### Database Schema:
CREATE TABLE country (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	country_name	TEXT	NULL	DEFAULT NULL
);

CREATE TABLE ranking_criteria (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	ranking_system_id	INTEGER	NULL	DEFAULT NULL,
	criteria_name	TEXT	NULL	DEFAULT NULL,
	foreign key (ranking_system_id) references ranking_system (id)
);

CREATE TABLE university (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	country_id	INTEGER	NULL	DEFAULT NULL,
	university_name	TEXT	NULL	DEFAULT NULL,
	foreign key (country_id) references country (id)
);

CREATE TABLE university_ranking_year (
	university_id	INTEGER	NULL	DEFAULT NULL,
	ranking_criteria_id	INTEGER	NULL	DEFAULT NULL,
	year	INTEGER	NULL	DEFAULT NULL,
	score	INTEGER	NULL	DEFAULT NULL,
	foreign key (university_id) references university (id),
	foreign key (ranking_criteria_id) references ranking_criteria (id)
);

CREATE TABLE university_year (
	university_id	INTEGER	NULL	DEFAULT NULL,
	year	INTEGER	NULL	DEFAULT NULL,
	num_students	INTEGER	NULL	DEFAULT NULL,
	student_staff_ratio	REAL	NULL	DEFAULT NULL,
	pct_international_students	INTEGER	NULL	DEFAULT NULL,
	pct_female_students	INTEGER	NULL	DEFAULT NULL,
	foreign key (university_id) references university (id)
);

CREATE TABLE ranking_system (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	system_name	TEXT	NULL	DEFAULT NULL
);

### User's Query:
Provide the country name of universities with the number of students greater than 98% of the average student population of all universities in 2013.

### Extra Knowledge:
number of students greater than 98% of the average student population of all universities refers to num_students >  MULTPLY(num_students, 0.98); in 2013 refers to year = 2013
SELECT DISTINCT T3.country_name FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2013 AND T2.num_students * 100 > ( SELECT AVG(num_students) FROM university_year ) * 98