proposition: Lemma Derive_n_scal_r (f : R -> R) (n : nat) (a x : R) : Derive_n (fun y => f y * a) n x = Derive_n f n x * a.
proof: Proof. rewrite Rmult_comm -Derive_n_scal_l. apply Derive_n_ext => y ; ring. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lim_seq Iter Hierarchy Continuity Equiv