Thank you very much to all the organizers for the invitation. Is my mic working? Someone tell me if it's working. It's working? OK, great. So today, I'll be telling you about soliton quantization and random partitions. And just to begin, I want to emphasize that the theory of soliton quantization has a vast history in theoretical physics. And in fact, during the lunch break, I went to the personal library of Abdus Salam. And you can see here right next to his desk, there is a big book on solitons. Right next to it, many books on string theory. And what I'll be doing today is I won't be doing anything non-rigorous. Everything will be totally rigorous. But I'll be focusing on the underlying classical dynamics of solitons. So let me write down the equation that I'll be studying and presenting some recent results for. So I'll be studying these classical Benjamin-Ohno equation. Let me write the equation down. So the time derivative of v plus v times the spatial derivative of v is equal to some constant epsilon bar times j, the Hilbert transform of the second derivative of v. So this is the equation that I'll be looking at. So epsilon bar throughout is a positive constant. And j is the Hilbert transform, which I can write in the following way. I just have to tell you what this thing does to a plane wave. And what it does, either it multiplies by minus i times the sine of the plane wave. And that would be of case positive, or it multiplies by 0. So this is the Fourier multiplier of j. You could write it as an integral operator, which is singular. And yes, so without this j, this equation would be the viscous Berger's equation in one dimension. It would be a diffusive equation. However, due to this non-local operator j, this is actually not diffusive. It's conservative. And so the goal, in general, so given v of x0, possibly depending on epsilon, you want to find and study the solutions of this equation. So there are many well-posedness results for this equation in literature, which I'll mention if you want to know. And a special example is this special initial condition, which is 2 cosine x. So we'll be revisiting this initial value problem with this initial data throughout the talk. Now that we have that on the board, let's look at the outline of the talk. So first, I'll tell you about some special solutions to that equation. These are the periodic analogs of multisyltons, also known as multi-phase solutions. Then I'll tell you about the problem of studying this equation with arbitrary initial data. After that, I'll tell you the quantum versions of each. And the main goal of the talk, which is part 3, let's see if the pointer works. Oh, yeah. The main goal of the talk is to arrive actually at a non-random partition. After that, I can state some results for random partitions. So this material all appears in these three works of mine on the archive. So what is a soliton? Well, here I'll start and present these solitons. So a soliton is just an example of a traveling wave. So a traveling wave is any v of xt that has this kind of form. It has a permanent form eta. And it has a speed, a wave speed c, in some direction. And so throughout the talk, wave speeds is going to appear in red. It's going to be very important for us. And if this eta is localized in x, then we say it's a solitary traveling wave or a one soliton. If you look at the survey by Terry Tao, why are solitons stable? There's a very important footnote at the very beginning where he says that some people actually require stability in its definition of a soliton. But here I won't be addressing questions of stability. The term soliton was introduced by Zabowski-Cruzgl, where they studied not this initial value problem on the board, but they studied the same initial data for the KDV equation. And this is a plot of the trajectory of the initial data to cosine x for the KDV equation after some finite amount of time. And what they point out in this figure from their paper is that there's a bunch of bumps, eight of them, and they call them solitons. And these are interacting. So technically speaking, these are not solitons. These are periodic solitons because they studied periodic boundary conditions. So just be clear and define what is periodic soliton. Okay, a periodic soliton more precisely is a periodic traveling wave. So a traveling wave is any shape eta that just moves in some direction with some fixed speed. And we say this is periodic if the wave form eta, this permanent form is actually periodic in some direction. And we call these for short of one phase wave. So here is actually a photograph of a football stadium sized wave pool where from the paper of Benjamin where he studied these periodic traveling waves in two plus one dimensions. And these are very importantly not stable. In the same year, Benjamin discovered this Benjamin-Ono equation. So what I wanna do now is present to you what are the one soliton and one phase solutions of the Benjamin-Ono equation. So here's a Benjamin-Ono equation. I've already written it on the board. And the Benjamin-Ono equation originally arises as a one plus one dimensional model at the interface of two fluids. Okay, this is the original formal applied math derivation by Benjamin and by Ono. But I also wanna point out in the physics literature recently this same equation was derived by Vigman and Bogotsky where they studied a large number of point matrices. So Vigman and collaborators have been looking at both classical and quantum Benjamin-Ono over the years, also 2D random matrix models. And what's very important for them in their argument is that the, sorry, the vortices actually accumulate in a bit more densely towards the edge. So in a paper with Kahn, Forrester and Telez, Vigman studied for random matrix models in 2D this kind of bump that occurs towards the edge. So that bump is the reason that they think that at the edge of this large number of vortices you should see the Benjamin-Ono equation. So in a sense, the Benjamin-Ono equation is predicted to be the universal dynamics at the edge of a large number of vortices. But for now I won't be addressing any of those universality questions. We'll just start with the equation. Okay, and Benjamin and Ono in both of their original papers they each found both a one soliton solution and a one phase solution. So I'll present those now. Okay, so how many one phase solutions periodic traveling waves do you have? We have a four parameter family of them given by three variables labeled S and one variable labeled chi. And it's written here. So it's very important so I'm gonna write it on the board. One phase solutions. Okay, so you give in S1 up, S1 down, S0 up. Three real variables, these are open conditions open inequalities on these variables. And some chi one in R. I can build for you some solution of that equation. Okay, and what is this solution? Well, I need to tell you what a wave speed, what the wave speed is and what the permanent form is. The wave speed is this average value of S1 down and S0 up. And the permanent form is written here. It may look like a horrendous formula but it's definitely not if you compare it to even the KDV equation where you need elliptic functions to write down the periodic traveling wave. Okay, so there's the permanent form. It's written through this nice cosine. And you can see what's very important is that the wavelength is gonna be, oops, the wavelength inversely proportional to this, sorry, the wavelength is proportional to epsilon bar. So at low epsilon, this solution doesn't actually exist anymore. Okay, what we're gonna do, I wanna encode the conserved quantities, these S's by a picture. Yep. As epsilon bar goes to zero, this, you can see that this thing becomes effectively constant or doesn't have a limit. It's rapidly oscillating. Right, yes, thank you. So the limit does not exist point-wise. Right, so you have rapid oscillations at small dispersion. And so what I wanna do for these solutions, it has a certain, what I'm gonna call the Dover called of Critchford Profiles. And what this is, I'm just gonna draw here, write my three variables, S1 up, S1 down. Oops, let me draw first a picture. Okay, at these lower regions, these local minima, I'll put these variables up. And at this local max, I'll put S1 down. And then the rule is that where I have slope negative one, I'll shade it in. That goes down to negative infinity. And here I'm gonna have another shaded region. Shaded region I'll call bands, B-A-N-D, band. Here, the variable here is C on the real line. C is for wave speed. And I'll write F as a function of C, which depends on these S's, okay? And the reason we use variable C for wave speed is that in this formula, you can just see that the midpoint of the band is the wave speed. So this midpoint is the wave speed. Okay, so the claim is that you write this function down, v of xt, it does depend on epsilon bar. You plug it into this equation, you get a solution. And it is a periodic traveling wave with this permanent wave form here on the left, and it moves at some speed. Okay, now notice that in order to have this permanent form be two pi periodic in space, I have a condition on the band length, okay? So you can read this off from this cosine term pretty easily, but it is so important for us that I'm gonna write it down on a big board, two pi spatial conditions, okay? So this is the one phase solution. And the statement is that vS chi B, xt epsilon bar is two pi periodic in X, if and only if the band length S one down minus S, oh sorry, S zero up, minus S one down is equal to epsilon bar times N one for sum N one in Z plus. I'm defining F to be, I give in my S's, I draw these variables here. So this, I'm calling it a Dobro-Cott of Critchiver profile, I'll see you'll see in a couple slides, but these S's variables are appearing in their paper, their description of these one phase solutions, okay? And so there I had no constraints on any of my S's, but now I have a constraint on the band length. So if I'm gonna draw this picture again, right, there's the big band that goes off to infinity, here's this first band. And here I might take like N one is equal to three here. So this thing is gonna have length three epsilon bar, this direction here. And what that will do is it will chop up this profile, this reach underneath into three pieces, okay? And those three pieces correspond to the three bumps on that plot there. All right, so more can be read off from these profiles. The average height of the wave is given by what would happen if you went down here and put this band right next to it and drew the center, or equivalently, you can draw like this. This picks out A, the average height. Next, the wavelength, like I said, it's proportional to epsilon bar, but it is also inversely proportional to the length of the band. That means that you have these open conditions on S's as if you shrink the band, then the one phase solution, the periodic traveling wave, becomes a one soliton. Okay, so in that limit, the second limit down here, if you shrink this band, the wavelength diverges and you get a one soliton, the one soliton's written there. So this one soliton, you can also see that as epsilon bar goes to zero, it becomes constant. In the other limit, if instead of shrinking this band, I allow the bands to merge, then I approach a constant. So what's next? So next, there actually, there exists kind of super positions of these one phase waves or periodic solitons. These are called multi-solitons. So let me define that for you now. So what is a multi-soliton? A multi-soliton is by definition, or n-soliton wave, it's just any function of x and t so that in some asymptotic regime, it becomes the literal additive sum of one soliton. Here is a picture of an actual solution to the Benjamin-Ohno equation. This is the two soliton of Benjamin-Ohno from work of Christie and the Atmospherical Sciences. And in this case, for the case of solitons, the asymptotic regime of interest is long time. So at long time, these solitons will get spatially separated and then the function will be pretty close to the actual sum. Similarly, an n-phase wave or the periodic multi-solitons, this is the same thing. It's just some v of x, t so that in some asymptotic regime, it's actually a sum. So the regime of interest is not the scattering regime of long time, but instead when we have well-separated wave speeds. I'll show you on that on the next slide. For the Benjamin-Ohno equation, the n-soliton n-phase waves are discovered respectively by Matsuno and Satsuma Ishimori in 1979. What I'm gonna work with is a presentation of these n-phase solutions by Doberquot of Critchiver. So, all right, so here is the formula. The Doberquot of Critchiver formula, this appeared in their work on the modulation theory when they show that the Wittem equations were completely decoupled, but at the very beginning of the paper, they did something remarkable. They gave a completely new formula for these n-phase solutions. And here's the formula. It's some constant times the logarithmic derivative of a determinant of some matrix. Again, you might think this looks horrendous, but it is simpler than the inexpensive formula for the n-phase solutions of KDV. And indeed, you can see that these simple plane waves here, just like we had a cosine from before. Okay?  