we're going to be talking about some of my most expensive makeup products that I would buy again in heartbeat so I'm a big believer and you don't need to spend a ton of money for products to be good but I'm also a believer in the luxury beauty experience as well so these products I'll give me the luxury beauty experience and I would drop some coin on these products again before we get into that I want to thank today's sponsor for the video which is Lily silk I've worked with them a couple times in the past as well so I already know that I love the products so I'm excited to be speaking about them again Lily silk offers a ton of different silk products from bedding to clothing to accessories I've tried everything in every category I have some Lily silk products on my bed I use their scrunchies I'm wearing them right now is non-stop Lily silk around here Lily silk is an environmentally conscious brand they are working with TerraCycle and are committed to zero waste production meaning they used fabric remains to make small accessories like silk masks and silk scrunchies which are really good I love my silk scrunchies and they believe that not all silk is created equal and all products are clean and toxin free with certification so they have all of these different silk products across the board and some reasons why silk are really good for you is they help retain moisture in your skin and they help reduce wrinkles if you're using like a silk pillowcase it helps the hair become less frizzy because there's less abrasion with the pillow good for those with allergies and it's good to wear silk clothing because it helps regulate temperatures especially at night as well with pajamas and sheets if your partner is like a hot sleeper I know mine is so silk is a great option for those things now when you do order from Lily silk they come in a beautiful eco-friendly packaging oh my gosh it really is a luxury experience this is my first time since the last time I ordered getting their new packaging it is so beautiful and elevated so some of the new products that I have I'm wearing two of them right now let's first start off with the robe that you see right here it is a silk robe I actually didn't have a robe before this I'm gonna be wearing this all the time all weekend at the home I'm gonna have to wash it all the time but I love the pattern on it the color it feels really lightweight so it's perfect for the summer yeah this one is cute I can't believe I didn't own a robe before and I really like it oh I feel so luxurious in this and then the next item is a little bit more clothing base it is this color top right here really cute it definitely feels very expensive and soft and you can style a lot of different ways I thought it was really cute paired with a skirt doesn't look so cute with the skirt I love this outfit I also paired it with some jeans to make it more casual so that's a very simple piece but it makes you look very put together so I do enjoy this one a lot mine is in the size small and I don't know if you can see up close but it really is such a nice product and then my favorite thing I think so this one size silk tank top with built-in bra is what it's called okay so it's the same material as the one size wireless silk bra and I don't know if you recall the first time I worked with silk I got that bra and I was like oh my gosh you need to have it because I still wear it all the time I've ordered some more of my own I'm obsessed with that bra they now have it in the same material in a tank top style with a built-in bra so now I can feel like I'm wearing nothing and actually wear it out and for those of you who are petite like me or if you just struggle with straps in general there are adjustable straps for me I always need to shorten the straps but you can also elongate them as well it's really comfy so I'm excited to wear that out now and I'm always too lazy to put on a bra so like that the bra is built in and again it's that silky soft material so it's super comfortable feels like you're wearing a cloud if you do plan on picking anything up Lily silk is currently having their 12 year anniversary sale so if you use the code Morgan Turner at checkout you will save 12% off your purchase so again I use thank you to Lily silk for working with me on this video and let's get into it my favorite luxury products that are very pricey so let me clarify this you don't need to spend an exuberant amount of makeup for it to be good you can get great things at the drugstore I truly believe that these are just specifically products that I have spent a lot of money on and I have no regrets so it was worth my money but you know like I said it's not necessary but guilty pleasures love these products so the first one that I have is from Charlotte Tilbury this is Charlotte's magic cream now the size that I have here is actually not the worst I tend to buy mine in travel sizes or I'll get them with gift it with purchases as often as I can because the smallest size 30 milliliters is $64 which is crazy from what I've heard this moisturizer isn't supposed to have that special of ingredients to warrant the price but I love this moisturizer I think it's so good I think it's the perfect consistency to apply before makeup so anytime I can catch a deal on this I'm gonna pick it up and if I run out I have and will pay the normal prices so I freaking love this moisturizer I think it's the perfect consistency it sinks into the skin so nice it leaves my skin feeling so hydrated I love it love it love it before makeup I honestly believe it improves the appearance of my makeup so it's one of those things where is it overpriced maybe but I don't even care it's still worth it for me I love this moisturizer the next product that I have is a makeup primer this is from Gucci Beauty Gucci is definitely one of the more pricier brands on the market this is the silk priming serum again I typically prefer smoothing slash hydrating primers and this is just perfect it's one of my favorite kind of silky style primers right here and I was looking at Sephora at the most expensive items this one is up there in terms of primers there's not many more primers that compete with this price point the glass is beautiful the aesthetic of Gucci Beauty I think in general is just beautiful but I really do believe that this improves the surface of my skin before I apply makeup it has a really nice hydrating aspect about it but it still leaves the skin feeling super smooth and silky so I love this guy I think it's awesome it's definitely a luxury primer for sure but it's so good obsessed with it this is the most expensive foundation that I own but I'm not gonna lie to you guys when it comes to luxury foundation when you get a good one you get a good one and they can't be beat you know I have a lot of foundations that are fantastic there's a few very pricey foundations that are totally worth every penny and one of them is this guy from La Mer this is the soft fluid long wear foundation and I would be lying to you if I didn't tell you how beautiful this foundation was on the skin now this is a hundred and forty dollars it's actually a bit light for me right now but I'm not gonna buy a darker color we're just gonna make it work anyways so I'm minding the shade natural one too and there's just something about this that I can tell that it's luxury and then I can't get it with any other foundation the way that it sits on the skin is so natural and skin like it doesn't look too heavy but it also isn't gonna give me super light coverage it gives me that perfect medium coverage and the way that it wears and it sits on the skin it continues to look great throughout the day there's just something special about the way that this foundation sits on the skin again do I think you need to spend a hundred and forty dollars on a foundation absolutely not you can get a great foundation for under twenty dollars but even though it is a hundred forty dollars it is one of the prettiest foundations ever to sit on my skin and I cannot deny that and I only use this really for special occasions and let me tell you it was such a luxury to be able to use it today for this video I'm loving the way my skin looks I love the way my skin looks every time I wear this it wears great for events so I'm happy I got to use it today and when I run out I will pick up a new one because I just I love it so much the next product that I have is from Shauntakai Shauntakai is definitely one of the briciest brands and a lot of times you'll hear me say that their products while all of them are lovely I really have not tried a bad product from Shauntakai I do think they're overpriced but this with the skin and complexion I just feel like that's something that you can't mess with and they're just skin tinted moisturizer truly amazing this is an $80 tinted moisturizer but it's such a beautiful tinted moisturizer you guys wish Shauntakai you can trust that they're going to be using great ingredients in their products for you so that's what you're paying for there but it sits beautifully on the skin it wears beautifully and I'm very picky about tinted moisturizers just because I do have semi problematic skin I'm at a decent point right now but you know at different points of my life I've struggled with pores I've struggled with dryness I've struggled with acne acne scarring all of that so I've always been very picky about light coverage this is beautiful it actually gives a little bit more than like coverage it sits on the skin beautifully for it being a tinted moisturizer it doesn't make me look super oily super quickly so as I stated before when