Solution. From the digits $1,2,3,4$, 24 different integers can be formed $(4 \cdot 3 \cdot 2=24)$; in these numbers, each of the given digits appears 6 times in each place value $(24: 4=6)$. Therefore, the sum of the digits in each place value is $60((1+2+3+4) \cdot 6=60)$. Consequently, the sum of all these 24 numbers is

$$
60+600+6000+60000=66660 .
$$

From this, it is clear that the desired sum is

$$
6666+666.6+66.66=7399.26
$$

Answer: 7399.26 .
109. From the digits $1,2,3,4$, all possible positive decimal fractions with one, two, or three decimal places are formed, each containing each of these digits exactly once. Find the sum of these fractions.