This yields a system of linear equations in i 1, i 2, i 3 : { i 1 − − i 2 − − i 3 = 0 − − R 2 i 2 + E 1 − − R 1 i 1 = 0 − − R 3 i 3 − − E 2 − − E 1 + R 2 i 2 = 0 which is equivalent to { i 1 + ( − − i 2 ) + ( − − i 3 ) = 0 R 1 i 1 + R 2 i 2 + 0 i 3 = E 1 0 i 1 + R 2 i 2 − − R 3 i 3 = E 1 + E 2 Assuming R 1 = 100 Ω Ω , R 2 = 200 Ω Ω , R 3 = 300 Ω Ω , E 1 = 3 V , E 2 = 4 V the solution is { i 1 = 1 1100 A i 2 = 4 275 A i 3 = − − 3 220 A