### Database Schema:
CREATE TABLE beers (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	brewery_id	INTEGER	NOT NULL,
	abv	REAL	NULL,
	ibu	REAL	NULL,
	name	TEXT	NOT NULL,
	style	TEXT	NULL,
	ounces	REAL	NOT NULL,
	foreign key (brewery_id) references breweries (id)
);

CREATE TABLE breweries (
	id	INTEGER	NOT NULL	PRIMARY KEY,
	name	TEXT	NULL,
	city	TEXT	NULL,
	state	TEXT	NULL
);

### User's Query:
When compared to the total number of breweries in the US producing American Blonde Ale, how many in the state of Wisconsin produces American Blonde Ale? Indicate your answer in percentage (%).

### Extra Knowledge:
Percentage of the state of Wisconsin produces American Blonde Ale could be computed by count(breweries in Wisconsin producing American Blonde Ale) / count(all breweries)
SELECT CAST(SUM(IIF(T2.state = 'WI', 1, 0)) AS REAL) * 100 / COUNT(T1.id) FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T1.style = 'American Blonde Ale'