A diver leaves the springboard with a vertical velocity of 5.7m/s, and horizontal velocity of 1.2 m/s, and a height of 3.49m. How long will it take her to return to the same height? What horizontal range will she cover in this time? Would I use: Time = 2Vvert/g for the first part? And Range = (Vhor)(Time) for the second part? MY ANSWERS: 1st part --> Time = 1.16 s 2nd part --> Range = 1.4 m Is this correct?