I think started with first dci, so let us write down the equations first. So now that we know that the method of projection gives the same as the variation method, we are going to use the method of projection to write the equation. We have done that, it is a matrix Eigen value equation, but I want to rewrite this once more. So h then C0 psi Hartree-Fock plus sum over a less than b. So we are writing only doubles, so no singles, because doubles are the first important terms. So it is what is called truncated ci, which means I have truncated the ci expansion only to doubles, it is not a full ci, it is not exact even in the m dimensional basis. So then what we do is to project, so first we project with this psi Hartree-Fock.  So this will survive. Remember when you did only singles, this was the block which was 0, because of Bravais theorem, but here this will survive with these c a b r s plus equal to E0. Now it is very easy to see here, the psi Hartree-Fock psi Hartree-Fock is 1, so you have E0 times C0 and these are orthogonal, so you do not have to write. The right hand side when I project with psi Hartree-Fock, you have only coefficient C0 because this is equal to 1, so coefficient comes out, psi Hartree-Fock is orthogonal to psi a b r s, so you do not have to write. So this is the reason you get a Eigen value type of equation. Then you have the next set of equation which is one of the specific W excited determinant, let me call it now psi CDTU, I do not want to use the dummy variable a b r s, so it is one of the W excited determinants where a b is equal to CD, r s is same as TU.  So this is basically the matrix element of the Hamiltonian between doubles and doubles, as we talked in the last class the doubles and doubles h dd, so this is that part into the coefficient, again you have an energy, this part is very easy because when I do psi CDTU this is orthogonal to psi Hartree-Fock, even this is orthogonal to all psi a b r s unless a b is equal to CD, r s equal to TU, so that time only c CDTU will survive. So you can see whatever is the configuration with which I am projecting that corresponding coefficient comes in the right hand side, that is all, the right hand side is very simple and that is the reason we call this matrix Eigen value equation. So this is h times c, you can see h times c equal to e times c, one of the c's, you have actually the set of equation, so if I write this as a matrix problem then you have the first part, so there is a matrix of h where the first part is e Hartree-Fock because this is nothing but e Hartree-Fock, please remember and then you have a set of numbers which are psi Hartree-Fock, h psi a b r s and then on the column side you have again psi CDTU h psi Hartree-Fock and then you have, maybe I push it little bit further where it looks nicer, so that is my matrix. So you can see this is for all CDTU, this is written for specific CDTU but you have to keep on changing, so as I change I have all the numbers here, I will have all the numbers here and this, so this is basically one number, this is a row, this is exactly a conjugate column and this is a square matrix, square matrix between doubles to doubles and then you have c0 and c a b r s, the doubles coefficient equal to e0 the same thing c0 c a b r s or c CDTU whatever. So you can see that whatever I am multiplying I will have exactly the same number coming up, these a b r s are just a generic thing, they are all doubles. So in a very simple way I can write this as e Hartree-Fock, psi Hartree-Fock, h psi doubles, so psi d I am introducing psi d just to say it is a block of all doubles and then you have similarly psi d h psi Hartree-Fock and then you have a psi d h psi d is c0 c d equal to e0 c0 c d, of course c d is not a one number, c d is a column, so c d is a column, so it is a let us say n number of w x r a determinant, so it is total n plus one dimension in that case, so this is actually a set of number c d. So similarly this is a block, this is a row and this is a corresponding column, so it is a 2 by 2 block, so 2 by 2 block, so that is the reason when you have only singles then these two blocks become 0 because of Brillouin's theorem and the matrix becomes a block diagonal, so you just have this one value e0, so this is the reason we are calling it matrix eigenvalue equation, so I just want to rewrite. So if you now add singles, doubles, triples whatever I can keep on writing very easily by the similar block which I will explain little later, so this becomes your double CI equations. So I have to calculate the coefficient and then put it in this equation I will get the energy, how do I calculate coefficient from this equation, so the second set of equation will give me the coefficient, if I solve this equation say linear equation I can put it back here that is one way to look at it or you can say I simply construct the Hamiltonian and diagonalize that is one and the same thing, you construct the Hamiltonian and diagonalize then you will get the e0 and all the coefficient, of course if you construct the Hamiltonian and diagonalize we know that you are not going to get only one e0, you will get the entire dimension, so whatever is the total number of elements you will get that many e0, so this is what leads you to what are called excited states. So all those higher energies will now be actually excited states and they also follow the theorem that I told McDonald separation theorem, they are the upper bounds to exact excited states not just for the ground state, so all those numbers will come, so there are many ways of solving it, so one is to simplest way to think is to construct the matrix and then diagonalize, however very often this is a very tedious task because the number of WXRA determinants if it is very large then the matrix becomes very large and diagonalization of large matrix is very often time consuming, further the advantage that I have in diagonalizing is that I get lots of energies but very often I am not interested in those energies because let us say I am only interested in getting ground state, so I am doing a lot of work for no reason, so is there a simple way to solve this Eigen value equation without actually diagonalizing the full matrix, so you have to understand that this matrix size is very very large and we do not want, if it is 1 million by 1 million matrix, you do not want 1 million Eigen values and what will you do with 1 millionth excited state, this is not interesting chemistry, we often want ground state and maybe first or second excited states, so there are better ways of doing it and those are actually called iterative solutions, iterative solutions to this Eigen value problem which is much better, so something that I will mention in during the course of the CI problem if not today maybe tomorrow, so there is a iterative solution in which you can at least get 1 or 2 roots ground state and first excited state quite quickly and at a reasonable accuracy but you do not get all the states, so you do not have to actually diagonalize this full matrices, so let me just try to again understand whether you are all in sync with me, so essentially you have to construct a matrix of the Hamiltonian in the basis of the determinants which are included in the CI that is the first thing, so first determinant is psi Hartree-Fock, so that gives you a number e Hartree-Fock, then there is a set of numbers everything is a number of course, there is a set of numbers which is between psi Hartree-Fock and all psi A, B, R, S, similarly I have all W, X are determinant project this with psi Hartree-Fock, there is a set of I call them a column and then between doubles and doubles, so I have the full matrix which I am looking at as a two block, one is the Hartree-Fock block which is one by one and the rest is all doubles, so if my doubles number is n then what is the dimension of the matrix n plus 1, is it clear? Because Hartree-Fock you have to add, so my total number is Hartree-Fock plus all doubles, so if I give you some small problem you should be able to calculate at least the dimension