day. So it's my pleasure to introduce Una Bazou, who is giving a talk on activity-driven transport in harmonic chains and who could not come here because it's still very difficult to travel. And we are very happy that you nevertheless accepted our invitation and we are looking forward to your talk. Thank you, Sarah. Yeah, I'd like to start by thanking the organizers for inviting me in this conference and giving me the opportunity to speak online, even though I could not be there. So I'm going to talk about activity-driven transport in harmonic chains. So this is the sort of outline of this talk. First, I'll very briefly recapitulate the energy transport in a thermally-driven harmonic chain. And then I'll go over to the case when the drive is active, not the usual thermal one. And in particular, I'll focus on two observables. The first one is energy current and the other one is kinetic temperature profile. And then I'll conclude with some open questions. So yeah, energy transport in one dimension. So whenever we talk about energy transport, the typical setup we have in mind is the macroscopic system, which is subjected to temperature gradient and then energy flows from the hot air end to the cooler end of the system. And the simplest theoretical model to understand is the phenomenon is an oscillator chain, in particular in 1D, an oscillator chain which is connected to two thermal reservoirs at the two ends. And the point to remember is that these reservoirs, thermal reservoirs are in equilibrium themselves. So each reservoir is in equilibrium, even though the temperature could be different. So the reservoir itself satisfies fluctuation dissipation theorem, which means that the coupling to the reservoir has to satisfy certain conditions. And the relevant questions that are usually asked in this setup is what is the energy current, what is the thermal conductivity, and how is the local temperature profile and velocity fluctuations, how does it behave locally, et cetera. So the paradigmatic example is the harmonic chain connected to Langeva mass, which was studied by Lijder, Leibowitz, and Lieb in 1967. So let me briefly go over to the model and the results that they obtained exactly. So we are talking about a harmonic chain. So a chain of N harmonically coupled identical, meaning say mass oscillators. And the LF oscillator has a displacement axle from its equilibrium position. And the boundary oscillators, so L equal to 1 and N, they are coupled to two different thermal reservoirs at temperatures T1 and TN. And this coupling is, in the most simplest case, is modeled by adding two forces on the boundary oscillators. One is the dissipation, this gamma x dot kind of term. And the other one is a Gaussian white noise. And because the reservoir is in equilibrium, that means that the strength of this noise is related to the dissipation in a certain way. So we have two different thermal reservoirs at the two ends, with different temperatures T1 and TN, and each of which satisfies fluctuation theory. So the temperature, I mean, the noise at each end is related to the dissipation at that end in a certain way. There are of course various other models of thermal reservoirs. I mean, it's possible to model in various other ways. But this condition of fluctuation dissipation theorem must be satisfied by all. But we'll stick to the most simplest model here. So for this simple model, linearity and Gaussianity allow for an exact solution in the stationary state. And they showed, the RLM paper showed that eventually it reaches a non-equilibrium stationary state, although it's Gaussian and it carries a current. And most importantly, in the thermodynamic limit, that's when the number of oscillators is very large, the current that flows through the system is proportional to the temperature difference of the two reservoirs. It's simply proportional to T1 minus TN. The proportionality constant depends on the mass of oscillators and the constant, I mean, the harmonic constant kappa and all these things. And another important point is that when one looks at the local temperature, it remains uniform at the bulk at the average of the two temperatures at the two ends. So the bulk temperature is simply T1 plus TN by two, and the current flowing is proportional to T1 minus TN. So a natural question to ask is what happens when reservoirs are away from equilibrium themselves? So the reservoirs that we are connecting to the system are not in equilibrium. And in particular, what happens, the question that we are going to ask here is what happens when one considers active reservoirs. So by active reservoirs, I simply mean a medium consisting of active particles. We have already heard a few talks about active particles in this conference. So these are self-propelled particles. Examples are like bacteria, genus particles, and various other kinds of microswimmers and nanoswimmers. They are inherently non-equilibrium in nature. So the barge that the makeup, the reservoir that the makeup would also be out of equilibrium. And recently, there have been many studies, both theoretical and experimental, which study the behavior of single probe particles in such active reservoirs. And they already show various kinds of intriguing features like images of memory, modification of equilibrium theorem and all these things. So what we are going to ask here is what happens? How are the transport properties of extended systems affected when one connects such a system to active reservoirs? So this is like a cartoon. You can think of a system connecting to material bars, just a cartoon representation. And the bars are different. Their activities are different. And we are going to take the most simple model