") => "Not valid"

```

```Haskell
In Haskell, return a Maybe Int with Nothing for negative numbers.
```

Other Kata in this Series:
Numerical Palindrome #1
Numerical Palindrome #1.5
Numerical Palindrome #2
Numerical Palindrome #3
Numerical Palindrome #3.5
Numerical Palindrome #4
Numerical Palindrome #5
user
Step 1: Check if the input is a valid integer and is greater than or equal to 0. If not, return "Not valid".
Step 2: Convert the integer into a string representation.
Step 3: Initialize a count variable to keep track of the number of numerical palindromes.
Step 4: Iterate through the string representation of the number.
Step 5: For each number in the string, check if it is a palindrome by comparing it to its reversed version.
Step 6: If it is a palindrome, increment the count variable.
Step 7: Return the count variable as the result.




```python
# Step 8: 


def palindrome(num):
    if not isinstance(num, int) or num < 0:
        return "Not valid"
    
    # Step 9: 
    num_str = str(num)
    
    # Step 10: 
    count = 0
    
    # Step 11: 
    for i in range(len(num_str)):
        # Step 12: 
        if num_str[i] == num_str[i-1::-1]:
            # Step 13: 
            count += 1
    
    # Step 14: 
    return count
```
assistant
Your answer is wrong.
Your function is incorrect because it only checks for two-digit palindromes. The task requires you to find palindromes of any length. To accomplish this, instead of comparing each digit with the previous one, you should generate all possible substrings of the input string and check if each one is a palindrome. 
Meanwhile, a palindrome is a sequence that reads the same backwards as forwards, so while checking the given substring if it is a palindrome, comparing it to its reversed version isn't enough, you should also make sure the length of the substring is greater than 1 (since single digit numbers are not considered numerical palindromes according to the task's requirements). 
Remember to update the count variable only when you find a valid palindrome, and return just the count of these palindromes, rather than counting every number.

 
user
Step 1: Check if the input is a valid integer and is greater than or equal to 0. If not, return "Not valid".
Step 2: Convert the integer into a string representation.
Step 3: Initialize a count variable to keep track of the number of numerical palindromes.
Step 4: Generate all possible substrings of the string representation of the number.
Step 5: For each substring, check if it is a palindrome by comparing it to its reversed version and ensuring that the length of the substring is greater than 1.
Step 6: If it is a palindrome, increment the count variable.
Step 7: Return the count variable as the result.




```python
# Step 8: 
def palindrome(num):
    if not isinstance(num, int) or num < 0:
        return "Not valid"
    
    # Step 9: 
    num_str = str(num)
    
    # Step 10: 
    count = 0
    
    # Step 11: 
    for i in range(2, len(num_str)+1):
        for j in range(len(num_str)-i+1):
            substring = num_str[j:j+i]
            # Step 12: 
            if substring == substring[::-1] and len(substring) > 1:
                # Step 13: 
                count += 1
    
    # Step 14: 
    return count
```
assistant