it comes to complexion I don't mess around if I need to pay a little extra for a good reliable complexion product that doesn't break me out I'm happy to do so so the Shauntakai is definitely my favorite tinted moisturizer in my collection for sure I have been into tinted moisturizers more recently because I've cleared up the majority of my acne so I've been enjoying that even more than usual this concealer honestly I'm doubtful of anymore so I kind of want to give you an update especially in the beginning last year when this first launched and I bought it I loved it it was instantly one of my favorite concealers this is the Tom Ford shade and illuminate concealers a beautiful concealer it has the perfect amount of coverage the perfect finish but I have owned this concealer for about a year now and I'm noticing I don't feel it's as magical as it once was so I really don't believe this has the longest lifespan I'm starting to notice it looking a little bit more thick on the under eyes than it used to look and it seeping into the lines of the under eyes more than it did so my hesitation about putting this in this video is very big because I don't know that it has the longest lifespan it is a $95 concealer yeah I spend that much on it and in the first I want to say seven months six seven months that I had this I regretted nothing and I really love this concealer but now I have an eyebrow raised because for $95 I mean I've had it for a year I said hmm it says the lifespan on this is six months okay that makes a lot of sense not that the lifespan should dictate anything for it being $95 it should last at least a year I'm doubtful okay it was worth it in the first six months I'll give it that but just keep that in mind I wanted to update you after six months that ingredients something happens in there but when it was good y'all it was good I don't talk about this product too much but I really do love it this is my second one of it this is from La Mer and this is the powder okay if that's a really cocky name but it is it is the powder this is $110 it comes in about the heaviest packaging you will ever feel in your life it is such a powerful powder okay it lays it down it sets your foundation in place it looks really natural it allows the glowiness of the product that you have underneath it to continue to show through it's one of those powders where yes it sets the makeup down but it holds the integrity of your foundation underneath I mean there's so many good powders out there you don't need to spend $110 but for me such a special powder I use this powder on my wedding day it really helps the longevity of makeup it doesn't overpower the makeup and completely changed the consistency and finish of the product that you have underneath and like I said it holds it down so I don't use it every day I'm not going to use a 110 powder in my everyday makeup routine but when I do use this it is such a gem definitely a diamond out there on the market I have preached my love for these many many times so you guys probably already know the hourglass ambient lighting palettes these guys come out at the end of the year every year for the holidays they're a whopping $80 but these actually I would think of this whole video as probably the best value because an individual hourglass powder she's fancy so this is somewhat of a value now my favorite one that's ever come out was the ambient lighting edit ghost unlocked I think this had the best combination of colors here but that being said I just feel like they don't go wrong with these palettes even though the one that came out this previous year which you can still get is the lighting edit universe I still love it I still reach for it all the time hourglass powders truly cannot be beat they look so natural on the skin for being powders they glow beautifully in the sunshine they look good in real life you know how sometimes powders like on camera and photography they'll look really good but in person you look a little cakey you look a little dry these are good real life powders and often they'll have a highlight a couple blushes a bronzer and you get it all in these palettes it's a semi good value and the powders blend beautifully onto their skin they buff out so nice it truly is just a luxurious experience to use these products and they are worth every penny and I've been telling you with some of these products like you can still get really great products at a much better price point I haven't found powders that rival this they're worth every penny I'm about to show you a $75 bronzer now you don't need to spend $75 on this bronzer luckily you can get this on sale but it is worth the full price point in my opinion this is the tomford glow bronzer in the shade terra at least for my skin tone I enjoy the shade terra this is a bronzer that blends out so beautifully it gives enough color to really make you look like you got some color in the sun it's super easy to use it has a very even application I find a lot of times with bronzers they can look uneven on the skin they can be darker in sunspots later in sunspots this one is so even on the skin so beautiful and I would pay $75 again for this but luckily you can get this on sale a lot so I'd maybe recommend that you go and get it on sale cosmetic company store sex office you get lucky but it's a beautiful bronzer and it's been a cult favorite for a long time by many people for that reason all right these blushes are ridiculous for what they are they are not a luxurious experience but the product itself is so beautiful these are the shantakai blushes these tiny little things with non intricate packaging at all like super cheap really lightweight $42 each that's crazy but I just love the blushes so much that I'll buy them again I'm currently wearing the shade joy on my cheeks and I don't know they're tiny little blushes they have terrible packaging a peachy or one that I also love is the shade of motion but there's something about the width these lay on the cheeks the way that they look the way that they kind of morph in with your foundation bronzer and highlight they have a good lasting power the colors that they have in their collection are beautiful it really is a luxurious blush formulations and I keep coming back for these blushes they're amongst my very favorite formulas when it comes to blushes so shantakai killed it with these love these they probably see but I love them would I ever advise anybody to spend $60 on a highlight absolutely not but pam graph that girl did it with the bridgerton skin fetish sublime skin highlight I have mine in the shade incandescent gold they also have the shade extreme gold so you can tell that this is an expensive highlight just based on the embossment in the product itself but this is such a beautiful highlight it's definitely one of her best formulas I have it on my cheeks today she is glazed she is glowy she took a somewhat glittery highlight and made it elevated made it luxurious like there's super micro fine glitters in here but it's not bad looking it just looks so good and smooth on the skin I can't get a finish like this with a drugstore highlighter I just can't this is so pretty it definitely is a dramatic highlight you know it's not a seamless blend in with the skin natural kind of highlight not at all but it's a glowy and showy highlight that is elevated and is luxurious and I'd spend $60 on this all over again and there are some really great highlighters out there on the market but I love this one let's talk charlotte ivory quads now the reason I'm featuring these in today's video is because value-wise they are some of the worst on the market just based on price per gram however she has a couple shades that just like blow my mind that I don't even care so I don't actually recommend that you pick up a bunch of these quads there's a small handful that are 1000% worth the price and there's a lot that simply are not and I would advise against you purchasing but let's talk about the one that I'm currently wearing that you can get you must try if you're interested and these are $53 each BTW the queen of glow this is the ultimate golden palette the matte shade in here is so rich so buttery so pigmented so blendable the shimmer is in here so rich so buttery so shimmery so glittery so delicious fantastic just everything I would want in an eyeshadow formula the queen of glow contains and it also is really great on deeper skin tones as well the other one that is a newer one is pillow talk dreams like I said not all of her quads are worth it but these two are amongst my favorite that you're still able to get same deal with the super buttery mattes in here the shimmers are a little bit different than what you're going to get in queen of glow these are a little bit more kind of like siliconey filling but they're so gorgeous on the eyelids these two are definitely must-haves from the line if they are something that you're going to pick up a couple more palettes that were worth every penny and I'm not mentioning Pat McGrath in here but of course you know I very happily pay 120 something dollars for one of her palettes but they're on sale all the time so I just didn't want to mention them because you can get Pat McGrath palettes on sale like 80 out of the year so that's why I'm not I'm not picking them but a brand that does not go on sale too often is Natasha Denona so of course I'm going to mention them one of my personal favorites that's worth it is the gold palette so these guys range in price Natasha Denona also does offer some more palatable ways to buy her quality eyeshadows she has her $27 eyeshadow palettes where you get