again, just the linear harmonic chain. And we use a very simple model for the reservoir as well. So let me define the model more precisely. So as before, we have a chain of n harmonically coupled oscillators, which we spent XL for the inlet oscillator. And the boundary oscillators, L equal to one and n, are coupled to these active reservoirs now. So how do we model these active reservoirs? We simply add an extra active force, which does not satisfy fluctuation dissipation theorem, and which has a memory. So apart from the usual thermal noises, so the dissipation constant dissipation and white noise at the two ends. So we have xi one and xi n. We have two additional forces, which I call f one and f n, at the two boundary oscillators. These f one and f n are exponentially correlated. So they have memory. So that gives non-marcopian nature of the system. And most importantly, because this is completely independent of the dissipation. And so they do not satisfy any kind of fluctuation dissipation theorem. The reservoirs themselves are away from equilibrium by virtue of this kind of modeling. And this correlation time scales tau one and tau n, they are the measure of reservoir activity. So when tau one and tau n are very small, we go towards the passive limit. And when tau is large, that's more active reservoirs. Okay, so as I already said, so presence of this correlated active force that makes the dynamics, this XB dynamics non-marcopian. But more importantly, because this force is not related to the dissipation, there's no FD in the system. And that's what is going to give rise to certain interesting properties as I'm sure I'll be later. But before that, let me give some examples how one can generate such exponentially correlated forces. So suppose we have, suppose this force FD is simply a run on table like force. So FD is some sigma t, sigma is a dichotomous noise, which flips its sign with some red alpha. In that case tau, the time scale is simply one by two alpha. Similarly, one can think of the boundary particle as an active Brownian particle where FD is cos theta, we also saw this, I mean, each of these examples we have already seen in the in the conference.  And similarly, one can think of an active one-stranded process at the boundary also. So we'll not consider any specific details, but just the case that the active force has an exponentially correlated form, exponential correlation. And we'll see that that's enough to compute the energy current and temperature profile, which are going to be the quantities of primary interest for this talk. And yeah, so we'll be concentrating in the stationary state. And yeah, because the system is linear. So that again allows exact computation of certain observables, the observables we are particularly interested in. And I'll not go through the details of the computation, but just mentioned that we have used the matrix method introduced by Opishek Thor in this 2001 work. And using that method, one can show that in the stationary state, the displacement of the oscillator can be expressed in terms of a matrix G. This matrix G is the inverse of a tri-diagonal matrix, this here, I hope you can see my cursor. So this G matrix contains the properties of the system and the dissipation gamma. It does not depend on the noise. The noise appears here. So we have zy-tilde, which is the Fourier transform of the white noise, the thermal noise, and f-tilde, which is the Fourier transform of the active. So these two are have very different properties. As far as the white noise goes, the correlation is simply proportional to the temperature. Once again, I mean, remember that this white noise comes from the thermal component of the reservoir. So it satisfies fpt. The active noise, on the other hand, does not satisfy fpt. And it has a Lorentzian spectrum, which is reminiscent of the signature of the memory in the real time. So this zy-tilde, this Lorentzian spectrum of the active reservoir, that's the key quantity here. And that is what controls all the observables that we are going to see. So let's first look at the energy current. So by energy current, I mean the average energy flowing from the reservoir through the system per unique time. And that is, of course, same for all oscillators because there is no source or dissipation in the bulk. And then it's most convenient to write it in terms of the energy coming from the left reservoir to the boundary oscillator, which is here. So this is the velocity of the boundary oscillator, and this is the force that is exerted by the reservoir on the bottom. So it's the total force, including thermal component and the active component. And we want to find the average of this instantaneous current. So as it turns out, this can be computed exactly. And because of the linearity of the system, once again, what happens is this total current actually just separates into two different components, one, the thermal component, the other one is the active component. So the thermal component is exactly same as in the case where there is no active force, basically, the case which I did even with study. This thermal current is simply to the difference of the two reservoirs. The other one, the active current is much more interesting. And that's our main quantity of interest. So it can also be computed exactly. And formally, it's given by some integral. I mean, you don't have to bother about the exact form. But just notice that this g tilde, this reservoir spectrum appears here, g tilde at the left reservoir and right reservoir. Okay, so this Lorentzian spectrum is what controls the behavior. And in the in the end going to infinity limit, the thermodynamic limit, when the chain is very large, it can be computed