The horizontal net force on the ball is the horizontal component of the force from the road, which has magnitude | F h | = m | a n | sin θ. The vertical component of the force from the road must counteract the gravitational force: | F v | = m | a n | cos θ = m | g |, which implies | a n | = | g | / cos θ. Substituting into the above formula for | F h | yields a horizontal force to be: | F h | = m | g | sin ⁡ ⁡ θ θ cos ⁡ ⁡ θ θ = m | g | tan ⁡ ⁡ θ θ .