Note that the reciprocal problem is also solved by this method. If we have a charge q at vector position p outside of a grounded sphere of radius R, the potential outside of the sphere is given by the sum of the potentials of the charge and its image charge inside the sphere. Just as in the first case, the image charge will have charge − qR / p and will be located at vector position ( R 2 / p 2 ) p . The potential inside the sphere will be dependent only upon the true charge distribution inside the sphere. Unlike the first case the integral will be of value − qR / p.