explicitly. And in that case, the contribution comes from only the system phonon band within the system phonon band, so between omega minus two square k by m and plus two square k by m. That's the characteristic frequency of the of the harmonic chain. And, and this is the form of the active current. Again, you don't have to bother about the details. But note that the active current is some rather the difference of two terms, each coming from one, one reservoir. So let's first try to see how it behaves. This is a plot showing this active current as a function of the activity tau one of the left reservoir, for different values of the activity of the right reservoir. So the symbols show numerical simulations with a particular form of active force. Here we took the run and double kind of form and n equal to 64. And the does the solid lines are simply and going to infinity results, of course, the match. And what more is that we see that there are certain very interesting features which become apparent from this plot. First of all, the current is a non monotonic function of the activity drive or activity of one reservoir. So it first increases and then decreases with the with the maximum at some intermediate activity. So this means that the differential conductivity is negative in certain zone. We'll come back to this issue later. Another point of interest is that the current if you follow one car to see that it crosses zero twice, meaning that the current reverses its direction twice, one at the trivial value when tau one equal to tau n, of course, when there is no activity drive, the current has to be zero. But additionally, at a different value of tau one, if the current also changes sign. So these are two features which were both absent in the family different case, the family different case that kind was simply proportional to T1 minus Tn. So no non monotonicity and no reversal except at the trivial point when the when the temperatures are equal. So I'll just quickly describe these two features in a bit more detail. So I'll say already mentioned so negative differential conductivity means that the the this dj d tau is is negative in certain parameterity. So this negative differential conductivity is sort of a counterintuitive phenomenon. So we are increasing the drive and the current is changing non monotonically. And such this negative differential conductivity is possible only away from equilibrium near equilibrium, it's not possible. And there are certain known examples, but all of them are in nonlinear systems, in particular, in presence of some obstacles or or kinetic constants. So here, what we see is that this active drive somehow leads to this NDC in a in a in a completely linear system. So this, it was kind of surprising result for us. And to understand the physical origin somewhat, we looked at the at the, I mean, at the spectra of the system and the reservoir. So the system frequency spectrum, of course, is is picked. So here in this spot in the left panel, you can see the blue curve is the system's frequency spectrum. It has peaks near the boundary, meaning near the characteristic frequency omega C. On the other hand, the reservoir spectrum is a Lorenzian with peak at omega equal to zero, that's this orange curve. And what happens is that the overlap. Okay, yeah, thanks. And yeah, the overlap actually changes non-mortulnically. So here, if you see in the right panel, so the blue curve is for very small activity. And then the overlap increases when we go to tau equal to 0.5, some intermediate value. And then the overlap decreases again, when we go to a very large activity. So this is what gives rise to this non-mortulny behavior of the current as a function of tau. It's also possible to understand this NDC from the perspective of non equilibrium response theory, but I am not going to the details of that here. Let me quickly talk about the current reversal. So here is a plot of the current in tau and tau n plane. So here the green and the blue shaded regions show where current is positive and negative. So if we vary tau one by keeping tau n fixed, we see what we saw in the previous plot. So first the current is negative, and then it becomes positive, and then it becomes negative again. So here this curve here is a rather non trivial car, which I mean, it's a special car where the current is zero, even though there is a finite activity drive across the, across the system. Okay, except at so this happens at all values of tau one, tau two, tau one, tau n, except at the subtle point where the current is either positive or negative, depending on which way, which parameter we back. So this is also a kind of interesting result, which we don't see in, in, in, when we have thermal or equilibrium reservoirs driving a system, at least a harmonic system. And next I'll very briefly mention what happens to the kinetic temperature profile. So by kinetic temperature, I mean, the average kinetic energy of, of each oscillator. And that also can be computed exactly. So what, what is surprising is that similar to the thermally driven case, here also, the kinetic temperature profile remains flat at the bulk. So here in this plot, you can see, for a fixed value of tau one, the profile as a function of l for different values of tau n. So this orange curve is for tau one equal to tau n, and these two are two other, other different values. So the, it remains flat at the bulk. And one can show that it's actually of the form, it's half of some curly T one plus curly T n, where T n, T one and T n are depending on the tau one and tau n only. So it raises a possibility that whether one can think of an effective temperature picture where this one can associate this curly T