of the matrix, I give you a small basis, two basis problem, you should be able to calculate how many W excited, if in a DCI you should be able to find the dimension of this problem and should be able to write it as a doubles, block of doubles, is it clear? Before we go forward let me also mention that we introduce something called intermediate normalization in the perturbation theory, so you may like to know is there intermediate normalization here, can I do this? Clearly the wave function that I have proposed to you is not intermediately normalized, I hope you can see this, the proposition of this is that psi Hartree-Fock, if I do psi Hartree-Fock and exact psi naught that should be equal to 1, if you remember intermediate normalization, if I do this here the psi 0 which I now call psi 0 DCI as I have proposed, what is the value? Can somebody told me? It is not 1, what is the value? As I have proposed the DCI wave function, what is the value of that? C0 plus anything is there, can there be anything? Because this is orthogonal, so only C0, only C0 and I have no control over C0 because C0 will come out of the solution, I have no control over C0 except that I know that C0 must be very large, very large because in the exact wave function Hartree-Fock is a dominating term, C0 must be close to 1 and of course C0 square plus all coefficient a less than b or less than s C a b r s square or mod square equal to 1, you can call this mod square, that is the normal normalization. But obviously this is the most dominating term and these are very very small, typically when you do a CI, this C0 may be 0.95, 96, 97, so you can imagine that large, so it is very very large, the Hartree-Fock itself is very large, the probability of Hartree-Fock would be easily about 90 percent or more and then all the rest contribute to the last 10 percent. So you have to understand that these values are very very small because you have already said Hartree-Fock is a very good wave function except that we cannot be satisfied with that because of chemical accuracy that we want for the properties, for the difference energies. So we still have to take those small small quantities as accurately as possible. So this is the thing that we get and clearly this is not an intermediate normalization because for intermediate normalization you must have C0 equal to 1. So the question is can I introduce intermediate normalization in CI? So if you look at the problem then you will realize that this can be trivially done, simply set C0 equal to 1. So I set C0 equal to 1, so if I write DCI in intermediate normalization then what will happen is that this wave function will not have C0 because that is one, the rest will remain as it is, so the C0 will go, this will go, this will go, this will go. So it is absolutely trivial to write it, everything is same and your equation here will be exactly same except that this will be 1. So everywhere I can put C0 equal to 1 and immediately you can see that your wave function is now intermediately normalized because obviously you know by previous discussion that if that is so, if C0 equal to 1 then of course C0 C0 cannot be 1 because C0 C0 is nothing but mod C0 square plus this quantity, this is already 1.  So they are non-zero, survive so this will be obviously greater than 1 and that is something that we have to accept and I can always renormalize later to get back C0. If I renormalize then I will get back 1 by square root n, that will be my C0. So this is very easy to do, I hope you realize that this is really not a problem. Often we want to write it in this manner only because the perturbation theory we have done with the intermediate normalizations, we like to compare with the perturbation theory. So in this case it is easy to put the DCI equation in the, in the intermediately normalized form, any question? You want to ask anything? Yes, you do not need to do as I said, you do not need to do but it is convenient, the convenience is the following that you will immediately see because I want to calculate the difference of E0 and E Hartree-Fock as a correlation energy that comes out easily otherwise there is a C0 which gets stuck here with E Hartree-Fock as I showed you. It becomes E Hartree-Fock times C0, I will come to that so that becomes very easy to look at the correlation energy but you do not need to do, you are right. I can still divide by C0 and do it, it is not a big problem and comparison with the MP2 and all that that I have done becomes more easy but so I just want to tell you the intermediate normalization is not a new theory of course it is the same DCI, I have forced this equal to 1 and obviously this coefficients will change because I have forced C0 equal to 1 so everything will get normalized, everything will get renormalized. So let us look at the equation in intermediate normalize, so I have finally this block. So let me go back, let us see how the iterative solution will look like in intermediate normalize form, so essentially I am going to look at this. So the first term is E Hartree-Fock, so what I am going to do, I am going to multiply the first row times the first column, so E Hartree-Fock, this is a set of numbers which is a row, which is a row, let me call it bidagger, we will see why I am calling it dagger, bidagger multiplied by CD, so this becomes bidagger C or CD, please remember I am now using a matrix notation, bidagger is a row, so B is a column, so this will be my B, this is bidagger, it is a bidagger times this column, is it clear to everybody, I mean I am just using a matrix, so this is a matrix, this is not a number, this is a matrix, obviously this has to be a set of numbers, so it is a row, this is a column, it is a one dimensional matrix actually, bidagger CD equal to E naught, so first row into first column equal to E naught and you can quite clearly now, why I use E naught, why I put E naught equal to 1, because you can clearly identify the correlation energy as this, I do not have to divide by C naught later, so that is easy, so whatever is the bidagger and CD, CD is the set of coefficients, lovely excited coefficient, bidagger is this matrix element, where Hartree-Fock is on the left, Psi D on the right and obviously it is a set of numbers, set of Psi D, so all this together becomes a column index, column index, row index, so this is basically, this is bidagger let us say, this is some bidagger and this is some column, CD, so this is my bidagger, this is my CD, so you just multiply this, you get one number, if you multiply row times column, you get one number, so that is what you will get, because I need a number here, these are all numbers, by dimension you can see that, then I go to the second equation, the second equation I have CD, so sorry I have B, note that if this is bidagger, this must be B, so B into 1, so B, again this is a column, it is not just a number, B into 1, plus you have now a set of block which is the matrix now, D, let me call it D, I put 2 bar to denote that this is a 2 dimensional array, it is a matrix, why it is 2 dimensional, because you have a set of numbers here, you have a set of numbers here, so it is a 2D matrix, is it clear, one side is A, B, R, S, another side some CDT, so all doubles with all doubles, so one row will be one doubles, so basically I am looking at this, these elements, all elements, so one row will be defined by CDT, one column will be defined by B, so I am calling it a 2D matrix, it is really a matrix, square matrix, of course it is a square matrix, this should be multiplied by what? CD, it is a column, this is a column, now you see look at the dimension of the problem, it is exactly same, this is a column, this matrix times column, column is also a column and you will get a column on the right side, because it is E0 times CD, so everything is beautiful, that means this column, this is a column thing, so it is actually a set of equations, if I want to write it is a set of equations, I have written in one equation, it is actually a set of equation, Bi plus Dij CDj equal to E0 CDj, it is a set of equation, but