at 30 degrees, so this t is t minus t 0 it is a 10. it is a delta t this L means length of the rod which was L 0, so that is now L. Now, alpha equal to L Minus L 0 by L 0 t; this is this t as I told delta t and this are delta L one can write del L by del t 1 by L 0. here, here we are getting, this due to the temperature difference from the original one, of course, L 0 corresponding that temperature t 0 this for temperature difference from the original what are the increment of the length that we are noting down
मूळ लांबी L0 इतकी आहे आणि तापमानाचा फरक 10 इतका आहे. हे समीकरण वरील प्रमाणे सोडवावे.