proposition: Lemma bigmaxD1 j P F : P j -> \big[max/x]_(i | P i) F i = max (F j) (\big[max/x]_(i | P i && (i != j)) F i).
proof: Proof. by move/(bigD1 _) ->. Qed.
imports: HB(structures) mathcomp(ssreflect ssrfun ssrbool eqtype ssrnat choice seq) mathcomp(path fintype tuple bigop finset div prime finfun) mathcomp(finset)