Challenging Valleys
You are given an array $$$a[0 \dots n-1]$$$ of $$$n$$$ integers. This array is called a "valley" if there exists exactly one subarray $$$a[l \dots r]$$$ such that:  $$$0 \le l \le r \le n-1$$$,  $$$a_l = a_{l+1} = a_{l+2} = \dots = a_r$$$,  $$$l = 0$$$ or $$$a_{l-1} > a_{l}$$$,  $$$r = n-1$$$ or $$$a_r < a_{r+1}$$$. Here are three examples:  The first image shows the array [$$$3, 2, 2, 1, 2, 2, 3$$$], it is a valley because only subarray with indices $$$l=r=3$$$ satisfies the condition.The second image shows the array [$$$1, 1, 1, 2, 3, 3, 4, 5, 6, 6, 6$$$], it is a valley because only subarray with indices $$$l=0, r=2$$$ satisfies the codition.The third image shows the array [$$$1, 2, 3, 4, 3, 2, 1$$$], it is not a valley because two subarrays $$$l=r=0$$$ and $$$l=r=6$$$ that satisfy the condition.You are asked whether the given array is a valley or not.Note that we consider the array to be indexed from $$$0$$$.
The first three test cases are explained in the statement.
The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 10^4$$$) — the number of test cases.The first line of each test case contains a single integer $$$n$$$ ($$$1 \leq n \leq 2\cdot10^5$$$) — the length of the array.The second line of each test case contains $$$n$$$ integers $$$a_i$$$ ($$$1 \leq a_i \leq 10^9$$$) — the elements of the array.It is guaranteed that the sum of $$$n$$$ over all test cases is smaller than $$$2\cdot10^5$$$.
For each test case, output "YES" (without quotes) if the array is a valley, and "NO" (without quotes) otherwise.You can output the answer in any case (for example, the strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive answer).
from itertools import *
for s in [*open(0)][2::2]:
    a = [k for (k, g) in groupby(map(int, s.split()))]
    print('YNEOS'[sum((x > y < z for (x, y, z) in zip([2000000000.0] + a, a, a[1:] + [2000000000.0]))) > 1::2])
from itertools import *
m = [8 ** 10]
for s in [*open(0)][2::2]:
    a = [k for (k, g) in groupby(map(int, s.split()))]
    print('YNEOS'[sum((x > y < z for (x, y, z) in zip(m + a, a, a[1:] + m))) > 1::2])
from itertools import *
for m in [*open(0)][2::2]:
    a = [k for (k, g) in groupby(map(int, m.split()))]
    print('YNEOS'[sum((x > y < z for (x, y, z) in zip([2000000000.0] + a, a, a[1:] + [2000000000.0]))) > 1::2])