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Cada\n+    elemento será um objeto no formato:\n+    { number: [NUMBER] }\n+    Os números devem ser de 1 a 10.\n+    Mostre esse array no console.\n+    */\n+    console.log( 'Number Objects Array:' );\n+    // var numberObjects = [\n+    //     { number: 1 },\n+    //     { number: 2 },\n+    //     { number: 3 },\n+    //     { number: 4 },\n+    //     { number: 5 },\n+    //     { number: 6 },\n+    //     { number: 7 },\n+    //     { number: 8 },\n+    //     { number: 9 },\n+    //     { number: 10 }\n+    // ];\n+    var numberObjects = [];\n+    for ( i = 1; i <= 10; i++ ){\n+        numberObjects.push({ number: i });\n+    }\n+    console.log( numberObjects );\n \n-/*\n-Crie um array chamado numberObjects. Esse array deve ter 10 elementos. Cada\n-elemento será um objeto no formato:\n-{ number: [NUMBER] }\n-Os números devem ser de 1 a 10.\n-Mostre esse array no console.\n-*/\n-console.log( 'Number Objects Array:' );\n-// ?\n+    /*\n+    Crie um array chamado `justNumbers`, que terá como elementos somente os\n+    números do array criado acima. Mostre esse novo array no console.\n+    */\n+    console.log( '\\nJust Numbers:' );\n+    var justNumbers = numberObjects.map(function(item){\n+        return item.number;\n+    });\n+    console.log( justNumbers );\n \n-/*\n-Crie um array chamado `justNumbers`, que terá como elementos somente os\n-números do array criado acima. Mostre esse novo array no console.\n-*/\n-console.log( '\\nJust Numbers:' );\n-// ?\n+    /*\n+    Crie um novo array chamado `justMod2Or3`, que receberá do array criado acima\n+    somente os números que forem divisíveis por 2 ou 3. Mostre esse novo array\n+    no console.\n+    */\n+    console.log( '\\nJust module of division by 2 or 3:' );\n+    var justMod2Or3 = justNumbers.filter(function(item, index, array){\n+        return item % 2 === 0 || item % 3 === 0;\n+    });\n+    console.log( justMod2Or3 );\n \n-/*\n-Crie um novo array chamado `justMod2Or3`, que receberá do array criado acima\n-somente os números que forem divisíveis por 2 ou 3. Mostre esse novo array\n-no console.\n-*/\n-console.log( '\\nJust module of division by 2 or 3:' );\n-// ?\n+    /*\n+    Declare uma variável chamada operation que receba, do array criado acima,\n+    um valor reduzido pela seguinte operação:\n+    - Somar 1 ao último valor retornado;\n+    - Multiplicar o resultado pelo valor atual.\n+    O cálculo deve começar com zero.\n+    Mostre o resultado no console.\n+    */\n+    console.log( '\\nOperation:' );\n+    var operation = justMod2Or3.reduce(function(acumulado, atual){\n+        return ( acumulado + 1 ) * atual;\n+    }, 0);\n+    console.log( operation );\n \n-/*\n-Declare uma variável chamada operation que receba, do array criado acima,\n-um valor reduzido pela seguinte operação:\n-- Somar 1 ao último valor retornado;\n-- Multiplicar o resultado pelo valor atual.\n-O cálculo deve começar com zero.\n-Mostre o resultado no console.\n-*/\n-console.log( '\\nOperation:' );\n-// ?\n+    /*\n+    Faça o mesmo cálculo passado acima, mas começando do último item para o\n+    primeiro. O nome da variável deve ser operation2. Mostre o resultado no\n+    console.\n+    */\n+    console.log( '\\nOperation 2:' );\n+    var operation2 = justMod2Or3.reduceRight(function(acumulado, atual){\n+        return ( acumulado + 1 ) * atual;\n+    }, 0);\n+    console.log( operation2 );\n \n-/*\n-Faça o mesmo cálculo passado acima, mas começando do último item para o\n-primeiro. O nome da variável deve ser operation2. Mostre o resultado no\n-console.