I am writing only one equation here, in a matrix form, I hope all of you are sophisticated enough to write things in matrix form now, by now you are sophisticated, mathematically sophisticated, so and here of course everything is a number, so this is a one dimensional equation, this is the dimension of the equation is number of W excited amplitudes here, so I need to calculate this quantity, remember what is unknown, what is known, Bidagar is known, because that is the matrix element, that is later rule, I can apply this later rule, I can find out, what is not known is the CD, CD is in the intermediate normalize form, the coefficients are all that is unknown in the CI, the wave function is otherwise known, so I need to get CD, how do I get CD, I look at the second equation, from the second equation B is again known, so from the second equation I will try to get a form of CD and substitute this here, so matrix form, so all of you should be able to do this, so how do I get, so I will write this as B equal to E0 times CD minus D times CD, or I can write the reverse manner, I can write this as D times CD minus E0 times CD equal to minus B, again it is a column equation, this is the matrix times a column minus a number times a column equal to a column, is it okay, note again this is known, I am repeating this is my B which is just the matrix element of the Hamiltonian between W excited determinant and Hartree-Foggan, I will do that actually, I can use Slater rule and find it out, I have not done it yet, but that Slater rule can be trivially applied, I need to find out CD, so what will I do, I will write this as D minus E0, but note that now I have a problem, this is a matrix, this is a number, so how do I multiply, I have to multiply this by a identity matrix, correct, this is basically subtracting from diagonal elements of D E0, so how do you do this, you write this as E0 times identity matrix times a column CD equal to minus B, so I have a matrix times a column equal to another column which is minus B, so now I should be able to get CD from here by inversion, formally I can write an inversion of this matrix, multiply from the left, this will cancel, I will get CD, so let me write this now, so all W excited, although I am writing for a CD, remember I am writing for all the configure, all the amplitudes of W excited, so CD equal to minus D E0 inverse, so CD is just negative of D minus E0 inverse, we do not need, we do not need, yes you are right, we will see, yes that is where the iteration will come in, absolutely, you have already got the point, we do not know E0 also, so but let me write CD formally in this manner and then write the correlation energy, so correlation energy is nothing but E0 minus E hard to pop, let us define it in this manner which is nothing but B dagger CD, so I put this value of CD, so I have very nicely got minus B dagger D minus E0 into identity inverse, just want to make sure that I put 1 bar and 2 bar right, just for the time being it does not matter as long as you understand or for the time being I want to be correct formally, so this is what you get, so your correlation energy is in some way dependent on this total energy, you can actually subtract the E hard to pop from both sides, I can write this in terms of correlation energy itself but or I can write the E0 whatever, whichever way you want to do, so there is a there is a simple way to do is that when I write the E hard to pop itself, you can write as E hard to pop minus E hard to pop, so you can make it 0 and everywhere you will get correlation energy, so that is again a trivial thing but let me not worry about that right now, it depends on how I define B E C dagger etcetera, so I can write this quantity in this manner, now note this quantity very carefully, the D is a matrix element between the Hamiltonian of the Hamiltonian between two sets of W X are a determinants, minus some E0 inverse and then you have one set of elements which is doubly excited and then B dagger or B, B dagger and this is B, psi C d t right, so you have a B dagger and B, compare with the MP2 energy, if you look at MP2 energy there are exactly two such sets B dagger and B, if you look at MP2 energy what was MP2 energy psi hard to pop ABRS, ABRS into psi hard to pop right, so that was really B dagger B divided by some orbital energy, if that orbital energy happens to be this, some approximation of this then I can get MP2 from here obviously it is not, so only some approximation of this will actually give me orbital energy, so one of the approximations is basically to write D minus E0, remember D is this whole Hamiltonian inverse as simply the difference of the orbital energies of the one doubly excited to another doubly excited, so this is where approximation has to be made, so we will come back to this, so otherwise of course you will not get it, if you see it normally there is a iterative procedure required because I do not know I can take out E hard to pop, I can write this in terms of E correlation and then I have to do an iterative procedure, so first what you do you start with E correlation equal to 0, calculate this quantity, find out again E correlation, put back and keep doing, keep doing you will get final value, so that is the trivial way to do this that you can actually iterate and get a value of E0 depending on where we start from, so you can start from E correlation as 0 and then you can keep iterating, of course during the iteration it is not very easy because every time you have to do this matrix inversion which is also not a very easy thing to do, a matrix inversion of this kind where this is a Hamiltonian, so this is where approximation have to be done, but formally that is how this step will go, you have to just invert this matrix D matrix D minus E0 matrix, so basically in this matrix simply on the diagonal term whenever there is ABRS, ABRS subtract E0, so one simple way to approximate this is assume D to be diagonal that is easy, what do you mean by D to be diagonal? It means any time ABRS and CDT were different the elements are 0, so all I have is a diagonal matrix where diagonal elements are psi ABRS H psi ABRS and you subtract your E0, subtract the total elements, so assume D to be diagonal under the diagonal approximation, I hope all of you can easily do this, you can actually invert this because it is a diagonal matrix, so all you have to find out are the matrix elements between doubly excited determinant psi ABRS H psi ABRS, so you can use later rule to calculate this, so you have one particle term of all Hartree-Fock spin orbital except AB instead of that RS will be there and then there will be two particle term where again AB is replaced by RS, so you can actually do this calculation quite easily and this is not very difficult, so with this approximation it is very easy to diagonalize this matrix or iteratively diagonalizes matrix and this is something that was initially attempted as a first approximation of a DCI method that let us do a trivial diagonalize, no there is no bound except that your E0 finally E0 has an upper bound to the exact amount, this is of course I should call it not really E0 but E0 tilde because this is not the exact E0 remember, this is an approximate E0 where I have used DCI, so this has a bound, so only to that extent whatever results you get it will not go but at every iteration there is no bound, the bound is only when you converge, so you cannot say that the first iteration it will be greater than exact E0, second iteration also it is greater than exact E0 that cannot be showed, so essentially this is my exact E0 and these are my iterations, I start with iteration 1, let us iteration 2, I cannot guarantee that it will converge like this, you understand, these are these points are iterative values, it may so happen that it may go like this, like this, like this and eventually reach here which is higher than E0 exact, so this is let us say 0th iteration value, this is first iteration, I am just plotting E0 basically, so this is my first iteration, this is second iteration, third