Joint pdf - find C  Announcements Posted on     • Thread Starter
The joint probability density function is:      The C is a
constant.      The ranges are x<1, y<1, x+y>1      They're
supposed to be less than or equal to, greater than or equal to.
I am trying to find what the constant C is.      I know the
method as I have done similar questions before but this one
doesn't seem to be working out for me.      My method: integrate
Cexp(x)exp(y), first with respect to y in between 1-x and 1.
This gives me Cexp(x)(exp(1) - exp(1-x)      I find that odd
already with the exp(1).      Then integrating again with
respect to x between 0 and 1, I get  C (exp(2) +1)      As the
joint pdf equals one, this then gives me  C = \frac{1}{exp(2)+1}
Doesn't look right to me...      Can someone please point out
where I went wrong?     (Original post by Mathlete29)     Agree
with your limits.      After integrating wrt y, I get e^{x+1}-e
and then after integrating wrt x, I get  e^2-2e      Edit: Both
times