GCD Partition
While at Kira's house, Josuke saw a piece of paper on the table with a task written on it.The task sounded as follows. There is an array $$$a$$$ of length $$$n$$$. On this array, do the following:  select an integer $$$k > 1$$$;  split the array into $$$k$$$ subsegments $$$^\dagger$$$;  calculate the sum in each of $$$k$$$ subsegments and write these sums to another array $$$b$$$ (where the sum of the subsegment $$$(l, r)$$$ is $$${\sum_{j = l}^{r}a_j}$$$);  the final score of such a split will be $$$\gcd(b_1, b_2, \ldots, b_k)^\ddagger$$$. The task is to find such a partition that the score is maximum possible. Josuke is interested in this task but is not strong in computer science. Help him to find the maximum possible score.$$$^\dagger$$$ A division of an array into $$$k$$$ subsegments is $$$k$$$ pairs of numbers $$$(l_1, r_1), (l_2, r_2), \ldots, (l_k, r_k)$$$ such that $$$l_i \le r_i$$$ and for every $$$1 \le j \le k - 1$$$ $$$l_{j + 1} = r_j + 1$$$, also $$$l_1 = 1$$$ and $$$r_k = n$$$. These pairs represent the subsegments.$$$^\ddagger$$$ $$$\gcd(b_1, b_2, \ldots, b_k)$$$ stands for the greatest common divisor (GCD) of the array $$$b$$$.
In the first test case, you can choose $$$k = 2$$$ and split the array into subsegments $$$(1, 2)$$$ and $$$(3, 4)$$$.Then the score of such a partition will be equal to $$$\gcd(a_1 + a_2, a_3 + a_4) = \gcd(2 + 2, 1 + 3) = \gcd(4, 4) = 4$$$.In the fourth test case, you can choose $$$k = 3$$$ and split the array into subsegments $$$(1, 2), (3, 5), (6, 6)$$$.The split score is $$$\gcd(1 + 2, 1 + 1 + 1, 3) = 3$$$.
The first line contains a single number $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases.For each test case, the first line contains one integer $$$n$$$ ($$$2 \le n \le 2 \cdot 10^5$$$) — the length of the array $$$a$$$.The second line contains $$$n$$$ integers $$$a_1, a_2, a_3, \ldots, a_n$$$ ($$$1 \le a_i \le 10^9 $$$) — the array $$$a$$$ itself.It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.
For each test case print a single integer — the maximum score for the optimal partition.
import math
for s in [*open(0)][2::2]:
    (*a, s) = map(int, s.split())
    s += sum(a)
    m = r = 0
    for x in a:
        r += x
        m = max(m, math.gcd(s, r))
    print(m)
from math import gcd

def solve():
    n = int(input())
    a = list(map(int, input().split()))
    s = sum(a)
    ans = 0
    pref = 0
    for i in range(n - 1):
        pref += a[i]
        ans = max(ans, gcd(pref, s - pref))
    return ans
if __name__ == '__main__':
    t = int(input())
    for _ in range(t):
        print(solve())
import math
for s in [*open(0)][2::2]:
    (*a, l) = map(int, s.split())
    s = sum(a) + l
    m = r = 0
    for x in a:
        r += x
        m = max(m, math.gcd(s, r))
    print(m)