proposition: Lemma asimpl_f_quant q f s : (quant q f)[s] = quant q (f[$0 .: (s >> subst_term (S >> var))]).
proof: Proof. easy. Qed.
imports: Undecidability.FOL.Syntax(Core Facts) Coq.Classes.Init Relation_Definitions Coq.Classes.RelationClasses Coq.Classes.Morphisms Setoid