The rotor of the helicopter makes 600 revolutions in 0.5 minutes. What is the period of rotation of the screw?

Task data: t (duration of rotation of the helicopter rotor) = 0.5 min (in SI t = 30 s); n (the number of revolutions that the screw made) = 600 revolutions.

The period of rotation of the rotor of the helicopter can be calculated by the formula: T = t / n.

Calculation: T = 30/600 = 0.05 s or 50 ms.

Answer: b) the helicopter rotor has a rotation period of 50 ms.