iteration, let us assume that it is converged at fourth iteration, when it is converged it must be greater than exact E0 because of the upper bound theorem, but I cannot guarantee that every iteration this will be greater than E0 and iteratively it will actually monotonically approach, that is not that I cannot guarantee, so if you make a diagonal approximation then of course this can be easily calculated D-E0 inverse and you can then show further that if this D-E0 inverse is simply the difference of the orbital energies of diagonal orbital energies, so basically energies of A, B, R, S, then this will actually give you MP2, I hope that you can see very easily because B dagger B is already MP2 numerator and then denominator this will is a diagonal approximation, so it will simply come as the denominator epsilon A plus epsilon B minus epsilon R minus epsilon S will come, actually this will become epsilon R plus epsilon S minus epsilon A minus epsilon B, but this negative sign will change it to that, so you can actually get an MP2 and I will show when I write this full form next time, I will actually write the full form by a slider rule, I hope all of you can expand this by a slider rule, then I will show what is the approximation which will give to MP2, so what I want to tell you is that while there is an exact solution of BCI possible, we can make two approximations, one is a diagonal approximation of D minus E0 inverse, then further approximation is to assume the value of the diagonal as only the orbital energy difference, then what I get is an MP2 energy, so MP2 comes from BCI following two approximations, if I do an iterative solution, remember iterative solution, so first iteration itself, so I have iterative solution, so at the very first iteration, I make an approximation that D minus E0, one inverse, one is diagonal, so that is the first approximation, A and then you assume this diagonal as the difference of the orbital energies of this A, B, R, S, now they are only diagonal, so no CDTU is there, so it is only A, B, R, S on both sides and you can clearly see that with this you will get the, of course when I say orbital energy difference, it is D minus E0, not just D, D minus E0, you will have orbital energy difference and then you can clearly see that I will get MP2, so from the DCI, the process of DCI, very first iteration under some approximation gives MP2, which is very interesting to see that there is a connection between CI and perturbation, but quite clearly that value will have no upper bound, because I made already, first of all it is only first iteration, so it is a first iteration, I am stopping at first iteration, second is that I am making two approximations, the D minus E0 is diagonal, I am also assuming the diagonal as the difference of the orbital energies, so obviously it is no longer CI, so there is no upper bound in any case, as I explained to you is only when you have completely converged the DCI solution, so this will actually give you an MP2, so if you have an iterative solution, then you can recover MP2, MP2 energy with the following approximations and this is important to understand the difference of DCI and MP2, of course if I do SDCI you will never get MP2, because MP2 does not have singly excited configurations, MP2 only has also doubly excited configurations, so only with DCI you may be able to get, but not the exact DCI, an approximate DCI can give you MP2 energy and I think it is important to understand next, I think next class what we will do, we will actually try to expand this to see what approximations will give you that as the difference of the orbital energies, so I am not stopping just to show you MP2, of course if you go ahead further then the relation with MP2 will I am not stopping, I am saying under what approximations can I recover MP2, it is actually an iterative solution, so to recover MP2 I have to stop at the first iteration itself, because you can see if I go ahead then of course this will become much more complicated, you will have a further term, so you continue to build many more times this coefficient, so I have to actually substitute that coefficient here, so whatever coefficient I have got I have to go and substitute there again, so that will actually give you third order fourth order, in fact you can also make a analysis, higher order terms will start to get generated, but only from doubles, because MP3 also has only doubles, MP4 has singles I have not done this, so these are something that I will like to do when I introduce diagramatics, so please remember that perturbation theory is not over, I will come back to that when I introduce diagramatics, but right now without introducing diagramatics I am just saying that if I take a DCI then you have a very simple way to recover MP2 energy, under some approximation at the very first iteration you can recover MP2, if I do full again value equation solution then of course you lose it, you do not really see where the MP2 came and went, only when you iteratively solve you can see the MP2 value, so the details can be worked out, but I think the philosophically you should understand what we are trying to do, because essentially this is the crux of the equation, this is the crux of the equation and this inversion is actually quite complicated, matrix inversion, so we have assumed a diagonal approximation and then we have assumed the diagonal values as the difference of energies and then only you can recover MP2. Before I come back to MP2, the further details on the DCI,


I'm Jay Fidel. This is Community Matters here on ThinkTech. And the question is, can we reach immortality? What is the way we can do that? And to help us through that journey, we have Corey Martin-Jewel, and he is going to help us. Welcome to the show, Corey. Hi, thanks for having me, Jay. It's very excited to be here, and we have some really exciting news. I understand you're 102 years old. Is that true? Well, last time I checked, yeah. No, today I was born 45 years ago, but my actual biological age is now 36, and it's going to be getting lower. So, but we'll get to 102. We'll get there. Okay, just checking up. I want to know how to reach immortality. I mean, we have tried to reach immortality since Ponce de Leon in St. Augustine and the Fountain of Youth in the year 1513. So far, I haven't stumbled across anybody who says they can do it, and actually, sadly, Ponce de Leon is no longer with us. So, give me a handle on the general idea about reaching immortality, and you could help me by defining immortality, because immortality, you can quote me on this, Corey, is not forever. Oh, well, we use the name immortality, the French spelling for our company here, we're a Hawaii-based company, and the meaning behind it is, the intention behind it is to extend people's lifespan, to give them more quality years. I know you were mentioning the Fountain of Youth, and water is also really important in the Hawaiian culture. I mean, the middle Hawaii is water, and I've also traveled to Egypt, and I studied how they use healing water in ancient Egypt. So it's a very, very ancient concept, and even if you go back to the Bible, there's, you know, Methuselah and Enoch, we're supposed to live 700 or 900 years. So we're not quite sure, I would say like that's, you know, absolutely out of this world, but we're getting to the point again in history where we're not quite sure how long we can live. No, but you know there's a problem about reaching immortality. And I do want to ask you about the French connection on some of the drug show, the French connection. So if I make everybody immortal, or I enable them to lead a very long life, they're still going to want to have children, les enfants, if you don't mind. And if they keep having children, and they do, you know, I mean, there are those people in this country who would like to everybody to have as many children as they want, as they can. What happens?  