(5) $(32,35)$ Hint: Without loss of generality, when $a4$, according to $f(c)=f(d)$ we get $c+d=12$, and $4<c<5$, so
$$
a b c d=c d=c(12-c)=-(c-6)^{2}+36,
$$

When $4<c<5$, $32<a b c d<35$.
(5) Function $f(x)=\left\{\begin{array}{ll}\left|\log _{2} x\right|, & 04,\end{array}\right.$ If $a, b, c, d$ are all different, and $f(a)=f(b)=f(c)=f(d)$, then the range of values for $a b c d$ is $\qquad$