Alors, je me souviens de ce que j'ai étudiant sur l'uristique de Cohen-Lenzra. Donc, P est le prime-getter des trois, et on aimerait prouver ce que j'ai appelé C6 pour référer au travail original de Cohen-Lenzra, C10. Donc, ce sont toutes ces conjectures, ce qui devrait être vrai pour tout le prime-getter des trois, pour tout le K equals 1, 2, OK. Et, oui, D est un discriminant fondamental de l'équatétique. Cd est un groupe narroclas. Si vous confusez avec un groupe ordinaire, ce n'est pas un drame, parce que j'explique qu'ils sont souvent les mêmes. Et donc, nous espérons que c'est asymptotique pour NkP, OK, 1. Et ici, Nk plus 1 P minus NkP divided by P power K, OK. Donc, ce sont les conjectures. Et donc, ce n'est NkP. Ce n'est pas la version originale. C'est seulement une forme équivalente. NkP est la cardinale de la ligne de vector spécifique, la ligne de vector spécifique de l'Esprit Power K, de la dimension née. Donc, c'est quand vous avez le moment, j'explique à vous, comment nous pouvons obtenir la probabilité que l'Esprit Power K, l'Esprit Power P, soit equal à R, avec ce que nous appelons la théorie de la forme. OK. Donc, ce n'est pas tout. Donc, ce qui s'est passé dans l'histoire, c'est quelque chose de très, très important. Je pense que c'est l'influence de Gert. Donc, Gert a dit que quand l'Esprit Power K est plus grand que 3, ce n'est pas un problème d'essayer avec les deux rangs de la classe de groupes de Q de l'équivalent de D. Parce que par la théorie de Gauss, nous savons que c'est le nombre de prime divisor minus 1. Donc, l'idée de Gert dit, en fait, nous pouvons externer la théorie de Gauss-le-Saint-Huristique à P est equal à 2, mais au lieu de considérer que c'est D, vous considérez que c'est D squared. OK. Donc, qu'est-ce que cela veut dire? Cela veut dire que maintenant, je vais expliquer quelques commentaires. Donc, vous mettez ici P greater than 2, c'est D squared, et le même asymptotex. Pourquoi? Parce que c'est facile de voir que si P est plus ou moins que 2, 3, le P rank de CD squared est le P rank de CD. Et donc, qu'est-ce que les deux rangs de CD squared sont ce que l'on appelle le four rank. Le four rank. Et si vous write, donc, le four rank, si vous avez un groupe finitif, le four rank est la dimension de la dimension de la dimension de ce que je dis, si c'est additive 2a ou d'autre façon, si vous write ce groupe habélien comme le produit du tout primaire, produit de nu equals 1 à l'infinité, un produit de groupes de groupes avec la fréquence alpha p nu, puis le four rank est le exponent alpha 2 nu de nu equals 2 à l'infinité. Donc, je dirais une extension audacieuse, je dirais, donc on dirait, bien sûr, les deux rangs sont bloqués par un groupe mais on peut dire quelque chose sur le four rank et c'est, et il était correct. Ce que j'explique, donc, bien sûr, vous le réplacez, c'est ce que j'ai fait ici, vous l'avez maintenant pour A, P greater than 2 et vous avez en mind que P equals 2 est equal au four rank. Ok. Donc, ce qui était remarquable dans le travail de Gert c'est qu'il prouve quelque chose qui était réellement dans le POPOM. Donc, c'est positive. Donc, vous voyez, c6 correspond à d négative.  So, this is so when you have a c6 you have that so I write it only for a negative d and the function eta infinity is the product 1 minus t minus j or t power j and you from g equals 1 to infinity and you suppose that t is less than 1. You see this function that you met in Venkatesh lecture which has a strong link with partition function and so on and so on. So, in fact with Cluner's enemies some time ago we saw the Cohen-Lenzra conjecture in the case p equals 2 which means that the 4 wrongs, the disruption or the 4 wrongs now is known and exactly fits to the prediction of Cohen-Lenzra and what yes so what did Gerth prove? So, not only he had intuition of extended but he proved something which is very attractive so it's around I think maybe around this year so he proved Je dirais que c'est une étrange façon de combattre, vous comptez d, pour l'instant je l'écoute, pour négative d, pour la montagne négative d, comme le 4 rang de cd est equal à r et comme le nombre de prime divisor est equal à k, je compte dans le set, vous voyez, je bloque le nombre de prime divisor, pour l'instant je ne peux pas raconter le nombre de prime, donc maintenant il divise par la cardinale de d, ok ? c'est le nombre de prime divisor, et puis il bloque le nombre de prime divisor et puis le nombre de prime divisor je pense que c'est, et il fait le nombre de prime divisor, il y a de l'infinité, vous voyez, il ne compte, avant tout il mesure le nombre de prime divisor et puis il bloque le nombre de prime divisor et puis le nombre de prime divisor va à l'infinité, et ce qui est très encourageant, c'est qu'il a trouvé que ce limiter est exactement 2-r² à l'infinité de 2, le produit de 1-2-k². C'est la première fois que je pense qu'il y a de l'infinité de l'infinité de l'infinité de l'infinité, donc c'est plutôt de l'olde, et ce sont les matrices de redame, donc vous êtes très végélés, donc c'est le ronde. Donc vous considérez, je l'ai simplifié, donc je n'ai oublié de dire que c'est la même chose pour positive d. Vous avez écrit d equals p1 pt, et vous considérez la matrice m, qui a l'élément m e g, et m e g est equal à le le gendre symbole p e j. Alors, je ne vais pas dans les détails sur ce qui s'occupe de 2-2, donc pour vous donner très végélés, en parlant de ce qui s'occupe. Donc redame, par la théorie de les matrices redames, nous savons que le fort ronde de cd est, je ne sais pas si c'est t plus 1, t minus le ronde de les matrices redames. Ok, donc vous avez une grande matrice, qui n'est pas exactement symétrique, parce que, on peut dire que c'est un symbole de jacobi, non, pour le gendre symbole. Donc, oui, c'est très positif, vous voyez, on voit cette formule, mais on peut dire que c'est une étude étrange. C'est comme si, vous vous souvenez, Yvaniex, on parle d'H of D, vous avez une manière naturelle, qui est, selon le size de D, et puis vous pouvez compter, selon le length de la géodésie. Ici, il compte sur quelque chose, vous voyez, le size des matrices sont bloquées, et puis elles vont à l'infinité. Donc, oui, donc, ce que je veux vous dire, c'est que ceci est un théorème de moi-même et de Cluner, qui dit, en fait, que c6, c10 sont vrais, et la probabilité que le 4 rang de C of D est equal à R est coincé, exactement, vous êtes absolument right, oui. C'est coincé avec la prediction de Cohen-Lenz-Stra. Donc, vous pouvez dire que, dans mon cerveau, c'est impossible d'aller d'une manière naturelle, sur le théorème de Geur, pour une autre manière de compter. Donc, je vous donne un peu d'intes de la preuve, oui. Donc, en fait, je le rappelle, je dois concentrer sur la preuve de ces choses, c'est-à-dire un autre théorème, qui est la même chose que j'ai écrit. Donc, c'est-à-dire que je dois plus concentrer sur le négatif D, c'est équivalent. Il dépend de K et de K2. Et donc, vous allez X à l'infinité. Et je fais quelques commentaires. Donc, en fait, nous allons prouver que ces choses, minus ces choses, donc ces choses, vous voyez, j'ai dit oui, oui, oui, oui, ces choses sont autour d'une chose, comme quelque chose de constant C0X.  