The asymptotic regime is when all of the gaps diverge. Okay, so I'm calling gaps the reasons between SI up and SI down. Okay? And again, the wave speeds will be the midpoints of the bands and the wavelengths will be inversely proportional to the bands. Okay? So here is this formula for these solutions. Okay? So let's look at a couple of examples. What about an n-equals two-phase solution? Well, in order to construct the n-equals two-phase solution, I need three n plus one, which is seven parameters. That's gonna be five s's and two chi's. So I can collect the s's and draw this picture just as before. And the chi variables are phases, determine where I am. Okay? And in this example, you see three bumps, but I thought I was telling you about a two-phase solution, and the reason you see this is that actually this first band has length epsilon and this band has length two epsilon. Okay? And that's why it's three, three bumps. If you allow these two bands to merge, you would get back the periodic traveling wave from before. Okay? And here, next slide, here's another example. Here's a 26-phase solution. So I need to specify for you 79 parameters. I put these parameters down, all these s variables, just write them down, and I choose some chi's and then I plot the function. Okay? Now, some of you may have seen this picture before. There's absolutely nothing random so far in the talk. The claim on this slide is that unlike the previous slide, when I chose some s variables like this and some chi variables and I plugged it into the formula and I got this picture, instead, if you choose s's that are fairly close to this curve, here and you choose certain chi's, you will get in fact some function v of x that is pretty close to cosine x. Okay? And what's important is that this is non-random but there's an important point process we can even see right now which is the collection of the wave speeds.  Okay? So what I've done here is I've taken some s's, I've taken some chi's, I plug it into the formula which is very crazy and then I get some v. The question now is can you go in the opposite direction?  That's the question. That's the question I'll address now. So before I go on, are there any questions about this review of these multi-soliton solutions? Okay, please interrupt for any time for questions. Okay, so now I'll tell you about the problem of addressing this equation with arbitrary initial data and what can we even say about this? Okay, so the results that I'll present from here are from this paper that I've written on finite gap conditions and small dispersion asymptotics for this problem. Okay, right, that's a typical problem and figuring out how to solve that is part of how to set up rigorously the complete integrability of the problem. Right, so okay, so let's see how do we get started? Well, the main goal in this next part, just like I wrote down these periodic multi-solitons encoded the conserved quantities through a profile, I wanna do the same thing now for an arbitrary initial condition. Okay, so let's start. So let's look now at some simulations of what this equation looks like for generic kind of arbitrary initial data. Here's the equation again. Now I consider an initial data here on the left, which is independent of epsilon bar. Okay, if you choose a large impulse initial data, we have hope of studying the small dispersion asymptotics of this problem. Here's a simulation from Miller and Shoe, who in what you can see here, you plug in some initial data and then over time it starts to shoot out these bumps. A remarkable thing is that if the height here is two and the height of these bumps is about eight and so you expect that an initial impulse of height H should become this should spit out these bumps or solitons that are about height four times H, okay? And moreover, you expect that as epsilon bar goes to zero, so here it's about point four, you expect to see universal behavior in these solutions that is independent of the initial data. Okay, so I just wanna mention that there are analogs of a Dubrovian universality that have been formulated by Masuaro-Romainzo-Antunes for this equation. Okay, so let's look at one more simulation here. This is from a recent survey by Jean-Claude So, which includes a definitive survey of pure and applied research on Benjamin Ono and the intermediate long wave equation. And here's a plot of what another epsilon independent impulse looks like. It shoots out those bumps before. These bumps are moving through time, which is this axis here, the bumps move, but something you can make out that's really interesting is that you see these faint ripples on the side. So you see these low amplitude waves on the left. Okay, and so for this equation, Peter Miller and collaborators have been developing non-local Riemann-Hilbert techniques for this problem.  And also if you wanna see a definitive survey of the KDV case and the analogies with random matrix theory, please look at Professor Grava's critical asymptotic behavior for KDV and random matrix theory. Okay, but so for now I won't be addressing these difficult questions about the fine local details of these patterns that form from a solution. What I wanna do is just locate some conserved quantities and then figure out how to formulate the quantum version of this problem. So how do we get started? How can we possibly compute anything for this model? Well, there's one structure that will invoke now, which is it has a lax pair. So, namely, I start with this equation. It's a remarkable fact at the bottom of the slide that the eigenvalues of something should all be conserved. So let's work through that for a quick second. Here's the equation again. Now I ask that I have a periodic initial data and it's, let's say, smooth and it doesn't have to be epsilon independent anymore. And let's say vk are the Fourier coefficients, okay? Then let's consider the Hardy space in the circle and use this Hardy space with this basis e to the ihx to write down this specific operator. It's not a tophalus operator. It's a perturbation of a tophalus operator by epsilon bar times derivative. You write down this matrix here. The claim is you can check that it actually is essentially self-adjoint and that it has a unique self-adjoint extension. And moreover, that the spectrum is actually simple. It's got no accumulation points and it only goes to negative infinity and it's bounded above, okay? So this, sorry? Any epsilon, any epsilon, yep. So this is a remarkable fact here that formally, if you just work with the equation and rewrite the equation as a lax pair using this lax matrix and some other ingredients, then you think formally that everything should be conserved, the spectrum should be conserved. Okay, so you would expect that these eigenvalues would be conserved. But technically speaking, when you work with a lax pair, you've only rewritten the equation. You have not incorporated the boundary conditions and the regularity of the data, okay? So at first glance, this equation doesn't make analytic sense, but figuring out how to extract from this spectrum something that a bunch of conserved quantities that are actually meaningful was discovered recently by several authors. So let me highlight this now. So let me define for you a dispersive action profile. What I do, I take the eigenvalues of that matrix, which is, sorry, not a matrix, it's an operator. I take the eigenvalues and I put a delta function there and that's gonna define my second derivative. But I'm subtracting off a shift of the eigenvalues, okay? So what I do is I try to put, so given v, v of x, and here, two pi periodic on the circle, and epsilon bar positive, then I plot this shape above ch up v where ch up is the h, h eigenvalue, eigenvalue of the lax operator, okay? And you plot this picture above the shift. And if you have them both at the same time, then you draw nothing, okay? So there's a lot of cancellation that will occur, okay? So the dispersive action profile is defined here and we have these conditions at infinity. It agrees with absolute value of c minus a where a is the mean, okay? And the theorem is that this is actually conserved. So a quick remark about this theorem. This result that this profile encodes all conserved quantities. So for any c, this is conserved. This was discovered is a degeneration of a result in the quantum setting by Mazarovsk-Leonid and also Sergei Veselov, okay? So I work to just figure out how the remarkable works in the quantum case imply this fact. And then this result was actually independently discovered by Gerard Kapler, very recently in April, who showed that not only are these conserved, these are actually accompanied by action very angle variables that evolve and they establish the global action angle variables for the periodic problem. So the fact that the periodic problem is actually integrable in the strictest sense in L2, which is the subcritical regularity where well-poseness was already known, was established definitively by Gerard Kapler. So a bit earlier than that, I showed that actually this construction of the dispersive action profile, which is true for, it's available for any V, if you plug in the multi-phase V, then you get back the Doberpov-Krichever profile. Okay, so it's consistency check. All right, so just to review, if you look at this picture here, then over time, this V is evolving in a complicated way, but at each time, if you take the V and you compute this F from V, you will get the same thing. Okay, so this entire picture is conserved as you evolve for this equation, okay? And we can see here, again, if I draw the midpoints of these bands, all of these wave speeds will be conserved as well. Okay, so next I wanna say, well, what does this look like for small epsilon bar? This will be the second result. So just let's quickly review, what is the epsilon bar equals zero version of this equation, so the dispersionless version? Okay, well, here is the equation, sorry, yep, in this one. So, yeah, in this one, this is from Sol's paper. I don't remember which was the specific function. Oh, it's just a heuristic sketch. Yeah, thank you. Yeah, any other questions? Right, so now let's look at the simpler equation when I just completely destroy this non-local term. This is the inviscid burgers equation, but in our problem, it's the dispersionless Benjamin Ono equation. I set epsilon bar equals to zero. Well, there's a similar conserved quantity you can write. It's the convex action profile. Okay, so this is a function, f of c, which is defined for any v, and it's defined by the same asymptotic condition we saw before, but now I just ask that it's first derivative up to a shift and code the relative volume on the circle that is where v is less than or equal to c. And then you can just check that for short time that