proposition: Lemma monoidfunidleft {A B : monoid} (f : monoidfun A B) : monoidfuncomp (idmonoidiso A) f = f.
proof: Proof. use monoidfun_paths. use idpath. Qed.
imports: UniMath.Algebra.BinaryOperations UniMath.MoreFoundations.Subtypes UniMath.MoreFoundations.Sets UniMath.MoreFoundations.Orders