Donc, vous voyez, vous avez K equals 10, c'est très bien. Donc, votre terme est très petit. Et quelque chose qui est très surprise, si je l'ai écrit ici, vous ne serez pas surpris, mais dans la preuve, nous sommes surpris, que c'est vrai, c'est asymptotique, si vous ajoutez sur les deux côtés, excusez-moi, c'est la même chose pour le positif, mais bien sûr, vous réplacez ça par NK plus 1, 2 minus NK, 2 divided by 2 power K. Et donc, ce qui est très surprise, c'est pas ici, mais dans la preuve, que je peux... Donc, c'est D, oui. Donc, vous voyez, pour moi, il y a six types de discriminations fondamentales, le positif, le négatif, et puis, le power of 2, qui arrive. No power of 2, 2 to the power 2, or 2 to the power 3. You can go on to 0 mod 8. So, I say it's not surprising, but in the proof, it's surprising. For me, it's a miracle, I don't understand what happens when you are doing combinatorics. Yes. So, okay. So, now, what is the approach? So, you see, I must say that we invented the word because implicitly, all that I'm going to say during 10 minutes is implicitly in many papers like Reday, of course, all that guy, and we were... I would say we had chance to put that in the context of method that analytic number theory could say something. So, I'm going to make some algebraic number theory, which is absolutely not a revolution. So, I write, like, first of all, I write D on the form P1, Pt, and maybe here, if it is 2, you may have the exponent 1, 2 or 3, okay? And what I consider now is... So, I consider Pi, the prime ideal, which are... So, that means P1, Pi... Yes, like that. Okay, Pi, okay. And now, I consider the set of curly B, which is a set of P1, E1, Pt, Et, with E1 and all the EI, between 0 and 1, okay? So, first of all, something which is... it goes, it goes. That means that if you take CD, and you divide it by CD squared, so you consider this group, cushion group, each class, so I write each class of... as exactly two representatives in B, okay? And so, you see, how many... you have two power T divided by two, and you arrive at what I wrote somewhere about Gauss, somewhere... Yes, you see. It's another way to state that. So, now, I shall... so, something which are now classical. So, lemma. So, always D, fundamental. So, the first one is... the cardinality is that two power R of C of D is... no, is a cardinality of the square... square of classes, such that B4 is principal. I am counting elements. And now, something which is also classical is that... is equal to 1,5. The cardinality of B in curly B such that you can write this ideal as a product of an ideal and alpha belongs to the ring of integer and is an ideal of okay. So, here it's only to discuss to translate this phenomenon. And to state... so, this is absolutely not new. It's... So, I shall introduce a symbol which is something like a Hilbert symbol. So, you take A and B integer... not integer, rational number and you say that it is equal to 1 or 0 if... if the quadratic form x square minus a non trivial solution and 0, otherwise. So, what is... what is our detecting? So, you see, when we are here, we are happy we are certainly quote Legendre theorem in some minutes that will be the case. And so, for... our characterization is the following one. So, a proposition. So, I say it's... what we did is to put in an exploitable way. So, you see that... So, 2 to the power is equal to 1 half the cardinality of B B positive B square free B device D B this symbol B minus B prime is equal to 1 where B prime is square free square free and such that B D is equal to B prime C square for some... C greater or equal to 1. So, it's... it's very difficult to understand not very difficult yes. So, what about all this stuff? All this stuff is always due to this problem here. It's always due to the prime 2. I remember Cohen told me, but in that context you need that context. Remember 2 is not a prime, but 4 is a prime. It's exactly what I have in mind. So, you may... So, you don't understand what that means? No. Yes, you understand, of course. But you must have in mind if D is congruent to 1 mod 4 the B prime d negative so I shall give the proof for d negative and d congruent to 1 mod 4. In fact, the segment is equivalent to the following thing is equal to 1 half the cardinality of B such that B positive B divides D and the symbol B minus D over P is equal to 1. Yes. You take only the division. This stuff of C squared is only for the power of 2. So, yes. Now, how to prove that? So, yes. So, you must think that all first to have an idea that all the all the norm all the ideal which have norm B are in the set curly B. Ok? The 1 half come from I say this 1 half which is here and now you play so I... So, using that ok? So, the proof reduces to S squared is equal to alpha B what I wrote here if and only if B minus D over B is equal to 1. So, 2 directions can be done. I take only 1. So, I shall do in that direction you start from... you see you have a lot of easy relation because you are solving the definition where I put the symbol yes. You see you can multiply by your square interverge has a lot of evident obvious property and here when you do that in that sense so you know so you start from this is equal to 1. So, by easy transformation D B hence you know that the equation minus D y square minus B z square is solvable in Q that means that in fact solvable so that means that B is a norm in Q a square root of 2. So, by clearing denominators we know that there is this alpha such that alpha of okay such that norm of alpha is equal to this B W square so the norm and W belongs to Z okay after without yes and then you can you can suppose for NAP alpha P does not belong to okay you see by clearing denominators and then it's rather boring to explain and after you finish are using that all the yes use the fact that ideals with norm P square are either generated by P or the square of an ideal of norm P so it's rather I would say not boring but you have it rather and you arrive so I suppose that yes you arrive at this equality here and you see the fact is that B when with this B all the representatives are in curly B in the opposite direction so another one if you want to do the other direction so you suppose that A square is equal to alpha B so with the property I said so that means that norm of alpha is equal to B norm of this is ideal divided by B square so that means that so the norm we know how norm of an element so x square minus dy square minus 1 over B z square is solvable and so you have 1 equals dB dB prime so so it's rather classical algebraic number theory so I insist about that fact we did not invented we did not invent the word but we were lucky to push in the direction of quadratic form and now a very easy consequence of that so boom so I like this statement because so you see the fact of this B prime I wrote somewhere spoil the exposition you see the square it's always to do with power of 2 so let us concentrate for d negative d congruent to 1 mod 4 so you see what happened I say I am counting the B square 3 which are device D and B prime here is inverse so what does that mean that means that that means that the equation minus B plus d over B solvable so here we know a criterion we do not speak of as a principle local global is ok we refer to Lejean and Lejean says that this thing is solvable if and only if so you check the sign and you see the local position so that means here this thing has to be a square modulo this thing and this thing has to be a square cool so with