Consider the combination of capacitors in the figure below(C1 = 25.0 µF,C2 = 1.50 µF).
(a) Find the equivalent single capacitance ofthe two capacitors in series and redraw the diagram (called diagram1) with this equivalent capacitance.
1 µF

(b) In diagram 1 find the equivalent capacitance of the threecapacitors in parallel and redraw the diagram as a single batteryand single capacitor in a loop.

(c) Compute the charge on the single equivalent capacitor.

(d) Returning to diagram 1, compute the charge on each individualcapacitor.
4.00 µF capacitor
4 µC

1.50 µF capacitor
5 µC

far right capacitor
6 µC

Does the sum agree with the value found in part (b)?

(e) What is the charge on the 25.0µF capacitor and on the 8-µF capacitor?
8 µC

(f) Compute the voltage drop across the 25.0 µF capacitor.
9 V

(g) Compute the voltage drop across the 1.50 µF capacitor.
10 V


Get this answer with Chegg Study