this is conserved. Okay, so for any c, I have conserved quantities for the dispersionless problem. All right, so how do you prove this? It's like one integration by parts or you can use a method of characteristics. And indeed, if you think about what the method of characteristics is telling you, it says that this conserved guy, capital F, is just the relative mass of a uniform continuum of free classical particles on the circle with wave speeds that are less than or equal to c. Now, for this much simpler problem, we know that at finite time we have a gradient catastrophe, but there are all these conserved quantities encoded by this convex action profile, and these have appeared before, all as limit shapes. Okay, so the very special case of my favorite initial data, two cosine x, appeared in this, the Vergey-Karov-Loganchev Limit Shape. Okay, so you take the simplest nonlinear equation with initial data, two cosine x, it has infinitely many conserved quantities encoded by the Vergey-Karov curve. For general v, this is discovered by Limit Shape for sure measures by Akun-Gov in 2003 in the uses of random partitions. And more generally, these dispersive action profiles have appeared as limit shapes as well in the work of Nekrasov-Preston and Shaddaf's feeling. Okay, so all of these are limit shapes for models of random partitions, but here I'm arriving at them from the point of view of the limit just writing down this classical problem, thinking about the conserved quantities. Okay, and so as promised, I wanna tell you what are the small epsilon bar asymptotics of these dispersive action profiles? Okay, so here's the theorem, second result. As epsilon bar goes to zero, the dispersive action profile concentrates weekly on the convex action profile, as you might expect. So that's the result, yeah, that's the result. And what does this result actually tell us about the solution? Well, technically speaking, nothing, because I'm only studying the conserved quantities. However, because the equation is dispersive, unlike the ordinary wave equation, this is a dispersive equation. What that means is that we expect that at small time, this will form some dispersive shock wave, and then the anatomy of this shock wave will be built up out of low amplitude waves, modulated one phase waves, and separated one solitons, whose wave speeds should be pretty much captured by the wave speeds you see here in this picture. Okay, so that's a heuristic motivation for looking at the small epsilon bar asymptotics of these conserved quantities. Okay, but the result is only about the conserved quantities. Okay, so now I wanna move on to the quantum setting, and I'll give you some ideas to what's happening in the quantum setting. All right, okay, so the quantum version, this is from the second paper. Okay, so first I wanna now invoke another structure of the equation. I already told you that it has a structure of a lax equation, and now it actually has a structure of a Hamiltonian equation. So let's consider the Hamiltonian structure of this problem, okay? Here I'm gonna again use VK for the Fourier modes. Well, first of all, energy is conserved. If you form this big cubic expression of the Fourier modes, this is conserved over time. Next, more is true, and action is conserved, okay? So in phase space, we have well-posedness of the flow. Any loop that you draw allow the loop to evolve in phase space. The area enclosed by this loop will not change. That's what it means to be Hamiltonian. So here you have a bunch of different kinds of conservation laws given by the conservation of the action. And so technically speaking, what this action is with respect to the little one form of the first bracket of KDV, all right? So what I wanna do now is to tell you, compute the actions and the energies of these multi-phase solutions from beginning. Those will be the next results. So what does that mean? For any V, I have an energy. For any V, I have an actions that I can compute. Now let's just plug in those complicated solutions from before and see what we get. So, first of all, the classical energy. This is a corollary of the earlier results from the first paper. The classical energy of the periodic multisolatons will be given by this alternating sum of the cubes of those Doverquad of Critchiver variables, okay? This nice formula here can be more compactly written as the integral of C cubed against the second derivative of the profile, okay? So the energy depends globally on the profile. But next we can ask about the actions. The theorem is that take again this one form here. It's just an explicit thing. And now which loops are we gonna take? We take the loops which live on the Liouville-Torai defined by the multi-phase solutions. That means more precisely, I just go to these Doverquad of Critchiver formula and I just vary one of the phases. And the result is that the action is just two pi epsilon bar times the length of the gap. You remember I was very excited about these conditions we had earlier on the lengths of the bands, which was the spatial periodicity condition. Now I'm telling you that the gaps, which I didn't even talk about before, are actually the actions, okay? And these depend locally on the profile. All right, so right now this is actually a theorem about quantization, staring at us. If we take the first form of quantization ever formulated, which is the Bohr-Sommerfeld quantization conditions, the Bohr-Sommerfeld quantization conditions say that the action should be quantized because it's an adiabatic invariant. Okay, so now let's see what this looks like in a theorem. So let's recall that if you have any loop of any type, gamma i, in some symplectic phase space with an exact symplectic form, then by definition, the loop is h-bar Bohr-Sommerfeld if the integral of this one form around the loop is two pi h-bar times some integer. Why do we like the Bohr-Sommerfeld conditions on the actions is because it gives us an approximation to the energy. Okay, so here you can see that for the classical energies of these guys will approximate the quantum spectrum. This only works for integrable systems, but as you all know in random matrix theory, the relationship to quantum chaos relies on the chaotic version of this, the Good-Swiller trace formula, where all the predictions about GOE come from. But okay, so here is this result. Now I can restate it. These actions are given by two pi epsilon bar times the gap length, and that means that in order to be Bohr-Sommerfeld, the gap lengths have to be given by h-bar divided by epsilon bar. So let me write this down here. So what are the conditions now? VS Chi XT epsilon bar is h-bar Bohr-Sommerfeld. I'll do this for the one phase, if and only if the gap length given by h-bar divided by epsilon bar times n1 prime for some n1 prime in Z plus. Okay, so now let's take again as before, n1 is equal to three and n1 prime is equal to nine. That means I will have in this direction three, and then I'll have one, two, three, four, five, six, seven, eight. Okay, so what does the theorem say in general that actually what does it mean to be a quantum multi-salaton? It just means that you're a classical one, but the profile you draw has to be of a partition. That's it. So now we've completed what I promised, which is arriving at a young diagram, a non-random partition from dynamical first principles. So what can I show you here? What's nice is that this has to be actually volume proportional to h-bar, yep, and what next? Well, more is true, but actually in light of the fact that the, not an approximation of the spectrum, but the exact spectrum is known by works of Sergei Veselov and Nazarov-Sklyan and others, that actually if you write down this operator, which is you choose to be your quantum version of the Hamiltonian, the eigenfunctions are jack functions. You can regard that actually as a definition of a jack function. What this means is that if this is another result that the Borsamer-Pell approximation is exact if you just choose this renormalization of the coefficient of dispersion, okay? And this is discovered by Abana Vigman in the Lagrangian picture. And indeed here, now all you have to do to find the exact spectrum, you just draw these shifted young diagrams here and draw the same picture. So definitively jack functions are actually the states of the quantum version of the multi-phase solutions, okay? Last but not least, I should quickly say that it is a result of Dubrovian that if you look at the dispersionless problem and you try to quantize this, you arrive at sure functions. This gives a new interpretation of that result, which is that, well, at epsilon bar equals zero, the renormalized coefficient is still present. And that means sure functions themselves are actually also Benjamin Ono multi-soluton solutions. So this is a new characterization of sure functions. Okay, so with the last couple of minutes, I wanna quickly tell you how these ingredients of the dispersive action profile and the convex action profile have appeared before in the theory of random partitions. This is a quick statement of like one result of mine for random partitions and then I'll be in. Okay, so what are the random partitions? Well, start with a Fox base, which you'll see more in the next talk. I just take this Hilbert space and I have this basis and I declare it to be orthogonal with this inner product. That's what a Fox base is. It's just polynomials with an inner product. Then I have some ladder operators. So I can write multiplication by VK and H bar times K times dvk and I can define this Hamiltonian here. It's just a self-adjoint operator in Fox base in the completion. And Jack functions are by definition the eigenfunctions of this thing. Okay, and to connect to the conventions, here I'm using the cross-off variables, but to connect to the usual conventions, the power sums are a rescaling of VK and the Jack parameter is the ratio of these epsilons. Okay, and so you can define a natural model of random partitions where you just pick some specializations of VK, which are the Fourier modes of some of V, and you choose a random partition proportional to this law. Okay, so at first glance, this is a very confusing model of random partitions because it's defined through these transcendental special functions. But they have appeared before in a variety of contexts. So these are generalizations of sure measures. And these are also the generalization of the Poissonized Jack-Plancherale measures for my favorite initial data to cosine x. And there are special case of the McDonald measures introduced by Boarding Coral. Okay, so for these, this model of random partitions here, which has been introduced before, not first by me, they're in the, you can study, I can present now some limit shape results. So here's the result. Draw this profile of the partition. Sample from a Jack measure. Then there's two asymptotic regimes. I can set h bar goes to zero. And if I recall, h bar is minus epsilon one, epsilon two. And epsilon bar is epsilon one plus epsilon two. Look at this regime where h bar goes to zero. Then, oops. Then for fixed epsilon positive, the random partition concentrates in the dispersive action profile that I spent the whole talking about. Also, as h bar goes to zero, which is quantum to classical, and you also send dispersion to zero at a comparable rate, given through some beta, which is indeed our beta, then you get the concentration on the convex action profile, okay? And the last but not least, I'll just quickly say that results of Professor Guignet and Huang showed that for these models, these Poissonized Jack-Plancherale measures, at the local scale, you see the same universality as you do in random matrix theory. And so even though the results I've presented are only at the global scale, what I've shown is that if you orient yourself from the point of view of the limit where nothing is random, then the point process for which we see universality is in fact the point process of the wave speeds of the interacting solitons. So thank you very much.


