### Database Schema:
CREATE TABLE unemployed (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE disabled (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE male (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE no_payment_due (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	bool	TEXT	NULL,
	foreign key (bool) references bool (name),
	foreign key (name) references person (name)
);

CREATE TABLE enrolled (
	name	TEXT	NOT NULL	PRIMARY KEY,
	school	TEXT	NOT NULL	PRIMARY KEY,
	month	INTEGER	NOT NULL	DEFAULT 0,
	foreign key (name) references person (name)
);

CREATE TABLE longest_absense_from_school (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	month	INTEGER	NULL	DEFAULT 0,
	foreign key (name) references person (name)
);

CREATE TABLE bool (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY
);

CREATE TABLE enlist (
	name	TEXT	NOT NULL,
	organ	TEXT	NOT NULL,
	foreign key (name) references person (name)
);

CREATE TABLE filed_for_bankrupcy (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE person (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY
);

### User's Query:
How many male students filed for bankruptcy as compare to female students?

### Extra Knowledge:
difference = SUBTRACT(COUNT(filed_for_bankrupcy.name who are In male.name), COUNT(filed_for_bankrupcy.name who are NOT in male.name)); male students are mentioned in male.name; female students refers to filed_for_bankrupy.name who are NOT in male.name;
SELECT COUNT(T2.name) - SUM(IIF(T2.name IS NULL, 1, 0)) AS num FROM filed_for_bankrupcy AS T1 LEFT JOIN male AS T2 ON T2.name = T1.name