proposition: Lemma sum_lb {A B eq_A eq_B} (A_lb : forall x y : A, x = y -> eq_A x y = true) (B_lb : forall x y : B, x = y -> eq_B x y = true) {x y} : x = y -> sum_beq eq_A eq_B x y = true.
proof: Proof. apply internal_sum_dec_lb; assumption. Qed.
imports: Coq.Lists.List Coq.Lists.SetoidList Coq.Bool.Bool Coq.Arith.PeanoNat Coq.Strings.Ascii Coq.Strings.String Coq.Logic.Eqdep_dec Fiat.Common