this criteria so yes so d fundamental discriminant so what we have is a 2 c of d is equal to 1 half cardinality so of you write ok and you excuse me I can't remember if it is so you write ah yes ok yes it's correct because d is negative yes you write it and r is a square modulo B and B a square modulo r so you say so I use le genre ok to pass this and you have a very you see and we are lucky to find this which was which is not written explicitly et so I told you types type of fundamental discriminant and this one this expression is the most simplest one for instance suppose that d is positive and d congruent to 0 mod 8 so we have so we have this formula so we will have problem with the number 8 so cardinality so you write d on the form d equals 8ab so you write you ask to minus to a to be a square modulo B and B a square modulo r plus 1 half cardinality so you write the same thing minus a a square mod B and to be and to end and to be a square modulo r ok so you see it's what I said to you for me it's a not a miracle but a very surprise our proof we have the same formula when you insert other condition when you write them the condition and you see with such a mess all the coefficient will match together the symbol 2 over P at the end it exactly matches to coin and let's draw guest so now we go more to what is this yes so now so I will concentrate for d negative d congruent to 1 mod 4 and so it's very easy now we see you are happy with this thing because we see that the legend symbol jacobi will arrive we guess that we will use consolation about character sum and so on what we call in France le grand jeu so what did I write yes so yes ok yes ok so we write it so I use this az criteria r is a square modulo b and I suppose that a is b you detect this by this formula which is product so you p divides b yes 1 plus a over p so I suppose to be correct that b is positive b odd to be more square free for instance to be this thing is equal to 1 otherwise it is equal to 0 ok so yes ok so I always see this thing if a is a square modulo p so did I write I must to be sure not to have problem a b is equal to 1 so you see when you factorize fundamental discriminant particularly if it is odd you are sure to have a co-prime component because it is square free so yes yes ok so ok so so now I continue the analysis and I concentrate always for this case ok and what I want to say is that with this we will have this exact formula so we have the one half 2 power omega of d and then we have the product minus d equals a b and here you the sum p divides b 1 plus a over p and here I the product p divides a so you see you have this decomposition now minus d is positive problem and so it is a square free so you develop and you use a jacobi symbol and it's rather simple that you are it's 2 omega of d so I should put absolute value yes and you write multiplied by so you see you you expand this product and you glue you will meet at the denominator any divisor of b any divisor of a you put that together and you obtain that it is something like d equals a1 a2 b1 b2 so you will have a1 a2 divided by b1 b1b2 divided by a1 so you see this a1 will be a divisor of a and so on the complementary a2 and so of course you write it like sum over d so I should have rather put minus minus d yes and so you factorize it at a2b1 b2 a1 a1 over b1 b1 over a1 so you may see yes you know that it is a reciprocity law but we don't use it for the moment we don't use it and I write only the fundamental first equality which is that after some some work which is that so the moment of order 1 moment of order 1 which is the sum of 2 power rkc of d so I take minus d less than x and I add d congruent to 1 mod 4 is equal to 1 1 half so we will have a triple sum so such that a1, a2, b1 b2 is less than x so a fundamental discriminant ok and here you put a2 over b1 so b2 over a1 a1 over b1 b1 over a1 and here I must not forget the coefficient which is 1 over 2 omega of a1, a2, b1, b2 ok so you see it's only split minus d in 4 components and then follow the equality the equality it's nothing deep what is crucial is corollary we have the philosophy the following philosophy jacobi symbol m over n always oscillates unless unless m equals 1 or n equals 1 so you may be shocked but when it is a square it does not oscillate yes I know but square it's not frequent in the topic I am doing so what happens here so we see I want to guess what is the main term what is the main term the main term I say you are detecting when this product of forcing does not oscillate so you take a1 equals 1 a2 equals 1 so it gives the first one a1 equals 1 a2 is equal to 1 I found the second one which is a1 is equal to 1 b1 is equal to 1 b1 equals to 1 so these one are very easy to guess so 3 main terms another one is more delicate to see it corresponds to a2 equals 1 and b2 equals 1 so in that case a2 equals 1 b2 equals 1 so you recognize you have only this symbol but this symbol it's the numerator and numerator different from 1 but however it is it does not oscillate because what do we know we know that we have minus d a1 a2 b1 b2 is congruent to 1 mod 4 so a2 equals 1 b2 equals 1 so that means that a1 b1 is congruent to 3 mod 4 and this and this symbol is equal to 1 because the product is congruent to 3 mod 4 so in that case this symbol is equal to 1 so we have 4 we see 4 main terms only with my philosophy ok and now what to do with this main term this main term we do like that so for instance you see a1 a2 so you block this thing does not oscillate so sum of 1 2 omega of a b some congruences and here you have 2 power omega a b ok so you do that you have 4 main terms and it's an exercise to see you have now you check what happens you obtain the main term is asymptotic 4 over 2 asymptotique to 4 over 2 the sum over minus d less than x d congruence to 1 mod 4 of 1 and what is 4 over 2 it is 2 ok and I think it is the number of all the yes all the vector spaces in f2 so they are 0 and f2 alone so you see it's very simple and we think that no I am cheating a little because what about the other term so there are 2 difficulties now I want to present is how to raise to any power so we cross difficulties that is Brown had already when he when he computed the size of the 2-cell mer group of an elliptic curve which has a congruent problem and if you see you see his papers there are 2 papers of him the first one in invention where he makes the first moment several time pass and then he makes all the all the exponent so you see so we have an exact formula and yes and now what about so I have to raise this formula which is here raise this formula 2 power k so it's a nightmare you can you see you have 4, you take the square you have 16 ok and then what we use and we follow this idea is to use f2 f2 square to code the decomposition that means that instead of a1 so you write d so minus d d00 d01 d01 and you consider this this thing belonging to f2 square et now you are ready to go to the case power however it's not easy absolutely not so you will see that the sum c of d will be something like I am very vague voluntarily so you take indices f2 power 2k and then v 2k here you put du over dv which is a symbol of jacobi symbol here you put vq of uv and then so d less than x blah blah blah du du du du product dv less than x et là vous voyez ce qui ne arrive pas lorsque vous터 place du course k pour