1056_D. Decorate Apple Tree_5134
There is one apple tree in Arkady's garden. It can be represented as a set of junctions connected with branches so that there is only one way to reach any junctions from any other one using branches. The junctions are enumerated from 1 to n, the junction 1 is called the root.

A subtree of a junction v is a set of junctions u such that the path from u to the root must pass through v. Note that v itself is included in a subtree of v.

A leaf is such a junction that its subtree contains exactly one junction.

The New Year is coming, so Arkady wants to decorate the tree. He will put a light bulb of some color on each leaf junction and then count the number happy junctions. A happy junction is such a junction t that all light bulbs in the subtree of t have different colors.

Arkady is interested in the following question: for each k from 1 to n, what is the minimum number of different colors needed to make the number of happy junctions be greater than or equal to k?

Input

The first line contains a single integer n (1 ≤ n ≤ 10^5) — the number of junctions in the tree.

The second line contains n - 1 integers p_2, p_3, ..., p_n (1 ≤ p_i < i), where p_i means there is a branch between junctions i and p_i. It is guaranteed that this set of branches forms a tree.

Output

Output n integers. The i-th of them should be the minimum number of colors needed to make the number of happy junctions be at least i.

Examples

Input


3
1 1


Output


1 1 2 


Input


5
1 1 3 3


Output


1 1 1 2 3 

Note

In the first example for k = 1 and k = 2 we can use only one color: the junctions 2 and 3 will be happy. For k = 3 you have to put the bulbs of different colors to make all the junctions happy.

In the second example for k = 4 you can, for example, put the bulbs of color 1 in junctions 2 and 4, and a bulb of color 2 into junction 5. The happy junctions are the ones with indices 2, 3, 4 and 5 then.
n=int(input())
p=[0,0]+list(map(int,input().split()))#tomamos la entrada
d=[0]*(n+1)#aki vamos a contar la cantidad d colores q necesita cada union
for i in range(n,1,-1):#empezamos x las hojas hasta llegar a la raiz
    if d[i]==0:#si no estas visitado eres una hoja => solo necesitas un color
        d[i]=1
    d[p[i]]+=d[i]#si no necesitas tantos colores como la cantidad q necesitan tus hijos
if n==1:#si la entrada es 1 solo necesitas un color
    d[1]=1
d=d[1:]#quitamos el vertice 0(al final todo empieza en 1-n)
d.sort()#ordenamos para dar la cantidad d colores en orden d los vertices(o sea, de k)
print(*d)