proposition: Lemma ex_filterdiff_ext {F} {FF : Filter F} (f g : U -> V) : (forall y , f y = g y) -> ex_filterdiff f F -> ex_filterdiff g F.
proof: Proof. intros H [l Hl]. exists l ; by apply filterdiff_ext with f. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lim_seq Iter Hierarchy Continuity Equiv