proposition: Theorem B2FF_FF2B : forall x Hx, B2FF (FF2B x Hx) = x.
proof: Proof. now intros [sx|sx|sx plx|sx mx ex] Hx. Qed.
imports: Coq(ZArith Reals Psatz SpecFloat) Core Round Bracket Operations Div Sqrt Relative BinarySingleNaN