The equation x + y = 2x – 1 is solved for the unknown x by the solution x = y + 1, because substituting y + 1 for x in the equation results in (y + 1) + y = 2(y + 1) – 1, a true statement.
Isolate x by dividing each term by the x coefficient. Just divide 3x and 9 by 3, the x term coefficient, to solve for x. 3x/3 = x and 3/3 = 1, so you're left with x = 1. 5. Check your work. To check your work, just plug x back in to the original equation to make sure that it works. Isolate the variable. The last thing you have to do to solve for x is to isolate the variable by dividing both sides of the equation by 2, the coefficient of the x term. 2x/2 = x and 16/2 = 8, so you're left with x = 8. In order to find the slope, it is simplest to put this line equation into slope-intercept form. If I rearrange this line to be in the form  y = mx + b , it will be easy to read off the slope m. So I'll solve: 3x + 2y = 8 2y = –3x + 8 y = (–3/2) x + 4. Then the slope is m = –3/2. Warning: There are many contexts, such as graphing and systems of equations, in which you will need to be able to solve a linear equation for  y = , so make sure you are comfortable with these techniques. 1  Find the slope and y-intercept of the line with equation 2x – y = 5. Then y = 2x – 5, and, from the slope-intercept form of y = mx + b, I can see that: the slope is m = 2 and the y-intercept is b = –5. 1  Find the slope and y-intercept of the line with equation x – 2y = 5. A wording such as an equation in x and y , or solve for x and y , implies that the unknowns are as indicated: in these cases x and y. For example, the equation x + y = 2x – 1 is solved for the unknown x by the solution x = y + 1, because substituting y + 1 for x in the equation results in (y + 1) + y = 2(y + 1) – 1, a true statement. It is also possible to take the variable y to be the unknown, and then the equation is solved by y = x – 1 Solve equation for y 8 + 5x = 9 - 4y. 8 + 5x + 4y = 9 - 4y + 4y 8 + 5x + 4y = 9. 8 + 5x + 4y - 8 = 9 - 8 5x + 4y = 1. 5x + 4y - 5x = 1 - 5x 4y = 1 - 5x. 4y/4 = (1 - 5x)/4 y = 1/4 - 5/4 x. Hi Rosie, Often for this type of problem the instructions will read Solve for y in terms of x.. You are not going to obtain a numeric value for y but rather an expression for y which involves the variable x. I do a similar problem. Solve equation for  If, then | x | = x, so y = /8 = /2, x/4. If, then | x | = x, so y = /8 = x/4, /2. In either case, y = x/4 or y = /2. Since I derived these y= solution-equations from the second of the original equations, I will plug them into the first equation to solve for some actual numerical values: If y = x/4: Copyright 2002-2011 Elizabeth Stapel All Rights Reserved.  I have troubling solving Systems of Linear Equations with 2 variables. I'm finding it difficult to solve them through the Substitution and Elimination by addition methods. I'm solving for both X and Y. EXAMPLES: Solve by using substitution or elimination by addition: 2X-3Y=21 5X+4Y=-5 ---------- Solve by using substitution or elimination by addition: -10X-3Y=3 50X+15Y=-14 A step by step tutorial would be great. Thanks. Follow. 1 answer 1. Report Abuse.  I'll solve for  y = : x – 2y = 5 x = 2y + 5 x – 5 = 2y (1/2) x – (5/2) = y. Then y = (1/2) x – (5/2) , so: the slope is m = 1/2 and the y-intercept is b = –5/2. 1  Find the slope and y-intercept of the line with equation 4x + 5y = 12. Then y = 2x – 5, and, from the slope-intercept form of y = mx + b, I can see that: the slope is m = 2 and the y-intercept is b = –5. 1  Find the slope and y-intercept of the line with equation x – 2y = 5. Equation to solve in standard form. Subtract x from both sides. Simplify the left side of the equation. Put equation in slope/intercept form. Table 10: Solving for y. 1  Jones, Burton. 2  Elementary Concepts of Mathematics, pp 141-144. 3  MacMillan and Company, 1947. 
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how to solve an equation for x in terms of y