Take the tour ×  The Task: During a technical control lights and
brakes was controlled on randomly selected cars. 18% had errors
with the lights and 12% with the brakes. 74% had both lights and
brakes in order. What is the probability that: a) The lights
were in order? b) The brakes were in order? c) No brakes and no
lights? d) Lights, but no brakes.  My answers(d is the problem):
a) 82% b) 88% c) 18+12-26=4% d) What I have scribbled so far:
p(A) = Lights = 0.88, p(B) = brakes = 0.88 $P(A \cap B) = 0.74$
$P(A \cup B) = 0.88+0.82 - 0.74 = 0.96$ At least one of the two
is functioning. The complement of that last would be both is not
working; 4%. 26% that both or at least one is not working.  From
there I don't see what I'm suppose to do. The book says the
answer is 8% on d). I'll check back here in the morning. Good
night.  share|improve this question isn't the answer just is 82%
x 12%? –  Victor Jul 19 '11 at 23:02 @Alg: Saying that you will
"check back in the morning" gives me the sense that you do not
care a