proposition: Lemma umPtUPt2E (k1 k2 : K) (v1 v2 : V) f : (k1 \\-> v1 == f \+ k2 \\-> v2) = [&& k1 == k2, v1 == v2 & unitb f].
proof: Proof. by rewrite joinC umPtPtUE. Qed.
imports: Coq(ssreflect ssrbool ssrfun) mathcomp(ssrnat eqtype seq path bigop) pcm(options prelude finmap seqperm pred seqext) pcm(pcm morphism)