You have all these children being born into the society, but everybody's living longer, and now you have kind of too many people or more, significantly more people alive on the planet. How do you deal with that as a matter of public policy? Well, the world is moving towards more sustainable planet. And we are really interested in making our bodies more sustainable. And if you really look at the resource allocation, we could have, you know, there's been UN studies that show that we could have up to 14 billion people living sustainably on this planet, which is more than double what we currently have. So as far as there being more people, I don't know if that's really a problem yet, but as we live longer, we may not be inclined to need to have as many children because people that were having many children in the past were to help on the farms and to help them with their labor and they knew like maybe one or two children weren't gonna make it. So they had a couple extra and they were, you know, all working together to perpetuate the family, which is very important. But if we can sustain our lives and our bodies in this new way, we can live dramatically longer and we won't have those concerns about, we need to have eight children, you know? We will be able to populate the earth with, you know, as many people as we need, but we're not reaching that point yet. And the beauty of this is that people will be living longer. So you won't need, you'll be longer quality years.  You will be out and thriving and you'll still be active and you'll be doing everything that you wanna be doing. Including sex. Including, if I'm immortal, just in French way, I'd like to have as much sex as possible. And I'd like to have that at 70, 80, 90 and 100. And so as a matter of public policy, it may not be a great idea to increase the population to 14 billion. It may get very increased, not only by the fact that nobody's dying, but by the fact that everybody's procreating like crazy in their later years. Why not? It's fun. Well, you may need to restrain yourself, Jay, but I think that as we no longer have these needs to procreate for the perpetuation of the species, because we're living dramatically longer, we might just do it for enjoyment or for social, just for all the other reasons to share love. You're talking about birth control, aren't you? Well, no, I'm not going that far, but there's other ways to do things. Okay, that's not why we're here actually. Yeah, well yeah. Okay, so let's talk about how you do it. Because I think all the people are out there waiting to hear what Ponce de Léon could not deliver. And I saw two terms in your write-up. One was a regenerative longevity and the other was regenerative beauty products. So what does regenerative mean, Corey? And what's the common denominator between longevity in terms of immortality and regenerative in terms of beauty? Well, like I said, at the beginning, we're a Hawaii-based company and we've just set a world record for the fastest epigenetic age reduction. So that's something to be very, very proud of, unique to Hawaii. And one of the reasons that we were able to- Could you define epigenetic? I know and love that term, but I'd like everybody to know and love that term. So we have a chronological age and then we have a biological age. And forever we've seen them as equal, but you know that you can now, measuring your DNA, you can lower your biological age so that you might be 45, but your body is operating like it's 36. And we can continue to lower that. And that is through the process of regeneration, which you were just talking about. What we do differently here in Hawaii, which is something to be very proud of, is we have all of these different influences. We have Chinese medicine. We have regenerative farmers. All of these insights that we came to uniquely here in Hawaii were because of this diversity of all this knowledge that doctors may not be aware of. And so it's taken them down a certain path, but we have insights that we've come to during the pandemic, it actually happened. I dislocated my shoulder and my elbow and we can get into that. But the regeneration process, what that means is that as your cells replicate, we are gonna replicate perfect cells. In the past, as you age, your cells slowly degrade over time.  Well, I feel it every day. Yeah. Well, it's no longer gonna be a reality if we can continue to replicate perfectly. And we have lots of technologies and techniques that we use here to replicate these cells perfectly. Let's talk about it. Let's say, first of all, you gotta answer my question. What is the common denominator between regenerative longevity and regenerative beauty? Is it the same kind of technologies and the same kind of substance and biological process? It's a very similar concept. We're using the same concepts. The difference is the longevity is designed to extend your lifespan. So we're working from the inside out. We're regenerating your organs. We're regenerating your kidneys, your liver. The regenerative beauty is working from the outside in because to be honest, a lot of people don't wanna wait long enough to look better. So they want it on the face first so that it regenerates the face and then they'll worry about the rest of the body later. We're not here to judge. We're here to give people what they want. So how do you do that biochemically? We're working with the body. So we are giving the body both the nutrition it needs, but also this major component which is overlooked is the bioelectrical component of the body. If you study anything in Chinese medicine, you'll know that there's chi or in the Hawaiian culture, it's mana or in Indian culture, it's prana. But this has been disregarded in Western medicine and they focus on the chemical aspects and they focus on more mechanical aspects.  So what our products and our technologies do that's different is we incorporate this electrical component and that allows the body to receive an abundance of what's life force or mana. And that is what is the real power behind what we're doing that is empowering all of the things that everybody else has already tried. It's kicking this into high gear. Can you divide for me the thing with the acupuncture and the electrical and the thing with the thing with a substance and I guess I can go by the substance at TMC in Illinois Center, I can buy a little bottle of it. What does it look like? Is it granular? Is it liquid? Does it look like sand or powder? Is it granular? Is it- It is liquid. We have them in our tinctures and our tinctures are made up of 16 different herbs, Chinese herbs that empower your kidneys. But like I was just saying, the most important factor is the life force. And so we've empowered these herbs in a way that they are bioactive and that they go straight into your cells and they empower your body. So there's the electrical component as well into these products. They are liquid. You can take five drops a day. Sometimes that's even too much for people. So we have them bring it down to two or three. Your body regenerates when it sleeps. So when we say it's too much, it may make people tired. Most people are out vacuuming and they're just doing, they're doing housework that they haven't done in years. They feel so great. But if we wanna take it up a level, we also have a transformative longevity program and that is now online where people throughout the world can watch online and participate and they can learn all the science behind this. And they can also do a week long class where they actually go through a program to regenerate their body and begin that process. That's about- Is that physical? Is that brick and mortar? Or is that online where I can do it from anywhere in the world? It's all online at the moment. So anywhere in the world. In the future, in the next few months, now that we've broken this world record, we are hoping to open a physical clinic here on Island so people can come and do a treatment for a week. Okay, so gee, that sounds really interesting. So what is the, from a medicinal point of view, what is happening in the cell to rejuvenate it that way, to give it this kind of regenerative and electric quality? It sounds really interesting. Can