proposition: Lemma integral_mkcondl D P f : \int[mu]_(x in P `&` D) f x = \int[mu]_(x in D) (f \_ P) x.
proof: Proof. by rewrite setIC integral_mkcondr. Qed.
imports: HB(structures) mathcomp(all_ssreflect ssralg ssrnum ssrint interval finmap) mathcomp(mathcomp_extra boolp classical_sets functions) mathcomp(cardinality fsbigop ) signed reals ereal topology normedtype sequences real_interval esum measure lebesgue_measure numfun