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Who can explain why

select case when '' = ' ' then 1 else 0 end, LEN(''), LEN(' '), DATALENGTH(''), DATALENGTH(' ');


1           0           0           0           1

The funny consequence of this is that in

create table test ( val varchar(10) );
insert into test values( '' );
update test set val = ' ' where val = '';

the update will indeed replace the empty string by a blank, but the where clause keeps to be true and repeated executions of the update statement tell

(1 row(s) affected)
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1 Answer 1

up vote 15 down vote accepted

Trailing blanks explained:

SQL Server follows the ANSI/ISO SQL-92 specification (Section 8.2, , General rules #3) on how to compare strings with spaces. The ANSI standard requires padding for the character strings used in comparisons so that their lengths match before comparing them. The padding directly affects the semantics of WHERE and HAVING clause predicates and other Transact-SQL string comparisons. For example, Transact-SQL considers the strings 'abc' and 'abc ' to be equivalent for most comparison operations.

The only exception to this rule is the LIKE predicate. When the right side of a LIKE predicate expression features a value with a trailing space, SQL Server does not pad the two values to the same length before the comparison occurs. Because the purpose of the LIKE predicate, by definition, is to facilitate pattern searches rather than simple string equality tests, this does not violate the section of the ANSI SQL-92 specification mentioned earlier.

Here's a well known example of all the cases mentioned above:

DECLARE @b varchar(10)

SET @a = '1'
SET @b = '1 ' --with trailing blank

    @a = @b 
AND @b LIKE @a

Here's some more detail about trailing blanks and the LIKE clause.

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