61. For \(3 \frac{9}{17}\) min. The team in still water covers \(\frac{1}{5}\) of the total distance per minute, while the current contributes \(-\frac{1}{12}\) of the total distance per minute. The difference and sum of these fractions are \(\frac{7}{60}\) and \(\frac{17}{60}\), respectively. Therefore, the journey against the current will take \(\frac{60}{7}\) (or \(8 \frac{4}{7}\)) min, while the journey with the current will take \(\frac{60}{17}\) (or \(3 \frac{9}{17}\)) min.
61. The rowers' puzzle. A team of rowers can cover a given distance against the current in $8 \frac{4}{7}$ minutes. In the absence of the current, the same distance is covered in 7 minutes less than it would take to cover it with the current. How many minutes does it take the team to cover the given distance with the current?