proposition: Lemma DH0_DH1_disp_nat_z_iso {DH0 DH1 :disp_functor H D' D''} (β: disp_nat_z_iso (DF ◦ DH0) (DF ◦ DH1) (nat_z_iso_id (F ∙ H))) : disp_nat_z_iso DH0 DH1 (nat_z_iso_id H).
proof: Proof. use tpair. - exact (DH0_DH1_nat_trans β). - apply DH0_DH1_is_disp_nat_z_iso. Defined.
imports: UniMath.Foundations.All UniMath.MoreFoundations.All UniMath.CategoryTheory.Core.Categories UniMath.CategoryTheory.Core.Functors UniMath.CategoryTheory.Core.NaturalTransformations UniMath.CategoryTheory.Core.Univalence UniMath.CategoryTheory.Core.Isos UniMath.CategoryTheory.DisplayedCats.Core UniMath.CategoryTheory.DisplayedCats.Functors UniMath.CategoryTheory.DisplayedCats.NaturalTransformations UniMath.CategoryTheory.DisplayedCats.Isos UniMath.CategoryTheory.DisplayedCats.Univalence UniMath.CategoryTheory.DisplayedCats.Fibrations UniMath.CategoryTheory.DisplayedCats.StreetFibration