As the fraction is equal to an integer, its numerator must be a multiple of its denominator. Let's test all possibilities and choose the ones that satisfy the conditions of the problem:

$$
\begin{aligned}
& \frac{3+5+6}{2}=7 ; \frac{3+11+6}{2}=10 ; \frac{5+11+6}{2}=11 \longrightarrow \text { do not satisfy } \\
& \frac{2+5+11}{3}=6 \quad \longrightarrow \quad \text { satisfies } \\
& \frac{3+6+11}{5}=4 \quad \longrightarrow \quad \text { does not satisfy } \\
& \frac{2+5+11}{6}=3 \quad \longrightarrow \quad \text { satisfies } \\
& \frac{2+3+6}{11}=1 \quad \longrightarrow \quad \text { does not satisfy. }
\end{aligned}
$$

Thus, we have two answers:

$$
\frac{(2)+(5)+(11)}{(3)}=6 \quad \frac{(2)+(5)+(11)}{6}=(3)
$$
Laura drew 5 circles inside which she wants to place numbers. She arranges the circles to form a fraction and its integer value.

In how many ways did Laura place the numbers 2, 3, 5, 6, and 11 inside the circles so that the equality is true?