Sin of the other portion will be negative and when I do the integration that term goes to 0. So, what we are left with is 1 over pi integral 0 to pi cosine of x cos beta and I think some books already give you the direct expression in this form and again applying the symmetries that are present, you do not have to integrate from 0 to pi.
तो, जो हमारे पास बचा है वह है और मुझे लगता है कि कुछ किताबें पहले से ही आपको यही एक्सप्रेशन देती हैं।