I have tried this problem and don't know where to go: Show that
the area of the Babylonian bullseye is given by A=9/32a^2, where
a is the length of the arc (1/3 circumference) also the length
of the long transversal of the bull's eye is 7/8a and the the
short transversal is 1/2a.  Also known: area of circle = C^2/12,
7/4 = sq root of 3.  Help please!