proposition: Lemma T_assoc (a b c d : C) (f : a ⇒ b) (g : b ⇒ c) (h : c ⇒ d) : f ∘ (g ∘ h) = (f ∘ g) ∘ h.
proof: Proof. apply (pr2 (pr2 (pr2 (pr2 C))) a b c d f g h (f ∘ g) (g ∘ h)). - apply T_func_T. - apply T_func_T. - apply T_func_T. - apply T_func_T. Defined.
imports: UniMath.Folds.UnicodeNotations UniMath.Foundations.PartD UniMath.Foundations.Propositions UniMath.Foundations.Sets