9. (3 points) A student, when multiplying 1.23 by a number $\alpha$, mistakenly read 1.23 as 1.23, causing the product to be 0.3 less than the correct result. Then the correct result should be $\qquad$.

【Solution】Solution: According to the problem, we have
$$
\begin{array}{l}
\frac{1}{30} \alpha-0.03 \alpha=0.3, \\
\frac{1}{300} \alpha=0.3, \\
\alpha=90 . \\
1.23 \alpha=\left(1.2+\frac{1}{30}\right) \times 90 \\
=1.2 \times 90+\frac{1}{30} \times 90 \\
=108+3 \\
=111 .
\end{array}
$$

Therefore, the answer is: 111
9. (3 points) A student, when multiplying 1.23 by a number $\alpha$, mistakenly read 1.23 as 1.23, causing the product to be 0.3 less than the correct result. Then the correct result should be $\qquad$ .