Yet Another Dividing into Teams
You are a coach of a group consisting of $$$n$$$ students. The $$$i$$$-th student has programming skill $$$a_i$$$. All students have distinct programming skills. You want to divide them into teams in such a way that:  No two students $$$i$$$ and $$$j$$$ such that $$$|a_i - a_j| = 1$$$ belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than $$$1$$$);  the number of teams is the minimum possible. You have to answer $$$q$$$ independent queries.
In the first query of the example, there are $$$n=4$$$ students with the skills $$$a=[2, 10, 1, 20]$$$. There is only one restriction here: the $$$1$$$-st and the $$$3$$$-th students can't be in the same team (because of $$$|a_1 - a_3|=|2-1|=1$$$). It is possible to divide them into $$$2$$$ teams: for example, students $$$1$$$, $$$2$$$ and $$$4$$$ are in the first team and the student $$$3$$$ in the second team.In the second query of the example, there are $$$n=2$$$ students with the skills $$$a=[3, 6]$$$. It is possible to compose just a single team containing both students.
The first line of the input contains one integer $$$q$$$ ($$$1 \le q \le 100$$$) — the number of queries. Then $$$q$$$ queries follow.The first line of the query contains one integer $$$n$$$ ($$$1 \le n \le 100$$$) — the number of students in the query. The second line of the query contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$1 \le a_i \le 100$$$, all $$$a_i$$$ are distinct), where $$$a_i$$$ is the programming skill of the $$$i$$$-th student.
For each query, print the answer on it — the minimum number of teams you can form if no two students $$$i$$$ and $$$j$$$ such that $$$|a_i - a_j| = 1$$$ may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than $$$1$$$)
t = int(input())
for _ in range(t):
    n = int(input())
    a = sorted(list(map(int, input().split())))
    for i in range(1, n):
        if a[i] - a[i - 1] == 1:
            print(2)
            break
    else:
        print(1)
for fi in range(int(input())):
    n = int(input())
    a = list(map(int, input().split()))
    a.sort()
    fin_of_the_fish = True
    for i in range(n - 1):
        if a[i + 1] - a[i] == 1:
            fin_of_the_fish = False
            break
    print(1 if fin_of_the_fish else 2)
import sys
for _ in range(int(input())):
    a = int(input(''))
    b = [int(i) for i in sys.stdin.readline().split()]
    c = 1
    for i in range(0, a):
        if b[i] + 1 in b:
            c = 2
            break
    print(c)