2. C From the diagram, it can be seen that the sides of the larger squares are $2 \times 20 \mathrm{~cm}=40 \mathrm{~cm}$ and $3 \times 20 \mathrm{~cm}=60 \mathrm{~cm}$. Therefore the distance Adam walks is $(5 \times 20+5 \times 40+2 \times 60) \mathrm{cm}=420 \mathrm{~cm}$.
2. The diagram shows squares of three different sizes arranged into a rectangle. The length of each side of the smallest squares is $20 \mathrm{~cm}$. Adam Ant walks along the path marked from $P$ to $Q$. How far does Adam walk?
A $380 \mathrm{~cm}$
B $400 \mathrm{~cm}$
C $420 \mathrm{~cm}$
D $440 \mathrm{~cm}$
E $460 \mathrm{~cm}$