Take the 2-minute tour ×  Possible Duplicate: Current against
the inverse of resistance graph, I = V/R +c  How would you set
up a circuit with a fixed resistor in parallel with a variable
one. We are told to measure the current across the combination
resistors and our Voltage is $1V$ and then construct an $I$
against $1/R$ graph what sort of correlation would this be?
share|improve this question I think the entire point of this
exercise is for you to discover the relationship between the
current I and the resistance of the variable resistor R. It'd be
a spoiler to give you the relationship here, wouldn't it? – 
Adam Zalcman Feb 5 '12 at 11:21 We have already done the
experiment but the relationship of the graph ws a positive
correlation which is were im cnfused about –  Jeff Feb 5 '12 at
11:24 add comment  marked as duplicate by Qmechanic, dmckee Feb
5 '12 at 17:44   1 Answer  Assuming that R refers to the
variable resistance, the graph should be: $Y=V(x +\frac{1}{r})$
(r is the fixed resistance), which is a