Vlad and Shapes
Vladislav has a binary square grid of $$$n \times n$$$ cells. A triangle or a square is drawn on the grid with symbols $$$\texttt{1}$$$. As he is too busy being cool, he asks you to tell him which shape is drawn on the grid. A triangle is a shape consisting of $$$k$$$ ($$$k>1$$$) consecutive rows, where the $$$i$$$-th row has $$$2 \cdot i-1$$$ consecutive characters $$$\texttt{1}$$$, and the central 1s are located in one column. An upside down triangle is also considered a valid triangle (but not rotated by 90 degrees).  Two left pictures contain examples of triangles: $$$k=4$$$, $$$k=3$$$. The two right pictures don't contain triangles.  A square is a shape consisting of $$$k$$$ ($$$k>1$$$) consecutive rows, where the $$$i$$$-th row has $$$k$$$ consecutive characters $$$\texttt{1}$$$, which are positioned at an equal distance from the left edge of the grid.  Examples of two squares: $$$k=2$$$, $$$k=4$$$. For the given grid, determine the type of shape that is drawn on it.
The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases.The first line of each test case contains a single integer $$$n$$$ ($$$2 \leq n \leq 10$$$) — the size of the grid.The next $$$n$$$ lines each contain $$$n$$$ characters $$$\texttt{0}$$$ or $$$\texttt{1}$$$.The grid contains exactly one triangle or exactly one square that contains all the $$$\texttt{1}$$$s in the grid. It is guaranteed that the size of the triangle or square is greater than $$$1$$$ (i.e., the shape cannot consist of exactly one 1).
For each test case, output "SQUARE" if all the $$$\texttt{1}$$$s in the grid form a square, and "TRIANGLE" otherwise (without quotes).
def solve():
    rows = [input() for _ in range(int(input()))]
    for row in rows:
        if len(row) == len(row.replace('1', '')) + 1:
            print('TRIANGLE')
            return
    print('SQUARE')
for _ in range(int(input())):
    solve()
import math
mod = 998244353
suit = ['S', 'C', 'D', 'H']

def solve():
    n = int(input())
    arr = []
    for i in range(n):
        arr.append(input())
    flag = False
    for i in range(n):
        for j in range(n):
            if arr[i][j] == '1':
                flag = True
                if arr[i + 1][j] == '0' or arr[i][j + 1] == '0':
                    print('TRIANGLE')
                    return
                break
        if flag:
            break
    print('SQUARE')
t = int(input())
for i in range(t):
    solve()
t = int(input())
for _ in range(t):
    n = int(input())
    f = True
    for i in range(n):
        k = 0
        s = input()
        if f == False:
            continue
        for j in range(n):
            if s[j] == '1':
                k += 1
        if k == 1:
            f = False
    if f == False:
        print('TRIANGLE')
    else:
        print('SQUARE')