proposition: Lemma close_exp_wrt_exp_rec_inj : forall e1 e2 x1 n1, close_exp_wrt_exp_rec n1 x1 e1 = close_exp_wrt_exp_rec n1 x1 e2 -> e1 = e2.
proof: Proof. pose proof close_exp_wrt_exp_rec_inj_mutual as H; intuition eauto. Qed.
imports: Coq.Logic.FunctionalExtensionality Coq.Program.Equality Metalib.Metatheory Metalib.LibLNgen Stlc