in the last class we have done something about temperature gradient okay which one is important is it interface gradient or interface gradient by the by which one is which one is important interface if I ask the question why can you answer why all the resistance for heat transfer lies in film whereas you have almost same isothermal particle that is the main reason conductivity of solids is very very high so whatever temperature is raised there due to exothermic heat or endothermic heat anyway so then immediately it is uniformly distributed in the particle whereas the conductivity of the gas is less so that is why you have the gradient in the interface okay Philippe now we will see for mass transfer what will happen okay again equations are known to you there is no new equation you have to learn and the equation which you have already used one was R O B equal to K G A C B minus C S equal to Eta K C S right this is the balance for overall effectiveness factor right overall rate of reaction observed rate of reaction or measured rate of reaction so that must be the film and the reaction that is going on inside the particle right so of course we are taking first order reaction so this is the rate that is going on multiplied by Eta will give me for the entire particle now that is equated to mass transfer because unless these two are balanced you will not have steady state rate good so this equation I will take only this portion so that equation can be written as C B minus C S by C S equal to C S I have brought this side Eta K by K G A okay yeah what is this K by K G A already you are experts in this this is nothing but Eta Phi square by good nice so that is all I think with this equation we should be able to tell yeah this is equation 2 minus 1 equal to Eta Phi square by odd number mass okay so now we imagine first that we are in reaction controlling regime okay reaction control regime so when you are in reaction control regime what is Phi value and what is Eta value generally in the particles Eta equal to 1 and Phi square will be much smaller that divided by a by odd number okay what are the general values of by odd number very high I think you know 10 to the power of 4 so 10,000 is the one which you have seen yesterday okay the other range 10 to 10,000 so in between also if you take it will be in thousands so that means because Eta equal to 1 and Phi small Phi small and Bim large all these conditions will give me C B C S minus 1 is approximately 0 so what is this C B equal to yeah C B equal to C S okay good so that means in reaction control regime C B equal to C S means on the surface as well as yeah in the bulk it is same so now you go to the other regime diffusional regime that is mass transfer regime inside the particle so here Eta is less than 1 right so Phi of course large values of Phi you will have Phi may be greater than 10 okay yeah but still when you have Eta can be even 0.1, 0.01 like that if you see the graph like this you draw now so when you go to 100 it may go to even 0.01 I am only drawing in the area okay you know that one yeah like this it goes like this this side so if you take that 1 by Phi Eta equal to 1 by Phi that is the equation right asymptote so Phi equal to 100 means Eta equal to 0.01 so it is very small again so even here you will on the biot number is large and yeah even here you get C B by C S minus 1 is again approximately 0 biot number B I M large okay again C B equal to C S so that means whatever may be the condition inside the particle okay whether you have a reaction control or diffusion control finally you are going to end up C B equal to C S where C B equal to concentration in the bulk and C S equal to concentration on the surface so that is why safely one can ignore mass transfer resistance through the film okay told in a different way we also feel because some of these feelings I think you know we cannot express that clearly but I think whenever you have film and diffusion through the yeah pores is difficult to then diffusion through the film because it is molecules molecules just going through the film whereas there these molecules have to go through the pores okay so that is why they feel they encounter more resistance than they are you know colliding with molecules in the gas phase so that is also the physical reasoning why we have C B equal to C S all the time whether you have this regime or that regime and the other one I already explained because gas conductivity is very less solid conductivity is very high so solid will always maintain isothermal particle okay so that is why when you are actually writing the material and energy balance as you can simplify automatically many things here because inside temperature gradient will not play a role so you can assume isothermal particle and analyze only you have to worry about is the external heat transfer okay how much is the temperature drop from bulk to surface right yeah and if you go to mass transfer always you can safely ignore film okay so then you have to think about how the diffusion is taking place through the pores that is why most of the time when teachers tell you about the effectiveness factors we always talk about effectiveness factor of particle not external you know based on through the film right but this analysis also Carberry did so beautifully just to say that yes there are many situations where the catalyst need not be porous then internal porosity and all that will not come into picture diffusion through pores and all that so everything may happen only in the film so concentrate on the film and also try to find out what will be the effectiveness factors for non porous particles okay good so with all this I think we have thoroughly done about heterogeneous catalysis the basics what we are trying to understand how do you design a catalyst particle in fact you can design a catalyst particle using wise preter criteria you can find out that means all of us would like to be in only reaction control regime correct no that means more amount of mass transfer but reaction is the controlling factor so if the moment you are increasing temperature of the particle okay in the bulk which also automatically reflects there if there is no external heat transfer resistance so you can also increase the rate of reaction right so that is why the always under reaction control regime we would like to operate that is why that criteria tells that you maintain less than 1 then you can design a particle where always you will be in reaction control regime okay and to be very specific you can take exact