【Solution】Solution: According to the problem, we have: $1994+a+b+c=a b c$; when $a=3, b=5$, $15 c=c+2002, c=143$, which is not a prime number; when $a=3, b=7$, $21 c=c+2004, c=50 \frac{1}{5}$, which is not an integer; when $a=5, b=7$, $35 c=c+2006, c=59$, which satisfies the condition; therefore, the answer is: $5, 7, 59$.
12. (6 points) There are 1997 odd numbers, the sum of which equals their product. Among them, three numbers are not 1, but three different prime numbers. Then, these three prime numbers are $\qquad$、$\qquad$、$\qquad$.