Leicester Square was one of the smartest residential quarters of early Georgian London. On its north side stood Leicester House, occupied by members of the British royal family. On its west and east sides, elegant, terraced houses looked out over the square's exquisitely manicured communal garden. It was into one of these houses on the south-east corner of the square that the artist William Hogarth and his wife Jane moved in the spring of 1733. Hogarth, now 35 years old, was flush with money and fame thanks to the phenomenal success he had enjoyed the previous year, with his pictorial series A Harnet's Progress. The sequence of six paintings and engravings had chronicled the London life and death of a fictional prostitute, Moll Haggabout, in vivid detail with a compelling combination of satire, sensuality and sympathy. A Harnet's Progress caused a sensation and sets of Hogarth's engravings sold in the hundreds. In the words of the contemporary engraver George Virtue, they had the greatest subscription and public esteem that any prince ever had. It was the profits he made from a Harnet's Progress that, at least in part, financed Hogarth's move to Leicester Square. It enabled him, the son of an itinerant and often impoverished schoolteacher, to start imagining a new kind of future for himself, as not only a famous artist, but an affluent one. But such overnight success brings its own challenges. As he settled into his expensive new house and studio and looked out at the Gentile Square beyond his windows, Hogarth would have known that he couldn't afford to rest on his laurels. How, he would have asked himself, was he going to be able to repeat the success he'd enjoyed with A Harnet's Progress? What kind of new work might once again attract hundreds of visitors to his studio and persuade them to part with their money? The answer, it turns out, was what became his second major pictorial series, or modern moral subject, a rake's progress. My name is Mark Hallett and I'm delighted to welcome you to the second in a series of six films devoted to William Hogarth, produced as part of the Paul Mellon Centre's 2021 Public Lecture Series programme. All have been made in close collaboration with the filmmaker John Law. In this film I'll be focusing on a rake's progress, which took the form of eight paintings that Hogarth executed and exhibited in his new studio over 1733 and 1734, and that he then reproduced as a series of engravings. Let's start by quickly introducing ourselves to the eight painted instalments of the progress, which are today housed at the Sir John Sones Museum in London. Hogarth's series tells a story of a young man called Tom Raquel, and it begins by showing him being measured for a suit soon after inheriting his miserly father's fortune. His hand cradling a pile of coins, he tries to buy off a pregnant young woman, Sarah Young, who has appeared at his door with her angry mother, having been seduced with promises of marriage, while Tom was a student at Oxford. The second canvas depicts Tom standing at the centre of a crowded retinue of servants and lackeys in a newly acquired London townhouse, playing the role of an aristocratic man of fashion. The third, very differently, shows him at the Rose Tavern in Drury Lane, sprawling open-legged amongst a riotous group of prostitutes, two of whom surreptitiously steal his pocket watch. The fourth canvas shows Tom about to be arrested for debt, having been ambushed by bailiffs on his way to a grand royal reception at the court in St. James's. However, he is temporarily rescued by the loyal figure of Sarah Young, who you'll remember from the first picture, and who offers her purse to secure Tom's freedom. Her efforts are in vain. The next painting shows Tom marrying a rich old woman purely for her money. In the background of the church, we once again see Sarah and her mother protesting at the door. The former now carrying the child she conceived with Tom. The sixth painting in the series is set in a gloomy gambling den, and pictures Tom having thrown away his newly gained wealth in a game of cards. Kneeling on the ground, stripped of his wig, and shaking a fist in despair, he rails against his misfortune. O'Gar's penultimate painting shows Tom sitting dejectedly in the fleet, the debtor's prison. His cron-like wife shats in his ear, while Sarah Young, visiting with her child, swoons away in an anguished faint. Finally, we're taken into Bedlam Hospital for the Insane, where the near-naked figure of Tom, his ankle and wrist clamped in chains, rise across the floor, accompanied once again by the long-suffering figure of Sarah. The handkerchief with which she dabs her eye is a replica of that she uses in the first painting. Precisely the same purposes. This is a series bracketed by the imagery of tears. Such details testify to the visual subtlety and artistic invention of O'Gar's new pictorial sequence. Qualities that carry through to his eight engravings of the progress, which he published in the summer of 1735. In this talk, I'll be exploring a rake's progress's status as an especially interesting case study in the history, dynamics, and logic of the artistic sequel. In this case, of course, a sequel to O'Gar's first huge artistic hit, a harlot's progress. In doing so, I'll be looking at a rake's progress not only as a work of art, but as a commodity. Here it is worth noting that O'Gar was astute and creative and entrepreneur as he was a painter and engraver. He was constantly thinking about how he might craft novel kinds of product or repackage those that had already been profitable. The rake's progress, as we shall see, was shaped by these concerns, which, for O'Garth, were inseparable from his artistic practice. But the history of this second modern moral subject was also shaped by another very particular commercial preoccupation of the artist at this point in his career. His seething anger with his competitors in London's print trade. Over the spring and summer of 1732, O'Garth had watched powerless as numerous print publishers and engravers had profited from the popularity of a harlot's progress by producing rapidly executed plagiaries of his prints of the series. There was no law of copyright for engravers in early 18th century England and this kind of plagiarism was not in itself, especially unusual. However, the sheer scale of this unauthorized form of copying in the case of a harlot's progress, the pictorial vandalism that the artist perceived as having been done to his images, and, crucially, the fact that he himself did not gain a single penny from the process drove him to distraction. In the years that immediately followed, the years he was working on a rake's progress, O'Garth, with the help of some like-minded fellow practitioners, campaigned to persuade Parliament to change the law so as to protect the copyright of independent engravers like himself. And, as this campaign seemed ever more likely to succeed, so O'Garth began to hope that the rake would not suffer the same kind of fate experienced by his first great artistic breakthrough. As we shall see, however, things didn't turn out quite as he planned. Let's now return to the challenges that faced O'Garth in the winter of 1732-33, as he mulled upon what he might produce as his follow-up to a harlot's progress. His greatest challenge, like all those who have had a huge hit with an early piece of work, was that of creating something that reproduced all the elements that had made that work so successful, whilst avoiding the dangers of repetitiousness and over familiarity and thereby frittering away the sense of novelty and excitement that had greeted the original. Furthermore, he faced the problem that the heroine of his first series, Moll Hackabout, had died at its conclusion. It was thus impossible to produce what would have amounted to a harlot's progress too. What O'Garth gambled upon, however, was that he might find success by returning not so much to the heroine of his original series, but to its fundamental narrative arc and pictorial format. Once again he decided he was going to use a sequence of pictures to tell a story that traced the doomed trajectory of a young newcomer to the city. Someone who, just like Moll Hackabout, initially pursues a superficially fashionable and luxurious lifestyle before descending into sexual promiscuity, disease, punishment and death. In this sequel, however, the fictional figure O'Garth chose to play this role was not a prostitute, but a rake. That is, a disloot male libertine. His choice was not especially surprising, for in this period rakes were often depicted as both the masculine counterparts too and the natural companions of the courtesan and the prostitute. But his choice was an extremely astute one, for O'Garth recognized that there was a great appetite for stories of such figures in contemporary culture. Numerous books, pamphlets and commentaries of the day traced the rake's life in gleefully voyeuristic and sometimes highly moralistic detail. Moreover, perfectly for O'Garth's purposes, they tended to tell what had become a stereotypical story of rise and fall. In these texts, the rake is repeatedly introduced as a young man who arrives in the city following his wealthy father's death and who runs through his inheritance with reckless abandon, cutting a riotous, extravagant and increasingly seedy path through the city's nightlife and places of ill repute. In such accounts, the rake is sometimes shown recognising the error of his ways and given the chance to reform himself. But often, these figures remain incorrigibly disillute till they meet a lonely, diseased and miserable end. Such is the case in an illustrated poem called significantly The Rake's Progress or Templar's Exit, which was published in 1732 and advertised alongside O'Garth's engravings of a harlot's progress. In this poetic predecessor to O'Garth's work, the eponymous protagonist breaks down in his garret, bemoaning his fate. Ah, woeful, miserable me, that can't one grain of comfort see. Where now are all my whores, false friends? Now they have secured the devil's ends. He goes on to commit suicide, hanging himself in an eerie of telling detail from a nail that pins the third print from O'Garth's harlot's progress on the wall. O'Garth, in adopting a fictional rake as his new pictorial protagonist and deciding to tell the story of a similar decline into dissolution and despair, was thus unable to craft a work that might fulfil the twin demands of a successful sequel. It would recycle many of the elements of the first series. Indeed, it was at work that he could once again call, ironically, a progress, but it would also be very different. Enjoying as it did, an entirely new anti-hero. As this idea began to develop, we can see O'Garth making a number of other artistic and commercial choices that were shaped by the rake's progress status as a sequel. Crucially, O'Garth saw that he could hide an interest in his new artistic project, even while reprising the formula that he had used in the harlot. By casting the rake's progress as a work of art, it operated on a larger and more ambitious scale than its predecessor. He did this, first of all, through