proposition: Lemma lt_subterm1 a a' n' b': lt a a' -> lt a (cons a' n' b').
proof: Proof. intro H; apply lt_trans with (cons a n' b'); auto with T1. Qed.
imports: Coq(Arith Lia Compare_dec Relations Wellfounded Wf_nat List Bool Eqdep_dec Ensembles ArithRing Logic) hydras(More_Arith Restriction DecPreOrder rpo.term rpo.rpo Epsilon0.T1)