ce moment à1 à2 neoon à1 et puis la série ckv ckv c'est une forme quadratique, non, c'est u1 plus v1, u1 plus v2 plus u2k plus minus 1 plus v2k minus 1. Yes, it's something like that, plus plus v2k. So, what is important, it's a quadratic. You see, either it's in modular, with value in F2. So, if the exponent is equal to 0, you say, this rich Jacobi symbol does not appear. If the exponent is equal to 1, you say it appears. And this way of coding, you see, you are sure that if you, when I write that, yes. So, you can say that if you consider that is equal to 1, if and only if only one of the symbols du over dv or dv over du appears. Ok, so we have an excellent way of coding via F2. And what happens, I spoke to you of vector spaces. So, I would say how do they appear, the total number. So, when you have this, I write it. The vector subspaces appear when studying orthogonality. Orthogonality for this 4 phi k. So, I was quite happy. It's a nightmare for me to study quadratic form over F2. You know why. And so, we have a quadratic form. There is some orthogonality. And then, these vector spaces appear. So, now, yes.  And then, you see, it's for me, it's a mess. You see, you compute, it's a mess. And then, at the end, it just appears. What Quentin and Stray guessed. And particularly, when you enter, you see, you have six types of discriminants. Suppose, I put here a minus a somewhere. What would be the effect at the end? It has no effect. Everything is ok. So, now, what about, yes, so I wrote to see combinatorics. I would say F2. So, I would like to make two remarks. You see, now, when you are doing computational number theory, people want to check by using a computer. Suppose x to x equals 10 power 10. You compute what the restics are, what you obtain. Here, it's really a catastrophe. Because let's, let's think that you want to compute the second moment. You see, so, for instance, something like that, ok? So, you go to my interpretation. You see, when I take the first moment, I have already four variables. So, here, there will be, when you expand, 16 variables. Which are of the types, see? D00001. So, you have a product of these Jacobi symbols. And so, when you want to have oscillation, you want to be sure that the D has non-trivial decomposition. So, that means that D, at least, 16 prime divisor. Ok, so, you see what is an integer which has at least 16 prime divisor. It's rather large. And if you want a lot, that means that, on average, that you know that omega of n is something like log log n. So, for instance, if you want to see oscillation of this sum, you have to work with x, which are of the types, e to power e to the power 16. So, you see, nothing, nothing. And this phenomenon is round-quoted also in his Selmer paper. Ok? So, the combinatorics can be done. So, now, what about analytic tools for themselves? They are rather, I would say, classical. But I put them here. So, two main tools. I say how. So, the first one is, I would say, coming from a L function theory. So, that means around, I would say, Ziegel-Valfisch type. You see what we call Ziegel-Valfisch is some oscillation theorem, for instance, about n over d, d is fixed. And then, here, what we have, it's not like that, it's something like sum over m, m over d. And what is d? In our context, d will be something, which will be, I count n, m less than x, d will be something like log x to the power a. And you see this function, 2 over 1 over 2 Mfm, is as difficult, in some point of view, that the divisor function. So, to do that, you have several techniques combinatorics, but you have, for instance, take the square root of this function and taking the square root, that means that you have to control the zero-free region. So, it's not, this thing is not trivial at all, first ingredients, so that means that our result is ineffective. And the second one is what I call double oscillation, double oscillation theorem. So, this double oscillation theorem, so I give you an example, I think it's well known. I think the oldest one is due to Isle-Bron, and, for instance, Utila proved that the stronger one is due to Isle-Bron, which famous paper, Attac-Taritmetica, that he calls that launch of inequality for a quadratic character. So, it's very simple. So, you take this double sum. So, you take alpha m beta n. And to be sure, I write this to be sure that they are odd, square-free, and I sum m around capital M and around capital N. Yes. And I multiply by the Jacobi symbol m over n. So, what do we know, is that we have the feeling that m over n does not factorize as a product of two functions. So, it's proved in this way. So, if I suppose that alpha m is less than 1, beta n is equal to 1. This thing is less than mn, which is the trivial bound. And then, you can gain that, provided that m and n are greater than log of mn power a. So, this result is rather easy to prove. It's only using, you use Cauchy-Schwarz, of course, as usual. You interpret summation, and either you use Polyavinogradoff or you use the fact that a character, when you sum it over, all the period is zero. So, this theorem as... So, this is the first one, the second one and the second one as absolutely not the strength of this one. Ok, c'est fini. Yes. Bon. So, thank you. I have a question. What is the source of the small error term? Excuse me, what is it? The source of the small error term. Yeah. Why you... You say the small power of log? Yes. How can I say that? So, the variables are so... It's come from here. Yes, it's come from here. The logarit, the tiny power, it's come from... And they're so... How can I say that? The room of variation of variable is very small. But it's very... So, genetic tools are very classical simple, but to arrive at that, to say, you see we take a season of... and you cut some spaces and then it oscillates and the... you know, it's... So, you mean the decomposition of... So, when you decompose the sum... Yes, you are... Yes, you are square, you have to take care of many things. I can't explain in one second why the error term is so small, I would say. But it's not a multiple application of question cards. No, no, no, no. Only one, only one. No, no, no, no. Yes, the 2 power k is like, you see, it's like the f2 power 2k. This is the same, it has to do with this 2k. I can't take me a quarter of an hour to explain. So, you see, we have to deal when... So, you see the m and the n will be some part of the... of this... DU, DV, such that. And either you take that or this that without, of course, you must keep the main term.


mental and cardiovascular health interact in complex ways. Here, the authors demonstrate an association of blood pressure with depressive symptoms, well-being, and emotion-related brain activity that may be relevant to the development of hypertension. This article was authored by H. Lena Shah, Maria Blockl, D. Nys-Kumril, and others.


Leslie is just an amazing teammate. She's an amazing student athlete, does such a great job in the classroom, on and off the floor, and she's going to be missed tremendously. It's really awesome. I just had a great coach here to really prepare me for that and it's just a really great feeling. I've had great teammates, so I'm really excited to put you back. I know some of the girls there on the team and they're pretty good last year. They made it to the final four, so I'm just pretty excited.


