proposition: Lemma lt_tail: forall a b n c, nf (cons a b n c) -> c < cons a b n c.
proof: Proof. intros. replace c with (tail (cons a b n c)). apply lt_tail0. simpl;auto with T2. discriminate. trivial. Qed.
imports: EPSILON0 Arith List Omega Compare_dec Relations Wellfounded Max Tools More_nat AccP not_decreasing EPSILON0 More_nat Gamma0_prelude Gamma0_length term rpo