Metric Space of Ontic Points has a Completion

To build geometric space let us introduce point-like constructs.

Ontic point: Let ξ ⊂ Θ be a family of things. We say that ξ is a complete family of united things if it satisfies:

1. Any two things of ξ are united.

2. For anything x̸ ∉ ξ there is a thing y ∈ ξ separated of x.

Now we define a distance between ontic points

Distance between ontic points:  The distance between ontic points is:

dG(ξ,η) = sup(i,j) d(xi, yj), where i ∈ I , j ∈ J belong to the respective index sets.


Theorem (Metricity): The set of ontic points is a metric space with distance dG.

Proof: The first three distance conditions are satisfied because d is a pseudo-metric. To show that the fourth is satisfied observe that if ξ ≠ η, there are xi≀yand d(xi, yj) > 0. So we find

ξ ≠ η ⇒ dG(ξ, η) > 0

dG(ξ, η) > 0 ⇒ ξ = η

The isometric completion theorem guarantees that the metric space of ontic points has a completion. This justifies the definition of Geometric space: The completion of ontic space is the geometric space EG.


Leave a Reply


You are commenting using your account. Log Out / Change )

Twitter picture


Facebook photo


Google+ photo


Connecting to %s