proposition: Lemma functor_mx_sub: forall n' m' x y n m M, mxF _ _ (@mx_sub _ A n' m' x y n m M) = mx_sub x y n m (mxF _ _ M).
proof: Proof. reflexivity. Qed.
imports: ATBR(Common) ATBR(Classes) ATBR(Monoid) ATBR(SemiLattice) ATBR(SemiRing) ATBR(KleeneAlgebra) ATBR(MxGraph) ATBR(MxSemiLattice) ATBR(MxSemiRing) ATBR(MxKleeneAlgebra) ATBR(Functors)