### Database Schema:
CREATE TABLE incidents (
	case_number	TEXT	NOT NULL	PRIMARY KEY,
	date	DATE	NOT NULL,
	location	TEXT	NOT NULL,
	subject_statuses	TEXT	NOT NULL,
	subject_weapon	TEXT	NOT NULL,
	subjects	TEXT	NOT NULL,
	subject_count	INTEGER	NOT NULL,
	officers	TEXT	NOT NULL
);

CREATE TABLE officers (
	case_number	TEXT	NOT NULL,
	race	TEXT	NULL,
	gender	TEXT	NOT NULL,
	last_name	TEXT	NOT NULL,
	first_name	TEXT	NULL,
	full_name	TEXT	NOT NULL,
	foreign key (case_number) references incidents (case_number)
);

CREATE TABLE subjects (
	case_number	TEXT	NOT NULL,
	race	TEXT	NOT NULL,
	gender	TEXT	NOT NULL,
	last_name	TEXT	NOT NULL,
	first_name	TEXT	NULL,
	full_name	TEXT	NOT NULL,
	foreign key (case_number) references incidents (case_number)
);

### User's Query:
What is the percentage of the cases involved more than 3 officers from year 2010 to 2015?

### Extra Knowledge:
more than 3 officers refers to officer_count > 3; from year 2010 to 2015 refers to date between '2010-01-01' and '2015-12-31'; percentage = divide(count(case_number where officer_count > 3), count(case_number)) where date between '2010-01-01' and '2015-12-31' * 100%
SELECT CAST(SUM(IIF(officer_count > 3, 1, 0)) AS REAL) * 100 / COUNT(case_number) FROM incidents WHERE STRFTIME('%Y', date) BETWEEN '2010' AND '2015'