Computing this one term at a time may be difficult, but it is easy to prove by induction a closed formula which holds for all natural numbers.
What is the sum of the squares of the first eight natural numbers, that is one squared plus two squared plus three squared up to eight squared? Computing this one term at a time may be difficult, but it is easy to prove by induction a closed formula which holds for all natural numbers. Those of you who have already learned the formula should know that the sum of the squares from one to "n" is equal to n times the quantity n plus one times the quantity two n plus one divided by six.
What is the sum of the squares of the first eight natural numbers, that is one squared plus two squared plus three squared up to eight squared?
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