proposition: Lemma ZToWord_Npow2_add_k : forall (sz : nat) (z : Z) (k: nat), ZToWord sz (z + Z.of_nat k * Z.of_N (Npow2 sz)) = ZToWord sz z.
proof: Proof. intros. replace z with (z + Z.of_nat k * Z.of_N (Npow2 sz) - Z.of_nat k * Z.of_N (Npow2 sz))%Z at 2 by lia. symmetry. apply ZToWord_Npow2_sub_k. Qed.
imports: Coq.Classes.Morphisms Coq.Classes.Morphisms_Prop Coq.Classes.Equivalence Coq.Arith.PeanoNat Coq.ZArith.BinInt  Coq.Arith.Arith Coq.NArith.NArith Coq.Bool.Bool Coq.ZArith.ZArith Coq.Logic.Eqdep_dec Coq.Logic.EqdepFacts Coq.Program.Tactics Coq.Program.Equality Coq.setoid_ring.Ring Coq.setoid_ring.Ring_polynom bbv.Nomega bbv.ZLib bbv.NatLib bbv.NLib bbv.N_Z_nat_conversions bbv.DepEq bbv.DepEqNat bbv.ReservedNotations Coq.micromega.Lia