proposition: Lemma is_lim_seq_mult (u v : nat -> R) (l1 l2 l : Rbar) : is_lim_seq u l1 -> is_lim_seq v l2 -> is_Rbar_mult l1 l2 l -> is_lim_seq (fun n => u n * v n) l.
proof: Proof. intros Hu Hv Hp. eapply filterlim_comp_2 ; try eassumption. now apply filterlim_Rbar_mult. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lub Markov Hierarchy