Consider four vectors ~ F1, ~ F2, ~ F3, and ~ F4, wheretheir
magnitudes are F1= 43 N, F2= 36 N, F3 = 19 N, andF4 = 54 N.Let
θ1 =120o, θ2 =
−130o,θ3 = 200, and θ4 =
−67o, measured from thepositive x axis with
the counter-clockwiseangular direction aspositive.
What is the magnitudeof the resultant vector ~F , where ~F = ~
F1 +~ F2 +~ F3 +~ F4? Answer in units of N. What is the direction
ofthis resultant vector~F?
Note: Give the anglein degrees, use counterclockwise as the
positiveangular direction, between the limits
from the positive
xaxis. Answer in units ofo
I worked out the first part of thequestion by using
trigonomic rules. My X value=-5.68671and my Y
value=-33.5474. The magnitude came out to 34.026N. I tried
finding the direction by usingθ=tan-1(y/x) but i
cant get the rightanswer.