one and curly T n as the temperatures of this active universe. So the answer to that is actually no. So even though, I mean, even though the profile is flat, and it has this form, which is kind of reminiscent of the thermal case, there are certain very significant similarities with the thermal case. One is that even when tau one is equal to tau one, tau n, so there is no activity drive at all. In that case, also, if you see this orange curve here, in the thermal case of the profile in that case is completely flat, no boundary layer at all. Here, there's still a natural boundary layer present. And more importantly, if we look at what happens, if we associate this effective temperatures and compute what would have been the thermal current given these temperatures and whether that matches with the activity current that we actually get, these two do not match. So here in this spot, you can see the solid lines are the actual active currents that we compute. The dashed lines are the projected currents if this were taken to be effective temperatures. So these do not match, except here, if you see in this brown curve, which is for tau n equal to point one and also when tau one is very small. So when tau one and tau n are very small, then we see that these two currents are kind of converging with each other. So that tells us that in this passive limit, when tau one and tau n are very small, there is some sort of a thermal picture emerging. And that is also not very surprising, because if we remember our activity was coming from these active forces, which had exponential correlations with time scales tau's. And when tau goes to zero, those exponential correlations actually emulate the kind of a delta function correlation. And in that case, one can associate an effective temperature, which is of this form. And one can show explicitly that to the leading order, the active current in that case actually does match with the thermal current with this effective temperature. Okay, so I'll quickly conclude. So what we have done is study the energy transport of harmonic chain connected to active reservoirs. Active reservoirs we model very simply just by adding a temporarily correlated force, which gives rise to non-marcovian features in the system. But more over, I mean, more important than non-marcovianity is the breaking of fluctuation distribution theorem. So that makes these reservoirs non-equilibrium. And that gives rise to some surprising behavior, like this negative differential conductivity and current reversal in the current. And this I just like to point out that these are very robust results. So we did not use any particular form of active force, we just assumed that it's exponentially correlated. So even if we take an RTP like dynamics or ABP like dynamics or some other dynamics, all of which have this exponential correlation, the result would not change. The result would remain exactly the same. And that's all. I mean, there are many open questions, of course, in particular what happens. So here we have used a very simple model of this active reservoir. But what happens if one takes a more realistic model in the sense that if one considers an assembly of active particles and coupling to them like in the cases where single particle probe were considered. And another thing is that whether this NDC and current reversals survive in the presence of a disorder and what happens when there are the oscillators are not linear, but there is some harm in sitting. So thank you for your attention. Thank you very much, Una, for this very interesting and clear talk. So we have time for questions. And I also want to encourage people in the chat. And of course, also for the people in the audience, we'll give priority to students first. But we already have a question in the chat, so I will just read it out. So in general, when the system and the reservoirs are strongly coupled, is it easy to identify what the energy current between the system and the reservoir is? For strong coupling, I would expect also a finite contribution from the coupling Hamiltonian. So here there is no coupling. Which coupling Hamiltonian do you mean? The coupling with the reservoir is not happening to a Hamiltonian. It's just dissipation and noise. So maybe I did not understand the question. Can you clarify which coupling Hamiltonian you mean? So Tobias Becker, I hope you can hear her. If you would like, you can type something in the chat. Okay, okay. Yeah, and there's a student first. Okay, I'm going to release it. Just out of curiosity in this phase diagram, where you show the sort of shrinking of this reverse current phase. Exactly. There's like that point where the two reversal regions meet. Yeah, does it have some interesting features? So this is just a subtle point in that. So if you see this, I did not show this. So this is the plot of the current. I mean, the 3D plot. So this crossing of the two cars, that's a subtle point. And so if tau n is equal to this tau bar and we change tau one, then the current remains negative all through. Okay, except it touches zero at this point. So there is no, there is no reversal, it remains negative and touching this zero at this point. And on the other hand, if we fix tau one at this value and change tau n, then the current remains positive throughout. That's the feature of this point. Ayurna. So a question. So do you expect anything interesting in the large deviation function of the current? Possibly, we have not looked at the large deviation yet. But possibly, yes. So here, of course, I mean, once we have this active drive, the whole system is not doubted anymore. And we expect some signature of that also appearing in the large deviation function. Okay, we