Answer: It is possible. Solution. The result follows from the Pythagorean theorem (since $10^{2}=6^{2}+8^{2}$) and construction (see figure). The area of the polygon is $\frac{6 \cdot 8}{2}-8=16$.

![](https://cdn.mathpix.com/cropped/2024_05_06_3dd70a95ef181e12bd34g-2.jpg?height=320&width=508&top_left_y=1399&top_left_x=800)
9.3. There are 12 matches, each 2 cm long. Can a polygon with an area of 16 cm $^{2}$ be formed from them? (The matches cannot be broken, and all matches must be used.)