proposition: Lemma s_of_p1 p : [s_of p, 1%:pr] = 1%:pr.
proof: Proof. by apply/val_inj; rewrite /= s_of_pqE onem1 mulr0 onem0. Qed.
imports: mathcomp(all_ssreflect ssralg ssrnum) mathcomp(reals normedtype) mathcomp(mathcomp_extra boolp) mathcomp(lra ring Rstruct)