proposition: Lemma is_limit_cons_inv : forall b1 b2 n c, nf (cons b1 b2 n c) -> is_limit (cons b1 b2 n c) -> is_limit c \/ c = zero.
proof: Proof. inversion_clear 1;auto. inversion 1;auto. Qed.
imports: EPSILON0 Arith List Omega Compare_dec Relations Wellfounded Max Tools More_nat AccP not_decreasing EPSILON0 More_nat Gamma0_prelude Gamma0_length term rpo