Equal or Not Equal
You had $$$n$$$ positive integers $$$a_1, a_2, \dots, a_n$$$ arranged in a circle. For each pair of neighboring numbers ($$$a_1$$$ and $$$a_2$$$, $$$a_2$$$ and $$$a_3$$$, ..., $$$a_{n - 1}$$$ and $$$a_n$$$, and $$$a_n$$$ and $$$a_1$$$), you wrote down: are the numbers in the pair equal or not.Unfortunately, you've lost a piece of paper with the array $$$a$$$. Moreover, you are afraid that even information about equality of neighboring elements may be inconsistent. So, you are wondering: is there any array $$$a$$$ which is consistent with information you have about equality or non-equality of corresponding pairs?
In the first test case, you can choose, for example, $$$a_1 = a_2 = a_3 = 5$$$.In the second test case, there is no array $$$a$$$, since, according to $$$s_1$$$, $$$a_1$$$ is equal to $$$a_2$$$, but, according to $$$s_2$$$, $$$a_2$$$ is not equal to $$$a_1$$$.In the third test case, you can, for example, choose array $$$a = [20, 20, 4, 50, 50, 50, 20]$$$.In the fourth test case, you can, for example, choose $$$a = [1, 3, 3, 7]$$$.
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases. Next $$$t$$$ cases follow.The first and only line of each test case contains a non-empty string $$$s$$$ consisting of characters E and/or N. The length of $$$s$$$ is equal to the size of array $$$n$$$ and $$$2 \le n \le 50$$$. For each $$$i$$$ from $$$1$$$ to $$$n$$$:   if $$$s_i =$$$ E then $$$a_i$$$ is equal to $$$a_{i + 1}$$$ ($$$a_n = a_1$$$ for $$$i = n$$$);  if $$$s_i =$$$ N then $$$a_i$$$ is not equal to $$$a_{i + 1}$$$ ($$$a_n \neq a_1$$$ for $$$i = n$$$). 
For each test case, print YES if it's possible to choose array $$$a$$$ that are consistent with information from $$$s$$$ you know. Otherwise, print NO.It can be proved, that if there exists some array $$$a$$$, then there exists an array $$$a$$$ of positive integers with values less or equal to $$$10^9$$$.
for s in [*open(0)][1:]:
    print('YNEOS'[s.count('N') == 1::2])
import sys
input = sys.stdin.readline
for _ in range(int(input())):
    print(['NO', 'YES'][input().count('N') != 1])
times = int(input())
ans = []
for time in range(times):
    x = input()
    leng = len(x)
    med = 0
    if leng == 2:
        if x[0] != x[1]:
            ans.append('NO')
            continue
        ans.append('YES')
        continue
    for i in x:
        if i == 'N':
            med += 1
    if med == 1:
        ans.append('NO')
        continue
    ans.append('YES')
for i in ans:
    print(i)