value I think it will come as 0.3 or so for actual one you take that one so that definitely you will be in reaction controlling regime so that entire surface area is used for chemical reaction because the catalysts are very very costly so that is why one has to use all the surface and by the by how do you make catalyst at least like a small story can you tell how do you make catalyst? yeah why should I have a career what better properties because science and engineering is not vague you know you have to use very specific reasons yeah what properties you are talking first of all why should you take a support you cannot use straight catalyst itself for example iron ore not iron ore for ammonia what is the catalyst iron right so that iron will be in what form is there a support for that? Molybdenum support yeah directly why they are not using iron to create active sites to utilize all active sites in the iron so if I have a porous particle it cannot use all the active sites let us say I have porous iron particle what you make porous iron particle by the by porous iron particle can you make no what is called sponge iron then why I think rich is telling you cannot make as if God said that let there not be any porous iron one can do that okay but I think in every catalyst there are some other side metals also which will come and you know enhance yeah improve the activity of the catalyst okay that is why it is like cooking where if you are a good cook you can produce a beautiful catalyst okay really 23 years back that was the one but recently after you try to explain what is happening on the surface where are these active sites at atomic level when you go that is narrow technology level then we know exactly what are the active sites how do you put them and how do you place them we need a support or not all these things will come into picture they have already come into picture that is why design of catalyst alone is a separate course and the starting point is for example your periodic table from the periodic table you can pick up for some groups you know for some reaction some groups will be very very useful I do not know whether you heard of that or not so that one first you have to make and generally I mean there are many many procedures it is not only one method how to impregnation of you know because it is I told that impregnation of for example iron on some support okay or any other catalyst on some support is also one of the biggest techniques where lifelong you have to only get expertise in that particular technique how do they do that how do they impregnate just think what salt if there is no salt what do you have you know yeah there is also one of the techniques make it vapour allow it flow through this porous support then everything will go and you know it will coat and you have to again ensure that whether only all the pores are filled up with this not filled up the surface area is completely covered with this vapour and then it is one of the you have to take it out and then test again whether you have what is the surface area so you have the bare surface area porous particle if after coating also you get almost the same surface area that means it is almost coated and of course activity also one has to check so there are lot of techniques and another simple techniques are you know precipitation techniques like you take the catalyst make as a precipitate and then make a powder take this powder and again compress as a pellet and making a spherical pellet is very difficult that is why even though all the time we draw here spherical particle in industry only cylinder because it is easy to make cylinders in the industry for catalyst why because all the powder you push through the extruders okay and then whatever pressure you want you can apply and then make the pellets cut cut cut you know depending on the size what you require what are the normal sizes required or normal sizes that are used in industry it cannot be definitely 3 4 inches correct know it cannot be definitely nanoparticles how many microns milli to you have gone to industry know probably you have taken your internship internship where what did you do there there is no catalyst catalytic reactors and all that FCC that is a beautiful catalyst SR oils they produce diesel petrol and all that so then I think you have gone to one of the best parts of chemical industries in fact chemical engineering developed because of petroleum only when petroleum industry wanted more and more information chemical engineering also was supplying more and more information so that is why both grew parallel okay so what catalyst they use in the FCC 2 years ago 20 years ago I remember zeolites zeolites I think you know these general things all of you should remember I said because everyday we are using petrol otherwise you cannot come to the class how you are using bike I am not saying you are using bike for transportation and all that so you go there and no space at all for any vehicle on the road how much petroleum how much petrol and diesel they must be using and who is producing all that chemical engineers you have to really lift your collar that because of you transportation is happening otherwise stand still should have been better for the planet okay because pollution is less so like that many things what you produce so at least the basic things like petroleum production ammonium because again fertilizers no food without that okay because too much population less area you want to produce more effectiveness factor should be increased of the land so that is why you put more petrol on a petrol more fertilizers more fertilizers so to produce more and more so again who is producing all that chemical engineers okay so lots of things we are doing and I think general things definitely you should remember like when you take a course in the reaction engineering general things like you know what kind of reactors you have when do you use which reactor okay what kind of catalyst what are the general catalytic processes and when do you use fluidized beds when do you use packed beds you are telling microns okay microns size so Kumar if you use microns size you can never use packed bed why pressure drop is tremendous because it packs so beautifully there is no wide edge for the gas to go through mostly gas solid reactions so that is why they use fluidized bed why in fluidized bed you have a freedom of you know a degree of one degree of freedom expansion so when gas enters it pushes the powder outside and then it goes okay so that is why and of course when