First Order Linear ODE

Image text transcribed for accessibility: In the circuit shown in Figure 2 below, a battery supplies a constant voltage of 40V. Figure 2: RL Electric circuit Given the inductance L = 2H and R = 10Ohm, obtain the following: The differential equation that represents the RL circuit. The general solution for the current that flows through the RL circuit. Hint: Use your knowledge of circuit theory to obtain the differential equation. Remember that the voltage drop across the inductor is given LdI/dt. 1/L dl/dt + Rl = E l = 4 + ce-5t Rdl/dt + 1/C = 0 l = ce-5t Ldl/dt + l/R = 0 1 = 0.4 + ce-5t Ldl/dt + Rl = E 1 = 4 + ce-5t None of the above: see Problem Work