def sort_dict ( d , key = None , reverse = False ) : kv_items = [ kv for kv in d . items ( ) ] # Sort kv_items according to key. if key is None : kv_items . sort ( key = lambda t : t [ 1 ] , reverse = reverse ) else : kv_items . sort ( key = key , reverse = reverse ) # Build ordered dict. return collections . OrderedDict ( kv_items )
python order a dictionary alphabetically
Sorts a dict by value .
def sort_dict(d, key=None, reverse=False):
    """
    Sorts a dict by value.

    Args:
        d: Input dictionary
        key: Function which takes an tuple (key, object) and returns a value to
            compare and sort by. By default, the function compares the values
            of the dict i.e. key = lambda t : t[1]
        reverse: Allows to reverse sort order.

    Returns:
        OrderedDict object whose keys are ordered according to their value.
    """
    kv_items = [kv for kv in d.items()]

    # Sort kv_items according to key.
    if key is None:
        kv_items.sort(key=lambda t: t[1], reverse=reverse)
    else:
        kv_items.sort(key=key, reverse=reverse)

    # Build ordered dict.
    return collections.OrderedDict(kv_items)