five mini shades she has her midi palettes which I think are the best value of her brands but sometimes she doesn't put them out in the midi format and they're like 120 something dollars like this one but it's worth every penny because I think Natasha Denona probably has the best formula on the market for most people I love Pat McGrath but I don't think a Pat McGrath formula is for everybody I think Natasha Denona's formula is for everybody so that's kind of where I would recommend this Natasha Denona has the best mattes and the best shimmers period she offers color stories for just about everybody gold one sticks true to my heart and it's the one I was feeling today so I pulled this one for you this palette I paid $150 for but it's one of my most used and abused this is a vizier grande pro volume one they now have a remastered one that you're able to get it's called the one X so it's a bit different than the one I'm showing you today but you can see she is loved she is used she is abused vizier has some of the best matte formulations on the market super easy to use it's a very pro friendly brand so maybe it's not the prettiest of packaging but I absolutely love this palette because it has any neutral matte shade that you would need this is more so of a palette that you reach for for certain colors oftentimes I will grab into other palettes to get a shimmer on the lid but I have been on multiple occasions where I felt that I have needed colors from here obviously as you can see I mean just quality wise the best this is just a handy dandy palette that I always like to have on hand and I use all the time and you know what this palette also made me love all matte looks you don't always need a shimmer and it pains me to say that but sometimes a matte look just looks so clean and I get that with this so next up I have a 62 dollar liquid liner that's embarrassing to say out loud but this is the tomford eye defining pen the best liquid liner I've ever used period point blank there's something about this you guys this formula never dries out it has two ends a small end to let you get really into detail here and a larger end and there's something about the brush tip applicator as well that just makes it so easy and quick to get the most perfect wing the formula is not too watery it's the perfect amount of black it lasts all day it doesn't smudge and you'll have it for such a long time 62 dollars I mean that hurts for an eyeliner but I will say eyeliner is such a key product for your look that for me it's worth it this is a must have in my collection at all times the best liquid liner so this is the cheapest product in today's video and if I'm being 100% honest you guys I don't have lip products in this video except for this one because you don't need to pay a lot of money for lip products I have very few lip items that I've spent so much money on that I'm like oh I do this all over again I just lip products is just not one of those categories for me but the steward lip oil is so good it is 38 dollars which sounds pretty cheap compared to the items that I've been mentioning today but for me this is one of those luxury items that is worth it I have mine in the shade rosewood this is the perfect all-purpose lip product it's conditioning it makes the lips look juicy it goes with every look you can layer it by itself you can layer it over other lip products it makes the lips look more plump it doesn't tangle it's just perfect and it's super duper hydrating 38 dollars is still a lot for a lip product and I don't think you need to spend a ton of money for lip products there are so many drugs to our favorites that I have but this is one where I'm like it's worth every penny so so nice so there we are you guys those are my favorite luxury items that I've spent a ton of money on that I would do it all over again so I hope you guys enjoyed this video is there any guilty pleasures that you have with luxury makeup that you want to share down below I would love to hear it no judgment over here and again a huge thank you to Lily so for sponsoring today's video I will have the link down below to shop their anniversary sale don't forget to use my code and yeah thanks for liking this video and being subscribed to my channel and I'll catch you guys in the next one bye guys have a good one


Спасибо большое. Так что, я должен... Я немного извиняюсь. Мой первый разговор сегодня будет немного заборным, потому что я чувствую какую-то responsabilитию, для того, чтобы дать какие-то дефинитии, в связи с делающими категориями. Так что, в первом разговоре, мы видели какие-то интересные геометрии, в связи с делающими категориями, но дайте мне тоже дать brief introduction, объяснить, что делающие категории есть. Ок, так, давайте начнем с категории, а потом эти делающие категории находятся как следы. Вы начнете с категории, скажем, соединения комплексов и объектов. Так что, я думаю, что все знают, что это комплекс. Бунт means, that it has a defining number of non-zero terms. И обычно мы используем геомологический грейдинг, which means that the differential increases the gradient by one. Ок, так, вот эта категория комплексов, она идет с notion of amorphism of complexes. Конечно, amorphism of complexes is the amorphism of underlying graded objects in this abelian category, which commutes with the differential of the complexes. And because of that property, if you have amorphism of complexes from f dot to g dot, say, phi dot, then it induces amorphism between the cohomology objects of these complexes. First of all, for each integer i, one can define the cohomology object of the complex f dot to be the quotient of the kernel of the morphism from f i to f i plus one by the image of the object, of the morphism from f i minus one to f i. Just the usual definition. And then, because amorphism of complexes commutes with the differential, by definition it induces amorphism between cohomology objects of these complexes. So this is denoted by h i of phi. Ок, so for every morphism we have this bunch of morphisms between these cohomologies. And so the crucial definition here is the definition of a quasiisomorphism. So amorphism of complexes phi is called a quasiisomorphism if h i of phi is an isomorphism for every i. So in other words, the condition is that the morphism induces an isomorphism on the cohomology objects. The bounded derived category of an Iberian category A is defined as the localization of the category of complexes with respect to the class of quasiisomorphisms. Which means that we artificially add morphisms to our category which are inverse for every quasiisomorphism. Or saying it informally we just don't distinguish between complexes that are quasiisomorphic. Ок, in fact, you have to do some work to show that this definition makes sense. In fact, to define a reasonable category structure with these properties it is not that simple, I will not discuss this. You can look into some standard textbooks where this process is described in detail. So for instance there is a textbook of Gelfand and Manin dealing with this subject and there are also more modern approaches using for instance differential graded categories and you can look for instance into the paper by Keller where all these are also described. So let me just assume that such operation, such localization operation is well defined on the category of complexes and there is a category in which the objects are the same as the objects of the category of complexes and the morphisms are just so to say formal compositions of usual morphisms and inverse to quasiisomorphisms. Ок, in fact, a bit later I will describe a bit the structure of the derived category and you will see that the definition itself is not very much important. It is much more important to understand how you can work with this category and this I will try to explain in more details. Ок, so this is the definition and let me also mention that by definition there is a natural factor from the category of complexes to this localization category so we can think about this as a factor from the category of complexes to the derived category so every complex can be considered as an object here and also we have a natural from the original from the initial abelian category to the category of complexes given an object we can just consider a complex which has zero terms everywhere except of degree zero and it has just this object as its term so we have this embedding so usually we will consider objects of this initial abelian category also as objects of the derived category by thinking of them as of complexes with only one term in degree zero with only one nonzero term in degree zero Ок so in fact the most important thing is the structure that we have on the derived category and the structure is called triangulated structure so in fact triangulated structure consists of two pieces of data that satisfies some properties so the first thing that should be specified is what is called the shift factor interpolate is also usually called suspension factor so this is just an automorphism from from a category to itself so maybe let me state it as a definition of what a triangulated category is so as a definition triangulated category is an additive category T first of all there should be an automorphism of this category called the shift factor and its iterations are usually denoted by the corresponding integers in the brackets so its kth power is denoted by k and since it is an automorphism you can also take k to be negative so for every integer we have the shift by k so this is the first piece of data and the second piece of data is a class of what is called distinguished