From the relations Ω Ω 2 ω ω 2 + ω ω 2 Ω Ω 2 ≥ ≥ 2 , | cos ⁡ ⁡ ( 4 ω ω t ) | ≤ ≤ 1 , we can conclude the following (the right most equality holds only when Ω = ω): σ σ x σ σ p ≥ ≥ ℏ ℏ 4 3 + 1 2 ( Ω Ω 2 ω ω 2 + ω ω 2 Ω Ω 2 ) − − ( 1 2 ( Ω Ω 2 ω ω 2 + ω ω 2 Ω Ω 2 ) − − 1 ) = ℏ ℏ 2 .