98 D. 12 midpoints of edges have no 3 points collinear. Every three points determine a plane, totaling $C_{12}^{3}=220$. Among them, 4 points are coplanar in 21 cases, and 6 points are coplanar in 4 cases, with repeated calculations $21 \times\left(C_{4}^{3}-1\right)+4 \times\left(C_{6}^{3}-1\right)=$ 139 cases. Therefore, the answer is $220-139=81$ cases.
98 The number of planes that pass through the midpoints of at least three edges of a cube is ( )
A. 220
B. 157
C. 144
D. 81