proposition: Lemma combine_map_join: forall {A B C} (f: A -> B) (g: A -> C) (l: list A), combine (map f l) (map g l) = map (fun x => (f x, g x)) l.
proof: Proof. intros. induction l; simpl; auto. rewrite IHl. reflexivity. Qed.
imports: Coq.Lists.List Coq.micromega.Lia Coq.Sorting.Permutation Coq.ZArith.ZArith_base Coq.ZArith.Zcomplements Coq.Logic.FunctionalExtensionality CertiGraph.lib.Coqlib CertiGraph.lib.EquivDec_ext VST.zlist.sublist VST.zlist.list_solver