proposition: Lemma FrobeniusJcompl x G H : [Frobenius G :^ x with complement H :^ x] = [Frobenius G with complement H].
proof: Proof. by congr (_ && _); rewrite ?(can_eq (conjsgK x)) // -conjD1g normedTI_J. Qed.
imports: mathcomp(ssreflect ssrfun ssrbool eqtype ssrnat div) mathcomp(fintype bigop prime finset fingroup morphism) mathcomp(perm action quotient gproduct cyclic center) mathcomp(pgroup nilpotent sylow hall abelian)