The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by the expression v\left( t \right) = \left( -3.0 \times 10^{7} \right) t^{2} + \left( 2.5 \times 10^{5} \right) t, where v is in m/s and t is in seconds. If the bullet is accelerated for 2.6ms (milliseconds), what is the length of the barrel?

Show the work, it is not 1.02 m.

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