Fence Painting
You finally woke up after this crazy dream and decided to walk around to clear your head. Outside you saw your house's fence — so plain and boring, that you'd like to repaint it.  You have a fence consisting of $$$n$$$ planks, where the $$$i$$$-th plank has the color $$$a_i$$$. You want to repaint the fence in such a way that the $$$i$$$-th plank has the color $$$b_i$$$.You've invited $$$m$$$ painters for this purpose. The $$$j$$$-th painter will arrive at the moment $$$j$$$ and will recolor exactly one plank to color $$$c_j$$$. For each painter you can choose which plank to recolor, but you can't turn them down, i. e. each painter has to color exactly one plank.Can you get the coloring $$$b$$$ you want? If it's possible, print for each painter which plank he must paint.
The first line contains one integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. Then $$$t$$$ test cases follow.The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n, m \le 10^5$$$) — the number of planks in the fence and the number of painters.The second line of each test case contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$1 \le a_i \le n$$$) — the initial colors of the fence.The third line of each test case contains $$$n$$$ integers $$$b_1, b_2, \dots, b_n$$$ ($$$1 \le b_i \le n$$$) — the desired colors of the fence.The fourth line of each test case contains $$$m$$$ integers $$$c_1, c_2, \dots, c_m$$$ ($$$1 \le c_j \le n$$$) — the colors painters have.It's guaranteed that the sum of $$$n$$$ doesn't exceed $$$10^5$$$ and the sum of $$$m$$$ doesn't exceed $$$10^5$$$ over all test cases.
For each test case, output "NO" if it is impossible to achieve the coloring $$$b$$$.Otherwise, print "YES" and $$$m$$$ integers $$$x_1, x_2, \dots, x_m$$$, where $$$x_j$$$ is the index of plank the $$$j$$$-th painter should paint.You may print every letter in any case you want (so, for example, the strings "yEs", "yes", "Yes" and "YES" are all recognized as positive answer).
import collections
import sys
p2D = lambda x: print(*x, sep='\n')

def II():
    return int(sys.stdin.buffer.readline())

def MI():
    return map(int, sys.stdin.buffer.readline().split())

def LI():
    return list(map(int, sys.stdin.buffer.readline().split()))

def LLI(rows_number):
    return [LI() for _ in range(rows_number)]

def BI():
    return sys.stdin.buffer.readline().rstrip()

def SI():
    return sys.stdin.buffer.readline().rstrip().decode()

def li():
    return [int(i) for i in input().split()]

def lli(rows):
    return [li() for _ in range(rows)]

def si():
    return input()

def ii():
    return int(input())

def ins():
    return input().split()

def drank(d, processing, da, rank):
    tmp = 10 ** 9
    if len(d[da]) == 1:
        return 1
    for di in d[da]:
        if processing[di - 1] == 0:
            processing[di - 1] = 1
            tmp = min(tmp, drank(d, processing, di, rank))
            processing[di - 1] = 0
    rank[da - 1] = tmp + 1
    return tmp + 1

def binary_search(n, a):
    l = len(a)
    low = 0
    high = l - 1
    while high >= low:
        mid = (high + low) // 2
        if a[mid] == n:
            return mid
        elif a[mid] > n:
            high = mid - 1
        else:
            low = mid + 1
    return -1
mod = 10 ** 9 + 7

def solve():
    (n, m) = LI()
    a = LI()
    b = LI()
    c = LI()
    als = collections.defaultdict(list)
    for i in range(m):
        als[c[i]].append(i)
    bis = [0] * n
    ans = [0] * m
    for i in range(n):
        bis[b[i] - 1] = i + 1
    for i in range(n):
        if b[i] != a[i]:
            if als[b[i]]:
                ans[als[b[i]].pop()] = i + 1
            else:
                return 'NO'
    ans.reverse()
    for i in range(m):
        if ans[i] == 0:
            if bis[c[m - i - 1] - 1]:
                ans[i] = bis[c[m - i - 1] - 1]
            else:
                if i == 0:
                    return 'NO'
                ans[i] = ans[i - 1]
    ans.reverse()
    return 'YES\n' + ' '.join(map(str, ans))

def main():
    for _ in range(II()):
        sys.stdout.write(str(solve()) + '\n')
if __name__ == '__main__':
    main()
from sys import stdin, stdout

def get_ints():
    return map(int, stdin.readline().split())

def PRINT(s):
    stdout.write(s + '\n')

def logic(n, m, A, B, C):
    differences = [[] for i in range(n)]
    for i in range(n):
        x = B[i]
        if A[i] != x:
            differences[x - 1].append(i)
    last = C[-1]
    if differences[last - 1] != []:
        throw = differences[last - 1].pop()
    else:
        throw = -1
        for i in range(n):
            if A[i] == B[i] == last:
                throw = i
                break
        if throw == -1:
            return 'NO'
    C.pop()
    ret = []
    for c in C:
        try:
            ret.append(differences[c - 1].pop() + 1)
        except:
            ret.append(throw + 1)
    for a in differences:
        if a != []:
            return 'NO'
    ret.append(throw + 1)
    return 'YES\n' + ' '.join([str(x) for x in ret])
for w in range(int(stdin.readline())):
    (n, m) = get_ints()
    A = [int(x) for x in stdin.readline().split()]
    B = [int(x) for x in stdin.readline().split()]
    C = [int(x) for x in stdin.readline().split()]
    PRINT(logic(n, m, A, B, C))
from collections import Counter
import sys

def solve():
    (n, m) = map(int, sys.stdin.readline().split())
    start = list(map(int, sys.stdin.readline().split()))
    end = list(map(int, sys.stdin.readline().split()))
    colors = list(map(int, sys.stdin.readline().split()))
    freqNeeded = Counter(end)
    freqHave = Counter(colors)
    remove_dump = 0
    if colors[-1] not in freqNeeded:
        print('NO')
        return
    location = [[] for x in range(n + 1)]
    for (i, color) in enumerate(start):
        if color == end[i]:
            freqNeeded[color] -= 1
            if remove_dump == 0 and color == colors[-1]:
                remove_dump = i
        else:
            location[end[i]].append(i)
    dumploc = location[colors[-1]][0] if location[colors[-1]] else remove_dump
    valid = True
    for color in freqNeeded:
        if freqNeeded[color] > freqHave[color]:
            valid = False
    if valid:
        output = []
        for (i, color) in enumerate(colors):
            if location[color]:
                output.append(str(location[color][-1] + 1))
                location[color].pop()
            else:
                output.append(str(dumploc + 1))
        print('YES')
        print(' '.join(output))
    else:
        print('NO')
if __name__ == '__main__':
    for _ in range(int(sys.stdin.readline())):
        solve()