10. $x=-\frac{18}{5}, y=\frac{12}{5}$. From $5 x+18=0, \frac{2}{5}=\frac{y}{6}$ we can get.
10. Given vector $\vec{a}=5 \vec{i}+6 \vec{j}$ is perpendicular to vector $\vec{b}=x \vec{i}+3 \vec{j}$, and parallel to vector $\vec{c}=2 \vec{i}+y \vec{j}$, $x$ and $y$ are respectively $\qquad$.