proposition: Theorem exist_irrel : forall A (P : A -> Prop) x1 pf1 x2 pf2, (forall x (pf1' pf2' : P x), pf1' = pf2') -> x1 = x2 -> exist P x1 pf1 = exist P x2 pf2.
proof: Proof. intros; subst; f_equal; auto. Qed.
imports: Fiat.Common.Coq__8_4__8_5__Compat CertifiedExtraction.Extraction.BinEncoders.Basics Coq.Lists.List Bedrock.Word