have another question. Hi, it's Marco. Hi, hi. In terms of magnitude, is it as can it become as large as the thermal current or it's of another order of magnitude? Which one? The current itself? I mean, this active current, is it as big as the other one? Or it's much smaller than the thermal current? Yes, I think it, yes, I think it can be. I mean, there is no, there is no relative competition between these two. So the actual magnitude will depend also on the strength of the noise. So here this is, so the correlation that we had, if FTFT prime, that also has a strength. And depending on if we increase that strength, the current would also, I mean, the overall magnitude can be scaled. I also have a question, Oana. So I was interested in the temperature profiles that you showed. And you showed that's different from the case of just thermal drive, your boundary effect spreads a little bit into the bulk, right? So there is a little bit of spreading into the bulk. And I was wondering if you know if that is because of the activity or is it because of the memory? In other words, if the two bars would have memory but would be FTFT fulfilling, would you also have this spreading or not? Do you know that? I don't, but I can check. I think it's very interesting because, of course, for equilibrium systems. This is exponential. I mean, the boundary layers are exponential, that we did check. Whether it survives, if one does not have activity but still non-Marcovian. Yes, I don't know. Okay. Yeah, very interesting. Thank you. Okay, I think we had a lot of discussion. And if there are more questions, you can send them to Oana in the chat. And I think we should, or to me, and we can move on to the next speaker and thank Oana again very much for the nice talk.


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It is all base Ben Simmons Jalen. How ya doing? Three minutes to rip what? Fast break Yeah, cuz once you I mean once you break enough of something, you know how it's set up It's a little bit easier that way to Blake Wesley to 199 for the spurs Zion Pachimora You have Minnesota Brock Lesnar and a collegiate product. It's Dyson Daniels rookie future legends Be stew Isaiah Stewart 53 of 99 for the Pistons This one there to trifle like four of those already According to market on Isaiah Stewart pulls AJ Griffin rookie, I pulled like four of those Isaiah Stewart Colin Sexton to 199 corn in the market on that clearly. That's my end game. It's rookie rookie Jalen Dern That is a Ryan Rollins to 49 49 of 49 for the Warriors Jared Vanderbilt Trey Jones markets more senior Dyson Daniels Tim Hardaway. There's a Jabari Smith 19 of 25. There you go Houston. Nice one there Grats on the Jabari Smith at junior rookie auto that is as well. I'm assuming probably not but I might have It is the 25 okay Jabari Smith rock the rim. There's a Spencer Dinwiddy to 2 2 99 for the Nets. There's some peeling on that I'm gonna send you an empty box and rapper Shane peeling on the bottom of that one CP3 That is a rookie review Donovan Mitchell for the jazz Tyrese Martin Osemane Zhang Hopefully that's not a that means we'll probably get a Delac probably here's a link to your guys's break schedule again.  It's a red Malcolm Brogdon to 100 the C's Donovan Mitchell Jason kid Malachi random rookie a great strategy Chris Chat has been well sold at night. Let's run back over this break. Yeah, I'll clear it with rich later. Oh, yeah, Zion Williamson monitor nobly Ryan Rollins and Pete Maravich Yeah, I'll go I'll go and open a case. I'll first of all open a case of impeccable and That I'll take one and bring it in here So something that's not released yet and for free and that's expensive. Yeah I'm sure I'd sure I'd be the man of the hour if I did that Laurie marketing disco Very Asian Johnny Davis nice one there for the Wizards. God He can bury you be a man without a boy bit be a man without a job is right Man without a job Very up those eBay sales. Yeah, right? Honestly start grinding a little more Chris Weber blue to 150 Nice one here is going to the Celtics. That is Marcus smart Mac a smat Fast break auto not numbered on that one Arabia and CJ McConaugh Yeah, there's a little indent on the back. I thought I noticed that Let's take a double check on that. You can see it kind of yeah right there. We'll send it at the empty Boston wrapper with Celtics on that one Blaming on Kyle. All right. Yeah, all right. We can make that happen then Kyle told me to do it blue precious a shoe up for the Raptors to 150 Jason Tatum fearless Brody, you know, it's Valence shewness Tobias Harris disco as well as a Nicola Yolkich disco fireworks Trevor Keels and Tyrese Martin disco RJ Hampton Silver T Mac Patrick Baldwin and Tony Parker. It's a red Jay Crowder to 100 for the we're seeing this the Suns Yeah, Suns she was silver Dirk and another J. Nivey rookie. All right, that'll do it for a prism or a prism fast break We'll do optic fast break next I Kind of hope so to be honest J. Blaze. I think that'd be pretty fun. That'd just be a cool story, dude, you know Seen eight seed win freaking championship. That's yeah, that's true. It's nice Jalen Durin on the blue disco 249 grads on that pistons. I was just a dominator shea that went flying Gold vinyl Katie. Let's see if we can make that happen Shane Pretty sweet nem hard rookie Silver T. J. McConnell. There's optic Gary Trent Melo Cole, Jason Preston, Terry Eason Chrome does finally get into man. Silver Schroeder Didn't have to look up at the light to sneeze on that one Jabari Smith disco Bruce Brown For the nuggets Marjanbo champ pink disco. It's you nice. That's the 25 One of 25 for the bucks check this one really quick nice one there. That's a disco Brandon Ingram It's a