\n-*/\n-console.log( '\\nOperation 2:' );\n-// ?\n+    /*\n+    Crie um array chamado `name`. Cada elemento desse array deve ser uma sílaba\n+    do seu nome. Vamos reduzir esse array, juntando todas as sílabas, mas usando\n+    a \"língua do P\".\n+    PS.: Lembra da língua do \"P\"? Não? A língua do \"P\" é uma brincadeira\n+    infantil, onde você coloca a letra \"P\" antes de cada sílaba de uma palavra\n+    falada, como se você estivesse falando em código xD\n+    */\n+    console.log( '\\nSeu nome na língua do \"P\":' );\n+    var myName = [ 'Ve', 're', 'na' ];\n+    var pLanguage = myName.reduce(function(acumulado, atual){\n+        return acumulado + 'p' + atual;\n+    }, '');\n+    console.log( pLanguage );\n+    // Eu tive que trocar o nome da variável pq no console do navegador, que é onde eu testo, ele dá TypeError: name.reduce is not a function\n \n-/*\n-Crie um array chamado `name`. Cada elemento desse array deve ser uma sílaba\n-do seu nome. Vamos reduzir esse array, juntando todas as sílabas, mas usando\n-a \"língua do P\".\n-PS.: Lembra da língua do \"P\"? Não? A língua do \"P\" é uma brincadeira\n-infantil, onde você coloca a letra \"P\" antes de cada sílaba de uma palavra\n-falada, como se você estivesse falando em código xD\n-*/\n-console.log( '\\nSeu nome na língua do \"P\":' );\n-// ?\n+    /*\n+    Crie uma variável chamada `inversedName`, que reduzirá o array em uma string\n+    e atribuirá o seu nome invertido (usando o array criado acima).\n+    */\n+    console.log( '\\nInversed Name:' );\n+    var inversedName = myName.reduceRight(function(acumulado, atual){\n+        return acumulado + atual;\n+    });\n+    console.log( inversedName );\n \n-/*\n-Crie uma variável chamada `inversedName`, que reduzirá o array em uma string\n-e atribuirá o seu nome invertido (usando o array criado acima).\n-*/\n-console.log( '\\nInversed Name:' );\n-// ?\n+    /*\n+    Mostre no console o array `numberObjects`.\n+    */\n+    console.log( '\\nNumber objects' );\n+    console.log( numberObjects );\n \n-/*\n-Mostre no console o array `numberObjects`.\n-*/\n-console.log( '\\nNumber objects' );\n-// ?\n+    /*\n+    Verifique se existem em algum índice de numberObjects um objeto ìgual a\n+    { number: 2 }. Se houver, mostre no console:\n+    - \"Existe um objeto { number: 2 } em numberObjects!\"\n+    Senão, mostre a frase:\n+    - \"Não existe um objeto { number: 2 } em numberObjects :(\"\n+    Consegue prever o resultado? Deixe uma mensagem no console tentando explicar\n+    o que acontece ;)\n+    */\n+    console.log( '\\nExiste um { number: 2 } em numberObjects?' );\n+    var objeto = numberObjects[1];\n+    if( numberObjects.indexOf( objeto ) === -1 ){\n+        console.log( 'Não existe um objeto { number: 2 } em numberObjects :(' );\n+    } else {\n+        console.log( 'Existe um objeto { number: 2 } em numberObjects :) !' );\n+    }\n+    console.log( 'Como os objetos não são iguais, mesmo sendo iguais, tive que fazer uma variável que recebe esse objeto pra ser igual a ele.' );\n+    /*\n+    Fazendo o mesmo do exercício acima, mas começando a buscar do último índice,\n+    será que obtemos um resultado diferente? Faça a busca a partir do índice 2.\n+    */\n+    console.log( '\\nE buscando a partir do último índice, o { number: 2 } existe?' );\n+    var objeto = numberObjects[1];\n+    if( numberObjects.lastIndexOf( objeto ) === -1 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