Need help with linked list sorting function  Printable View
I'll let you think about that much for now.   • 06-01-2009
Whoa, I should have previewed that. Code tags don't work so well
inside a bullet list!     The 3 lines are:      plat1 = first;
plat3 = first;     (*plat3).next = plat1;    • 06-02-2009
Thank you both for taking the time to look at my code and
respond.      @ c.user:     I'm assuming that by telling me to
change '(*first).name' to 'first->name' you're asking me to
change the format I'm using for all instances of (*[pntr]).name,
since I can't find a use of '(*first).name' anywhere in my code
aside from a set of comments I used to hide away a test to see
if my lists were being properly copied. If so, then why? I was
told there was no difference between using either styles.      @
iMalc:     The first two ('plat1= first;' and 'plat3 = first:')
are meant to return the two "platforms" to the beginning of the
linked list so that they're ready for a second round of sorting.
The third pi