triangles which adjust sequences of morphisms that look as follows f1 goes to f2 goes to f3 and the automorphism goes to f1 shifted by one so this shift by one is precisely this shift automorphism which is usually denotation for it is this bracket notation after the object to which it is applied so to specify a class of distinguished triangles means to specify some number of sequences of morphisms and of course they should satisfy a number of axioms list of axioms and I also don't want to list these axioms here you can easily find them in the textbooks or even in Wikipedia or wherever you like let me just mention only some of them so to say maybe to say that the most important is not the right word but those axioms or properties that I used most frequently so the first property or axiom in fact is the following whenever you have a morphism between two objects of your category T it can be extended to a distinguished triangle so maybe every morphism extends a distinguished triangle that means that for any morphism you can find f3 and phi2 and phi3 such that this sequence is a distinguished triangle and the corresponding object f3 that extends this morphism to a distinguished triangle is in fact defined up to a non-canonical isomorphism and it is usually called the cone of the morphism so typically you can write this distinguished triangle in this form so this object called and let me repeat again that the cone of a morphism is defined up to a non-canonical isomorphism which means that any two extensions for any two extensions of this morphism to a distinguished triangle the corresponding objects are isomorphic but there are different choices of such an isomorphism and there is no canonical choice which leads to some of the theory but still the isomorphism class of the object is well defined so so this is the first property which I would like to mention the next property is that whenever you have a distinguished triangle you can construct from it many other distinguished triangles so for instance you can write about its first object and then you can write what you have and then you can add F2 shifted by 1 on the right and the morphism F1 shifted by 1 here and one of the axioms says that this triangle is distinguished if and only if this triangle is distinguished and this second triangle is usually called rotation of the original triangle rotation and so in other words a triangle is distinguished if and only if its rotation is distinguished and in particular this axiom I mean in fact you can using this procedure you can extend your original triangle to an infinite sequence of morphisms like this and so on and it goes both to right and left and such a sequence which you can always construct starting from a distinguished triangle is called a helix associated with this distinguished triangle and it has a property that if you take any three consecutive arrows in this helix this triangle also and one of the main properties is that if you have a helix like that one you can apply to it the function of morphisms from any object of your category or to any object of your category and then you will get a long exact sequence of home spaces so this is also a very important property which is maybe most frequently used that for any object G in T you can just apply the functor from G you will get something like that and so on and this sequence is exact is a long exact sequence and analogously you can apply instead of applying functor home from G you can also apply functor home to G of course this functor is contravariant so you will get a sequence with arrows going in the opposite direction so maybe let me write it like this minus one to G so it is also a longer exact sequence and maybe I will also mention some useful exercises for those who haven't worked with triangulated categories this will be quite useful so first of all assume that you have a distinguished triangle in which the morphism phi3 is 0 then from this that f2 the object f2 in the distinguished triangle is in fact isomorphic to the direct sum of f1 and f3 in such a way that the morphism f1 is the embedding of the direct cement and the morphism f2 is the projection on the other direct cement so this is a useful thing to check and another one is that if the third object of the triangle is 0 then phi1 is an isomorphism so this is if and only if so a morphism in a triangulated category is an isomorphism if and only if its cone is 0 so in some sense is a mixture between the notion of a kernel and of a co-kernel in an abelian category so if you have a morphism in an abelian category such that its kernel and its co-kernel are 0 then the morphism is an isomorphism and this is an analogous property in a triangulated category ok and now let me just say that derived category triangulated structure this is an important theorem so probably due to Verdiere db of a has a triangulated structure such that the shift functor is given by the shift of grading of complexes which means that if you have a complex f dot then if you want to shift it by 1 then its term and degree i should be f i plus 1 which eventually means that you shift the complex to the left so you should keep it in mind and also the differential of the complex changes its sign this is by definition so the shift functor is given by this shift of grading of complexes and with the cone of amorphism defined to be the mapping cone of complexes phi from f dot to g dot being mapping cone which basically means the following so if you take amorphism of complexes g i minus 1 and if you have amorphism of complexes then you have this diagram with commutative squares and so you can consider this diagram as a by complex so there are arrows of two directions and if you imagine that it is not concentrated in two rows but in infinitely many rows just all the other rows being zero then the composition of two horizontal arrows will be zero the composition of two vertical arrows will be zero and the arrows themselves will commute so this is what is called a by complex and whenever you have a by complex you can consider its totalization which just means that you sum up along the diagonals of this complex and use these arrows to put a differential on this totalization this is what is called the cone of amorphism of complexes and so the theorem of Verdiya says that if you define a cone of amorphism in this way and if you define the shift in this way then all this gives you a triangulated structure ok so say a couple of words about how one can think about objects of the derived category so in fact from the definition and this is a kind of naive approach to think about objects as about complexes that have their terms and differential and so on but this is not a very good point of view terms are because you can have two isomorphic objects in the derived category that have completely different terms the term of a complex is not a notion which is invariant under a quasi isomorphism so it is not a good notion but the notion that is good is the notion of the cohomology of a complex so one should think of objects of db of a as cohomology objects are linked to each other and let me explain what does it mean linked together so to explain this let me introduce one more notion which is very useful which is the notion of the canonical filtration so assume that you have a complex fi plus 1 and so on let me define now to other complexes so for each integer k let me define tau less than or equal than k of f dot to be a complex which has the following terms so the term in degree i will be equal to fi if i is less or equal than k minus 1 it will be equal to the kernel of the morphism from fk to fk plus 1 if i equals k and it will be 0 when a is greater or equal than k plus 1 and similarly you can define t greater or equal than k tau greater or equal than k of f to be the complex which has term 0 for i less or equal than k minus 1 so it should have term image from fk to fk plus 1 when a equals k i equals k and fi when i greater or equal than k plus 1 then what it is very easy to see is that for any k there is a morphism from tau less or equal than k of f to f so it is just given by natural embeddings and it is easy to see that everything is compatible with the natural differentials and then there is a morphism from here to tau greater or equal than k plus 1 of f and in fact this gives you a distinguished triangle there is a distinguished triangle of this form for any k also it is very easy to see that if you ok and also a very important property is that if you consider thecachomology of these truncated complexes then thecachomology is the same as thecachomology of your original complex when the index when the degree corresponds to the degree in the notation for this truncation functor and zero otherwise and analogously for the other truncation functor so ok let me check yeah so maybe this is the crucial property that should be satisfied and let us just see whether it holds for this definition or not I mean in fact maybe just to be on the safe side let me write it in a bit different way so let me first do it for this truncation complex and then this quotient of your original complex but what you see here yeah then this is right and here you should take just the quotient of fk by this kernel and this will be precisely the image so I think that this is correct ok sorry ok yeah this canonical truncation distinguished triangle is in some sense the main tool to think about objects of the derived category in some sense you can think about this object as about glued from this part and that part and with this morphism being the gluing data and know that these two objects are more