Take the 2-minute tour ×  Let's have a simple code as below
public class Sandbox {      public static void run(String[]
args) {         int i = Integer.MAX_VALUE;         int j = i+1;
This will print output    Value at j is overlowed without any
notice to me when the code is executed.  I use Netbeans IDE to
run this code.  Is it possible to configure the system to notify
us when such arithmetic overflow occurs?  share|improve this
question You have to use if-else for this, to check for overflow
manually.. Also,you have to create your own exeption. –  Rohit
Jain Oct 14 '12 at 7:45 add comment  2 Answers  up vote 3 down
vote accepted  See the last sentence in the Java Language
Specification (Chapter 15.18.2. Additive Operators (+ and -) for
Numeric Types) :  Despite the fact that overflow, underflow, or
loss of information may occur, evaluation of a numeric additive
operator never throws a runtime exception.  For a lengthy
article on this problem and the presentation of a tool for
workaround see the article S