If two deuterium nuclei (charge + e, mass 3.34 \times 10^{ - 27} {\rm{ kg}}) get close enough together, the attraction of thestrong nuclear force will fuse them to make an isotope of helium,releasing vast amounts of energy. The range of this force is about10^{ - 15} {\rm{ m}}. This is the principle behind the fusion reactor.The deuterium nuclei are moving much too fast to be contained byphysical walls, so they are confined magnetically.
a) How fast would two nuclei have to move so that in a head-oncollision they would get close enough to fuse? (Treat the nuclei aspoint charges, and assume that a separation of 1.0 \times 10^{ - 15}{\rm{ m}} is required for fusion.)
Express your answer using twosignificant figures.
b) What strength magnetic field isneeded to make deuterium nuclei with this speed travel in a circleof diameter 3.00 m?
Express your answer using twosignificant figures.
What formula do I use??? How do Iapproach the problem? Please help!!!


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