you describe to me at the cellular level, the human cellular level, what is happening? There's a couple of things that are happening. Well, there's more than a couple of things. There's more things than we can possibly list. There's things we don't even know that are happening that we're seeing it happen. But in general, you've got your DNA and it's encapsulated inside of a chromosome. And on the ends of these chromosomes, there's the tips of the chromosomes. And if you think of those like shoelaces, over time, as we age, they get shorter and shorter and shorter. Right, and you can measure expectancy. You can look at the chromosome for anyone and measure life expectancy. This is really fabulous. So this is kind of like reverse engineering. If I make the chromosome longer, I mean, if it gets shorter, my life expectancy is less. But you're talking about making it longer, forcing it to be longer, and then my life expectancy, is that what you're talking about? Yeah, so we're not actually getting it longer, longer. We are restoring it to its original length so that your cells will then perfectly reproduce without breaking. We don't want, as things get shorter, they start to mutate, they start to change, and then it's not... I feel that, I feel that. Yeah, so what we're doing is we're, that's one of the elements. And that's based on Nobel Prize winning research from 2009. And we've incorporated her knowledge into these products. You say her, who was her? Who was the Nobel Prize winner? Her name is Natalie Blackburn, I believe is her name. She, or it was Elizabeth Blackburn, one of the two. Apologize for that. But she came to this conclusion, won the Nobel Prize, and we've just incorporated it. And another thing we've done is we're empowering the kidneys. The kidneys are responsible for generating stem cells. The stem cells are created in your bone marrow. The kidneys signal your bone marrow to release stem cells. So some people are traveling to distant places to get injected with stem cells. We're not doing anything like that. We are using the body's own stem cells to regenerate itself. And stem cells are wonderful cells that you have a lot of when you're a baby. And they can turn into any different type of cell. Whether it's a heart cell, muscle cell, brain, you name it. So if we're releasing tons of those in your system, if we're signaling your body to release them, they're going everywhere in your body that they're needed to help regenerate you. So what's the kidney you got to do with that? You were talking about the kidney a minute ago. The kidneys are kind of the, in Chinese medicine, they are considered like your core, the core of your being there. They're the kidney that's responsible for blood pressure and all of the organs actually work together. But the kidneys are the ones that we signal with these herbs to activate the stem cells, yeah. I see, okay. Suppose I was to walk into Queen's Hospital and go to the reception area and say, I'd like to get regenerated. I'd like some of that liquid stuff. And can you put me in touch with a doctor here at Queen's Hospital with all your specialties? How about a nephrologist? Because that's about kidneys. What would they say to me about my request? Would they be able to help me? Not the way we do it. I'm not quite sure what they would propose, but I can tell you, I went to Queen's Hospital just at the beginning of the pandemic. I dislocated my elbow. I think you may have a picture of that. And- Now let's show a picture of Cory's elbow. There it is. Kind of, that looks very mechanical, Cory. Yeah, totally dislocated. And you can see there where it's supposed to be together. And in this process, I tore every single ligament and tendon in my elbow. So in the ER at Queen's, they were able to pull it back together. And there may be a photo of it back together. And once this happened, at that point, I was presented with the option of getting surgery. So that may be what they would also say for your kidneys. I'm not quite sure. But with my elbow, that was the option. So I was working with these regenerative farmers here in Hawaii. And I said, I've seen what you're doing with the plants. You guys got these plants. And the next day, they're just standing straight up and they look, they're just beaming. Can we do that to my elbow? Can I regenerate my elbow? Let's see what happens. And so they said, let's try it. And so we did. And for 13 weeks, I re-grew every single torn ligament and tendon in my elbow. And we have a diagram of the elbow. You can see how many ligaments and tendons are in there. It's very, very intricate. Now, the only way this is possible is the body is infinitely intelligent. The body knows what it's doing. What my job and the farmer's job to do was to get all the nutrition, the collagen. Those ligaments are made up of collagen. So we got the collagen in there. We carried it through the bloodstream using water. And that allowed the body over 13 weeks to completely re-grow 100% my elbow. And that was something that is not possible. Now, this little jar of liquid you're talking about where I take four or five drops a day, does that have collagen or was this a special mixture, a special conglomeration of things that helped you on the elbow? We do sell collagen on the website. And we tailored this. This was before the company existed.  If we were treating a heart or we were treating a kidney, we would infuse it with different things. The kidney would be like parsley and black garlic. Those are the things that are in this tincture. They're targeting your kidneys. So it's different tinctures for different problems. Yes. So we have to speak to somebody. We can't just make that decision. We have to make the decision of, hey, something wrong with my elbow or my whatever. But in the class, in the class we teach people how to go through this and we show them what the process. Now your stem cells will, and we sell the collagen as well, the stem cells will take care of things. Your body is intelligent. It will know. And so like I have no clicking and popping in my elbow. It's back 100%. And when I got the MRI test results, it demonstrated that it's back 100%. I think you have an image of that as well. Oh, let's see that. I want to see the MRI test results on Corey. That's the report. Yeah, that's the report. Okay, ligaments is normal. Radial ligament is normal. Lateral ligament is normal. So this would indicate a what? A complete. A complete re-growing.  Wow. And that is not currently possible. And that took, what'd you say, 14 weeks? Yes, 13 weeks to re-grow it. And then it took some working out to get it back to 100%. But yes, lifting some weights. It's funny that a friend of mine broke her ankle recently and they said, and they casted it and everything. And they said what they always say, this is going to take six weeks to heal. And we know that, break a leg, break a bone, break anything, six weeks. They always say six weeks. It's like they must learn that in day one of medical school, six weeks. Six weeks is a lot less than 14 weeks, Corey. It is, but this is 100% and it's never, ever gonna re-injure again, ever. And so. It's stronger than it was to begin. Well, that's up to me how much weight I wanna lift. But yes, it is equal to my right. Yeah, and it is perfect. So suppose I take a lot of your tincture.  