proposition: Lemma eq_cvg (T T' : Type) (F : set_system T) (f g : T -> T') (x : set_system T') : f =1 g -> (f @ F --> x) = (g @ F --> x).
proof: Proof. by move=> /funext->. Qed.
imports: HB(structures) mathcomp(all_ssreflect all_algebra finmap generic_quotient) mathcomp(boolp classical_sets functions) mathcomp(cardinality mathcomp_extra fsbigop) reals signed