Rearranging the equation, we have $2 x=-t-9$ or $x=\frac{-t-9}{2}$, so

$$
x+4=\frac{-t-9}{2}+4=\frac{-t-9+8}{2}=\frac{-t-1}{2}
$$

Substituting $t=7$ into this equation gives $x+4=\frac{-7-1}{2}=-4$.
Let $t$ be TNYWR.

If $6 x+t=4 x-9$, what is the value of $x+4$ ?

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