Partitioning the uniform spatial distribution into two equal bins is straightforward. We set the offset c = 1/2 so that the two bins span the distribution. P ⁡ ⁡ [ x 0 ] = ∫ ∫ − − a 0 1 2 a d x = 1 2 P ⁡ ⁡ [ x 1 ] = ∫ ∫ 0 a 1 2 a d x = 1 2 H x = − − ∑ ∑ j = 0 1 P ⁡ ⁡ [ x j ] ln ⁡ ⁡ P ⁡ ⁡ [ x j ] = − − 1 2 ln ⁡ ⁡ 1 2 − − 1 2 ln ⁡ ⁡ 1 2 = ln ⁡ ⁡ 2