【Solution】Solution: According to the problem, we have:
Dragon + Dragon + Dragon's unit digit is 2, so we have $3+3+3+3$ or $8+8+8+8$.
When Dragon $=3$, Cheng + Cheng + Cheng plus a carry-over unit digit is 1, without a carry-over unit digit is 0, there is no number that meets the condition. When Dragon $=8$, Cheng + Cheng + Cheng plus 3 carry-overs unit digit is 1, then Cheng + Cheng + Cheng unit digit is 8, then $6+6+6$ satisfies the condition.

Zi + Zi plus 2 carry-overs unit digit is 0, at the same time, Zi + Zi plus 2 carry-overs cannot carry over 2 to the thousand's place, then Zi $=$ 4 satisfies the condition.

Wang plus 1 carry-over equals 2, Wang $=1$.
Therefore, the answer is: 1468
4. (8 points) In the equation on the right, different Chinese characters represent different digits, and the same Chinese characters represent the same digits, making the equation true. Therefore, the four-digit number “望子成龙” is $\qquad$ .

