a) From the equation $x-6 \%=\frac{2}{5} x$ we get $\frac{3}{5} x=6 \%$. Therefore, the rejection rate was previously 10 $\%$.

b) Consequently, the reject rate now accounts for $4 \%$ of the production volume.

c) The saved $3351,-\mathrm{M}$ corresponds to $6 \%$. Thus, the value of the reject production now is $2234,-\mathrm{M}$.
## Task 2 - 020912

In the VEB Clock and Machine Factory "Klement Gottwald," a youth department reduced the rejection rate by 6 percent of the production volume, thereby saving almost 800 working hours. After this, the rejection rate was only $\frac{2}{5}$ of its previous value. At the same time, an economic benefit of 3351,- M was generated.

a) What percentage of the production volume was the rejection rate before?

b) What percentage is it now?

c) What value (in M) does the rejection rate now correspond to?