Since j k = ( R + j ω ω L ) ( G + j ω ω C ) + v ( + ) i ( + ) = R + j ω ω L j k = R + j ω ω L G + j ω ω C ≡ ≡ Z 0 − − v ( − − ) i ( − − ) = R + j ω ω L j k = R + j ω ω L G + j ω ω C ≡ ≡ Z 0 hence, for valid solutions require v ( + ) = + Z 0 i ( + ) and v ( − − ) = − − Z 0 i ( − − )