proposition: Lemma is_lim_seq_mult' (u v : nat -> R) (l1 l2 : R) : is_lim_seq u l1 -> is_lim_seq v l2 -> is_lim_seq (fun n => u n * v n) (l1 * l2).
proof: Proof. intros Hu Hv. eapply is_lim_seq_mult ; try eassumption. by []. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lub Markov Hierarchy