A metal forms two oxides. The higher oxide contains 80% metal. 0.72 g of of the lower oxide gives 0.8g of the higher oxide when oxidized. Illustrate using the law of multiple proportions

Asked by lekhakarthikeyan | 27th May, 2017, 11:42: PM

Expert Answer:

In higher oxide


Wt of metal= 0.8x80/100=0.64g


Wt. Of oxygen=0.8-0.64=0.16g


In lower Oxide


Wt. of metal will remain the same as in higher oxide=0.64g

wt. of oxygen =0.72-0.64=0.08g


The ratio of weight of oxygen which combines with a fixed weight of metal in two oxides is




As it is a whole number ratio . The law of multiple proportion is illustrated.


Answered by Vaibhav Chavan | 28th May, 2017, 12:18: PM
