Take the 2-minute tour ×  I need to implement something of a
ternary operator that can help me return some default values
from cypher query itself.  Scenario is -  if an employee's city
is Delhi, return 5 else return 10  Something like a ternary
operator.  start employee = node(5) return employee.city ==
'DELHI' ? 5 : 10 as val;  I tried things like  start employee =
node(5) return coalesce (employee.city == 'DELHI', 5)  but no
luck.  Is there a way to implement such a scenario in neo4j be
it Cypher or Traversal.  share|improve this question add comment
1 Answer  up vote 2 down vote accepted  Unfortunately it is not
supported out of the box but here is a hack to do it, using
filter, head and collection literals.  The idea is to have a two
element list and a filter expression that becomes true for the
first element for your "true-branch" and alternatively true for
the second element in the list whic represents the value of your
false-branch.  see this console example:
http://console.neo4j.org/r/6tig7g  start