I favor vanilla ice cream, but I don't think that's on the menu. So let's say instead of taking the recommended dose if dose is the right word, I double or triple or quadruple that dose. Am I gonna have side effects here? Am I gonna see spots in front of my eyes? Am I gonna be one of those characters in the Marvel movies that can lift a car? What's it gonna be like for me? Well, that's the exact approach we took to win this world record. I was doing about a bottle a day and I had a medical team here with me, watching over me and there was an acupuncturist as well as someone doing my vitals. What happens is, is that the bioelectrical energy I was talking about accelerates in your body. You start basically, it starts moving very, very quickly. And if all the things we teach in the class teach you how to manage that, what that can mean is it could feel like an emotional roller coaster where you're very angry one day, the next day you're calm because all of these things are leaving your body. It's a electrical detox, I guess you could call it. So there aren't any side effects. I mean, all these things are natural and they're organic and unless you're breastfeeding, these products are 100% safe. So it's not anything that people should be concerned about but you wanna not overdo it. We're talking about balance. Your body will regenerate faster when it's in balance. The faster you go unless you have all the support systems in place, which is what we will do when we open this clinic, people should stick to five drops a day because slow and steady wins this race with longevity. Hmm, okay. So what about you said that you had a life, that your real age, your real age was not in the 40s, it was in the 30s I think you said. Yes, yes. How do you know that? Did you measure your chromosomes? Yes. Did you find that they were shorter than or rather longer than shorter? Yeah, go ahead. They found that the process is called DNA methylation. It's the gold standard test for what we have today and it was done in San Diego at a place called Trumi Labs who are our partner and they measured my DNA for on July 15th which was my starting point which I was 45 and I have a graphic here now that shows I am now 8.4 epigenetic years younger. Now this is our second test on our world record attempt. We have one more test still coming so I may be in my low 30s now. In the past there is a billionaire, well last year, not in the past, there was a billionaire named Brian Johnson and he spent- I warn you I'm always suspicious of billionaires. Yeah. I became aware of that when I saw what Elon Musk was doing. Billionaires don't necessarily impress me.  He was the previous record holder and he spent $2 million a year testing different things on his body and he said what they concluded was that he got to 5.1 biological years younger in seven months. What we've done here in Hawaii which is something to be really proud of is we've done 8.4 years in only eight weeks which is almost double and we'll find out the final number here in about two weeks which is probably gonna be double what he did in less than half the time which is extraordinary. And so that is amazing, that's the world record. You know I asked a little while ago what happens if you double, triple, quadruple the, you know the dose, the number of drops and the bottle and the tincture and I'm thinking of a movie, I can't remember the name of the movie, it was about somebody who got younger all the time. Yeah. That's the very- Benjamin Buttons, Benjamin Buttons. That's it, that's it, Benjamin Buttons. Yeah. Do you wanna have a reference to that on your website, Benjamin Buttons? So suppose I kept doing this, you know and it was not necessarily with advice, I just felt I wanted to get the maximum effect of all of this. And I found that my age was no longer in the 30s, it was in the 20s, all Benjamin Buttons, it was in the teens and then I hadn't been born yet. I was, you know, is this possible? Can we have the Benjamin Buttons effect? Yes, yes, but hopefully we don't have to be born all old first, you know? We have another graphic for a 72-year-old and you were asking about the drops. She was on five drops a day. And as you can see, we didn't do a before test with her, we put her through some programs before we discovered this DNA process. But the first time we tested her, you can see she's 10.6, I think 10 years younger at least. Now on the drops, she's been able to sustain her age. So the chart there shows that it's level, she's not aging. As time goes on, this person is not aging. And that is remarkable. That's on the drops. So if you wanna do more than five drops, that's why we're gonna have, you know, if you wanna do 40 drops, you can take our program, it's online. If you wanna go further than that, we can do supervised sessions in this clinic, which we will hopefully open up. Who supervises? Is this a medical doctor? Who supervises what kind of professional expert is involved in making these choices and recommendations? Yes, well, we will have medical team as well, the people that helped me, and we will also have- Like doctors, like doctors, MD doctors. Yes, well, it's hard to find people that are regenerative doctors, but yes, yeah. And also the traditional Chinese medicine doctor that helped me, you know, I was doing acupuncture quite a bit, almost every day to keep this energy moving. And yeah, all those things will be in the clinic, but that's what happens when you drink too much. Oh, sure, anything that's too much is too much. So, you know, do you give this stuff away? Do you sell it? Does somebody else sell it? Can I buy it at TMC? Is there a variety of products I can look to online or on Amazon, you know? Where can I get it? And how much will it cost me? And after all, I'd like to add that if I'm losing 10 years in my, you know, if I'm gaining 10 years of my life expectancy, that's really worth something.  And if it works, if it's, I don't know, I'm saying guarantee, maybe it's not, but if it works and it increases my life expectancy by, say, 10 years or 20 or 30, I could go on, then that's worth a bundle of money. How much does it cost for the five drops and a little tincture? We have three drops on our website, mmortality.com. It's a three-tincture pack and that sells for 195. That lasts for three months. That's a three-month supply. That's cheap, about 195? Yes, yes. And you take five drops a day. No, 195. Oh, sorry. Yeah, yeah, yeah. But yes, it is still relatively cheap for what you're getting, which could be, you know, we know there's people living around the world in these blue zones already 30 years longer than in the West. So we know we can live to our 100 and we know here at the center, things that will take us past 100. So all these things are happening. So we don't, we're looking at 120, 140 now, which is amazing. And there's sharks, the Greenland shark lifts to 500. We know why that is. So if we can regenerate perpetually, we don't know how long we can live. But the science behind it is in also our class, the Transformative Longevity Program. That is also on our website. It sells for 7.95. But because we're celebrating this world record, we have a checkout coupon code, world record, all together, uppercase, and you can redeem that coupon at checkout.  I mean, that may write that down. So, you know, now to go to the question of the plants for a moment, you talked about a farmer who wants to grow his plants straight up and down like your elbow. How does that work for him? Does he drop the tincture on the plant? Yes, he has a different, they have a different formula. For years, I was working with the Center for Living with Nature and they have regenerative farmers and they have figured out how to take these plants and just, they literally stand straight up and they're beaming just by adding certain things. It's not like traditional fertilizer. It's regenerative fertilizer. And they tried for years to get funding, but they always lost out to bigger chemical companies every time they applied for a grant. So, the beauty of this is that we're helping regenerative farmers. We're all working together to regenerate the body. But they had the knowledge and they discovered this. We applied it to the human body and it's amazing. It's amazing. It's using our bodies as they were intended to be used. What about the reverse of that? I mean, if you say to the farmer here, here's a bottle of tincture or whatever, why don't you fertilize your plants, your crops, whatever crop it may be, say taro, and make it grow taller and stronger and live longer and what have you. Is that the same process? Is that the way it works? And wouldn't that have a huge effect on farming? Because all these chemicals, they try to make like GMOs and the like and they try to make the plants stronger and longer and what