So, in the first part, we have this x and then we have to put this as −1 for this eiαx, so x is at these two places, so first we will put 1. So, we have eiα and then with the minus sign and then −1, so we have e−iα and then because of the second integral, we will get again and then the limit of x is from −1 to 1.
तो, पहले पार्ट में हमारे पास यह x है और eiαx में x का मान −1 रखेंगे तो हमें e−iα मिलता है और दूसरे इंटीग्रल से जब −1 से 1 है हमें मिलता है।