proposition: Proposition rmap_const_profunctor {x₁ x₂: C} {y : D} (f : x₁ --> x₂) (h : X) : rmap const_profunctor f (h : const_profunctor y x₁) = h.
proof: Proof. cbn. apply idpath. Qed.
imports: UniMath.Foundations.All UniMath.CategoryTheory.Core.Prelude UniMath.CategoryTheory.Categories.HSET.All UniMath.CategoryTheory.Categories.HSET.SetCoends UniMath.CategoryTheory.Profunctors.Core