proposition: Lemma nf_nat_irrelevance : forall a b n n' c, nf (cons a b n c) -> nf (cons a b n' c).
proof: Proof. inversion_clear 1; constructor;auto with T2. Qed.
imports: EPSILON0 Arith List Omega Compare_dec Relations Wellfounded Max Tools More_nat AccP not_decreasing EPSILON0 More_nat Gamma0_prelude Gamma0_length term rpo