Take the 2-minute tour ×  Let's suppose that $h_1$, $h_2$, $b_1$
and $b_2$ are vectors of length $L\times 1$.  Where $h_1$ and
$h_2$ are real and unknowns and $b_1$ and $b_2$ are known
complexes  Is it possible to solve this expression?
$$h_1^T\times b_1=h_2^T\times b_2$$  I tried to see it as...
$$(1\times L)\times (L \times 1)= (1\times L)\times (L \times
1)$$ then becomes $$(1\times L)= (1\times L)\times (L \times 1)
\times (1\times L)$$ which indicates that $b_1$ and $b_2$ needs
to be a matrix dimension. However linear algebra rule doesn't
permit such move.  I want to see if I can find the relationship
between $h_1$ and $h_2$. The most logical way is to move one $b$
to another side, but since they are vectors I have no idea how
to.  share|improve this question Do you mean $1 \times L$, or do
you mean $L \times 1$? –  Robert Israel May 22 '12 at 2:42
$1\times L$ vector. So yes indeed both RHS and LHS will end up
with an single-element solution. –  JuniorEngie May 22 '12 at
2:47 No, if $h$ and $b$ are $1 \