Write Python code to solve the task:
A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward. Examples of numerical palindromes are:

2332 
110011 
54322345

You'll be given 2 numbers as arguments: ```(num,s)```.  Write a function which returns an array of ```s``` number of numerical palindromes that come after ```num```. If ```num``` is a palindrome itself, it should be included in the count. 

Return "Not valid" instead if any one of the inputs is not an integer or is less than 0.

For this kata, single digit numbers will NOT be considered numerical palindromes. 

```
palindrome(6,4) => [11,22,33,44]
palindrome(59,3) => [66,77,88]
palindrome(101,2) => [101,111]
palindrome("15651",5) => "Not valid" 
palindrome(1221,"8") => "Not valid" 
```

```Haskell

In Haskell, the return type is a Maybe which returns Nothing if either of the inputs is negative."
```


Other Kata in this Series:
Numerical Palindrome #1
Numerical Palindrome #1.5 
Numerical Palindrome #2
Numerical Palindrome #3
Numerical Palindrome #3.5
Numerical Palindrome #4
Numerical Palindrome #5
user
Step 1: Check if the inputs num and s are integers.
Step 2: Check if num is less than 0 or s is less than 1.
Step 3: Check if num is a palindrome.
Step 4: Initialize an empty list to store the palindromes.
Step 5: If num is a palindrome, add it to the list and decrement s by 1.
Step 6: Initialize a variable i as the next number after num.
Step 7: While s is greater than 0, check if i is a palindrome.
Step 8: If i is a palindrome, add it to the list and decrement s by 1.
Step 9: Increment i by 1.
Step 10: Return the list of palindromes.




```python
# Step 11: Check if the inputs num and s are integers.


def palindrome(num,s):
    if not isinstance(num, int) or not isinstance(s, int):
        return "Not valid"
    
    # Step 12: Check if num is less than 0 or s is less than 1.
    if num < 0 or s < 1:
        return "Not valid"
    
    # Step 13: Check if num is a palindrome.
    def is_palindrome(n):
        return str(n) == str(n)[::-1]
    
    # Step 14: Initialize an empty list to store the palindromes.
    palindromes = []
    
    # Step 15: If num is a palindrome, add it to the list and decrement s by 1.
    if is_palindrome(num):
        palindromes.append(num)
        s -= 1
    
    # Step 16: Initialize a variable i as the next number after num.
    i = num + 1
    
    # Step 17: While s is greater than 0, check if i is a palindrome.
    while s > 0:
        # Step 18: If i is a palindrome, add it to the list and decrement s by 1.
        if is_palindrome(i):
            palindromes.append(i)
            s -= 1
        
        # Step 19: Increment i by 1.
        i += 1
    
    # Step 20:  Return the list of palindromes.
    return palindromes
```
assistant
Your answer is wrong.
There are two errors in your function. The first mistake is the condition for when a number is considered a palindrome. In this task, it's mentioned that single digit numbers are not considered as palindromes, but your current implementation will consider them as such. You need to add an extra condition to exclude these cases. The second mistake is that if num is a palindrome and added to the list, you increment i starting from num + 1 but you forget that you may miss the case where all the digits next to num are also a palindrome. Instead, you should increment num by 1 regardless of whether it is a palindrome or not during each iteration.

 
user
Step 1: Check if the inputs num and s are integers.
Step 2: Check if num is less than 0 or s is less than 1.
Step 3: Check if num is a palindrome and if its length is greater than 1.
Step 4: Initialize an empty list to store the palindromes.
Step 5: If num is a palindrome, add it to the list and decrement s by 1.
Step 6: Initialize a variable i as 1.
Step 7: While s is greater than 0, check if i + num is a palindrome.
Step 8: If i + num is a palindrome, add it to the list and decrement s by 1.
Step 9: Increment i by 1.
Step 10: Return the list of palindromes.



```python
# Step 11:  Check if the inputs num and s are integers.



def palindrome(num,s):
    if not isinstance(num, int) or not isinstance(s, int):
        return "Not valid"
    
    # Step 12:  Check if num is less than 0 or s is less than 1.
    if num < 0 or s < 1:
        return "Not valid"
    
    # Step 13:  Check if num is a palindrome and if its length is greater than 1.
    def is_palindrome(n):
        return str(n) == str(n)[::-1] and len(str(n)) > 1
    
    # Step 14:  Initialize an empty list to store the palindromes.
    palindromes = []
    
    # Step 15:  If num is a palindrome, add it to the list and decrement s by 1.
    if is_palindrome(num):
        palindromes.append(num)
        s -= 1
    
    # Step 16:  Initialize a variable i as 1.
    i = 1
    
    # Step 17:  While s is greater than 0, check if i + num is a palindrome.
    while s > 0:
        # Step 18:  If i + num is a palindrome, add it to the list and decrement s by 1.
        if is_palindrome(i + num):
            palindromes.append(i + num)
            s -= 1
        
        # Step 19:  Increment i by 1.
        i += 1
    
    # Step 20:   Return the list of palindromes.
    return palindromes
```
assistant