### Database Schema:
CREATE TABLE unemployed (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE disabled (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE male (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE no_payment_due (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	bool	TEXT	NULL,
	foreign key (bool) references bool (name),
	foreign key (name) references person (name)
);

CREATE TABLE enrolled (
	name	TEXT	NOT NULL	PRIMARY KEY,
	school	TEXT	NOT NULL	PRIMARY KEY,
	month	INTEGER	NOT NULL	DEFAULT 0,
	foreign key (name) references person (name)
);

CREATE TABLE longest_absense_from_school (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	month	INTEGER	NULL	DEFAULT 0,
	foreign key (name) references person (name)
);

CREATE TABLE bool (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY
);

CREATE TABLE enlist (
	name	TEXT	NOT NULL,
	organ	TEXT	NOT NULL,
	foreign key (name) references person (name)
);

CREATE TABLE filed_for_bankrupcy (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY,
	foreign key (name) references person (name)
);

CREATE TABLE person (
	name	TEXT	NOT NULL	DEFAULT ''	PRIMARY KEY
);

### User's Query:
Which organization has the highest number of male students? Calculate for the percentage of the male students in the said organization.

### Extra Knowledge:
organization refers to organ; highest number of male students refers to MAX(COUNT(male.name)); percentage = DIVIDE(COUNT(male.name), COUNT(person.name)), 1.0;
SELECT T.organ, T.per FROM ( SELECT T1.organ, CAST(COUNT(T3.name) AS REAL) / COUNT(T2.name) AS per , COUNT(T3.name) AS num FROM enlist AS T1 INNER JOIN person AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T2.name = T3.name GROUP BY T1.organ ) T ORDER BY T.num DESC LIMIT 1