proposition: Lemma phi_to_psi_5 : forall beta1 beta2 n gamma, omega <= gamma \/ (0 < n)%nat -> [alpha,cons beta1 beta2 n gamma] = phi alpha (cons beta1 beta2 n gamma).
proof: Proof. intros. rewrite phi_of_any_cons;auto with T2. Qed.
imports: EPSILON0 Arith List Omega Compare_dec Relations Wellfounded Max Tools More_nat AccP not_decreasing EPSILON0 More_nat Gamma0_prelude Gamma0_length term rpo