So, consider, phi from Z to Q; phi from Z to Q. So, this is just the inclusion map, phi of n to be n for all let us say phi of r equal to phi of r, phi of r equal to r for I should really write n sorry is n for all n in Z.
అనేది అన్ని విలువలకు n అవుతుంది, Z లోని అన్ని n కోసం)