proposition: Lemma map_last : forall f x l, map f (l & x) = map f l & f x.
proof: Proof. Proof using. intros. rewrite~ map_app. Qed.
imports: Coq.Classes.Morphisms TLC(LibTactics LibLogic LibReflect LibOperation LibProd LibOption LibNat LibInt LibWf LibMonoid LibRelation)