Give me {square root} that contains the word {root} in their name
Reveal to ME SQUARE ROOT WHOSE NAME HAS THE WORD ROOT IN IT.
TELL ME SQUARE ROOT WHOSE NAME HAS THE WORD ROOT IN IT.
SELECT DISTINCT ?e WHERE { ?e rdf:type ontology:square_root . FILTER ( CONTAINS ( LCASE ( ?e ) , 'root' ) ) }
SELECT DISTINCT ?sbj ?sbj_label { ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#subject> ?sbj . ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#predicate> <http://www.wikidata.org/entity/P31> . ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#object> <http://wikidata.dbpedia.org/resource/Q134237>. ?sbj rdfs:label ?sbj_label . FILTER(CONTAINS(lcase(?sbj_label), 'root')) . FILTER (lang(?sbj_label) = 'en') } LIMIT 25
SELECT DISTINCT ?sbj ?sbj_label WHERE { ?sbj wdt:P31 wd:Q134237 . ?sbj rdfs:label ?sbj_label . FILTER(CONTAINS(lcase(?sbj_label), 'root')) . FILTER (lang(?sbj_label) = 'en') } LIMIT 25 
square root of 2 square root of 2 square root of 5 square root of 5 square root of 3 square root of 3