A particle has a charge of +1.5 µC and moves from pointA to point B, a distance of 0.19 m. The particle experiences a constant electricforce, and its motion is along the line of action of the force. Thedifference between the particle's electric potential energy atA and B is EPEA - EPEB =+5.50 10-4 J.
(a) Find the magnitude and direction of theelectric force that acts on the particle.
magnitude 1 N
direction 2

(b) Find the magnitude and direction of the electric field that theparticle experiences.
magnitude 3 N/C
direction 4

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