Not Quite Lee
Lee couldn't sleep lately, because he had nightmares. In one of his nightmares (which was about an unbalanced global round), he decided to fight back and propose a problem below (which you should solve) to balance the round, hopefully setting him free from the nightmares.A non-empty array $$$b_1, b_2, \ldots, b_m$$$ is called good, if there exist $$$m$$$ integer sequences which satisfy the following properties:  The $$$i$$$-th sequence consists of $$$b_i$$$ consecutive integers (for example if $$$b_i = 3$$$ then the $$$i$$$-th sequence can be $$$(-1, 0, 1)$$$ or $$$(-5, -4, -3)$$$ but not $$$(0, -1, 1)$$$ or $$$(1, 2, 3, 4)$$$).  Assuming the sum of integers in the $$$i$$$-th sequence is $$$sum_i$$$, we want $$$sum_1 + sum_2 + \ldots + sum_m$$$ to be equal to $$$0$$$. You are given an array $$$a_1, a_2, \ldots, a_n$$$. It has $$$2^n - 1$$$ nonempty subsequences. Find how many of them are good.As this number can be very large, output it modulo $$$10^9 + 7$$$.An array $$$c$$$ is a subsequence of an array $$$d$$$ if $$$c$$$ can be obtained from $$$d$$$ by deletion of several (possibly, zero or all) elements.
For the first test, two examples of good subsequences are $$$[2, 7]$$$ and $$$[2, 2, 4, 7]$$$:For $$$b = [2, 7]$$$ we can use $$$(-3, -4)$$$ as the first sequence and $$$(-2, -1, \ldots, 4)$$$ as the second. Note that subsequence $$$[2, 7]$$$ appears twice in $$$[2, 2, 4, 7]$$$, so we have to count it twice.  Green circles denote $$$(-3, -4)$$$ and orange squares denote $$$(-2, -1, \ldots, 4)$$$. For $$$b = [2, 2, 4, 7]$$$ the following sequences would satisfy the properties: $$$(-1, 0)$$$, $$$(-3, -2)$$$, $$$(0, 1, 2, 3)$$$ and $$$(-3, -2, \ldots, 3)$$$
The first line contains a single integer $$$n$$$ ($$$2 \le n \le 2 \cdot 10^5$$$) — the size of array $$$a$$$.The second line contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \le a_i \le 10^9$$$) — elements of the array.
Print a single integer — the number of nonempty good subsequences of $$$a$$$, modulo $$$10^9 + 7$$$.
import sys
mod = 10 ** 9 + 7
n = int(sys.stdin.readline())
arr = list(map(int, sys.stdin.readline().split()))
i = 0
cnt = {}
for x in arr:
    lb = x & -x
    cnt[lb] = cnt.get(lb, 0) + 1
c2 = [cnt.get(1 << i, 0) for i in range(32)]
while c2[-1] == 0:
    c2.pop()
x = 1
y = n - c2[0]
for i in c2[1:]:
    y -= i
    if i > 0:
        x = (x + pow(2, i - 1, mod) * pow(2, y, mod)) % mod
print((pow(2, n, mod) - x) % mod)
MD = 10 ** 9 + 7

def pow(x, y):
    if y == 0:
        return 1
    m = pow(x, y // 2)
    ans = m * m % MD
    return ans * x % MD if y & 1 else ans
n = int(input())
bit = [0] * 31
for num in map(int, input().split()):
    bit[bin(num)[::-1].index('1')] += 1
ans = pow(2, n) - 1
for i in range(1, 31):
    if bit[i]:
        ans = (ans - pow(2, sum(bit[i:]) - 1)) % MD
print(ans)
MD = 10 ** 9 + 7

def pow(x, y):
    if y == 0:
        return 1
    m = pow(x, y // 2)
    ans = m * m % MD
    return ans * x % MD if y & 1 else ans
n = int(input())
bit = [0] * 31
for num in map(int, input().split()):
    bit[bin(num)[::-1].index('1')] += 1
ans = pow(2, n) - 1
for i in range(1, 31):
    if bit[i]:
        ans = (ans - pow(2, sum(bit[i:]) - 1)) % MD
print(ans)