Give me {superhero} that {hair color} {black hair} and which contains the word {woman} in their name
which superhero that hair color black hair and which includes the word female in their title
which superhero that hair color black hair and which contains the word woman in their name
SELECT DISTINCT ?t WHERE { ?t property:hair_color resource:black_hair . ?t rdf:type ontology:superhero . FILTER ( CONTAINS ( LCASE ( ?t ) , 'woman' ) ) }
SELECT DISTINCT ?sbj ?sbj_label { ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#subject> ?sbj . ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#predicate> <http://www.wikidata.org/entity/P31> . ?statement1 <http://www.w3.org/1999/02/22-rdf-syntax-ns#object> <http://wikidata.dbpedia.org/resource/Q188784>. ?statement2 <http://www.w3.org/1999/02/22-rdf-syntax-ns#subject> ?sbj . ?statement2 <http://www.w3.org/1999/02/22-rdf-syntax-ns#predicate> <http://www.wikidata.org/entity/P1884> . ?statement2 <http://www.w3.org/1999/02/22-rdf-syntax-ns#object> <http://wikidata.dbpedia.org/resource/Q1922956>. ?sbj rdfs:label ?sbj_label . FILTER(CONTAINS(lcase(?sbj_label), 'woman')) . FILTER (lang(?sbj_label) = 'en') } LIMIT 25
SELECT DISTINCT ?sbj ?sbj_label WHERE { ?sbj wdt:P31 wd:Q188784 . ?sbj wdt:P1884 wd:Q1922956 . ?sbj rdfs:label ?sbj_label . FILTER(CONTAINS(lcase(?sbj_label), 'woman')) . FILTER (lang(?sbj_label) = 'en') } LIMIT 25 