proposition: Lemma is_lim_seq_le (u v : nat -> R) (l1 l2 : Rbar) : (forall n, u n <= v n) -> is_lim_seq u l1 -> is_lim_seq v l2 -> Rbar_le l1 l2.
proof: Proof. intros H. apply filterlim_le. now apply filter_forall. Qed.
imports: Coq(Reals Psatz ssreflect) Rcomplements Rbar Lub Markov Hierarchy