Take the 2-minute tour ×  Note: This is part of my preparations
for my exams, im getting the wrong answer as $32/17$ which is
not what wolfram alpha says, i would highly appreciate it if
somebody could provide a direct answer so i can see what went
wrong.  The equation here is $\frac{x+3}{x-2} - \frac{1-x}{x} =
\frac{17}{x}$  Note: brackets are there to seperate, they dont
haveany special meaning.  share|improve this question add
comment  1 Answer  up vote 0 down vote accepted  Hint: Multiply
through so that all values have the same denominator:
$\frac{x^2+3x}{x^2-2x} - \frac{-x^2+3x-2}{x^2-2x} =
\frac{17x-34}{x^2-2x}$  Then simplify:  $\frac{2x^2+2}{x^2-2x} =
\frac{17x-34}{x^2-2x}$  $2x^2+2 = 17x-34$  $2x^2-17x+36 = 0$
Edit: So, to continue, since you seem to have gotten to this
point, you come up with factors:  $(2x-9)(x-4) = 0$  So the
roots are $4$ and $4\frac{1}{2}$  share|improve this answer i
already did that –  Aayush Agrawal Mar 22 '13 at 14:48 See my
edits. I completed the equation. –  Jonathan Ri