simple than the original object that you started with just because by this property they have smaller number of cahomology shifts and in the end you can somehow to split any object into the bunch of its cahomology objects and that will be linked by morphisms of that type and let me maybe leave it as an exercise to check the following statement so assume that we have an object that has only two cahomologies such that h i of f is 0 or i not equal to k or l and assume that we fix integers k and l k is less than l so maybe let me write it like that so k is less than l and i is not equal all the cahomology except the cahomology in degree k and l are 0 then isomorphism classes of such objects asomorphism class of f is determined first of all hk of f hl of f and amorphism let me call it epsilon which is amorphism from fl of hl of f to hk of f shifted by l minus k plus 1 for instance if l equals k plus 1 if you have cahomology into adjacent degrees then this morphism lives in home from one cahomology to another shifted by two and by the way this is a standard convention to use ex notation for such home spaces so by definition this is just x l minus k plus 1 from one to another so in some sense in the same way as in an abelian category you can construct more complicated objects by considering short exact sequences and so by constructing them from simpler objects by using x1s to link in the same way in a triangulated category or in the derived category you can construct any object from shifts of objects in your original abelian category by using higher x groups and this is the way it is better to think about these objects ok so what goes next now we discussed a bit triangulated categories now let me say a couple of words about triangulated functors so if we have two triangulated categories T1 and T2 then a functor between these categories is called a triangulated functor if I mean basically it should preserve the triangulated structures of our categories which means that it should first compute with the shift functors if it commutes shifts which to be more precise it means that commutativity morphism should be specified but I mean in almost all cases when people discuss triangulated functors this commutativity morphism is left implicit but still you should be careful a bit with it so the first property that the functor should commute with shifts which means that if you shift an object then apply your functor it is the same as you first apply the functor and then shift the object and also the second property that it should take distinguished triangles in the first category to distinguish triangles in the second category keeps triangles distinguished ok so this is the notion of a functor and usually we will at least in my lectures we will discuss derived categories of coherent shifts on some smooth and projective varieties so we will start with some smooth and projective variety over some field and maybe for simplicity it is better to assume that the field is the field of complex numbers but of course in most cases it doesn't matter but let me use this assumption then we consider the category of coherent shifts on x this is a nice abelian category and then we consider its bounded derived category and usually we will discuss its properties and to simplify the notation I will denote it just by d of x I will skip this letter b but I will consider only the bounded category so what kind of functors do we have in geometry between derived categories of coherent shifts let me mention some of the most important functors in fact this is a very good property of the geometry is that it always comes with many functors so what kind of functors do we have Assume that we have a morphism between two algebraic varieties x and y Assume that both are smooth and proper then in this situation one can define the push forward functor between the categories of coherent shifts and the pullback functor and one can extend them to derived categories by considering derived functors so there is derived push forward functor from d of x to d of y left derived pullback functor from d of y to d of x okay and yeah and for instance if you take a coherent shift say f and k of x if you apply derived push forward functor to this object it will no longer be a coherent shift in general and if you compute the cahomology shifts of this object this will be the classical derived push forward functors so in some sense this total derived push forward is a derived category version of this usual derived push forward functors that takes that keeps not only these cahomology shifts but also these linking morphisms between them so to specify this functor is such a specification contains strictly more information than just specifying this sequence of classical derived push forward functors and similarly in the same way for pullback have an object in k of y then if you compute the cahomology of the derived pullback functor then this is l minus e pullback of g so usually for the derived pullback functors people use homological notation and because of that there is this change of sign from cahomological notation to homological notation here ok besides these two functors in the derived world there is one more important functor which is called the twisted pullback functor in fact coming back to this situation a very good property of these two functors is that they form in a joint pair so in fact if you compute homes from the pullback of any object of the derived category g in a so let g be in d of y and f be in d of x then if you compute homes in the derived category of x from the pullback of g to f then this is canonically isomorphic to homes from f to the derived push forward sorry from g to the derived push forward of f so there is this very useful adjunction isomorphism and means that the pullback functor is left joined to the push forward functor the right adjoint functor to the push forward so the next important functor is this twisted pullback functor which goes from d of y to d of x and which is right adjoint to the push forward so in a contrast to the previous situation this functor is not derived functor of some functor between a billion categories it is a nice triangulated functor so this adjunction means that we have a similar isomorphism to this one so let me also write it down so if you compute homes from the push forward of f to g this is the same as homes from f to f upper shriek of g this is this isomorphism which is frequently called the groten-decker junction and in fact in the nice situation if we consider this nice situation when both x and y are smooth and proper then one can even write down an explicit formula for this twisted pullback functor in terms of the usual pullback functor and the canonical class so in fact the formula is that this is the same as derived pullback of g tensored with relative canonical class and with the shift by the difference of the dimensions so this is another important functor okay so next functors that people frequently use are the tensor product and local home functors so let me also mention them so this time you don't need to consider two varieties so just start with one variety and again it is better to assume that it is smooth and then for any two coherent shifts I mean there is this standard tensor product functor on the category of coherent shifts and you can extend it to what is called derived tensor product functor of x to g of x and in the same way tensor product and derived tensor product so this is the notation for functors and also there is another functor so this takes F1, F2 F1 tensor F2 derived tensor product but if you have two objects to coherent shifts you can also consider the shift of local morphisms between F1 and F2 this is also a coherent shift on x so just to distinguish between this vector space of morphisms and this shift of morphisms I will use this calligraphic notation and in the same way if you have two objects of the derived category you can define r-home complex of coherent shifts in d of x and again these two functors are derived by a junction so if you compute homes from F1 derived tensor product F2 to F3 this is the same as home from F1 to r-home from F2 to F3 and again like in this property if you apply this derived tensor product or derived r-home functors to coherent shifts and then compute the cohomology shifts of these objects then you will recover tors of two coherent shifts in the first case and local x shifts in the second case ok so these are and of course these functors satisfy a long list of relations which is very useful to know if you want to work with derived categories of coherent shifts let me mention some of them so relations so first of all there are functoriality relations basically it means that if you have a sequence of two maps F and G then if you compose derived functors derived push forward functors then this is the same as derived push forward functor for the composition of morphisms and the same for the pullback and the same for the twisted pullback so the first are these functoriality isomorphisms second besides these adjunctions that were mentioned before so we have three adjunctions on the blackboard besides them there are also the local versions in fact everywhere we can just replace this global home by appropriate local homes these are called local adjunctions so for instance let me say what will it be in the first case of course you cannot do it just naively you cannot replace this home and this home by local r-home just because this will be shifts on different varieties so the right hand side will live on y but if you apply a push forward then everything will be fine so like if you