
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!

Dynamics: curvlinear motion

  1. May 22, 2014 #1
    A water droplet condenses at r0=0.80 m. The turbine is rotating at a fixed speed of N RPM.

    You can treat the water droplet as a point mass of m=0.002 kg. Starting from rest at its formation point, it starts moving outward on the radial vane as shown. Its mass stays constant during this motion (no new condensation nor evaporation).
    Calculate the time (in seconds) it takes for the droplet to move from the point of formation (ro) to the radius r.
    r0= 0.08m
    r= 4.13m
    w= 402rad/s

    2. Relevant equations

    V = w√(r^2-r0^2) = dr/dt

    3. The attempt at a solution

    ∫dt = ∫(dr/w√(r^2-r0^2))

    dt is from 0->t and dr is ro->r

    I know that this is the equation for determining the time taken but I do now how to to integrate that function. I have been told it is t= 1/w*ln(r+√r^2-r0^2). But when i attempted to calculate the time it was always wrong.
  2. jcsd
  3. May 22, 2014 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    Why don't you show your calculations?
  4. May 22, 2014 #3


    User Avatar

    Staff: Mentor

    Is the square root term in the numerator or denominator? If the latter, then you need another set of parentheses to show it.

Have something to add?
Draft saved Draft deleted

Similar Discussions: Dynamics: curvlinear motion
  1. Dynamics help - Motion (Replies: 1)