solid card for sure. Congrats on that one. It's good for the brand NBA script writers for sure Walker Kessler That is gonna be purple Brandon Ingram to 99 be like less than what a black Pandora was another in a black Pandora's disco Kennedy Chandler Validates the play yeah true Actually, you kind of write on that Looks like a black velocity Jaylin Williams jade does Did it really? Yeah, never mind them disco the mill of all stargazing and a Desmond Bain never mind Oseman Jang there's a Wendell Moore jr. Fast break rookie auto for the tibbles Minnesota use of it Nurkitsch space space Validates the play internets Chat rookie blue Trey Murphy the third to 49 it's good for the brand All right, let's do prism hobby now. That's the end of fast break You'll have one random to do at the end as well heat gone and impeccable tomorrow. I know well I think he said he's targeting what game three to come back. I think That's what I saw yesterday That could be huge. He can give them minutes. That'd be huge Silver or Darius Basley like Wesley rookie Red wave Denny of Dia It's a silver obi top and ain't no stoppin trying Davis rookie because just yeah, I know even as a decoy. It's a good point. Honestly It was kind of often junior red wave rookie Kevin Arant pulsar Jared Allen McGowan's and Nick Leopold They have the wild card that never doesn't have that's true. Honestly To me a purple ice Norman Powell to 149 for the Clippers first auto Jaylin Johnson's second year Signatures with you to your snub at Jalen job Johnson for the Hawks AJ Griffin hyper C-web Jalen Williams rookie and Brandon clerk Orange to 49 coming up here. It might be a rookie that is Cody Martin. It's the other Martin There you go. 35 49. That's Caleb's twin brother Anthony Edwards, Kenny Martin, Jr. Ben Wallace, Mr. Diabato as well blue ice magic to One 25 Boston team felt just short of a crazy comeback. What happened with the Red Sox? They just couldn't get it done You're entering the ninth down 93. Wow. Good Lord, dude Red Paul George to 299 for the Clippers hyper Reggie Bullock It's got a clip in junior J. Will Red wave Anthony Simons First Ray young that is not set there that good. I Think why are the nets better than the cart are the reds better than the cardinals That's kind of wild Attic Johnny Davis silver Dyson Daniels rookie is the one change in a series huge. Yeah, true Mildcat Bram's a good point J. Blazer. Very good point Silver or Joel and beat fireworks prismatic. There's carlin. Yeah, I'm kidding Jerry so on Punching each other over here My card Yeah Me Bruce Brown nice one there to 299 Jaylin Williams, that's J. Will on the auto nice one there for the Thunder Jaylin Williams, there's a pulsar of deer and Fox and a Keegan Murray Danny Green and David Roddy. Wow. They have the same record as the Phillies in the Padres That's sad that's sad for the Padres of Reds who are supposed to be like the worst team in baseball this year Not necessarily maybe the worst team but one of the worst teams. All right, we've got 22 23 optic hobby now Why are they not called up Ellie? I don't know if they're I don't know if they're trying to win. That's the thing like Maybe I mean they're a little too good to be tanking right now. You're kind of way out of it If you're that good unless you start really lose weight 25 and 29 Considering like Like a Porter junior. What's up Joe? Is it just me or but his forest in the Star Wars Star was what do you mean Joe? I would assume it. I Don't think so Christian brown off the look, but I don't believe he is I think so Red bones Highland 299 silver to Martha Rosen lights out John wall silver stargazing After lunches, I know honestly Reds have a payroll of 91 million God, dude Christian Brown. I saw in there in the basketballs rookie for the Nuggets Yeah, no, he's not Joe. There's Jaden Hardy. He was talking about going to buy a personal though Nice, let's go. That's awesome enough said silver Jaden Ivey or hollow rated rookie Jaden Ivey What was that out of again enough said the orange of Tony was that? Stadium Club chrome Dicerill 1 2 3 left 4 5 6 right unless it's a gold cosmic cosmic. That's right. I forgot you're in cosmic now It's gonna be a 5 going to the right with the Rockets. I'll go with Elijah one Thank you for the sub there William William F with the sub Paolo rookie pink velocity to Martha Rosen is 79. I just went there for the bulls and base Well flu game. Yeah, I know honestly probably not. I don't think we're gonna ever see anybody do a flu game like MJ They're getting poisoned by Pizza place in Utah Siddiq Bay Nice raw ones over 293 on bids. Hell. Yeah, dude big pole then Nice chat Holmgren for the thunder hollow rated rookie autograph Let's go congrats to the thunder that is gonna be Minsu. Okay. There you go. Minsu rats, buddy Big chat right there live chat as well. We'll get that bagged. Very nice Lime green AJ Liddell at 149 Pelicans Zaira Williams Terequil space Yeah, it looks very clean for sure Hello, Bama to bio. Hello CJ McCollum base Vaughn you ready for some funny names and 1718 select as well L'eravia Aaron Gordon orange to 199 the nuggets and Justin Holliday Yes, they're gonna look good.  That is disgusting Ramon sessions Tyler Ennis scope for the Lakers silver Dwight Howard courtside Ryan Anderson Enis Cantor he was there for like half a season when the brawn went back Then the Cavs weren't doing well, so they traded way back to the they traded back to the heat I believe Tatum courtside rookie nice.  That is legendary. Hell. Yeah, man. That's so sweet Fond maker and Kyrie Got my card Zeebo man.  