Sasha and the Beautiful Array
Sasha decided to give his girlfriend an array $$$a_1, a_2, \ldots, a_n$$$. He found out that his girlfriend evaluates the beauty of the array as the sum of the values $$$(a_i - a_{i - 1})$$$ for all integers $$$i$$$ from $$$2$$$ to $$$n$$$.Help Sasha and tell him the maximum beauty of the array $$$a$$$ that he can obtain, if he can rearrange its elements in any way.
In the first test case, the elements of the array $$$a$$$ can be rearranged to make $$$a = [1, 2, 3]$$$. Then its beauty will be equal to $$$(a_2 - a_1) + (a_3 - a_2) = (2 - 1) + (3 - 2) = 2$$$.In the second test case, there is no need to rearrange the elements of the array $$$a$$$. Then its beauty will be equal to $$$0$$$.
Each test consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 500$$$) — the number of test cases. The description of the test cases follows.The first line of each test case contains a single integer $$$n$$$ ($$$2 \leq n \leq 100$$$) — the length of the array $$$a$$$.The second line of each test case contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \leq a_i \leq 10^9$$$) — the elements of the array $$$a$$$.
For each test case, output a single integer — the maximum beauty of the array $$$a$$$ that can be obtained.
t = int(input())
while t > 0:
    n = int(input())
    ls = input().split()
    ls = list(map(int, ls))
    print(max(ls) - min(ls))
    t -= 1
for s in [*open(0)][2::2]:
    a = (*map(int, s.split()),)
    print(max(a) - min(a))
def max_beauty(n, arr):
    arr.sort()
    max_beauty = arr[-1] - arr[0]
    return max_beauty
t = int(input())
for _ in range(t):
    n = int(input())
    arr = list(map(int, input().split()))
    result = max_beauty(n, arr)
    print(result)