Pb(NO_{3})_{2}(aq) + 2NaI(aq) -> PbI_{2}(s) + 2NaNO_{3}(aq) L_{2}N(aq) + SI(aq) -> L_{2}I(s) + SN(aq) Pb_{2}N(aq) + NaI(aq) -> Pb_{2}I(s) NaN(aq) Fe(NO_{3})_{2}(aq) + 2NaI(aq) -> FeI_{2} + 2NaNO_{3}(aq)
I am hesitating between 4 options to answer the following question, which option should I choose?
Question: A solution of lead (II) nitrate reacts with a solution of sodium iodide to produce a yellow solid of lead (II) iodide and aqueous sodium nitrate. Which of these illustrates the reaction?
Possibilities:
- Pb(NO_{3})_{2}(aq) + 2NaI(aq) -> PbI_{2}(s) + 2NaNO_{3}(aq)
- L_{2}N(aq) + SI(aq) -> L_{2}I(s) + SN(aq)
- Pb_{2}N(aq) + NaI(aq) -> Pb_{2}I(s) NaN(aq)
- Fe(NO_{3})_{2}(aq) + 2NaI(aq) -> FeI_{2} + 2NaNO_{3}(aq)

Pb(NO_{3})_{2}(aq) + 2NaI(aq) -> PbI_{2}(s) + 2NaNO_{3}(aq)