Between the 15 holes, there are 14 spaces. Therefore, the distance between the centers of the outermost holes must be divided into 14 equal parts. At both ends, 2.5 times the diameter of a hole is subtracted, which is $100 \mathrm{~mm}$. Additionally, the radius must be added twice, as the previous specification referred to the hole edge.

Thus, $2380 \mathrm{~mm}$ must be divided into 14 segments. Each segment must therefore be $170 \mathrm{~mm}$ long.
## Task 2 - 020732

In a flat bar 2.5 m in length, 15 holes with a diameter of d $=20 \mathrm{~mm}$ are to be drilled at equal intervals.

At what distance must the holes be marked if the distance from the edge to the hole edge at both ends should be 2.5 times the hole diameter?