proposition: Lemma abmonoidshombinop_assoc {X Y : abmonoid} (f g h : monoidfun X Y) : abmonoidshombinop (abmonoidshombinop f g) h = abmonoidshombinop f (abmonoidshombinop g h).
proof: Proof. use monoidfun_paths. use funextfun. intros x. use assocax. Qed.
imports: UniMath.Algebra.BinaryOperations UniMath.MoreFoundations.Subtypes UniMath.MoreFoundations.Sets UniMath.MoreFoundations.Orders