apply derived push forward to r-home from lf upper star of g to f then this is the same as r-home from g to the push forward of f so there are relations like that and you can do the same for the other two adjunctions that you have on the blackboard then the next list of relations corresponds to the tensor structure to the monoidal structure given by this tensor product this derived tensor product defines a monoidal structure d of x which basically means that in fact it is symmetric monoidal structure which means that tensor product is commutative associative and also the pullback functor is compatible with this monoidal structure is a monoidal functor and on the other hand if you consider the push forward it is not compatible with the monoidal structure it is not true that if you take the tensor product of two objects and then push it forward it will not be equal to the tensor product of the push forwards but instead there is another important relation which is called the projection formula and which says that the push forward not of arbitrary tensor product of objects upstairs but if you take one arbitrary object and if you tensor it with the pullback of another object so if you consider push forward of a tensor product like that then what you will get is the tensor product of the push forward of the first object with the second object so this is also a very important relation and maybe let me finally mention the base change so what's that? Assume that you have amorphism and a fiber product Assume that you have this fiber product diagram this Cartesian diagram so this is vx and this is f sub t then you can always construct a natural morphism between the composition I mean the goal of the base change formula composition of the push forward with the pullback and of the pullback with the push forward and what you can easily do you can easily construct a natural morphism from the composition of the pullback and the push forward to the composition of the push forward and the pullback so there is always a natural morphism like that and so you can ask in which cases this morphism is an isomorphism and in fact you can say very explicitly that it is an isomorphism if the diagram is what is called tor independent and that means basically that if you take any two points on x and t that have the same image in s then if you take the local rings of these points on x and on t and consider the tensor product of the local ring of the corresponding point on s then this tensor product should not have higher tors so tors greater than zero from over o s sub s of o x sub x and o t sub t is zero for any pair of points x and t such that f of x equals s equals v of t so if this condition is satisfied then there is this base change isomorphism and of course this condition is satisfied when one of these two morphisms is flat just because in this case the corresponding ring is flat over the other ring and this tensor product its tors with any other module are zero but there are also other cases when this is correct for instance if both morphisms f and v are closed embeddings and if these sub varieties intersect transversally in s then also this is a tor independent condition t are all smooth varieties and the fiber product has expected dimension then the diagram is tor independent and this is a very useful thing in many cases I see that my short introduction become a bit long so probably I will not be able to do anything besides it so maybe let me introduce one last notion also a very important one and give several more exercises and then we will turn to some interesting stuff tomorrow so one notion is a notion is a more general notion of a functor that is used in most cases so this is what is called Fourier Mochae Functors so I assume that x and y are again smooth projective varieties then I assume that we are given an object some object in the derived category of their product in D of x times y then we can define a functor associated with this object which is called Fourier Mochae associated with k or sometimes one can say with kernel k is a functor which takes the following form so the usual notation is phi sub k from D of x to D of y and the definition is the following you should write the corresponding diagram so we have interactions p and q and then this functor is a composition of the derived pullback then you can tensor it with k in the derived sense and then you push it forward also in the derived sense so you pull back tensor product and push forward then just pullback push forward or tensor product this is like a general combination of these three funters that we have seen before and to finish let me just write some exercises about Fourier Mochae funters which are also quite useful yeah so first of all assume that you have amorphism then we can consider граф so let gamma f be the embedding from x to x times y the graph of f then one can show so this is the exercise is to show that the push forward functor is in fact the Fourier Mochae functor with the kernel being the structure the shift of the graph and similarly if you have if you want to express the pullback functor as a Fourier Mochae functor you can also do it let me just write it in this way derived pullback functor is also a Fourier Mochae functor also if you want to express the tensor product functor then it is also easy to do so let me denote by delta the diagonal embedding of x into its square then if you want to consider the derived tensor product functor with some object e in d of x then it is the same as Fourier Mochae functor with kernel being the push forward of e and also to show that a composition of Fourier Mochae functors is also a Fourier Mochae functor and is that all also adjoins Fourier Mochae functors are also Fourier Mochae so if you take the left or the right adjoint of a Fourier Mochae functor then it is also a Fourier Mochae it is better if you will be able to write the formula, write the kernels in the first case for the composition and in the second case for the adjoint functors ok, let me stop here and I hope next time it will be more interesting


Well, what's going on guys got Kyle here with late in sports cards, and we are ripping this is 2022 select football hybrid 5 box number 14 Did a randomizer for the break? I'll show you guys results again. We had Jason a with the bucks down to Jeffrey with the Raiders Alrighty guys. Good luck on this one. Let's see what we got here Box number one still got some work to do on one football as well as Star Wars tonight guys Star Wars and one football last spots or last breaks with spots We'll have Sam back in the mornings tomorrow starting at 10 a.m. Eastern We'll have Matt at 5 on channel 2 doing all Personals and we'll have for us here on channel 2 1 doing a group breaks tomorrow There's Garrett Wilson rookie Got a rookie Duran Harmon on the rookie sweet level Joseph and Williams Duran Harmon is about as far away from a rookie as you could be Thank you retired And then they gave him a rookie card There's a silver there tater Taylor Heineke Got a red Jay Jetta there on the sweet level that one is number to 49 Jay Jetta Mike White and Raymond Everybody loves Harold Raymond. Do it. I don't know take London rookie God silver this one's Donovan Wilson got red Bobby trees club level to 49 Jay Jetta and Daxon Hill rookie Man cave is Steelers all over that's sweet Herman. That's sweet Nothing like a good man cave man There's a Bailey zappy nice one there club level blue disco That one is the 25 nice it there for the Patriots Zappy the 25 Algier and Dalvin Box two Whenever I think of a man cave. I think that uh That Toronto Maple Leafs fan who has the most ridiculous man cave ever He has like wall-to-wall Maple Leafs jerseys. He has like 15 TVs in there. It's it's giant. I've seen a few different times Like on ESPN they're like showcasing it I don't know if you guys know who I'm talking about the the That Toronto fan. He has a crazy one. There's a rookie Tyler Linderbaum disco Uh Dylan Parham and Gabe Davis. Oh nice to go to training camp for the Steelers. That's sick That's gonna be fun Do they do it in Pittsburgh? I would assume like some couple people like uh Sometimes they like team up for training camp, but there's a Prescott. This one is Dawson Knox there red Number to 49 builds. I'm pretty sure they do it in Pittsburgh Breeze Hall I would think gotcha Yeah, I didn't know if it was like sometimes they do the combo So I don't know if he was going when it was like closer. Maybe they went to Cleveland or something There's a silver rookie Trey McBride Cardinals And blue disco rookie Nikobi Dean go birds to 25 Can you pick it rookie?  