proposition: Theorem FF2R_B2FF : forall x, FF2R radix2 (B2FF x) = B2R x.
proof: Proof. now intros [sx|sx|sx plx Hplx|sx mx ex Hx]. Qed.
imports: Coq(ZArith Reals Psatz SpecFloat) Core Round Bracket Operations Div Sqrt Relative BinarySingleNaN