Yes, 1718 lead so orange Tony Parker to 75 for the Spurs I agree Austin Rivers and Mike Muscala as a hawk. Yeah, Wade Wade and a Cavs uni was just not right Yeah, it doesn't sound right Puzzles Kawhi Leonard that is a nice 77 of 99 Jamal Murray on the game-worn Jersey Here you go Denver a good time to get that purple to 99 Josh Jackson rookie Dante Exum And what a name Dante Exum is good Lord Justin Patton Jared Allen rookie nice fro That is Mike Conley To 25 on the tie-dye nice one there for the gris. It's actually pretty sick Courtside that is Paul Gasol and Ricky Rubio Those are actually concourses my mistake They are not They are not Carmelo Anthony Raymond Felton That's oh my god, dude. That's a maverick That's a three-card game use patch auto goal. That's nasty dude. Oh, man One of ten game-worn Raymond Felton. Oh, man, dude. That's awesome Lance Stevenson and pathbehave It's over here it's soaking up information. Dude, this is just so right like some of these guys are so random Lucris Dunn as a bull. Oh, man. It's a two ninety nine Goran Drogic and but Bogdan Bogdanovich nice one there. I mean, I know everyone playing for the wrong teams is right Mj and the Wizards. Oh, man true Josh Jackson try Caller Lance Stevenson Dirk all world nice one there. We've got a D books third year and Jared Bayless, man. What a name that is shared Bayless John Henson, that's a name Gorgie Jean John Lure For the Pistons on the tri-color Kelly Ubre and a yogi feral dude. Oh my god, bro sanity Richardson Russell Westbrook silver Brook Lopez still is a Laker Michael Kilchrist and Tony Parker All right, we've got a quick random to do guys for this Colin Welp. What's up, Mike? Mike D. What's going on, dude? That was that was a masterclass of random names right there All right guys gonna roll the dice whatever teams on top after three times we'll get the Colin Welp one Two and three going to the Knicks Knicks getting the Colin Welp. Do a quick recap. Everything ready here Yanks up seven nothing. Let's go, baby. It's a Knicks, right? Yes, Knicks Raymond Fulton hash to ten Jamal Murray the Wayne Bacon to ten Jalen Williams Jalen Johnson Wendell Moore Marcus smart Jabari Smith Isaiah Stewart Josh Christopher RJ Cole Noah Kirkwood Audis guy again Tony Alondes Williams and Chet Holmgren Nice one there I'll do it for the break guys. Thanks again for the fill up next. We've got Star Wars


Hey, everybody. Everybody having as good a time as I'm having this weekend? Great. As Ashkahn said, my name is Kevin Johnson, and I'm the founder and CEO of Zero Gravity Institute in Austin, Texas. So Zero Gravity Institute is a very busy commercial flotation center that I operate alongside my incredible wife and business partner, Carol Johnson. If you haven't had an opportunity to meet Carol this week, I would really encourage you to do so before you leave the conference this weekend. If you'll stop by our booth and introduce yourself and talk to her for a minute, you're going to find out that among other things, she's a brilliant business person. She's extremely committed not only to her own floating practice, but also to the floating practices of our clientele and our staff. She also has this incredible, real-world, practical day-to-day understanding of what it takes to run a successful flotation business. There's no doubt in my mind that Zero Gravity would not be the success that it is today or not work for the hard work and commitment that Carol gives our company every day in her capacity as an owner and the head of operations. Carol and I are both willing to share our knowledge and experience with any of you because at Zero Gravity, we have a mandate to be in constant service to the floating community. And when we talk about the floating community, we're not just talking about the people who are coming to us to spend money at our float center or to purchase one of the flotation tanks that we manufacture, but we're talking about you, the people who are either actively involved in running a float business or are in the process of planning to open a float business. We take this mandate very seriously. We consider it a huge component in what we do at Zero Gravity. And indeed, whether it's profitable to us or not, we spend a great deal of our time in consultation with existing and prospective business owners, helping them to plan for meet and navigate the challenges that are associated with running a successful floating business. So if there's ever anything that we can do to help you, please don't hesitate to reach out and talk to us because we're happy to do that. Now in addition to running our float center, we also design and manufacture Zero Gravity float rooms. This is one of our rooms right here. And I want to take a minute to thank the organizers of the conference for providing us with the opportunity to bring this tank and put it on stage and share it with all of you. There's a lot that I could tell you about the trials and challenges of embarking on a project of this scale and this complexity. But in the interest of time and not to put too fine a point on it, let's just suffice it to say that I've had my butt handed back to me a few times in the last couple of years. It's been sometimes discouraging and disheartening and a lot of times when I felt like I wanted to throw in the towel. And the truth is, if it weren't for the support and encouragement that so many of you people have given me, I doubt very much that I would be standing here today as a proud representative of Zero Gravity. I like to describe these rooms to people as large luxury scale technologically advanced flotation rooms designed specifically to meet the rigorous demands of busy, high traffic commercial flotation centers like the one that we're operating down in Austin and like the one that you all are operating in your hometown. So if you ever have any questions