So, squaring we get C naught by 2 times i plus lambda into sigma root over D j C j square is equal to B square, i plus lambda is equal to C naught by 2 B square sigma root over whole square from which lambda is equal to C naught by 2 B square sigma whole square minus i.
अतः, वर्ग करने  पर {Co / 2 } x  Σ √ 2 = B2 के बराबर होता है, i +  ƛ = Σ √ 2  के बराबर होता है, जिससे  ƛ = Σ √ 2 - i ।