Take the 2-minute tour ×  I know (from Kinematics) that for an
object moving linearly with an acceleration and without air
resistance the following equations can be used to determine
v(velocity) or x(position of the object) at any time:    Where
$x_0$ is the position of the object at the start of accelerated
movement, $v_0$ is the velocity at the start of the motion and a
is the acceleration.  Now if I want to add air drag, say we take
the formula for air drag as:  $D=0.5CA\rho v^2$  $C$ is a
coefficent, $A$ is the reference Area, $\rho$ is the density and
$v$ the velocity. Since $D$ is a force the air drag results in
an acceleration, so in other words: The resulting acceleration
is $a-D/m$, however $D$ depends on $v$, which depends on the
acceleration. And that's where my problem is, I simply can't
wrap my mind around that.  How would I go about getting the
Equations for $x$ and $v$ including air drag (and don't forget
there's acceleration too)?  share|improve this question add
comment  2 Answers  up vote 2