Making Towers
You have a sequence of $$$n$$$ colored blocks. The color of the $$$i$$$-th block is $$$c_i$$$, an integer between $$$1$$$ and $$$n$$$.You will place the blocks down in sequence on an infinite coordinate grid in the following way.   Initially, you place block $$$1$$$ at $$$(0, 0)$$$.  For $$$2 \le i \le n$$$, if the $$$(i - 1)$$$-th block is placed at position $$$(x, y)$$$, then the $$$i$$$-th block can be placed at one of positions $$$(x + 1, y)$$$, $$$(x - 1, y)$$$, $$$(x, y + 1)$$$ (but not at position $$$(x, y - 1)$$$), as long no previous block was placed at that position. A tower is formed by $$$s$$$ blocks such that they are placed at positions $$$(x, y), (x, y + 1), \ldots, (x, y + s - 1)$$$ for some position $$$(x, y)$$$ and integer $$$s$$$. The size of the tower is $$$s$$$, the number of blocks in it. A tower of color $$$r$$$ is a tower such that all blocks in it have the color $$$r$$$.For each color $$$r$$$ from $$$1$$$ to $$$n$$$, solve the following problem independently:   Find the maximum size of a tower of color $$$r$$$ that you can form by placing down the blocks according to the rules. 
In the first test case, one of the possible ways to form a tower of color $$$1$$$ and size $$$3$$$ is:   place block $$$1$$$ at position $$$(0, 0)$$$;  place block $$$2$$$ to the right of block $$$1$$$, at position $$$(1, 0)$$$;  place block $$$3$$$ above block $$$2$$$, at position $$$(1, 1)$$$;  place block $$$4$$$ to the left of block $$$3$$$, at position $$$(0, 1)$$$;  place block $$$5$$$ to the left of block $$$4$$$, at position $$$(-1, 1)$$$;  place block $$$6$$$ above block $$$5$$$, at position $$$(-1, 2)$$$;  place block $$$7$$$ to the right of block $$$6$$$, at position $$$(0, 2)$$$.   The blocks at positions $$$(0, 0)$$$, $$$(0, 1)$$$, and $$$(0, 2)$$$ all have color $$$1$$$, forming an tower of size $$$3$$$.In the second test case, note that the following placement is not valid, since you are not allowed to place block $$$6$$$ under block $$$5$$$:  It can be shown that it is impossible to form a tower of color $$$4$$$ and size $$$3$$$.
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. The first line of each test case contains a single integer $$$n$$$ ($$$1 \le n \le 10^5$$$).The second line of each test case contains $$$n$$$ integers $$$c_1, c_2, \ldots, c_n$$$ ($$$1 \le c_i \le n$$$).It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.
For each test case, output $$$n$$$ integers. The $$$r$$$-th of them should be the maximum size of an tower of color $$$r$$$ you can form by following the given rules. If you cannot form any tower of color $$$r$$$, the $$$r$$$-th integer should be $$$0$$$.
import sys
t = int(sys.stdin.readline())
for i in range(t):
    n = int(sys.stdin.readline())
    tmp = sys.stdin.readline().split(' ')
    c = list(map(int, tmp))
    ans = [0 for j in range(n)]
    prev = [-1 for j in range(n)]
    for j in range(len(c)):
        if prev[c[j] - 1] == -1:
            prev[c[j] - 1] = j
            ans[c[j] - 1] += 1
        elif (j - prev[c[j] - 1]) % 2 == 1:
            prev[c[j] - 1] = j
            ans[c[j] - 1] += 1
    ans = list(map(str, ans))
    print(' '.join(ans))
t = int(input())
for i in range(t):
    n = int(input())
    nums = [int(x) for x in input().split()]
    result = [0] * n
    meta = [-1] * (n + 1)
    for (index, num) in enumerate(nums):
        last_index = meta[num]
        if last_index == -1:
            result[num - 1] = 1
            meta[num] = index
        elif index % 2 != last_index % 2:
            result[num - 1] += 1
            meta[num] = index
    print(' '.join([str(r) for r in result]))
import sys
from collections import defaultdict
input = sys.stdin.readline
import math
''
''
t = int(input())
for _ in range(t):
    n = int(input())
    a = list(map(int, input().split()))
    ans = [0] * (n + 1)
    pos = [-1] * (n + 1)
    for i in range(n):
        if pos[a[i]] != -1:
            if (i - pos[a[i]] - 1) % 2 == 0:
                ans[a[i]] += 1
                pos[a[i]] = i
        else:
            ans[a[i]] += 1
            pos[a[i]] = i
    print(*ans[1:])