proposition: Lemma sum_n_m_ext_loc (a b : nat -> G) (n m : nat) : (forall k, (n <= k <= m)%nat -> a k = b k) -> sum_n_m a n m = sum_n_m b n m.
proof: Proof. intros. by apply iter_nat_ext_loc. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Markov Iter Lub