proposition: Lemma mulq_def x y : mulq x y = fracq (mulq_subdef (valq x) (valq y)).
proof: Proof. by case: x; case: y. Qed.
imports: HB(structures) mathcomp(ssreflect ssrfun ssrbool eqtype ssrnat seq choice) mathcomp(fintype bigop order ssralg countalg div ssrnum) mathcomp(ssrint prime archimedean)