proposition: Lemma lt_cons_omega_inv : forall alpha beta n gamma, cons alpha beta n gamma < omega -> nf (cons alpha beta n gamma) -> alpha = zero /\ beta = zero /\ gamma = zero.
proof: Proof. inversion_clear 1; lt_clean. replace beta with zero. inversion 1; lt_clean;auto with T2. inversion H5; lt_clean. inversion H0;lt_clean;auto with T2. inversion H1; lt_clean;auto with T2. Qed.
imports: EPSILON0 Arith List Omega Compare_dec Relations Wellfounded Max Tools More_nat AccP not_decreasing EPSILON0 More_nat Gamma0_prelude Gamma0_length term rpo