【Analysis】If a number can be divided by 9, then the sum of its digits must also be divisible by 9. Therefore, the sum of any 9 consecutive numbers must be divisible by 9. Find the remainder when 2012 is divided by 9, and then deduce the answer based on the remainder.

【Solution】Solution: $2012 \div 9=223 \cdots 5$;
So the remainder is: $(1+2+3+4+5) \div 9$,
$$
\begin{array}{l}
=15 \div 9, \\
=1 \cdots 6 ;
\end{array}
$$

Therefore, the answer is: 6.
10. (3 points) Write down the natural numbers $1,2,3,4,5,6,7,8,9$ in sequence and repeat them to form a 2012-digit integer. The remainder when this integer is divided by 9 is $\qquad$ .