proposition: Lemma sub_comp_assoc s1 s2 s3 x : sub_comp (sub_comp s1 s2) s3 x = sub_comp s1 (sub_comp s2 s3) x.
proof: Proof. unfold sub_comp. rewrite sub_sub. refl. Qed.
imports: CoLoR(AInterpretation AContext VecUtil NatUtil LogicUtil ListUtil EqUtil)