【Analysis and Solution】
Journey, second meeting problem.
Second First
meeting meeting

From departure to the first face-to-face meeting, A and B together walked 1 full distance between $A$ and $B$;
From departure to the second face-to-face meeting, A and B together walked 3 full distances between $A$ and $B$;
The time from departure to the second face-to-face meeting is $3 \div 1=3$ times the time from departure to the first face-to-face meeting; A walked 8 kilometers from departure to the first face-to-face meeting;
A walked $8 \times 3=24$ kilometers from departure to the second face-to-face meeting;
The distance between $A$ and $B$ is $(24+6) \div 2=15$ kilometers.
Person A and Person B start from locations $A$ and $B$ respectively at the same time, moving towards each other at uniform speeds. They first meet at a point 8 kilometers away from $A$. After meeting, they continue to move forward, reach the other's starting point, and immediately return. They meet again at a point 6 kilometers away from $A$. The distance between $A$ and $B$ is $\qquad$ kilometers.