about these tanks, feel free to stop and talk to us about them. Now today I want to specifically acknowledge and thank two men for the profound effect that they've had on our ability to grow as a company this year. These are good men, like in the classic sense of the word. They're hardworking, they're as honest as the day is long. They're innovative businessmen who have inspired me to believe in myself, to set my standards higher and to work harder to accomplish my goals. They own a company that many of you all are already familiar with, in fact many of you already sell their products in your float centers. The company that I'm talking about is called On It Labs and the two men that I'm referring to are Joe Rogan and Aubrey Marcus. I'm proud today to be able to announce to you, our community, that Zero Gravity Float Rooms and On It Labs have formed a partnership with the shared goal of bringing to the industry the finest quality and most technologically advanced flotation rooms that we can create. Aubrey Marcus has prepared a few words that he wanted me to read for you guys today and I'll do that now. He says, congratulations on a successful 2015 float conference. On It is incredibly excited to be working with Zero Gravity to provide what we believe to be the world's best flotation experience. We are committed to total human optimization and flotation is one of the best tools I have encountered to assist with mental, physical and emotional performance. And even better, we're coming to you straight out of Austin, our mutual home. There's crazy Texans in their state pride, huh? So isn't it amazing? Isn't it beautiful to be reminded that when we're on the right path, the path of heart, the path of integrity, we get what we need. When we design our businesses around the concepts of service, when we align our thinking and we point our business down the road that leads to the greatest benefit for our whole community, we find the support and the resources that we need to succeed and to grow and to thrive. Maybe even thrive beyond our wildest expectations. That's where I feel like we're at this year. So how do we do this? How do we create a situation where we can be in constant service to our community? Well, one of the ways that we do that is that we gather on a regular basis at events like this, where we can share information with each other, encourage and inspire each other toward abundance. And we need to be grateful. The good news here is that we all, you and I, we all operate in one of the most uniquely supportive business communities that I've ever encountered. I firmly believe that any of us could pick up the phone today and call any other person in this industry with a problem or a question, and that person is going to bend over backwards to help us with an answer or a solution to our problem. It's really beautiful. It's also very fragile. And I worry sometimes how we're going to sustain this. As our industry explodes, as we grow at this unprecedented rate, as all these new people come in to share in the experience of being involved in the floating business, how do we keep it special like it is? The spirit of cooperation, this spirit of shared goals and shared values. Well, like I said, one of the ways that we do it is we come to events like this, where we can share information and inspire each other. And we've got to be grateful to the people that provide us with this opportunity. Let's be grateful to guys like Graham and Ashcon and Jake and Janine and the whole Motley crew at Floodon who worked so hard for so many months to organize this conference and make it such a success. It's because of them that we can do this. Let's be grateful to folks like Glenn and Lee Perry and Dr. Sudfeld and Dr. Fine, these brilliant, innovative pioneers who have blazed the trail that got us this far. It's because of these people that we can do this. Let's be grateful to Dr. Feinstein, Justin Feinstein and all the researchers and scientists who have picked up the torch and who are providing us with the scientific research and the data collection to give us the knowledge that we can share to our community about the benefits of floating. It's because of them that we can do this. Let's be grateful to Rich Martin and Paul Reeves and Bob Crandall and Shoshona Liebner for their work in helping us to understand and navigate the confusing and complex world of health department regulations and public safety. It's because of these people that we can do this. Let's be grateful to each other, to all your fellow entrepreneurs who are working hard to make all this possible. It's because of them that we can do this. Let's take the opportunity this weekend if you're an existing business owner, if you're already up and running. Let's take this opportunity to hit the refresh button, to recommit yourself to the way that we do things in this industry. Make yourselves available to the newcomers as mentors and guides and help them out. And if you're new to the industry, if you're just getting your float center open or you're still in the planning stages of that, take this opportunity to commit yourself to acknowledging that this is the way we do things as an industry. Spirit of cooperation, friendship, the realization that when we thrive as an industry, we all thrive as individuals. We can do this. I believe in every one of you. We can do this. Say it with me. We can do this. We can do this. Not like that.  We can do this. We can do this. Yeah, that's what I'm talking about Sunday go to church kind of we can do this. Yeah, I thank you guys. I believe in every one of you. I'm proud of you. I'm inspired by you. I thank you for your time and your attention. Now I'd like to buy you all lunch.