A particle has a charge of +1.9 μC and moves frompoint A to point B, a distance of0.29 m. The particle experiences a constant electric force, and itsmotion is along the line of action of the force. The differencebetween the particle's electric potential energyat A and B isEPEA - EPEB =+9.9 x 10-4 J.
Looking for simply PartB!

(b) Findthe magnitude of the electric field that the particleexperiences.