3. Answer: (C)
Note that $44^{2}=1936,45^{2}=2025$ and $46^{2}=2116$. So $2,3, \ldots, 2012$ has at most 2012 - 44 terms. For the 2012th term, we need to add the 44 numbers from 2013 to 2056. But in doing so, we are counting $45^{2}=2025$, so the 2012 th term should be $2012+44+1=2057$.
3. The increasing sequence $T=2356781011$ consists of all positive integers which are not perfect squares. What is the 2012th term of $T$ ?
(A) 2055
(B) 2056
(C) 2057
(D) 2058
(E) 2059