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Polar coordinates

  1. Feb 10, 2008 #1

    The angle is 59.1, which is in the second quadrant. Give the angle from the positive x-axis.

    2. Relevant equations

    3. The attempt at a solution


    Does that look right?

    Thank you very much
  2. jcsd
  3. Feb 10, 2008 #2
    Quadrant one is from 0 to 90 degrees. Quadrant two is 90 to 180.
  4. Feb 11, 2008 #3
    Thank you very much

    Do you see where I went wrong?

    A vector has an x component of -24.5 unites and a y component of 41.0 units. Find the magnitude and direction of this vector (from the positive x-axis)

    I got 47.8 by doing (41.0)^2 + (-24.5)^2=c^2
    c=47.8 units

    In order to find the magnitude I did sin(theta)=41.0/47.8
    =59.1 I need the magnitude from the positive x-axis. Would I then take 180-59.1?

    Thank you

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