proposition: Lemma pp_mulX : forall p, pp (p * 'X) %= pp p * 'X.
proof: Proof. by move=> p; rewrite (eqd_trans (pp_mul _ _)) // eqd_mul // ppX. Qed.
imports: HB(structures) mathcomp(ssreflect ssrfun ssrbool eqtype ssrnat div seq) mathcomp(path choice fintype tuple finset ssralg) mathcomp(matrix poly) mathcomp(bigop polydiv) CoqEAL(stronglydiscrete dvdring)