At 12 o'clock, the distance between the frogs has decreased to $2015-9=2006$ m. After this, every two minutes the frogs get closer by $9+8=17$ m. Since $2006: 17=118$, the frogs will meet after $118 \cdot 2=236$ minutes past noon. This is 3 hours and 56 minutes. Therefore, the meeting will occur at 15:56.
[ Movement Problems ]

A green and a blue frog were 2015 meters apart from each other. At exactly 12:00 PM, the green frog jumped towards the blue frog by 9 meters. After a minute, the blue frog jumped towards the green frog by 8 meters. Another minute later, the green frog jumped again by 9 meters, and so on. At what time will the frogs meet? (Each jump occurs instantaneously.)