proposition: Theorem comp_spec_eq_trans_l : forall (A B : Set){eqd : EqDec A}{eqd : EqDec B}(c1 c2 : Comp A)(c3 : Comp B) P, comp_spec eq c1 c2 -> comp_spec P c2 c3 -> comp_spec P c1 c3.
proof: Proof. intuition. despec. intuition. exists x. intuition. eapply comp_spec_eq_impl_eq in H; intuition. rewrite H. trivial. Qed.
imports: FCF.Crypto FCF.Bernoulli FCF.NotationV1