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1 Answer          x  - 6 2x+3 ) 2x2 - 9x - 20      -(2x2 + 3x)
 -12x - 20          -(-12x - 18)                 - 2  The
solution is x - 6 - 2/(2x+3).   I wanted to put the answer in a
formatted way first.  Now I'll talk about how I did this
problem.   First, I started by looking at 2x2.  If I divide this
first term by 2x, what do I get?  That answer is x.  So when I
multiply x by 2x+3, I get the quantity 2x2 + 3x.  Just like in
long division, you subtract this product out, leaving -12x -
20.  -12x goes into 2x -6 times.  Multiply 2x+3 by -6 gives you
-12x - 18, which you subtract out leaving -2.  You can't go any
further so the remainder is written in fractional form with the
divisor as the denominator: -2/(2x+3).  So you final answer is x
- 6 - 2/(2x+3).  This satisfies the question, as R has x to the
0th power and D has x to the 1st power, and has been expressed
as Q + R/D... q