{"action":"opened","issue":{"url":"https://api.github.com/repos/Khan/khan-i18n/issues/84269","labels_url":"https://api.github.com/repos/Khan/khan-i18n/issues/84269/labels{/name}","comments_url":"https://api.github.com/repos/Khan/khan-i18n/issues/84269/comments","events_url":"https://api.github.com/repos/Khan/khan-i18n/issues/84269/events","html_url":"https://github.com/Khan/khan-i18n/issues/84269","id":102711457,"number":84269,"title":"not-translated:Simplify the expression by removing a...","user":{"login":"KhanBugz","id":924247,"avatar_url":"https://avatars.githubusercontent.com/u/924247?v=3","gravatar_id":"","url":"https://api.github.com/users/KhanBugz","html_url":"https://github.com/KhanBugz","followers_url":"https://api.github.com/users/KhanBugz/followers","following_url":"https://api.github.com/users/KhanBugz/following{/other_user}","gists_url":"https://api.github.com/users/KhanBugz/gists{/gist_id}","starred_url":"https://api.github.com/users/KhanBugz/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/KhanBugz/subscriptions","organizations_url":"https://api.github.com/users/KhanBugz/orgs","repos_url":"https://api.github.com/users/KhanBugz/repos","events_url":"https://api.github.com/users/KhanBugz/events{/privacy}","received_events_url":"https://api.github.com/users/KhanBugz/received_events","type":"User","site_admin":false},"labels":[{"url":"https://api.github.com/repos/Khan/khan-i18n/labels/agent_chrome","name":"agent_chrome","color":"ededed"},{"url":"https://api.github.com/repos/Khan/khan-i18n/labels/agent_win7","name":"agent_win7","color":"ededed"},{"url":"https://api.github.com/repos/Khan/khan-i18n/labels/lang_es","name":"lang_es","color":"ededed"},{"url":"https://api.github.com/repos/Khan/khan-i18n/labels/type_not-translated","name":"type_not-translated","color":"ededed"}],"state":"open","locked":false,"assignee":null,"milestone":null,"comments":0,"created_at":"2015-08-24T05:36:36Z","updated_at":"2015-08-24T05:36:36Z","closed_at":null,"body":"Url: https://es.khanacademy.org/mission/algebra-basics/task/6417355447074816\n\nUser Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/40.0.2214.93 Safari/537.36\n\nProblem Text: \nSimplify the expression by removing all factors that are perfect squares from inside the radical.\n{\\sqrt[]{\\dfrac{1}{29}}}=\n​\n​​ √\n​\n​29\n​\n​1\n​​ \n​\n​​ =root, start index, end index, square root of, start fraction, 1, divided by, 29, end fraction, end square root, equals \nIf the expression cannot be simplified, enter it as given.\nPista #1\nRecall that we can take the ratio of radical expressions which have the same root:\nab−−√=a−−√b −−√\nWe can apply this property to the original radical expression:\n129−−−√= 1−−√29 −−−√\nSince \\sqrt 1 = 1√\n​1\n​\n​​ =1square root of, 1, end square root, equals, 1, we get:\n 1−−√29 −−−√=129−−√\nNow all we have to do is to simplify \\sqrt{29\\ }√\n​29 \n​\n​​ square root of, 29, space, end square root.\nPista #2\nNote that 292929 is not a perfect square. How did we know that?\n5^2=25\n 5, start superscript, 2, end superscript, equals, 256^2=36\n 6, start superscript, 2, end superscript, equals, 3629292525363655662929\nHowever, if it has factors which are perfect squares, we can remove them from inside the radical.\nDoes 292929 have any factors that are perfect squares?\nPista #3\nLet's factor 292929:\n{29=29\\times1}29=29×129, equals, 29, times, 1.\nIndeed, 292929 is a prime number, and therefore does not have any factors which are perfect squares.\nThis means that \\sqrt{29}√\n​29\n​\n​​ square root of, 29, end square root is a simplified radical expression.\nPista #4\nTo conclude,\n\nUser Description: \n\n\nNext Steps: \nIf this is a translation issue, fix it. Otherwise verify what is wrong, add a comment in English describing the issue and assign to tzjames."}}