Answer: $\frac{3}{10}$
Solution: The characteristic of a linear function that does not pass through the second quadrant is $\mathrm{k}>0, \mathrm{~b}<0$, there are $3 \times 2=6$ (ways) to choose such numbers,

All possible ways to choose numbers are $5 \times 4=20$ (ways), thus the probability we are looking for is
$$
\frac{6}{20}=\frac{3}{10} \text {. }
$$
71. Choose two numbers from $-2,-1,1,2,3$ as $\mathrm{k}$ and $\mathrm{b}$ in the linear function $\mathrm{y}=\mathrm{kx}+\mathrm{b}$, the probability that the obtained linear function does not pass through the second quadrant is $\qquad$ -.

