proposition: Lemma is_lim_seq_inv (u : nat -> R) (l : Rbar) : is_lim_seq u l -> l <> 0 -> is_lim_seq (fun n => / u n) (Rbar_inv l).
proof: Proof. intros Hu Hl. apply filterlim_comp with (1 := Hu). now apply filterlim_Rbar_inv. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lub Markov Hierarchy