Computing each of the first and fourth of the numbers, we have the four numbers $\sqrt{36}=6,35.2,35.19$ and $5^{2}=25$. Arranging these in increasing order gives $6,25,35.19,35.2$, or $\sqrt{36}=6,5^{2}=25,35.19$, 35.2.

Answer: (D)
When the numbers $\sqrt{36}, 35.2,35.19$, and $5^{2}$ are arranged from smallest to largest, the correct ordering is

(A) $5^{2}, 35.19,35.2, \sqrt{36}$

(B) $35.19,35.2,5^{2}, \sqrt{36}$

(C) $5^{2}, \sqrt{36}, 35.19,35.2$

(D) $\sqrt{36}, 5^{2}, 35.19,35.2$

(E) $\sqrt{36}, 5^{2}, 35.2,35.19$