proposition: Theorem rew_spminusf : forall (a b : Term A n) (nZb : ~ zeroP (A:=A) A0 eqA (n:=n) b) (p q : list (Term A n)), spminusf a b nZb p q = minuspf A A0 A1 eqA invA minusA multA eqA_dec n ltM ltM_dec p (mults (A:=A) multA (n:=n) (divTerm (A:=A) (A0:=A0) (eqA:=eqA) divA (n:=n) a (b:=b) nZb) q).
proof: Proof. simpl in |- *; auto. Qed.