The next item of business is portfolio question time and constitution, external affairs and culture. At question number one, I call Annabelle Ewing. To ask the Scottish Government what recent discussions it has had with Historic Environment Scotland about the reopening of assets in the Caledon Beath constituency. Minister Neil Gray. I have regular discussions with Historic Environment Scotland about the health and safety challenges of Scotland's properties in care. As regards to the Caledon Beath constituency, I understand that the main castle area of Aberdour Castle remain fenced until a tactile inspection has been completed. However, Historic Environment Scotland is aiming to have some areas of the site reopened to the public as soon as possible. Historic Environment Scotland would be more than happy to offer Annabelle Ewing a site visit to learn first hand from the experts about the situation there. Annabelle Ewing. I thank the minister for his helpful answer. In fact, it is not just parts of Aberdour Castle that are close to the public and have been so since the outset of the pandemic, but also Ingecom Abbey and St Bridges Kirk in Duggetty Bay. Obviously, that is impacting negatively on the local economy. While I would take up an opportunity to meet with Historic Environment Scotland, I would ask the minister to use his good offices to ensure that all three sites are opened as soon as possible and to provide a bit of clarity perhaps as to what as soon as possible might mean. Minister. I thank Annabelle Ewing for her question and for the way that she is advocating quite rightly and I would expect nothing less from her on behalf of her constituents and her constituency. I recognise the impact of access restrictions at historic sites on local businesses and communities as Annabelle Ewing has rightly outlined. I share absolutely the frustrations of members and our constituents regarding continued closures. As I am sure we all accept, the safety of visitors and his staff must take priority. I will pass the member's specific concerns to Historic Environment Scotland, including about community engagement. His is working hard to prioritise the most effective sites in the inspection schedule and to keep public access open where it is safe to do so. I am pleased to see that some sites have now partially opened such as Dooncastle this week, but I recognise that there is further to go in the member's constituency. I thank Annabelle Ewing again for her point. I thank the Scottish Government for providing an update on the work of its overseas officers. Scotland's international network creates domestic opportunities, attracts investment and ultimately benefits the people of Scotland. I am pleased to see the cross-party enthusiasm on the excellent job that Scotland's international officers do on a day-to-day basis within the Constitution, Europe and External Affairs and Culture Committee's recent report on the Scottish Government's international work. Building on my response to the committee's report on 6 June, I will be following up with the committee in the coming weeks in greater detail on the work that our international officers are currently doing and what they will be focused on in the months ahead. I recognise that the Scottish Government's overseas officers perform a function in seeking to promote Scottish businesses and culture abroad. The fact is that the SNP Government appeared to be misusing that resource in order to pursue a distinct foreign policy from the rest of the UK and to discuss independence with foreign governments all at taxpayer's expense. Can the minister confirm whether he has met foreign governments to discuss independence and, if so, on how many occasions? First, I think that he would benefit from visiting some of the officers. I do not know if he has been to any or if he has spoken to any of the staff in the offices, if he has satisfied himself about what they have been doing. They are highly professional representatives of Scotland. They benefit the economy of Scotland. They benefit in terms of inward investment. They promote the culture of Scotland. They promote Scotland's relations with the rest of the world. I think that they do a tremendous job. If I, as Cabinet Secretary or other ministers of the Scottish Government, hold conversations with others, of course we discuss the policy of the Government. That is what we have been elected to do, but please do not seek to undermine the professionalism and the effectiveness of Scottish Government offices around the world. It really is not worthy. Paul MacLennan. Thank you, Presiding Officer. The latest MSN Young Scotland Attractiveness Survey showed Scotland leading the way in the UK when it comes to securing foreign direct investment in spite of the significant challenges posed by Brexit and the pandemic. Given the findings of the report, can the cabinet secretary provide any further information about the work that the officers are on their taking to attract investment to Scotland? I thank my colleague for the sensible question. The EY results are fantastic for Scotland and they underline the strength of our inward investment offer with the growth in Scotland's FDI performance outpacing Europe and the rest of the UK. Scotland has maintained its position as the UK's most attractive FDI location outside London for nine of the last 11 years and for the seventh year running. The Scottish Government and its delivery partners, SDI and SE, will continue to focus support on attracting the high-quality inward investment that is required to deliver our ambitions in areas such as energy transition, focusing on Scotland's wind and hydrogen space, decarbonisation of transport and Scotland's international network is vital in supporting this work. The Scottish Government will continue to promote and showcase our world-leading capabilities on the international stage at events such as Dubai Expo, COP26 and the World Forum for FDI. To ask the Scottish Government whether it will provide an update on Scotland's census 2022. Following the end of the census collect period, national records of Scotland are now focused on planned post-collection quality control and assurance work, which includes the census coverage survey, the second largest social research exercise in Scotland after the census itself. NRS is confident that the national return rate and coverage across the country, coupled with the aforementioned post-collection quality control and assurance work, will provide a credible high-quality census output. NRS is working with a number of statisticians and global experts in census and administrative data to help to steer the statistical and methodological work of NRS over the next few months. Russell Finlay. I want to begin by sincerely thanking the cabinet secretary, who is a very important MSP indeed for providing a humble member like myself with that answer, so thank you. Trains, ferries, rangers' prosecutions, trams, prespic, bi-fab, NHS disasters, policing scandals and now the SNP's shambolic census. Hard-working Scots always end up footing the bill for the SNP's world-beating incompetence. Can the cabinet secretary tell them whether he or anyone else will pay the price for this £30 million census debacle? Forgive me. I'm not sure what number the member was talking to there in the speech, but the increase in census costs to raise the return rate from the 70s to 88 per cent constituted 4 per cent of the budget for this census round. Frankly, that is, relatively speaking, an affordable and reasonable rate of return to raise the census return rate to provide a solid foundation, which is what the experts have described it as. Given that all public services rely on a census and a return rate that provides such a solid foundation, we should all take the opportunity to thank the 2.3 million households that took part in the census and the great many people who worked, including the hundreds over 1,000 people who worked as enumerators, particularly in the past month to ensure that we have secured the solid foundation, which independent international experts have described it as being. Will some of the rhetoric in this chamber draw attention away from the fact that it is, as you mentioned, important to acknowledge that 2.3 million households did return the census, an enormous proportion of the population, and the data collected in this immense exercise will deliver very real and tangible advances in the delivery of local public services. Can the cabinet secretary put on record some examples of how census data directly translates into inclusive service planning for Scotland's communities? It remains the best way to gather vital information on which Government councils the NHS and a range of users in the public, private and third sectors need. The results help local authorities, businesses and Government plan a wide range of vital public services to improve the lives of those living and working in Scotland. The information that has been collected from the census helps us to understand who stays in Scotland, who they stay with, what sort of accommodation they stay in. This allows decisions to be made about where money is spent in local communities on things like schools where our children are educated, roads that we drive on every day and healthcare that we rely on. The census is a very important piece of work, and I'm delighted that it has reached the return rate that it has given the challenges through the census collect period. 4. Willie Rennie To ask the Scottish Government what its policy is for the currency of an independent Scotland. Scotland will continue to use the pound sterling at the point of independence, establishing an independent Scottish currency as soon as is practically possible through the most careful, managed and responsible transition when an independent Scottish parliament chooses to do so. Willie Rennie I'm honoured that the minister has felt able to answer my question. In 2014 the policy of the SNP was a monetary union. Now Ian Blackford wants sterlingisation. The SNP conference rejected the leadership position describing it as a dangerous experiment. Coalition partner Lorna Slater said that it would be catastrophic. Patrick Harvie said that it would prevent Scotland from joining the EU. Alex Salmond wants a Scottish pound, Alan Smith wants the euro. The independence movement is like two ball bankers fighting over a 50-pence piece. If they can't agree on the currency, why on earth should the public? There's literally no answer that I could give to Willie Rennie that would satisfy him. We are on different sides of the independence debate. If we can't agree on that, at least it would be nice for us to be able to agree as Democrats that this is an issue that the people should be able to decide on. Question 5, Bill Kidd. To ask the Scottish Government what its position is regarding the potential impact on Scotland on the upcoming first meeting of states parties to the UN Treaty on the Prohibition of Nuclear Weapons in Vienna. The Scottish Government is on record supporting the principles of the Treaty on the Prohibition of Nuclear Weapons and of welcomed countries, including Ireland, ratifying the treaty. However, Scotland will not be able to share our views and support like-minded partners at this first meeting of the state parties to the