making his second series longer than the first. Rather than the sequence of six pictures he had deployed for the harlot, O'Garth, in the rake, decided to provide visitors to his studio with eight canvases to peruse and a set of eight engravings to purchase. The latter of which, significantly, was somewhat larger than those he had made for his first progress. O'Garth, following this logic of expansion, made his new series not only longer than the first, but busier. First of all, he gives us far more people. The harlot was crowded enough, featuring as it did some 40 protagonists other than Maul herself. The rake, however, swarms with almost a hundred different figures. This, as O'Garth knew, was important. One of the great attractions of his first series was how it encouraged viewers to dwell upon its many different participants and to enjoy the ways they contributed to its narratives and meanings. He thereby ensured in the rake that such pleasures were even more readily on offer. Thus, just to give one example, the progress his gaming house scene is packed with 16 figures other than Tom, including a night watchman who races in to raise the alarm about a fire that breaks out in the background. And a cluster of gamblers, aristocrats, a clergyman, a high woman who sits gloomily by the fire, who run the gamut from exhilarated anticipation to crazed abjection. Tellingly, O'Garth added extra figures to his eight paintings even after they had first been put on display in his studio. Thus, in November 1734, he excused the late delivery of his set of prints by noting that he had, quote, found it necessary to introduce several additional characters in his paintings of the rake's progress. In a parallel move, O'Garth also significantly increased the weight of pictorial detail in this series when compared to its predecessor. In doing so, he was building upon one of the other features of the harlot's progress that had made it so successful. Its accumulation of symbolically charged objects, texts and images, scattered across the spaces which Mal passes through. In the rake, we're confronted by a blizzard of such things. Look, for instance, at the first engraving, which is unusual in featuring a relatively modest gathering of seven figures, including the sly lawyer who steals money from behind Tom's back. As if to compensate, O'Garth provides us with a cornucopia of visual details. At the centre of the image, he has piled up a mountain of inscribed papers, which were invited to visually sift through and decipher one by one. He also adds a painting on the wall that, in effect, serves as an internal pictorial prequel to the series, showing as it does Tom's father hunched over a table, counting his money. And O'Garth turns the image as a whole into something akin to an advent calendar, full of open doorways, cupboards and boxes, all of which invite us to peer inside and to inspect their contents. This relentless form of pictorial and textual addition is just as evident if we turn to the second image of the series, which Tom is surrounded by a cluster of hangers on. In the painting, the space behind the seated harpsichordist is left empty, but in the engraving, it is newly dominated by another long, unfurled scroll of text, inscribed with a satirical list of gifts to the fashionable castrato singer, Farinelli. Inserting another detail into his engraving's foreground, O'Garth pictures an engraved title page for a poem dedicated to T. Rayquilla's Squire lying on the floor. Nearby, meanwhile, we encounter the extended poetic caption commissioned from the dramatist John Hoadley which comes under this and all the other prints in the set that provides yet another layer of textual commentary within the series. The harlot prints had enjoyed no such supplement. There is a final form of a pictorial expansion that marks the Rayquilla's progress. This is the addition of a second important protagonist, the figure of Sarah Young. In the harlot, the closest we come to such a figure is the bunter or common servant who accompanies Marl from the third plate onwards but enjoys a relatively subdued presence within the series's overall narratives. In the Rayquilla, O'Garth decided to introduce a far more prominent character into his story right from the beginning. Sarah indeed features a no less than five of the progress's eight scenes and plays a crucial role right at the works heart when her outstretched purse offers Tom the possibility of redemption. In giving her this kind of visibility, O'Garth provided viewers of his new series not only with an added point of interest but with a character who have offered those same viewers a reassuringly sympathetic and virtuous counterpoint to the disreputable figure of Tom himself. Characteristically, however, O'Garth also ensured that his second series was populated with female figures who, like Mulhack about before them, could provide a more titillating and provocative pictorial focus. One such figure perhaps is the young bridesmaid whom Tom shifterly and lasciviously inspects in the marriage scene. Another, more obviously, is a striptease artist known as a posture maker who is pictured undressing in the rose tavern. She is shown preparing for an act that will see her spinning nakedly on the silver platter that is being brought into the room. O'Garth knew that the voyeuristic appreciation of such sexually loaded figures had been one of the key factors in the harlot's success particularly amongst its male consumers. Denied to his clientele, he made sure that his sequel provided more of the same, rather scurrilous pleasures. Thanks to all of these strategies, O'Garth must have hoped that with a rake's progress, he would once again strike gold. Leaving as little to chance as possible, he also embarked on an ingenious and ambitious marketing campaign for his prince, one that itself represented the more elaborate version of the campaign he had conducted for the harlot. As in the case of that work, he sold his new series by subscription and issued an engraved receipt for subscribers that provided them with a collectible work of art in its own right. That for the harlot's progress recorded a straightforward form of exchange in which the subscriber paid half a guinea up front and half a guinea on the completion of the engraved set. Interestingly, that for the rake outlined a different kind of transaction. First of all, it's worth noting that subscribers were asked to pay a substantially higher amount for O'Garth's new set of prints, one and a half guineas rather than a single guinea. They're also told that after the subscription period had closed, the set would cost no less than two guineas, that is twice the price of the harlot's progress. If this information about a future price rise provided one kind of incentive to would-be subscribers, so did another of O'Garth's marketing strategies. His offer of what amounted to a pictorial bonus, a ninth print depicting the humus of the fair, which he promised more over to deliver well in advance the rake's progress engravings themselves. Commit to paying me your one and a half guineas, he says, and I'll give you an extraordinarily crowded, entertaining and witty piece of graphic art to enjoy while you wait for the main set of engravings to be finished. O'Garth had one last card to play in ensuring the success of his sequel. Following his and his fellow engravers extended campaign for parliamentary legislation to protect their work, the spring of 1735 finally saw the engravers act being passed, giving practitioners like O'Garth exclusive rights to their designs for 14 years from the time of publication. The act received the royal assent in June of that year. To O'Garth's eyes, the prospect of this act being passed led to a crucial change of plan regarding the publication of his rake's progress engravings. Having already delayed their advertised date of publication, thanks to the changes he kept making to the paintings, O'Garth then delayed their publication still further to the date of the engravers act itself, that is to June the 25th, 1735. In the newspaper notice announcing this final delay which he issued in May, he certified his decision by noting that this would prevent, quote, the scandalous and unjust custom hitherto practiced with impunity of making and vending base copies of original prints to the manifest discouragement of the arts of painting and engraving. This time he must have thought the engravers and print sellers who had so flagrantly cannibalized that Harlett's progress would be stopped in their tracks. He was not to be so lucky. In what can almost be admired as a stroke of malevolent genius, a group of London's print publishers conspired together to send a succession of spies into O'Garth's studio in Leicester Square. There, these spies presented themselves as potential subscribers to the engravings and closely inspected the eight paintings on display. Their job, however, was not to admire these canvases, but to memorize them. Having done this to the best of their capacity, they then seemed to have travelled to the workshops of a clutch of engravers employed by the print publishers and told them in detail what they had seen. These engravers quickly proceeded to produce a set of eight prints based on these verbal descriptions and, we can surmise, on accompanying diagrams or sketches prepared by the informants. The resultant engravings were then advertised and sold in the first weeks of June, just weeks before O'Garth's original prints were due to be released and before the engravers' act came into effect. These plagiarists, which were themselves instantly plagiarized, are exceptionally intriguing images in their own right. Offering as they do, fascinating demonstration of, amongst other things, the strengths and weaknesses of visual memory. But to O'Garth, these prints were nothing short of nightmarish. Their contents disseminating a distorted and grotesque version of his series, a cross-contemporary graphic culture like a terrifyingly bad dream. All of his best-laid plans he must have worried were in danger of falling apart. His sequel, just like its predecessor, was going to be eaten alive. Happily and perhaps predictably, these pre-emptive plagiarists ultimately seemed not to have had too great an effect on either the sales or impact of O'Garth's second great modern moral subject. Indeed, in their own way, they only served to reinforce his contemporary reputation as London's most important and interesting artist. Nevertheless, their brazen form of pictorial theft offered O'Garth yet another demonstration of the challenges, even the dangers he faced as someone who, having crafted a successful product, in his case the new kind of satirical pictorial series embodied by the harlot's progress, had endeavoured in a rake's progress to both recycle and upgrade that product, and to assert his rights over it. It is no wonder, perhaps, that over the rest of his career O'Garth was to remain prickly and protective in regard to all those of his modern moral subjects that served as sequels to the rake's progress itself. For him, the vultures were always circling even above the cloistered grounds of Leicester Square.


