For a heteronuclear particle, it is equal to the square root of the differe
For a heteronuclear particle, it is equal to the square root of the difference between the bond dissociation enthalpy and the enthalpy change of atomization. It can also be determined by dividing effective nuclear charge by the square of the covalent (*) radius. The average of the first ionization energy and the first electron affinity is equal to this value according to Mulliken, and it can be used to determine the polarity of a bond. For 10 points, name this value that is highest for fluorine and represents the tendency of an atom to attract a shared electron pair.
For a heteronuclear particle, it is equal to the square root of the difference between the bond dissociation enthalpy and the enthalpy change of atomization.
electronegativity