proposition: Lemma if_aggregate {A} (b1 b2 : bool) (x y : A) : (if b1 then x else if b2 then x else y) = (if (b1 || b2)%bool then x else y).
proof: Proof. destruct b1, b2; reflexivity. Qed.
imports: Coq.Lists.List Coq.ZArith.ZArith Coq.Lists.SetoidList Coq.Setoids.Setoid Coq.Classes.RelationClasses Coq.Program.Program Coq.Classes.Morphisms Fiat.Common.Tactics.SplitInContext Fiat.Common.Tactics.Combinators Fiat.Common.Tactics.FreeIn Fiat.Common.Tactics.SetoidSubst Fiat.Common.Tactics.BreakMatch Fiat.Common.Tactics.Head Fiat.Common.Tactics.FoldIsTrue Fiat.Common.Tactics.SpecializeBy Fiat.Common.Tactics.DestructHyps Fiat.Common.Tactics.DestructSig Fiat.Common.Tactics.DestructHead Fiat.Common.Coq__8_4__8_5__Compat