treaty in Vienna later this month, which is due to be opened by the UN Secretary General. Scotland is not a sovereign independent country yet. UK opposition to the treaty means that they have chosen not to attend as observers only with independence can Scotland's interests be properly represented on the international stage. Bill Kidd. I thank the cabinet secretary for his answer. Now, it's long established that an independent Scotland will be free of nuclear weapons on the basis that these indiscriminate weapons of mass destruction and mass murder are morally important and should no circumstances be used. Despite the treaty on the prohibition of nuclear weapons making the use and stockpiling of those weapons illegal, as mentioned by the cabinet secretary, the UK Government is not engaging in this first meeting of states parties in Vienna at the UN next week. I'll be attending as part of UK ICANN's parliamentarians for the TPNW delegation, ensuring that a Scottish voice is heard and positioned on this consequential matter and can be heard. Can the minister, cabinet secretary, advise in the case of an independent Scotland how quickly this country will join the TPNW? Cabinet secretary. Thank you, Presiding Officer. I share my colleagues' disappointment that the UK Government is not engaging with this important process. I understand that a number of countries that are not parties to the treaty, including NATO member states, will be attending as observers. I welcome this commitment to multilateralism and a willingness to engage on these crucial issues. I'm also glad to hear that the member will join a delegation of parliamentarians in Vienna. As the First Minister and I have said this week, the Scottish Government will be publishing further papers setting out the prospectus for independence, and that will include our position on treaties. Question 6. Christine Grahame. Thank you very much, Deputy Presiding Officer. To ask the Scottish Government what contribution local culture evidenced in museums such as the Tramontium Museum in Melrose and the National Mining Museum Scotland in Newton Grades, makes to the local and wider Scottish economy. Minister Neil Gray. Thank you, Presiding Officer. The Tramontium Museum and National Mining Museum are fine examples of how this cultural sector can contribute to both the local and the wider economy. I recently attended the official opening of the Refurbish Tramontium Museum and viewed their fine collection of items from the Roman and Iron Age and was able to thank the trustees for their incredible work at the museum. I look forward to visiting the National Mining Museum, which is home to around 95,000 items of national significance, attracting 48,000 visitors each year and generating 1.3 million to the local economy. The Scottish Government continues to provide core funding to museums and galleries Scotland, which supports 430 museums and galleries across Scotland. Christine Grahame. I thank the minister for his reply. Minister, very small communities such as in Tweedsmure, high in the border sills can make a huge difference to the regeneration of their communities. Is the minister aware of the regeneration of the crook inn, closed in 2006 after more than 400 years of continuous operation, which is being done in phases? The first being the wee crook, a licensed bistro, which will certainly boost that local economy. Will he accept an invitation from me to see the project for himself? Not necessarily to go to the licensed bit, but just to visit the project. Minister. I've never spared the fun with Christine Grahame. I think it was a previous question that I actually took the invitation from Christine to go to Trimontheum, and I was very grateful to accept her hospitality and to be able to go along to the reopening with her on that special occasion. I agree that historic properties such as the crook inn in Tweedsmure are really important to local heritage and a community sense of place. If Christine Grahame would like to write to me with the further details, I'd be more than happy to consider that very generous invitation that she's made. I look forward to learning more about the restoration of this historic building and the tremendous work undertaken by local community. Sharon Dowie. Thank you, Presiding Officer. Christine Grahame makes a good point, but all too often culture spending is the first thing that gets cut by councils when funds are tight. For example, in Midlodau, in Christine Grahame's own area, the SNP Council have museum and galleries funding from 83,000 a year in 2016-17 to 10,000 in 2020-21. It's the same story in other SNP councils such as East Ayrshire or Glasgow. How does the minister expect our culture sector to grow locally when SNP councils are slashing culture spending across Scotland? With reference to the Trimontheum Museum in Melrose and the National Mining Museum in Newton Grange, I have regular conversations with local authority culture conveners. I'm hoping to be able to see them again once they're reappointed in order that I can make sure that we have a partnership approach to ensuring that our culture offering is strong and ensure that we are able to work together to ensure that our shared priorities around ensuring that people are able to enjoy our cultural facilities for both the community and the economic wellbeing, but also our own personal wellbeing as we recover from the pandemic. To ask the Scottish Government what priority it attaches to developing relationships with other European countries. I thank Liam McArthur for the question. The Scottish Government attaches a high priority to developing relationships with other European countries, which is why we want to rejoin the European Union. That is only possible by Scotland becoming an independent country. Our recently published Global Affairs Framework sets out the values and principles underpinning the Scottish Government's international work and the basis on which the Scottish Government will prioritise its European and wider international activity. Scottish Government will continue to take a positive and proactive role in engaging with European partners on shared challenges and opportunities, where Scotland is well placed to offer expertise and share best practice. I thank the cabinet secretary. The Erasmus programme is a fantastic initiative, which allowed us to forge relationships with our European friends and open the world for Scottish universities and Scottish students. It was a needless casualty of Brexit. However, the Welsh Government has already committed £65 million to their scheme with young people from Wales preparing to go abroad from September. Assuming that he believes that I have a sufficient electoral mandate, can I ask the cabinet secretary to confirm if the Scottish scheme will be up and running for the next academic year, or will thousands of young Scots continue to miss out on the opportunities of a lifetime? I thank Liam McArthur for that follow-up. As I have indicated in answers to his colleague from North East Fife, the loss of the Erasmus programme is indeed a tragedy. Its replacement is something that has been a matter of discussion between the Scottish Government and the commission, and we will continue to make progress in that, because I hope that we are all agreed that we need to do everything that we can do to ensure that young people from Scotland and other young people from the European continent are able to continue in the educational exchange that existed while we were part of the European Union. Perhaps it might give him cause to consider that the best future for Scotland is to re-establish all of the established programmes with the European Union. The only way of doing that is by rejoining the European Union. I would be delighted to welcome him as part of that campaign. Thank you, Presiding Officer. One of the best ways to develop relationship with their European countries is through educational ties. When my colleagues have recently asked the Scottish Government about delays to replacement for Erasmus, we have been told that the plan for Scotland to instead rejoin the EU. But while the Scottish Government waits for this theoretical solution, thousands of very real students are missing out on educational opportunities in Europe. They are limiting the opportunities of a generation in their gumball on a future EU membership that they cannot guarantee. Why can the Scottish Government not follow the example of the Welsh Labour Government and bring forward a replacement for Erasmus now? Cabinet Secretary. I think that it was only this week that we had confirmation from the British Labour Party that they were not going to seek the membership of the European Union for the United Kingdom. I think that that disappoints a great many and perhaps even some on Faisal Troudry's own benches, perhaps even himself. I already gave an answer to his Liberal Democrat colleague behind in relation to the Erasmus scheme in particular. He talks about Scotland rejoining the European Union and theoretical opportunities. This is not a theoretical opportunity. If one is a member state of the European Union, one can, with great ease, play a full part in the Erasmus programme. Perhaps he is one of those on the Labour benches that actually represents the 30 per cent of Labour voters that are in favour of Scottish independence and he can join us in the campaign when the referendum is under way. Question 8, Alex Cole-Hamilton. To ask the Scottish Government whether it has now published all of the legal advice that it has received in relation to a second independence referendum. Thank you, Presiding Officer. We have released the legal advice required under commissioner's decision as it does not merit the time and expense required for an appeal. Although we disagree with the decision, we have published precisely what the commissioner specified and in line with the ministerial code. I do not intend to comment on the content of other legal advice. Alex Cole-Hamilton. I am grateful for that reply. The information commissioner's ruling about this could not have been clearer. In it, he states that a second independence referendum in Scotland is of significant public interest for a substantial portion of the Scottish population. He goes on that the request to release it should be considered one of the exceptional circumstances that outweith the inbuilt public interest in maintaining the exemption on confidentiality. Presiding Officer, he was not talking about the legal advice as to whether the Government could road test a question with the Electoral Commission. He was talking about the central legality around the propositions open to the Scottish Government in pursuing its objective of holding an independence referendum next year. Does the Cabinet Secretary realise that, by withholding that central legality and that legal advice, he is holding not only the information commissioner in contempt but in this Parliament in contempt as well? Thank you, Presiding Officers. I have already made clear that, in line with the ministerial code, I do not intend to comment on the content of other legal advice. This is a position incidentally that has been held by Liberal Democrat ministers in this Parliament and by Liberal Democrat ministers at Westminster. I have no plans to depart from that position today.