Come on That's tracking That's all right J-mo rookie Taylor Britt, we've got a uh Carlot this blue disco Furious George 25 Joku and Jair Good luck guys box three Optic T-Mall coming up next guys Break three and break four There's a red Tua two of their number two 49 got a silver Maddie Corral and Rashid Shahid That's a good question. Tell me Free is always nice Got a silver rookie Rashid Shahid And blue disco this one is Mike Williams. Mike will It's a 25 Isaiah Spiller and Jason Kelsey 19 left now guys for uh one random the second one of the day Got the first one filled up second. Uh one random still is 19 Silver rookie Dan Bellinger Red cam at Juergens there uh birds to 49 Maddie ice and Heineke They just had free beer just sitting there. That's sick It's a good way to uh good way to do it There's a sauce gardener nice one there sweet level blue that one is to 25 nice one there jets Sauce sweet level to 25 That's a sweet sauce right there Stingly Two left I think I was gonna have a different movie. There's a uh Kyle doll. You probably were um sweet level disco Jared golf Because I think I've heard that Definitely definitely possible This one is uh unique It's Orlando Brown silver. We got a red Fred Warner disco club level Fred um nine or to 49 It's a mere whites and bush Oh legal just now started following my instagram Here we go Where was that seven months ago called strange silver and blue to 25 this one's nick bolton In a bar a trail on speaking of I supposed to post something up there. I didn't On instagram yeah What are we supposed to post? I got a another card for the galaxy atomic collection for some reason There's bland number to 49 Goddard and mark Andrews 94 more cards to go There you go Average of like on a roll good $15 a card on a roll Gonna be expensive All righty guys box five this one is select hybrid number 14 rookie sam howell base Got disco um cj moseley disco Elante taylor and taler smith So bret Oh gold Oh Got a silver of jerry judy and gold. It's going to be almond ross saint brown for the lions St. Brown number to 10 seven to 10 Chase claypool gold brandon iuk and red is devin bush dealers Number 249 mclaren and zion johnson last one Appreciate you jet for the subscription. There's a blue to 25 rookie brian cook chiefs Michi rookie and de forest buckner on the back All righty guys that'll do it for the break there. Um select h2 five box number 14 Uh, don't do a hit recap. It's a pretty short one. No autos. Um Get these right out to you guys. Let's get going on. Um Optic choice next or optic team on


Hey guys, it's Nate, aka The Foot Account, and welcome back to the channel. We're talking about the Summer Showdown SBCs that were released today in FIFA Ultimate Team as a part of the Summer Heat promo. We got to talk about the Summer Showdown SBCs because EA dropped them today. They're actually really interesting. EA is continuing with the quality content in this Summer Heat promo. It's honestly ridiculous that they keep coming out with solid content every single day for the past, what is this now? Five days, they have released solid content. Can they do it again on Tuesday today? We shall see. But I want to talk about these two SBCs, talk about the time frame, which is actually pretty interesting because these SBCs are not going to expire when we originally thought they were, right? This game by Leverkusen versus versus FSV Mines, right? Mines Leverkusen, that game is on Saturday at 2.30 p.m. UK time, 9.30 a.m. Eastern time, my time. And this SBC expires at 6 p.m. UK and at 1 p.m. Eastern, my time. So this SBC will be still available while the game is going on. And this is not how I imagine this to happen. I don't know if this is an EA mess up and if these will change. But I want to talk about this today and just talk about the time frame and just maybe how this could be hyped up still going forward in the future when we have more of these summer showdown cards released in the FIFA Ultimate Team. But again, this is the tweet from EA today. SBCs available for a limited time for Musa Diaby and Jean-Paul Boeysius. The winner of the Saturday's match will receive a plus three overall boost plus one in the event of a draw. Again, EA chose two pretty solid cards here, right? A Bundesliga center attack in mid with the Netherlands links, which is kind of Dutch links, which is dope. And then a French left mid. Now, this guy has a lot more hype in terms of like upvotes, right? That's one way to kind of gauge hype on an SBC card is to look at the upvotes, look at the stats on footpin 669 for Boeysius and over a thousand upvotes for Diaby. So I think Diaby is getting more upvotes because he is a French player. But this is the second left mid in the Bundesliga that we have gotten in the past couple of days because of the Paris SBC that has come out as well. But there's so many French cards. Again, it's like foot birthday all over again with all these French cards that we have gotten in Damboulay, the Mendy objective. And now Moussa Diaby as well. A lot of French cards being dropped onto FIFA Ultimate Team. And it's just kind of the way that it seems EA wants you to go with a French like team this year for whatever reason. Remember back to foot birthday, a lot of French cards are dropped then as well. But again, I like this concept. Did they choose the best matchup ever? I don't know if they chose the best matchup because you had City and Chelsea playing later this week. I actually tweeted about it earlier on Monday. I tweeted out Chelsea and Manchester City. That would have been a cool game for them to do the showdown for. And as well as I think it's this Milan, Atalanta and Lazio. So that was another game that I thought was possibly going to get in. And it didn't. They chose the Biolavercucen and the FC Mines game as well. But I do want to talk about this. I put out a poll earlier today just to kind of gauge the hype to see where you guys were at, at least where my Twitter followers are at on the summer showdown, which SBC you were going to do. And honestly, a lot of people voted neither. A lot of people voted neither. But then there's a lot of votes for Diabia 25.6%. There's just a lot of ways you could go with this. There's literally a lot of ways you could go with this. You could honestly, the way that EA has put out this content as well, you can do both SBCs, right? We thought that maybe it was going to be one SBC and you're going to have to choose a player pick for the two items. That is not how it is. And the SBC doesn't even expire before the game. So technically, the way that it is now, and I don't know if EA is going to change this. But again, as we mentioned, you could wait to see which team ends up winning the game before doing the SBC because this would go to a 95 rated left mid. This would go to a 95 rated center attack in mid. Both cards would be sick and juiced to the max. You know, they're already pretty, pretty boosted right now. They're not insane. But again, they boosted to the max depending on who wins. If I had to guess who would win, I feel like Leverkusen would win. That's just my personal opinion. But both of these cards coming in with an 84 rated squad and a tots player required, 80 chemistry is a lot. But both of these squads are coming in right around 80,000 coins to do. And honestly, you could probably craft these decently easy as well. This only has 75 chem for Boishes. But still, this is a W for FIFA content. And that's what you saw a lot of people talking about today. Just because this is a new concept, right? People love the new concepts and stuff that come out in the game. And this is another one. This is another great concept that EA has put out with this summer showdown kind of putting two teams head to head. And these cards are live, right? These are live items. And I would expect that we would see more of this in FIFA 21. Hopefully they carry this on in the next year as well as they continue to do this over the summer. But if I had to vote for either of these two cards, if I had to do one of them, I think I would do Boishes. But again, you might as well just wait until the, unless the SBC time changes. This says four days remaining. But what that actually means is like four days and however many hours, right? This is not like four days and then it's rounded down. It's actually rounded up. So four days and however many hours left on these SBCs, they will expire Saturday at 6 p.m. U.K. because they came out on Monday at 6 p.m. U.K. and they had five days remaining or four days, 23 hours. So that's when they're going to expire. You're going to have plenty of time to complete them this weekend if you want to. I'm probably going to end up completing both of these guys from doing upgrade packs this week just to try to grind these cards, right? You grind the menu content. You could do upgrades right now, pack a lot of really cool cards, dump them into a prime icon upgrade, dump them into all the player SBCs that are out. It's just a really, really fun time to be on the menus in FIFA Ultimate Team. And since the menus are where the hype is at and where the content is at, I showed you guys some of these trades yesterday. You can absolutely still trade with very high rated SBC fodder because SBC fodder is the name of the game right now. Everybody is buying these cards to do those prime icon upgrades. You might think that since they've been out for a couple of days that nobody is doing them and that the hype is going away. That is absolutely not true at all. And again, look at these guys' fluctuations. These guys fluctuate 10,000 to 15,000 coins so often. This guy, this Gabrielle, right, is showing right now on footpin for 80,000 coins. He's getting in as the cheapest solution. This is one of those cheap cards and he's getting bought up in price right now because people just go out and they find the cheapest solution and they buy whatever cards to show up, right? I'm going to look up Max Carusa as well. I talked about this in yesterday's video. I said, hey, dudes, there's plenty of opportunities to trade with these cards right now in the market. So Carusa is 84k. He shows as 82. I like trading with the 89 rated and higher, especially team of the season cards and not cards that are in packs. Just because the cards that are in packs still have that supply, they're still getting put on the market. But who else is one? Hamdala. Hamdala is a guy that fluctuates a lot. Let's take a look at this graph, right? And I know I've talked about this the past few days, but this is seriously the best way to trade and to make coins right now and honestly just to do something on FIFA. This is the best