have you. You're saying this would be a substitute for that? Absolutely, absolutely. And yeah, that is something that they've been trying for years, application after application. I've watched them do it. I've been there helping with the application process and it's kind of staggering that it hasn't taken off. But I think they have to wait for the tide to turn for more information to get out there that this is possible and get the awareness so that people make these choices. This is a completely viable and better option. Well, let's talk about the taro for a minute. Suppose I've been feeding my taro this tincture, this what do you call it, regenerative product. Now the taro is growing, it's in great shape, it's harvested, I put it on my table, I make poi out of it, for example, okay? And now I eat the taro. Do I have the benefit of the regenerative compounds? I do. Yes, I'll give you an example. We have beets that grow at that farm and those beets are pulling in all the micronutrients. So if you bought beets in the store, you would get excellent beets. If you bought organic beets, you'd get slightly better beets, but these beets have gold in them and the leaves, they have gold. They have micronutrients that generally aren't found because we're empowering those plants to be like the best that they can be. And all of the microorganisms are involved and everybody's working together to create this incredible plant. So with the taro, the same thing, you would get the most nutritious taro possible. And that would, if you fermented it, if you made poi and you ate it fresh while it was after fermentation, you would get the maximum benefit. So maybe I don't even have to take the four or five drops. I could just load up my kitchen table with taro that has had the benefit of this regenerative product. And then I could have it, then the taro could have it and I could have it both. We could share it in a way. You've touched on something phenomenal there, Jay. And that may be why Methuselah and Enoch and all those people lived to seven or 900 because they were doing things a different way and they were working with the environment and they were living on a different planet. I didn't tell you my middle initial was M and some people feel that that stands for Methuselah. Only kidding. So, okay, so how do you make this stuff? And now at the risk of giving away trade secrets and maybe something that's patented, how do you make it? What is the raw material? What is the process? And is it patented? Oh, it is definitely trade secret because we're working with nature and I don't believe it can be patented, but it is a 45 day process that combines all the plants into basically a new thing. It's a synergistic process. So all of the plants that are involved are now working, not just like if you added it, it's more exponentially powerful. And like I said- Did you do this yourself? No. Or do you have a laboratory do it somewhere? Yes, yes. Yeah, here in Hawaii, yes. The laboratory is here. Yes, and they work and yeah, they create this process. I don't wanna get into too much detail on how it's done, but I can tell you that it takes time and we're sourcing the highest quality ingredients, organic and wild harvested ingredients. It's all plant-based ingredients. So if you are vegetarian or vegan, it works for everybody regardless of what your diet is. So one last point, I wanna return to the name immortality is a French word. And in fact, as I recall, the website uses that name immortality with an accent de gout over the last E there. That's impressive. You gotta have a special typewriter on your computer to achieve the accent de gout. Anyway, so what's the connection? Is there other people in France or other places in the world? Is this a franchise? What is this? We want it to become a global brand. I mean, we started here in Hawaii. So it didn't come from France. We were looking at the best way to brand this product and the French, because part of this is gonna be a beauty product. You have Dior, you have all these high-end brands that are all French if you go to Alamoana. But the very day we launched, we saw this incredible picture in our Facebook feed of Princess Kallilani from like way back. And she was on this voyage going to Europe and the boat that she was on was the immortality. And it was across her, across her, you can see the hat. It's in the historical archives. And that was like a sign. Yes, it was like a sign. It was like, we are on the right path. It was amazing. So that we knew that that was the name to go with. Ah, okay. So you're saying this originated here and to the extent that there are, there are French names and people involved, I assume in Paris, am I right? Then it's really derived off what you have found and investigated and arranged for and what you sell on your website. What is the name of your website is immortality.com? Yes, yes. This is not a non-profit. This is an ordinary profit corporation. This is a for-profit business here in Hawaii, yes. Okay, is it licensed as a medical organization or just a sales organization? It's just a sales, yeah. Yeah. So where can I read more? Maybe it's on your website. Where can I read more about the process, the origin? You know, how this works, how it works in terms of longevity, how it works in terms of a beauty product, how it works here, there, and on crops also. The process for the crops, we're still looking for funding for that. The beauty products, we're also still awaiting funding. So we started with the longevity and that is taking off and we just got the world record. So as word spreads, more and more people will get on board. The biggest hurdle is people don't even know this is possible, like people have so many questions. So if you go to our YouTube, which is YouTube slash at immortality, you can watch videos. We post videos every single day of our journey, the 40 days we spent breaking this world record. We're also on Twitter, we're also on Facebook. At the very, very bottom of our website, you can see the links for Twitter, Facebook, and YouTube. We're also on TikTok. I don't dance, but we're on TikTok. And it's great, it's great. The news is getting out. As far as the regenerative farmers, we may be supporting them until they can actually get this regenerative product out there. It's ready to go. So, so is the beauty product, ready to go. And our clinic will hopefully be opening here on the island within the next couple of months. Where will that be? Where will that be? We're not sure. We want it in some place that is easily accessible so people can fly in from around the world. And yeah, we will be the first center and then hopefully it will spread globally. One other thing, Corey, what is your background on this? What is your training in terms of the physical sciences involved, the biochemistry involved? What's your business background? Can you talk about it? Sure. It's unexpected. I have a bachelor in science, but I'm actually a filmmaker. I was born on Kauai, come on Kauai. And I started at Square USA. We were doing Final Fantasy in 2000. I then worked on the major stuff. I remember that very well, yeah. What was the name of the heroine of Final Fantasy? Aki Ross. Yeah, I remember. I had such a thing for her. She was really no kidding. I have a big poster of her as well, yeah. Yeah, it was amazing. It was an amazing adventure. From there, I went on filmmaking and worked on The Matrix, worked on Lord of the Rings, Star Wars. And when I was going out filming, I had several accidents. Twisted my ankle. And then I also traveled to Egypt and I was learning these things in the background that I didn't really know how they all fit together.  So I am by trade a filmmaker, but I'm working with people here that know what's going on and they were able to translate my insights into actual practical application. And it worked. Very, very interesting. Well, so many elements coming together in what you're doing. Thank you very much for joining us, Corey. You're very welcome. Corey Martin-Jewel, we really appreciate the discussion. Aloha. Aloha.