Being an out-of-state student especially from Atlanta, I'm only three hours away from home So wasn't too far, but also wasn't too close leaving the comfort of you know Georgia crossing the state line and being only three hours away Provides you with a level of comfort where you can go back home and see your parents if you want to But also when you come to campus you have a community of people coming really from all across Atlanta So if I ever need to get back home or someone to carpool with me back home I always know that we have a little Alabama in Atlanta support network That's there to support me but then also that I could go back home and see all my friends But then also invite them to come and visit with me in Alabama because it's only three hours away


I'm Tracy Bible Rawlerson. I'm an Account Executive for Energy and Environmental Solutions for Siemens Industry, Infrastructure and Cities, and I'm a proud Navy veteran. What made me choose the Navy was I was, I had a daughter at 17 years old. I was still in high school, an additional child at 19 years old, and I wanted to, I had made a few mistakes in my life and I wanted to make a difference. So in order for me to make a difference, I knew the Navy was the right opportunity to change my life along with my children's lives. The first time I ever flew on an airplane was when I went to boot camp. Needless to say, that was an experience on itself coming from a small town in East Tennessee. I was terrified when I got there, didn't know what to expect, but it was, it was good for me. The best time I ever had in the Navy was joining BP-30 and the camaraderie that we had in our shop. When we would load weapons, of course, everyone's dependent upon the other to make sure that we did the proper job. And I had never had friends like that before. In the Navy, I would, in boot camp, everyone questions, right? The necessity for the extreme attention to detail, but once I got out in the field, you know, loading bombs, working with pilots on how to use, you know, the weapon systems, you know, on the P3 aircraft, and just the necessity of being extremely cautious, and again, then attention to detail on the points and everything that we did. The Navy made me assist in being more confident, absolutely it did. I had made several mistakes, and the Navy gave me the ability to realize that I could do anything with my life that I wanted to. The confidence that the Navy instilled in me, I pushed that onto my children today and teach them that no matter what, you can do anything you set your mind to. But at the end of the day, you get to be proud to serve your country, the best country in the entire world. Why would you not take pride in that?


The 7 Star Terraried Event for Delphox is now live in Pokemon Scarlet and Violet. We're going to go over all the details in today's video as well as the best Pokemon to solo this with in your game. So starting off hopping over to Ceribi to take a look at all the details for this Terraried Event. It is going to be the Delphox 7 Star Terraried. It is going to have that very terror typing will be level 100. And the first phase of this Terraried Event will be running from today as of recording this video on the 7th of July. I'm running over this weekend until the 9th. Just bear in mind if you don't go back online after the 9th of July, you'll keep this event in your game until the next time you do go online and then it will disappear after the 9th. But if it does go away through next week, then it will be returned for a second phase on the 14th of July until the 16th. So you'll have another chance to take part in this event once it returns. And it is only catchable once per save file. Just bear that in mind like all other 7 Star Terrarieds and it has got its hidden Ability Magician. But bear in mind, unlike a preview article where we thought Magician would play a big role in these Terrarieds, it does not work like it should so won't steal any of your items. So you're pretty much safe knowing that your Shell Bell or any of your boosting items that you're taking into the raid won't be stolen by the Delphox throughout. Now it's moveset it has got is Fire Blast, Psychic, Dazzling Gleam, Willow Asp, additional moves of Dazzling Gleam, Magic Room and Nasty Plot. So good coverage with Fire, Psychic and Fairy. It has got disruption with Willow Asp as well. Dazzling Gleam is the big fairy type and attack move that is going to take advantage of of course and it has got access to Magic Room. So for those of you that don't know Magic Room when it is used, it nullifies the effects of all items held items for 5 turns. So if you've got a Shell Bell, you're not going to be getting any recovery for 5 turns. If you've got a life form, you're not going to be getting any boosts to your moves for 5 turns until that effect wears off. All that has Nasty Plot as well, so it can boost its own stats. So that is something just to bear in mind. But that is its moveset and we were pretty close in our preview article with what we expected it to kind of run going into this raid. Now for the item drops as always with the 7 star Terrarieds, it's going to have a flurry of good items that are going to be useful for you in your games. Large Candies, XL Candies, Calciums, lots of Fairy Terror Shards, TM41 Ability Patches as well. And you can also get Ability Capsules, Bottle Caps, PP Ups, Timid Mint and then a lot of other high cost items. So a really good raid event if you have caught it to go back into it and just farm it for these items that are going to make it easy to stock up on with this particular event. But that is the Dull Fox, it will be running Phase 1 from the 7th to the 9th of July and then returning on the 14th to the 16th for its second time out. And to access this event in your game, you're going to need to come down to your Poker Portal and once you're here make sure you are connected online. And then come down to your Mystery Gifts and then into Check Poker Portal News. This will just update all of the Terrarieds in your area. And once you have done the update, you can come onto your map and you will be able to locate the Terraried then. It will look like a six-star Terraried, but it will have the Fairy Typing. So you want to just mark it on your map and head over to it. And the builds that we'll be featuring in today's video are going to be builds that we actually featured in our preview article. They're going to be the best options I feel currently as of recording this video to go in and solo this Dull Fox raid pretty consistently in Serral Edge, which probably has the edge over Armor Rouge, but both do a very good job. So kind of covering both games as well if you haven't got access to one of them because they are version exclusives. So for the Serral Edge, we have the Fire and Ghost Typing. We have the Steel Terra Typing on this that is really important with the Shell Bell item. It is set to level 100 and it has an EV spread of 252 HP, 252 Attack. You can change that Attack to 252 Special Defense if you want to take moves a bit better, but I don't feel like you need it going into this raid with an adamant nature. We've got that Flash Fire ability, which is the most important thing on here. And then a move set of Sword Stance, Clear Smog, Iron Head and Bitter Blade. And that is the Serral Edge. So very solid build going into this raid. And then we've got the Armor Rouge as well. It's not going to have a super effective attack, but it is going to be strong enough. It's going to be able to resist all of the big attacks coming out from the Delphox, set up on it and do some big damage in return. Fire and Psychic Typing. It has got the Terra Type of Psychic, level 100 again with the Shell Bell item with the move set of Psychic Terrain, Acid Spray, Calm Mind and Expanding Force. Flash Fire is the ability again and then the EV spread on this one is 252 Special Attack and 252 Special Defense with a modest nature. Both builds that we're featuring in today's video will be linked down in the description if you want to take a closer look at those. But the Armor Rouge, the basic idea is to go into the raid. You're going to see the Delphox go for Turn Zero, Dazzling Gleam. After that, go for two Calm Minds. Don't get too greedy here because there is reasoning behind this. Two Calm Minds to the start of the battle.  