Merge Equals
You are given an array of positive integers. While there are at least two equal elements, we will perform the following operation. We choose the smallest value $$$x$$$ that occurs in the array $$$2$$$ or more times. Take the first two occurrences of $$$x$$$ in this array (the two leftmost occurrences). Remove the left of these two occurrences, and the right one is replaced by the sum of this two values (that is, $$$2 \cdot x$$$).Determine how the array will look after described operations are performed.For example, consider the given array looks like $$$[3, 4, 1, 2, 2, 1, 1]$$$. It will be changed in the following way: $$$[3, 4, 1, 2, 2, 1, 1]~\rightarrow~[3, 4, 2, 2, 2, 1]~\rightarrow~[3, 4, 4, 2, 1]~\rightarrow~[3, 8, 2, 1]$$$.If the given array is look like $$$[1, 1, 3, 1, 1]$$$ it will be changed in the following way: $$$[1, 1, 3, 1, 1]~\rightarrow~[2, 3, 1, 1]~\rightarrow~[2, 3, 2]~\rightarrow~[3, 4]$$$.
The first two examples were considered in the statement.In the third example all integers in the given array are distinct, so it will not change.
The first line contains a single integer $$$n$$$ ($$$2 \le n \le 150\,000$$$) — the number of elements in the array.The second line contains a sequence from $$$n$$$ elements $$$a_1, a_2, \dots, a_n$$$ ($$$1 \le a_i \le 10^{9}$$$) — the elements of the array.
In the first line print an integer $$$k$$$ — the number of elements in the array after all the performed operations. In the second line print $$$k$$$ integers — the elements of the array after all the performed operations.
input()
a = {}
for i in list(map(int, input().split())):
    while i in a:
        del a[i]
        i *= 2
    a[i] = 1
print(len(a))
print(*a)
input()
a = {}
for i in list(map(int, input().split())):
    while i in a:
        del a[i]
        i *= 2
    a[i] = 1
print(len(a))
print(*a)
def main():
    input()
    arr = list(map(int, input().split()))
    dict = {}
    for i in range(len(arr)):
        item = arr[i]
        while item in dict:
            del dict[item]
            item *= 2
        dict[item] = i
    numbers = [str(x[0]) for x in sorted(dict.items(), key=lambda x: x[1])]
    print(len(numbers))
    print(' '.join(numbers))
if __name__ == '__main__':
    main()