The large hand is on the 8. The small hand is between the 4 and 5.

In 60 minutes, the small hand moves $30^{\circ}$. At 16:40, it has thus moved $\frac{40}{60} \cdot 30^{\circ}=20^{\circ}$ from the 4 towards the 5, or it is still $10^{\circ}$ before the 5.

The angle between the 5 and the 8 is a right angle, as there are $30^{\circ}$ between each hour mark.

Therefore, the angle between the large and the small hand is $90^{\circ} + 10^{\circ} = 100^{\circ}$.
## Task 2 - 080612

Calculate the size of the smaller of the two angles formed by the hour and minute hands of a clock at 16:40!