4. The answer is $\mathbf{( C )}$. Substituting $a=b=c=674$ (integers that indeed satisfy $a+b+c=$ 2022) we get $3 p(674)=p(674)$, which means $p(674)=0$. Substituting then $a=b=0$ and $c=2022$ we obtain

$$
2 p(0)+p(2022)=p(674)=0 \Rightarrow p(2022)=-2 p(0)=5392 \text {. }
$$
4. The polynomial $p(x)$ has the following property: for every triplet of integers $a, b, c$ such that $a+b+c=2022$ we have that $p(a)+p(b)+p(c)=p(674)$. It is also known that $p(0)=-2696$. What is the value of $p(2022)$?
(A) -2696
(B) 674
(C) 5392
(D) 8088
(E) It is not possible to determine it with the given data.