Notepad#
You want to type the string $$$s$$$, consisting of $$$n$$$ lowercase Latin letters, using your favorite text editor Notepad#.Notepad# supports two kinds of operations:   append any letter to the end of the string;  copy a continuous substring of an already typed string and paste this substring to the end of the string. Can you type string $$$s$$$ in strictly less than $$$n$$$ operations?
In the first testcase, you can start with typing "codef" ($$$5$$$ operations), then copy "o" ($$$1$$$ operation) from an already typed part, then finish with typing "rces" ($$$4$$$ operations). That will be $$$10$$$ operations, which is not strictly less than $$$n$$$. There exist other ways to type "codeforces". However, no matter what you do, you can't do less than $$$n$$$ operations.In the second testcase, you can type "labac" ($$$5$$$ operations), then copy "aba" ($$$1$$$ operation), finishing the string in $$$6$$$ operations.
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of testcases.The first line of each testcase contains a single integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the length of the string $$$s$$$.The second line contains a string $$$s$$$, consisting of $$$n$$$ lowercase Latin letters.The sum of $$$n$$$ doesn't exceed $$$2 \cdot 10^5$$$ over all testcases.
For each testcase, print "YES" if you can type string $$$s$$$ in strictly less than $$$n$$$ operations. Otherwise, print "NO".
for _ in range(int(input())):
    n = int(input())
    s = input()
    cur = {}
    for i in range(n - 1):
        t = s[i:i + 2]
        if t in cur:
            if cur[t] < i - 1:
                print('YES')
                break
        else:
            cur[t] = i
    else:
        print('NO')
def ii():
    return int(input())

def li():
    return list(map(int, input().split()))

def si():
    return input()

def mi():
    return map(int, input().split())

def di():
    return deque(map(int, input().split()))
import sys
input = sys.stdin.readline
aphlower = 'abcdefghijklmnopqrstuvwxyz'
aphupper = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for _ in range(ii()):
    n = ii()
    s = si()
    d = dict()
    flag = True
    for i in range(n - 1):
        a = s[i:i + 2]
        if a in d:
            if d[a] < i - 1:
                print('YES')
                flag = False
                break
        else:
            d[a] = i
    if flag:
        print('NO')
for _ in range(int(input())):
    n = int(input())
    s = input()
    cur = {}
    for i in range(n - 1):
        t = s[i:i + 2]
        if t in cur:
            if cur[t] < i - 1:
                print('YES')
                break
        else:
            cur[t] = i
    else:
        print('NO')