thing to do in the game. Hamdala is 88,000 coins. What did his price do today? He reached a low of 85,000. He peaked right around 100k. I'm going to ignore that because that is not correct from Footbin there. Went down to 76 and then back up to almost 100,000 coins again. And right now he is 88. So he's kind of chilling in the middle on the high range. As you can see right here, I've got a Hamdala on an open bid. If I can snag this at 81,000 coins, I think that I can sell this card around 90k at some point within the next day or so and we will be chilling and good to go on a quick flip like that. And that's honestly what I've been doing just very slowly and very steadily. I haven't done it with a lot of players, but it's something that you can very easily do right now in Foot. There's a lot of people that are playing this game and a lot of people that are grinding the menu content. That is what there is to do right now. So that's why I'm trading with this method and trading with these cards. You can still trade with other cards in the market as well. You can look at some of the OP, not SBC cards, but some of these special cards, maybe if they're out of packs, team of the season cards in general, like your League of Tots. I look at League 1 team of the season cards all the time. Some of these cards actually bounced up a bit today from what I'm seeing. Cards that people wanted to buy for their teams. Wow, look at this man. Lala is actually 390? Lala is almost 400k man. This guy was 340k Sunday night. So if you bought any Tots cards yesterday or at least some of the very meta ones, Hakimi is somebody that I'm kind of interested in as well. They keep dropping these Bundesliga cards, Bundesliga players in the game for summer heat. We've gotten the Parasich, right? We have gotten now two Bundesliga cards through the Boeysius and through the Diaby today. That's three Bundesliga cards. I'm not forgetting any of them. I don't think I am. But that Parasich was one that a lot of people did. There's a lot of hype on the Bundesliga right now, especially a couple weeks ago during Ultimate Tots when the guaranteed Sancho pack was out. So if you're looking for maybe some Thursday flips this week, and you're looking around the market for some possible panic, definitely look later this week in Bundesliga midfielders, Bundesliga defenders. Upa Makano is somebody that I'm really interested in just because that card has got all the French links and he has got the Bundesliga links as well. And I think right now he's kind of up in price around the 360, 370 range. But if this guy, if they would release a center back at any point this week and you see a guy like this drop down maybe 30, 40, 50,000 coins for whatever reason, that could be a card that you really, really start to look at and say, hey, along with some other Bundesliga cards, maybe like a Kimmich, right? As a CDM, there's not a lot of midfielders in the Bundesliga. Tots card wise, right? Because the only cards that I want to be trading with myself at this stage of the game is going to be team of the seasons, whether if we're talking for like a weak and lead caliber squad. Kimmich has got the high, low work rates in the Tots, right? Yeah, he does, but he's a very good CDM center mid. You've got Thomas Muller who you could throw on there and you've got like moments Kimmich who is not available on the market. So the key is the cards that are available on the market that people can buy for their teams. I feel like a lot of people could be rocking Bundesliga this weekend, especially on Saturday. And we'll have to see how long it takes EA to actually upgrade these summer showdown cards. I would assume that it's not going to be instantaneous, but probably, you know, in the range of like a day or so. So these guys, whichever team wins, or if they draw, they'll both get the plus one. Hopefully a team wins though, man, because I would like to see the plus three rating on either of these dudes in my opinion. But we should see that boost decently soon. And then I think that's where that card design is going to come in with the white flame on the top. You will see that white flame on the top of that card where right now it is kind of like, kind of, it's grayed out. I think you will see that kind of turn to the white activated, right? You know, like we had the headliners after they got that, the boost for their team winning four games in a row earlier this year. We did get a pack supply SBC today. I think it was like a, what was it? Was it a foot miss challenge? No, it was a, it was the black cats SBC from ultimate scream, a small prime gold players pack, which is, it was tradable, which that's a decent pack. And I didn't really see a lot of stuff drop today. Lucas dropped a little bit. He went from 70, 83,000 coins down to 76. Right now he's 78. I was hoping for a tradable pack supply SBC to maybe drop the market a little bit in terms of supplying these cards and supplying SBC fodder, but it didn't really look like it did too much on a lot of cards. Bruno Fernandez is 115 at the moment. That is maybe a little bit lower than what he, he was definitely higher than on the weekend after United play. He was 110 and he was, you know, 129 to one, almost 130 on the PlayStation. Actually, he's a decent bit higher on the Xbox, which is pretty interesting. But this might be a card that if, you know, if I can snag him at 110, this is a guy that's going to fluctuate a lot. Even though he has impacts, you know, we've got Manchester United playing IRL football again. And I think if I'm not mistaken, I think United play on, United play on a Wednesday, interesting. So United have a game coming up in two days. What we saw when United played Spurs on the weekend was this card went up like 20,000 coins in price just because those United fans got to see their beloved center attack in mid Bruno Fernandez actually play in the game of FIFA in real life, not in FIFA, in real life. They actually got to see him play and they were excited to watch United football. So they went out and they bought their United cards to play with in FIFA because football, of course, is now back, which we love to see.  I know this is not a live item, but this is something that when there's a lot of hype around football games, which there are right now because the games are back, just watch some of these items in foot, especially if Bruno Fernandez were to score a goal. Again, this is not a live item, but this guy would definitely, definitely go up in price because of that. Just because people want to play with this card because this is the best version of Bruno Fernandez you can buy at least right now in this game. So just watch out for maybe another pack supply of SBC today on Tuesday. They've been releasing a lot of these to try to sort of supply the market a little bit with the SBC fodder, but it's really not working. Just because so many people are just submitting their coins into the menus right now and doing whatever SBCs they need to do to have fun on this game because this really not much else left to do. If you're grinding Mendee as well, GLs, if you are grinding this objective right now, GLs, keep it up. I know it's a big time grind. I need to start working on the 89 Mendee, which is the next one that I have to go and get. So I got to score some outside the box goals with four star skills, five star weak foot and then get some crosses in with that 87 Mendee as well. So I would expect a probably a third objective player at some point in the next two days, either Tuesday or Wednesday. Some sort of objective I think would get re-released. We'd have a third one in here. The timeframe on Kessie, he goes away in three days. A lot of people have already done this while they were doing Summer Heat Mendee. People are still grinding this one, but I think we'll get a third one and then probably another SBC on, you know, today or tomorrow as well. Tomorrow on Wednesday, we do have a team of the week. I'll talk about that a little bit in tomorrow's video as well. But yeah, hey, Summer Heat content, again, this is a W from EA. I know it's only 84 rated squads. We look at that and we're like, man, that's very cheap. It's 80, 90,000 coins right now just because of how expensive fodder is. But still, that's a good value card. That's an end game stat boost was the most important thing for a lot of those cards. It was a very end game stat boost. EA did a very good job there. Hopefully we continue to see hype games chosen for the next few times. They said they're doing that every week. So every single week, we should get a Summer Showdown SBC selection. And I'm guessing it's going to continue to come out on Mondays for the next weekend's game, right? So the Monday SBCs will come out for the weekend games is what I would think we would see in the coming weeks over the Summer Heat promo. And then again today, watch out for any SBCs or objectives that could come because we've gotten some sort of content every single day and I don't think that stops. By the way, I think you guys might wonder where I finished a weekly. I did finish Gold II. I got to 17 wins. So we will have the 90 plus player pick guaranteed slot for our rewards on Thursday, which will be interesting to see how rewards are Thursday. It's going to be a whole different scenario with all the weird cards that are in packs. It's going to be interesting. But if you guys enjoyed this video and you're hyped for Summer Showdown, smash the thumbs up on the video. Comment down below if you have any questions and subscribe to the channel for new. It's been Nate, the Foot Accountant. Catch you guys later. Peace.