Solution. First method. We determine the side lengths of all the squares, as shown in the left diagram. Specifically, the side length of the second largest square is equal to $10-6=4 \mathrm{~cm}$, and the side length of the smallest square is equal to $6-4=2 \mathrm{~cm}$. The required perimeter is

$16+10+14+2+2+2+6=52 \mathrm{~cm}$.

Second method. The figure has a perimeter equal to the perimeter of a rectangle with sides $16 \mathrm{~cm}$ and $10 \mathrm{~cm}$, as shown in the diagram.

Therefore,

$$
L=2 \cdot(10+16)=52 \mathrm{~cm}
$$

![](https://cdn.mathpix.com/cropped/2024_06_05_c3c23cf15e32fbc44a06g-01.jpg?height=320&width=531&top_left_y=1686&top_left_x=917)

$16 \mathrm{~cm}$
Problem 2. The figure on the right is composed of four squares. Determine its perimeter.
![](https://cdn.mathpix.com/cropped/2024_06_05_c3c23cf15e32fbc44a06g-01.jpg?height=486&width=1234&top_left_y=1072&top_left_x=246)