Hey guys, it's Liana, and I'm here today with a book haul. These books are so heavy. Oh, no. This isn't even all of them. Yeah, I've been meaning to film a haul for a while, and then I kept being like, well, I know this one other book is coming, so I may as well wait. And I was like, okay, well, wait at this time. I know this one other book is coming, so I may as well wait. Waited long enough time to do the haul. So I'm just gonna start with this deck because it's the most precarious good plan. Some of these books are books that I bought for myself. Some of these are books that other people gave to me for Christmas. Some of them are books that people gave me randomly. I think that's every category. Yes, I bought it for myself. It was a Christmas present or a random present. You know what a book haul is. Let's get started. First book I have is The Girl Who Loved Tom Gordon. My friend Shaya gave me this. Shaya, whenever I haul Stephen King books or graphic novels. Oh fuck, there's a graphic novel that Shaya gave me over there. Not any of these stacks. Well, we'll just do that last, won't we? Yeah, pretty much with very few exceptions. If I'm hauling a Stephen King book, okay, a few have bought myself, but most of the time if I'm hauling Stephen King or a graphic novel is from Shaya. So Shaya gave me this because she had an extra copy. I was with her actually when she bought a pop-up book version of this, and so she didn't really especially want to keep. Oh my god, why do I look like a ghost now? The sun was just perfect when I set this up. Why? Why? I know if I close the blinds.  It's gonna go behind a cloud and then it'll be too dark. Okay, well, here's hoping for the best. Okay, so back to this, yeah. So she has the pop-up book version of this, so she didn't especially need to or want to keep this like mass market paperback. She's like, you want it? And I was like, sure.  I don't actually know what this is about really at all, other than like what I gleaned from flipping through the pop-up book with her in the store. So it's a book by Stephen King that I see the words Boston Red Sox on the back. That's all I know about this. Very useful, I know. Next is the book that me and Amanda are reading next month. Well, I say next month. I don't know when this video is going up, but we're reading it in February for our book clip. So for all I know, I've already posted a TBR and you already know that. I don't exactly know. Any hoosies, yeah. So this is Amanda's pick. The live show will be on her channel, and Mara and Bethany are also reading with us. That being Bethany from Beautifully Bookish Bethany and Mara from Books Like War. This is a chunky fantasy romance that they are making me read for reasons that remain a mystery to me. I think this one like Goodreads Choice Awards or something. So Amanda really wanted to read it and she's hopeful that I will like it. I am less hopeful that I will like it. What? Stranger things have happened. It is definitely long.   I do really like the cover. Like the first time I saw this cover and I didn't know who this author was or what this was. I was like, oh, is that a grimdark fantasy? It's like red and has a blade on it. And then I found out vaguely what it was. And I was like, oh, just kidding. It's definitely not a grimdark fantasy. I mean, I have been known to like a trashy book or two. So this could be another Infernal Devices Shatter Me situation. Those are few and far between, but here's hoping. Next is my pick for January, which is The Black Company. I accidentally got the omnibus version, so it's all three books in The Black Company in one bind up. But in January, as of the filming of this video, I haven't started it yet, me and Amanda, and we'll be reading the first book in The Black Company, which is called The Black Company. And that book is, enjoy my flipping noises.  Wait, did I pass it? Yeah, that was way too far. It's actually a lot shorter than that. So this is the first book. It's in the bind up version. It's less than 300 pages. The bind up version is bigger, like the pages are bigger, I think in the mass market. It's like 300 pages. Yeah, so it's not terribly long. So I can knock this out pretty quickly, hoping I like it enough to want to read the rest, because I've got it. And I do enjoy a flippity, slobbery paperback, so excited about that at least. Next is another book Shaya gave me, and that's In the Night Garden, by Catherine and Valenti. I really like Catherine Valenti's writing in Deathless. I don't think I've read anything else by Catherine Valenti. I don't think so. I own Radiance, not to be confused with Grace Draven's Radiance. When I talk about loving Radiance, I mean Grace Draven's Radiance. And oh, and I own all of the books in the The Girl Who Circumnavigated Fairyland and the ownership of her own main king. I think the series might be called Fairyland? I don't know. I own all those books, but I haven't read them. So yeah, I think the only Catherine Valenti book I've read is Deathless. I really liked Deathless. So Shaya read this and really liked it, I think. I don't think she loved it, but she liked it. And it's illustrated, these beautiful illustrations. So since this looks kind of fairy tale-esque, which is kind of how Deathless is, unlike Radiance, which is a sci-fi book, so I don't know how I'll do with that. But so I've seen her write fairy tale-esque things and enjoyed it, and these illustrations are so pretty. So I'm quite excited about this. Next up, I'll do these together. I have two Brandon Sanderson books that I bought myself. I already owned, in these editions, the hard covers of the Well of Ascension and the Hero of Ages. Hero of Ages being the one that kind of lost me. But I'm a completionist both in reading and in owning. So since I have the other two, it just has been bothering me that I don't have the first one. The reason I only have those other two is because I got them off like Book Outlet or something. It was like, you know, they had like one copy in and I was like, get it. And then since then I've like parted ways with Book Outlet. Not that I was ever affiliated with them, but like I won't chop there anymore. So they might have had this since then, I don't know. But there was no reason to wait anymore because I wasn't like waiting for it to hopefully also be on Book Outlet for a cheap price.  Just do it. So I got my hardcover Mistborn to complete my hardcover, American hardcover Mistborn trilogy set. And then I'm reading Elantris in this month with this being January. Again, I'm not sure what this video is going up. So I have not read it yet as of the filming of this video, but that's why I got it because I was going to read it in January. So I was like, I need to have a copy of it in order to do that. And I always get a hardcover if I can if it's not like exorbitant. The story of this purchase. Next I have Daughter of Smokin' Bone by Lainey Taylor. Why is there a bookmark here? This came, I bought the special edition Elima crate that was specifically Daughter of Smokin' Bone slash generally Lainey Taylor themed. Although the crate itself, like they intentionally said, you know, oh it's not going to be just Daughter of Smokin' Bone. It's going to be like the book will be, but it's going to be all Lainey Taylor things, except everything in the box was Daughter of Smokin' Bone related, except for one thing. And that one thing was Strange the Dreamer and it was a mug. And I was like, if it had been like a balance where like it was kind of half and half, I'd be like whatever. But I was like, why couldn't I have a Daughter of Smokin' Bone mug? Oh, I did that one thing have to be Strange the Dreamer. Everything else was Daughter of Smokin' Bone. Anyway, that's a petty thing to complain about. The mug is quite nice. And I do love Strange the Dreamer. Anyway, I've been bitching for years that Daughter of Smokin' Bone deserves the kind of like glorious special editions that all this, it seems that all new YA releases seem to be getting. And like it came out before that was a thing. And I've just been pissing and moaning about it.  So of course I had to get it. I mean the stuff in the crate was fine, but I was in it for the book. And I like, I would pay that amount of money just for the book. So like having extra stuff as well was quite nice. And I've ordered the, because they then separately sold books two and three, which is such a ploy for whatever. Ordered those, they're not here yet. But these editions, they're all, they all have sprayed pages. They all are hardcover. Because you can get this cover now. They re-released it in these covers in the UK, I think, but I think hotter. Is it a publisher? Maybe Simon and Schuster? I don't know. But you can only get it in hardcover from Aluma Crate. With Sprata just and the dust jackets, they're all illustrated by Lainie Taylor's husband, Jim de Bartolo. And the like naked cover has like a quote on it. So I mean it's quite deluxe. And I loved Outer Smokin' Bone. The international edition, which I also own, is the only blurbed review on it. It's from Patrick Rothfuss and the review just says, I wish I'd written this book. Wish like, can you get a better accolade than that? I don't think so. Anyway, yeah, so I've read this. I love it.  I'll do these next four together. I have another set of four Book of the Month Club books also. Then I'll do separately because they're in a different stack. But yeah, these are all Book of the Month Club books. I didn't get them all at once because you can only accept the other stack of four. I did get all at once because it's the end of the year and the end of the year. In addition to your usual one Book of the Month and two add-ons, you also get to pick, if you want to, one of the best of the year if you want. So I got four books in December. So that's coming up, sneak preview. But these came in separate boxes. I don't remember which came with which. Yeah, I don't remember at all. Oh, what I do know is that Hibbidi. This was actually a monthly pick, like one of the Books of the Month. When I got it. And it is a YA fantasy Asian inspired retelling of Romeo and Juliet. Hence the title, which is a quote from Romeo and Juliet. It looks like it was in November. So that's when I got it. The other ones were all add-ons. So because they could be from any time, I don't know which box they came in. So yeah, YA has generally kind of fallen out of favor with me a lot because in recent months and years, it has quite often more often than not let me down. But it couldn't resist a Shakespeare retelling with this cover. And it was like one of the Books of the Month. And I had to pick one and it was the one that most appealed to me. So I didn't have to pick when you can skip. But I like, I almost never skip because I'm like, but I want books. Also, you can't get add-ons if you skip. So generally I don't skip because I want the add-ons. Anyway, I haven't read this yet. It intrigues me. I haven't heard too much about it. I've just seen it around, but I don't actually haven't heard anyone say they've read it and what they think of it. So I don't know. Maybe people are hating it.  