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Proving Bloch's Theorem

  1. Feb 26, 2012 #1
    One of the more common ways of showing that a Hamiltonian with periodic potential commutes with the translation operator is to write the following (like Ashcroft and Mermin p. 133)


    I suspect this might be a dumb question, but what allows us to write [itex]T(R)H(r)\psi(r)=H(r+R)\psi(r+R)[/itex], that is why is the translation operator acting on both the Hamiltonian and the wave, and not just on the Hamiltonian?
  2. jcsd
  3. May 2, 2012 #2
    I think its because the potential is periodic then the Hamiltonian is too: H(x)=H(x+a), you can then sub this in directly and the translation operator now just acts on psi
  4. May 2, 2012 #3


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    Because that is the definition of how the space translation operator acts on a ket.

    It may help to write [itex]\theta(r) = H(r) \psi(r)[/itex]. [itex]\theta(r)[/itex] is a ket. What [itex]T(R) \theta(r)[/itex]....

    It may help more to consider more traditional function notation for what I believe is being written:
    [tex] (T(R) H \psi)(r) = (H \psi)(r + R).[/tex]

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