determine three consecutive even integers, if the square of the largest integer less the square of the middle integer is 20 less than the square of the smallest integer

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  1. so, if the numbers are x-2, x and x+2, we have
    (x+2)^2 - x^2 = (x-2)^2 - 20
    solve for x and you get -2,10
    12^2 - 10^2 = 8^2 - 20 -- yep
    0^2 - 2^2 = (-4)^2 - 20 -- yep

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