And then these three were all add-ons. They're all like mystery thrillers. So I got two by Ruth Ware, one by one and Turn of the Key. One by one I got because it's an isolated close circle mystery in the snow. And it just, it sounded very like, and then there were none, which is one of my favorites. And this I learned, oh god, why is everything falling? Okay. This I learned is inspired by, based on or in some way a retelling of The Turn of the Screw, which I read Turn of the Screw in 2020. Didn't love it that much, but I love The Haunting of Bly Manor, which is a retelling of The Turn of the Screw. So like I've become more, it intrigues me more now that I see something as in some way a reference to inspired by or a retelling of The Turn of the Screw. So that's why I got this because I heard good things about it and I was like, oh, Turn of the Screw. And then this one, The Broken Girls by Simone St. James. I think it's an isolated close circle mystery in a girl's boarding school, which sounds like a fun read and by fun I mean chilling. Anyway, they all sounded intriguing. Hence me choosing them. Next I have, oh, these are all gifts. Okay, this, Bethany got me this for Christmas. It's Hansel and Gretel, retold by Neil Gaiman with Art by Lorenzo Matoti. It's got this like little window in it. Why can't I flip the pages? It's quite nicely illustrated, quite darkly illustrated as is appropriate with Neil Gaiman. If you don't know, because you've been in Iraq, Neil Gaiman's my favorite author. So Bethany literally had me photograph every Neil Gaiman book that I own. So she could make sure that I didn't have this before she got it. Which is very wise, because I do own quite a bit. So the odds of me already having the thing you're thinking of getting me are quite high. And then Shaya got me, these are still wrapped in their plastic. Which, yeah, volumes one and two of the Neil Gaiman library. She was like, I knew you wouldn't buy these for yourself. I'm also here and I wouldn't, but I'm excited to own them. These are like bind ups of like some Dark Horse comics done by Neil Gaiman. So the first one of volume one has some of these I've actually bought for Shaya as gifts. A study in Emerald murder mysteries, how to talk to girls at parties and forbidden brides. And volume two has the facts in the case of the departure of Miss Finch. I got that for Shaya. Likely stories, Harlequin Valentine and Trollbridge. So I am quite excited to have these. I would never splurge on comics, but I'm quite excited about this. And these are heavy at the look. This is the recent purchase, the city of girls, or just city of girls know the by Elizabeth Gilbert. Because this is one of Joshana's favorite books, and she was just going on and on about why she loves it. And the more she talked about it, the more I was like, that does sound something I would like. Because I heard it before, I think Joshana, but I think the other people too compare it to the Seven Husbands of Evil in Hugo. And I really liked that book, but I liked it kind of despite the premise, the premise of a Hollywood starlet telling her life story. I was like, when I read that book, I was like, I don't expect to like this because this premise doesn't appeal to me. And yet it was so well written that like, I loved it anyway. So hearing that another story is similar to that one. I was like, well, it wasn't really the story that got me on that one. It was the writing. But when she explained it and kind of went over all the ways it's different from it, I was like, oh, that sounds way more at my alley. Because it's like a large portion of it takes place in a physical theater, I think in New York. And I quite like the atmosphere of a theater more so than Hollywood. So that as a setting appeals to me way more.  So I feel like the odds of me hating this are slim. I feel like at worst I'll just kind of be lukewarm on it. But yeah, I figured out how to give it a go. Then Gardens of the Moon by Stephen Erickson. This is on my list of series to read in 2021. I will be buddy reading this with my father. I got it for him for Christmas and told him that was why. He was like, all right, let's do it. So that's the plan in February that he and I will read this. I am moving. So that's throwing a hitch into like, because I know that will take time away from reading, but that's the plan is that we're going to buddy read this. So that's why I own it because I need to own it in order to accomplish that. Next is the next book in the All Souls Trilogy. I read Discovery of Witches and I was kind of lukewarm on Discovery of Witches. However, the way that it ends, I am, I know like, where the next book will be taking place and the where highly intrigues me and highly appeals to me.  So like, I decided to go ahead and give the second book a go. And then if I feel just as lukewarm about this as I did about the first book, then I probably won't read the third one, but I'm a complete sucker for the setting that, and I can't tell you the setting because it's spoilery for the first book. So the way the first book ends, if you've read the first book, you absolutely know where the next book will be taking place. I'm quite excited about it. Next is a gift from a friend of mine who's not on booktube and she's like, I'm quite bad at buying presents. So can you just give me a list of books that you want and then it'll be kind of a surprise what you get. And I was like, sure. So I told her I was interested in Steven, among the others that I said, I was interested in Steven Fry's retellings of the Greek myth. So she got me heroes by Steven Fry. I also need to get Mythos because I think Mythos is first.  Like, and it's really heavy as I think it's illustrated and it's just like on really thick paper. It's just a gorgeous book. This is like totally, totally, totally a coffee table book. So like it's kind of like epic to hold. I mean, I feel like reading it will feel like intimidating because I'm just like, oh, just holding this. I feel like I should be at the Huntington Library. But I think the audio book is read by Steven Fry. So that all quite appeals to me. So I might do it via audio. But I mean, I always like to own the physical book of any audio book that I do experience. Then I got for myself, my cousin Rachel, because I want to read more Daphne de Moria. I do own two other or, well, I read Rebecca and then I own two other Daphne de Moria books. Those being Frenchman's Creek and Jamaica Inn, which I do want to read. But I was wanting to read this next because I want to see the movie of this. And it's the one that I didn't own. Well, I shouldn't say the one that I don't own because I don't own every Daphne de Moria book. But so I went ahead and got it so that I could do that. That's why we have our books, right? To read them. And then this is another present from Shaya. I think this was a just because present, maybe it was a Christmas present. I don't know.  So I don't remember the occasion or if there was one. She got me the pop-up edition of The Little Prince. And I know she loves The Little Prince. So I suspect I also will love The Little Prince. Everything I've heard about it. Most people I feel like who read it love it and it breaks their heart. And this a pop-up edition? Like how fun is that? It's still in its plastic because I haven't. Okay, well, let's check it out together. Such a cute book. All right, let's see the pop-ups. Let's do this thing. Oh, where's the next pop-up? Oh, oh, that one moves. I don't know if you can see probably not. Very cute. Oh, whoa, whoa, whoa. Now that's a pop-up.  Okay, yeah. So I'm super excited about this. So thank you to Shaya. Next stack. This is Book of the Month Club books and one other. So the one other is Nosferatu by Johel, which is on my January TBR, but at the time of filming that TBR and for half of January, well, not half of January because I'm not halfway through January right now is the filming of this video.  It finally did. And I actually have read this already. So I will be filming a review and Miya and Shaya will be discussing it because this is the book. One of the two books that Miya and Shaya are buddy reading because we're reading each other's picks. She picked Nosferatu. So she's rereading it and I'm reading it. And I picked the wolf. So I'm rereading it and she's reading it. So Nosferatu by Johel. Do I need to explain what this is? I feel like it's pretty well known. Johel is Stephen King's son. People often say that this book is quite in the style of Stephen King. I am not an expert on Stephen King by any stretch, but from the experiences I have had with Stephen King, I would say this feels like if I didn't know who wrote this and you said Stephen King, did I be like, yeah, that checks out. So yeah, it's about this like vampiric type being that ferries children in his car with the license plate Nosferatu to Christmas land. And so it's just a real happy little fairytale as you can tell from the cover. Now all my end of year book of the month club books again, so my pick for that month, my two add-ons, and then one of the best of the year picks. I think I remember which is which. Pretty sure I remember which is which. Outlawed is my book of the month pick and it is, I would just get, is this January not December? I don't know. I think they do it in January so that you can include December in the best ofs.  Anyway, I picked Outlawed because I was super keen on any of the picks this month but this one somewhat appealed to me and I think Shaya picked it too. So whenever we can't decide we just go with whatever the other one picked. It seemed quite feminist and I'm very hit or miss on Westerns but I'm willing to give it a go.   It's the worst. I could not think of a cover that appeals to me less but you know, that's a terrible reason not to read something.  Pulled out of the box and I was like, is that it? And the text isn't very small so I should be able to knock this out in no time. Next is one of my pick for one of the best ofs and that was Anxious People by Friedrich Bachmann. I'd seen this around but I had never really been interested but I then read this analysis because I was trying to pick which of the best ofs I would want so I actually looked into what it is and it sounded, now I don't remember, oh it's would-be bank robbers and they're anxious about it and it just sounded like a very strange almost gallows humor comedy of errors that I've heard that his writing is just like excellent and it sounds quite character-driven so it sounded like something that very possibly could be up my alley. Given that in 2020 I was reading more contemporaries and things like Normal People and the Hearts and Visible Furies and Beatrice Reed quite liticky contemporaries and I liked those so I thought this might be a win with me especially if it was one of the best of the year like how bad could it be and then my add-ons I got A Rogue of Ones Owned by Evie Dunmore I really did not like bringing down the Duke which was her first in this series but as I've come to learn romance novel series are kind of more spin-offs where like it's like a group of friends or a family and then there's kind of a book for each one so this is a sequel in that way so I wasn't buttering this but I talked to a friend of mine who read both and she liked bringing down the Duke but I was like you know what my issues were were with bringing down the Duke do you think I would like a Rogue of Ones Owned better and she was like actually yeah she was like I I didn't she didn't have a problem with bringing down the Duke bringing down the Duke but having read both like she knows what things in bringing down the Duke were there and she doesn't disagree that they were there they just didn't bother her so she was like I can safely say that Rogue of Ones Owned does not have those things and you'd probably like it better so I was like all right because I the in bringing down the Duke the writing style like I I liked it I didn't hate it there was just more like specific elements to the romance that like really put me off but because the style of the writing was like you know quite amusing and fun and I do love me a Tessadero style Bridgerton style fun historical romance with like a lot of witty banter I was like all right let's give it a shot and then early riser this sounded strange and I also don't remember what it's about but I remember thinking actually that sounds great every winter the human population hibernates during those bitterly cold four months the nation is a snow draped landscape of desolate loneliness devoid of human activity well not quite your name is Charlotte Worthing and it's your first season with the winter consoles the committed but mildly unhinged group of misfits who are responsible for ensuring the hibernatory safe passage of the sleeping masses you are investigating an outbreak of viral dreams that you dismiss as nonsense nothing more than a quirky artifact born of the sleeping mind when the dreams start to kill people it's unsettling when you get the dreams too it's weird when they start to come true you begin to doubt your sanity but teasing the truth from the winter is never easy you have to avoid the villains and their penchant for murder kidnapping and stamp collecting ensure you aren't eaten by night walkers those whose thirst for human flesh can only be satisfied by comfort food and sidestep the increasingly less than mythical winter folk but so long as you remember to wrap up warmly you'll be fine so that sounds really weird really really weird but also as i read that description online when i ordered it and like some of the like book of the month reviews i was like yeah okay that i feel like i could definitely vibe with this okay and last but certainly not least is this entire stack of robin hob books because i've decided i quite like robin hob pooh um so i've i only just as of last night finished royal assassin which is the second book in the far seer trilogy but like even having not finished it i was like i robin hob is the is an author for me i already know this so i decided to just go ahead and get like with my christmas bonus all of the hob books so i and i stacked them in order so this is the live ship trader series which is on my list of series that if i can my list of series to finish this year included far seer and my list of series to start this year included live ship traders which i kept calling mad ship and mad ship is one of the books in the series but i like in four videos i think i refer to this series as the mad ship series i don't know what madness possessed me see what i did there any hoosies ship of magic is the first book followed by mad ship concluding with ship of destiny these covers are eight my favorite