proposition: Lemma lcmsr_cons : forall a s, lcmsr (a :: s) = lcmr a (lcmsr s).
proof: Proof. by []. Qed.
imports: HB(structures) Coq(ssreflect ssrfun ssrbool Arith.Wf_nat) mathcomp(eqtype ssrnat div seq path) mathcomp(ssralg fintype perm tuple choice generic_quotient) mathcomp(matrix bigop zmodp mxalgebra poly) stronglydiscrete