Let us now consider the local minimum of the Euclidean action S E with the double-well potential V ( x ) = 1 4 ( x 2 − − 1 ) 2 , and we set m = 1 just for simplicity of computation. Since we want to know how the two classically lowest energy states x = ± ± 1 are connected, let us set a = − − 1 and b = 1 . For a = − − 1 and b = 1 , we can rewrite the Euclidean action as