covers are of the final three and you'll see why they are objectively without question the prettiest covers but i knew next is the the tawny man trilogy which begins with fools errand then the golden fool and then fools fate like those covers are totally fine and then the final trilogy which is like definitely the best covers definitely definitely and that's the fits in the fool trilogy and they're just they're quite shiny especially the third book which is teal gotta love teal so fools assassin fools quest and the best cover of all assassins fate just just look at this fucking cover like like yum so yeah that does it i is oh wait graphic novel i did this last time where i said i'd haul something at the end and forgot okay i think in my december wrap up you saw shea give me this she read i hate fairyland a bind up i think of the first two volumes she gave me the first volume of i hate fairyland which apparently is oh my god just look look at that apparently the premise of this is that um it's basically like this girl who like falls into fairyland a la like alton waterland or whatever and like them like fairy creatures or whatever or like to leave fairyland return to your own realm you have to like perform you have to like go on this quest and it should take like a day and uh 27 years later she's still trying to fulfill this stupid quest it's not going well and it's blurbed actually by neil gayman it says it can be colored and vicious to light and always dangerously funny so based on shea's description and based on what i have like seen just kind of flipping through this i mean it looks like complete madness but also like it'd be quite fun yeah i mean it's kind of like each color is just like a creola box just like vomited everywhere so it's gonna be a dent so i might have to like wear sunglasses oh i read this all right yeah so those are all the books there may be some books that i acquired since my last haul that like it's like right after that haul so it's been so long that i've already like tbr'd and wrapped them up and forgot that i never hauled them so sorry if that's the case my bad oh i already see over there there's one huh do i go yeah i'll fucking go get it last last last is uh infernal the chronicles of stratus book one by marc diegher uh this was sent to me by the publisher and i need to read it okay four realsies that's it let me know in the comments down below if you've read any of these books if you want to read these books if you recommend these books if you are dreading me reading these books whenever you want to let me know i post videos on saturdays other random times as well but definitely saturdays so like and subscribe and i'll see you when i see you bye


What's up YouTube? We're here. We got 36,000 points on the MUT team with help from the chat We're going to open up as many packs as possible with this many things. So first we're gonna open the 40 Time gold premium bundle this 40 gold premium packs three elite player packs So hopefully I pull something the teams at 65 overall Don't really have anybody at this the first packs. I'm gonna pull So we're gonna rip through the gold premiums. Hopefully I'll go ahead and get something. That's really worth insane I Think all my soul elite right off the bat trade Boston. I mean, that's barely an elite Buddhist an elite What else I'm gonna get? Gold players a wire see the 71 West Horn that was my guy and mutt right there. This was my guy Check come on man. I know what's for and look he got this speed 65 come on man 74 power move right now West Horn might play for the team and might play West Horton and that was my guy Yeah, I just don't go right to the next pack. What's up with this here? Come on chat On open pack 42 so you get hella packs. So if you like a little rip and do packs It's definitely gonna be the move Man hit a couple from the back. So hopefully I can get at least A good amount of coins hating hers. He got be fast. He's good on regs 76 speed I guess that's fast right now for the for the tight end. I Open elite player West Horn man West Horn is definitely good. She's a great player This is an elite player pack. So hopefully I got to pull something of this That's gonna get my team started so I can repeat right away. I Pull the center You know, that's not always terrible Need a good line especially in this game the way I played the first couple days I need my tackle. So I'm gonna need good tackles probably gonna be the most important part of the line Oh, what's this? I got the Willy Rolf. Yeah, they're the tackle for you. I Love the animations on the cars now is his better than has been in the past Definitely more exciting. So 83 legend tackle where I go another legend Lorenzo Neil We got four golds in that pack So now we got 38 more gold packs left get animations of the cars are definitely dope Definitely speed through these things a little bit for golds again It looks slow like the gameplay y'all think the gameplay is slow, I mean there we go Anthony Sherman as an elite Terrell Edmonds. This is a good card 83 speedy 62 Not bad always knee height in the secondary I too is that good? I mean I guess the legends are good We'll see Kenan Allen power up some power up Kenan Allen Interesting to see how the power-ups work this year. I mean have y'all played mutt or have y'all played just regs Because I feel like regs isn't that slow Maybe I don't know. Maybe it's just me Definitely slower.    It's tough Yeah, that way it's not pokey. We were playing pokey Monogio and now the people playing regs The shine Hamilton I mean I need to pull something. This was a hundred dollar bundle right here So far put 300 on the game to start the season Marshall yonder power up. There you go. Jonathan Stewart. That's my like mom couple only a couple of leads in these gold player packs Definitely won't try to get my hands on the Tyree kill. That's probably the number one card I think was a must to start the season in mutt. So I'm gonna find a way to get to 91 speed Tyree kill get him on the team Definitely gonna play some games tonight tons of games probably one players to the end of the night And the night being then when I pass out so you know Stick around we're gonna be here for a while Corey Grant got to be fast 89 speed. There you go He might start it running back right now Corey Grant Jacksonville Jaguar legend for the last couple years. Actually the Paco blues are just that that's why they're here Actually Michael Yeah, it's cool had been in a tornado bunker for the last couple days because you know, he's really been On the D4 there we go.  I really I'm saying No, I actually I actually have the game. I'm not on EA access or early access. So I'll be here all night Hopefully till tomorrow night That's the goal. I got my coffee. I got a lot of water Got some Bud lights Say Quan Barkley Say Quan Barkley That's gotta be a decent pull right for gold. I guess I really don't know right now Gotta have a lot of water if you want to stay up. That's how we say it in Philadelphia water So I air Alexander 86 speed. That's not bad speed right there It's 85 speed fast. I really don't know the speed. I really looked I Haven't really looked at a lot of the cars like which one's fast which one's slow and all that stuff You know, I'm pretty much just been Playing There we go Devante Parker That's not bad. Always like Devante Park. He's got good. I always had good speed. I don't think 83 is that amazing really? I know a coach. There's I know true. Yes, trust me. I know true Yes, I'll stare at the regs roster for like months now looking for a brand in Marshall Cheese, but brand Marshall follow that was mine. No, we're not done yet. I don't know how many we have left I thought that was it Listen Hennessy and leaderboards, that's what if there's no leaderboards. Oh Man man 18 legend like Gary. Oh, he might start He might start Like Garrett blunt. I don't know. I don't know. That's a good pull But I like an elite like Garrett blunt. He's gonna start mutt He's gonna run people over 88 truck this early and he's got to be able to he's got to be tough Gotta be tough Well, listen, Jay, we won't find out. I'm gonna find out what works and what doesn't alright It's a slow process, but we're definitely gonna find out Charles clay. He's always had decent speed for a tight end Chris Hogan, I hate Chris Hogan with a passion because he is the reason I missed the first live event ever This book's mostly with Chris Hogan. That's just more and more every time I think well CJ Moseley not a bad pull 83 overall linebacker 78 speed Good hip power early in the game 85 hip power gotta be good So Gary blunts definitely one bit. He's definitely one big player with that much truck and he's a pride I would say my best pull I've had so far a Lot of messy stuff right now a lot of stuff. That's not that exciting When the Gary blunts your best pull, I got the Gary blunt and take one Barclay. I feel like that's a good one to punch you know Somebody sell sick Darren Sprouls. Darren Sprouls has always been killed in mutt Always like and not even a mutton man. Oh Alan Robinson. That's a nice. That's a nice card That's a nice pull nice elite wide receiver Not that fast. I feel like you get a goal. I receive it as fast I can probably perform a little bit better than Alan Robinson, but we'll see what the markets like Durham win James. That's a dog 6383 speed 82 hip power. He's probably on the team. That's a that's a good pull for me As far as I'm concerned there when James is somebody I wanted on a team when I looked at all the rookies and said He's gonna be a great He's gonna be a great mutt player and a great player in the game anytime you got that type of speed that type of height and Be able to hit people. That's that that's a good card We're gonna find out when we're done with another bundle worth or not We'll analyze and see how much money I made as far as coins are concerned and see if it's worth You know, this was a hundred dollar bundle. I don't know what I might build a cap team We'll see. I don't know what the cap is. I literally just got on my I've played a little bit of souls as much I put three hundred dollars on the game so far. That's what I'm probably gonna spend today. Oh B That's a card boys Now what I just say about the height to have another safety with that height 85 speed 81 hip power. You don't have two six three DB's in the secondary. That's great That's a great pull. I don't know how much it goes for But as far as it being a man player being a you know a player in the game. Oh, we will be tough Hey, can you pull the diamond players just pull them? That's what happens Exactly sure. He get there. Who are these? Christian Campbell or all rookies go blue like this. Is that like the rookie every rookie? It might it might be a little a It's my arms that are gonna leave Now all these power-up cars. I really don't know what to do with the power of the light I guess I got power up every card. I got the pet Pete. That's the one I got They cost a lot of training points to power up to where they're actually usable So when I play to the man, I do like it. It's been fun It's been a We'll see how it goes from here on that. I know might would be a lot slower Then how fast it's it again? 85 Oh, that's the end of the bundle. So let's see what this bundle had. This is the first bundle. Oh I went from I got about shoot 300. I'm probably like 270 items Let's see. These are I got an 83. That's what I wound up with from that pack How many leads four four eight? Plus five is what 13? 13 elites for a hundred dollars So you want to see what these can go for in a Keenan out there Allen Robinson might get me 10k So that's pretty much what we got 13 for that one I don't know I feel about that and then we got a bunch of gold how many golds we got Got a lot of golds probably got easily a hundred and thirty golds Did I get Troy? Let me see So, I mean, I don't know how I could possibly really be worth it like that I don't think I pulled anything amazing. I thought it was pretty pretty average So block grab that again. Is that something I go get again? Do I go with that bundle? Hmm? Let's see Why weren't some of my cards ready? What? All right, let's see what else we can go and grab Actually, we're gonna keep that that was the first bundle the first bundle of the year Thanks for watching Make sure you hit the sub like and comment on if that bundle was worth it And if I'm saying you would open another one. I still have 24,000 points So I get two more rolls if I wanted probably made me. I don't know maybe 200 K this early in the year I feel like I didn't pull anything that amazing But you know, it's a lot of pet is a lot of packs. So there's a lot of potential for a lot of things I definitely got about 300 cards from that So we'll try to flip them through as many points as possible many points as possible Like I said, hit the sub hit the like comment below whether or not you thought that pack was worth it Peace