proposition: Lemma nattorigS {X : rig} : ∏ (n : nat), nattorig (X := X) (S n) = (1 + nattorig n)%rig.
proof: Proof. intros. now apply (natmultS (X := rigaddabmonoid X)). Qed.
imports: UniMath.Foundations.NaturalNumbers UniMath.Algebra.RigsAndRings UniMath.Algebra.Groups UniMath.Algebra.DivisionRig UniMath.Algebra.Domains_and_Fields UniMath.Algebra.ConstructiveStructures UniMath.MoreFoundations.Tactics