proposition: Proposition eq_profunctor_square {C₁ C₂ D₁ D₂ : category} {F : C₁ ⟶ C₂} {G : D₁ ⟶ D₂} {P : D₁ ↛ C₁} {Q : D₂ ↛ C₂} {τ τ' : profunctor_square F G P Q} (p : ∏ (y : C₁) (x : D₁) (h : P y x), τ y x h = τ' y x h) : τ = τ'.
proof: Proof. use eq_profunctor_nat_trans. exact p. Qed.
imports: UniMath.Foundations.All UniMath.MoreFoundations.All UniMath.CategoryTheory.Core.Prelude UniMath.CategoryTheory.Categories.HSET.All UniMath.CategoryTheory.Categories.HSET.SetCoends UniMath.CategoryTheory.Profunctors.Core UniMath.CategoryTheory.Profunctors.Examples UniMath.CategoryTheory.Profunctors.Transformation