proposition: Lemma fold_right_map {A B C} (f : A -> B) g c ls : @fold_right C B g c (map f ls) = fold_right (g ∘ f) c ls.
proof: Proof. induction ls; unfold compose; simpl; f_equal; auto. Qed.
imports: Coq.Lists.List Coq.ZArith.ZArith Coq.Lists.SetoidList Coq.Setoids.Setoid Coq.Classes.RelationClasses Coq.Program.Program Coq.Classes.Morphisms Fiat.Common.Tactics.SplitInContext Fiat.Common.Tactics.Combinators Fiat.Common.Tactics.FreeIn Fiat.Common.Tactics.SetoidSubst Fiat.Common.Tactics.BreakMatch Fiat.Common.Tactics.Head Fiat.Common.Tactics.FoldIsTrue Fiat.Common.Tactics.SpecializeBy Fiat.Common.Tactics.DestructHyps Fiat.Common.Tactics.DestructSig Fiat.Common.Tactics.DestructHead Fiat.Common.Coq__8_4__8_5__Compat