Now, after that, the Delphox will likely nullify all of the stat drops on its side of the field, so you'll have to go for those Acid Sprays again and go for three of those again and then start firing those Expanding Forces off. It won't really negate any boosts on your side of the field until very, very late on in the battle. But you should be able to set up a few more Calm Minds later on in the battle if you need to and Omru is going to be able to kind of deal with it quite easily. But for the Cerrel Edge, we'll go into the raid now and I'll show you exactly what you need to do to take on this Delphox and make it super easy for you to do in your game. So turn zero when we come into the raid. You're going to see the Delphox go straight away for a Dazzling Gleam. This shouldn't do too much damage because you are going to resist it with your Cerrel Edge. Then you're going to want to concentrate on going for those Sword Stances. So you want to get three Sword Stances up as soon as possible. The Psychics will come out and they will hit you pretty hard to start with. So you might want to take turns and go for the Sword Stance. Then a bit of Blade, then your two other Sword Stances. So the bit of Blade is quite nice to use early on in this raid just to recover health back at this stage so you don't get knocked out too quickly because this next Psychic is going to take you down pretty low. But the bit of Blade will top all of your health up at this stage after that initial Sword Stance. So you can see here that we have full health again pretty much and then we're in a good position now to go for those two Sword Stances one after another. So turn three is when you are going to see the Shield go up on the Delphox. Sometimes it is turn four or the very beginning of turn four but normally turn three. So going into turn three now, obviously with a second Sword Stance here and this is likely when we'll see the Shield go up on the Delphox. So this is kind of the timing when you go but we only need one more Sword Stance here and we're not going to have to worry about getting our stats nullified anytime soon by this Delphox. So you can see it's going to go for another Psychic here. It takes us pretty low this time. We're getting another Sword Stance off but the next one we should be able to recover a good bunch of health with another bit of Blade and that's what you kind of want to rely on here until you have Terastalize and then you can utilize that Iron Head for super effective damage. So one more bit of Blade before we are able to Terastalize. Psychic will take us pretty low once again. That's 16 health and yeah you can see the Special Defense drops on the Psychic then it does fire off. Do make it a little bit tricky of course but we are still plus six attack but with Terastalizing into a Steel type we are going to be able to take the Psychic type attacks a little bit better. We'll start to resist those now going into this next turn and then you can see it removes the negative effects from itself but we still have that plus six. You can see we've still got that plus six attack stat so we're sitting all right at the minute. Minus two Special Defense isn't super helpful but we can now Terastalize and now we can go for these Iron Heads into the Delphox and this should break the shield on it right now. The Psychic coming out with all minus two Special Defense bear in mind so we do take a good chunk of damage there but the Iron Head going to be able to plus six return some nice big damage to this Delphox and not quite enough to take down the shield but doing a good respectable amount of damage. You put us out of range you get knocked out by a Psychic this next turn and there you see it comes it removes this stat changes from our side of the field and there's the Magic Room as well so we have to rely a little bit more on our Bitterblade now which is not ideal as it goes for a nasty plot. So this is the time when it goes for the nasty plot you want to use the Clear Smog just to remove the stat boost on its side of the field so that's the nice thing. We'll try and go for a Willowis but our Flash Fire will activate here so just want to get that Clear Smog off to remove any nasty pop boost so if it does go for a nasty plot just make sure to use that then we're going to have to try and get some sword stances up again now but with that Steel Typing that we do have access to now we should be able to take attacks a little bit better going into these next few turns. Just go for one more Bitterblade just to get a little bit more health back before we launch these final Iron Heads off. You can see the Bitterblade really useful in this match especially when that Magic Room is in effect. We are only plus two at the minute so we're not going to be doing as much damage as we would do on plus six but you're going to be in a good position right now to just fire off these last remaining Iron Heads and kind of clean up the battle pretty easily from this stage. It's a final Iron Head and we managed to take the Delphox down pretty handily with the Cerulege. You can see the item drops that we get from this Delphox so you've got Excel, large candies, Terry Farrishards and all the other good item drops that you get. Although it's not as quick as some of the previous raids that we've done we haven't been able to kind of run through this. The raid timer is pretty low when we finish off and it's the same with both Cerulege and Almerooge. They're about the same time both of them and you go into this raid to do this solo but between them I feel like the two best options for being able to kind of soak up the big attacks from the Delphox pretty easily and then do some good damage in return and kind of beat it consistently and that's the big thing here. They're both consistent options solo in your game to beat the Delphox and then farm for these high cost items. And of course, if you want to farm these raids after you've called the Delphox you want to just come onto your map and then go into your home menu then come to system settings down into system then down into date and time and show that your synchronized clock by the internet is off click into your date and time and just toggle through with a don't change anything here and click that okay button and then come back into your game and your raid dens will all respawn and you'll be able to locate that seven star Terrarid event for Delphox. Once again, head over to it and then just farm it and repeat the process over and over and over again in your game. So that is everything for today's video friends. I hope you have found this video useful. Let me know what you've been running through this Delphox with in your games and what you've had more success with doing this solo by yourself. If you've enjoyed today's video do drop a like and make sure that you do subscribe to the channel to stay up to date with all of our Pokemon scholar and violet content. Thank you so much for tuning in and I will catch you all in another video very soon. So until then take care of yourselves and bye bye.