proposition: Lemma stclosure_rclosure_eq_rstclosure : forall R, stclosure (rclosure R) = rstclosure R.
proof: Proof. Proof using. extens. intros x y. iff M. { induction* M. { applys* rstclosure_of_rclosure. } } { induction* M. } Qed.
imports: TLC(LibTactics LibLogic LibBool LibLogic LibProd LibSum)