Let the chord be AB, the diameter be CD and the point of intersection X. Then XA.XB = XC.XD, so the other part of the diameter has length 15. So the diameter has length 16 and the radius is 8. 3rd CaMO 1971 © John Scholes jscholes@kalva.demon.co.uk 10 June 2002
3rd CaMO 1971 Problem 1 A diameter and a chord of a circle intersect at a point inside the circle. The two parts of the chord are length 3 and 5 and one part of the diameter is length 1. What is the radius the circle?