it is going it is getting contact with the solids and then you have more of course diffusion everything is happening there much more surface area you get in a fluidized bed rather than packed bed but packed bed is still used because design is easy so sometimes we do not hire you know with not we in 80 we hire the maximum highly intelligent people okay but some industries they may not require very very highly intelligent people okay too much efficiency also is bad for them so that is why they compromise because the people who stay in the industry who work without questioning because you are more intelligent means more questions why you have to do like this you should you can also do like this all that if you question in the industry I think boss says that you stop all those questions because first of all you have to produce right production is important there and that is why that kind of people are very good in the research side where they can always question and then produce more and more information and for better and better things design okay good so that is why please remember that I think you know how do you produce for example catalysts how do you design the catalysts nowadays I think design of the catalyst with nano technology is going at really very very very sophisticated at atomic level at atomic level people are thinking about how do you arrange these things I mean recently also I saw some article in nature where to make you know whatever structure you want for the entire particle you can make by bringing 2 or 3 chemicals under certain conditions so then it forms automatically depending on the charge depending on the electric field around that and they can control the size of the particle structure of the particle and all that so that is why nano technology is really helping in customer made technologies I mean customer made catalysts if you want this particular surface area I can give you can specify that otherwise in the precipitation and gel techniques and normal techniques where I have the support also I do not have any choice with the my force okay either they naturally occur or when I take the powder and make it as a pellet then I do not have control so if I apply too much pressure then you will have too less force size force and if you do not apply much pressure then particle will be crumbling because mechanical strength is not there so all these things are problem but whereas with nano technology wonderful things are happening so that is why chemical engineering in which direction it is going means it is going from a larger size to smaller size chemistry always the reverse always starts with smaller size he wants to scale up to larger size so that is why I always used to tell that chemistry and chemical engineering departments if they are together then this direction they come this direction we come both will hit at one point they can straight rise up like Himalayas Himalayas also have reason because of that no this Indian plate moved and then hit that European plate and then raised so like that chemistry and chemical engineering together means we can also raise good excellent okay if you are going to some other new department start ask for chemical engineering and chemistry to be together why is people would do it but I think we cannot do it we could not do it here okay good so this is one and the next one is now all these things like for example this ROB how do we now find out that ROB what are the techniques we have because experimentally we have to also determine that rates we know how to determine this experimental rates for homogeneous systems okay if you have a single phase but here in heterogeneous system we have either a fluid and then solid most of the time right so under those conditions how do you contact this fluid and solid so that reaction can take place what kind of reactors we use so that is why we now discuss about experimental reactors experimental heterogeneous reactors okay we can also use first of all batch type reactor under even heterogeneous okay but only thing is we have to just see how you know in a batch reactor what happens you put the liquid or gas stir very well so that you get almost homogeneity and take the sample at various times and plot concentration versus time then you get rate and all that okay similarly for this you can also do but with your own innovation you have to do it so we have a box something like this may be I have to join this one here so somewhere here we will put our catalyst this is the pump yeah that is the stirrer so what we have is it is V inside we have well mixed this goes like this like this like this okay this is the catalyst W you may take 10 grams or 20 grams like that or may be 100 grams and then put it there and you see now the gas it is a gas phase reaction so always you have the uniform composition here that is why this one and it spends very short time here and then comes because that is why amount is very small there so it comes and continuously circulating all the time it is as if you are stirring the gas okay like in homogeneous reactions so now you can also use because the equation for this okay right here is already known to you T equal to C A naught V W is the weight of the catalyst integral 0 to X A F d X A by minus r A okay that is the equation you just try to derive that if you do not understand that you derive on your own because these are the simple reactions good so the next one is differential reactor very widely used this differential reactor is nothing but a plug flow reactor sorry a packed bed where we use our packed bed like this yeah so here we have the packing this is W yeah this is X A in that is X A F yeah so here the condition is delta X A okay should be small all enough so that the average rate can be used throughout the reactor yeah throughout the reactor but with yeah with a little error you cannot avoid that error with little okay so what is the equation we have to use here we have to use C A naught W by F A naught equal to I think I can also write this delta X A by minus r A right okay this is nothing but your plug flow equation when you integrate this delta X is X A F minus X A in if you want you can write that delta X anyway I have written here delta X okay this is the reaction I mean yeah but here what you have to see mainly is this is what I was telling you the chemist will take very lengthy reactor and put a small amount of differential volume you know that is where the catalyst is they put cotton in the bottom cotton in the top and all that so that you know they can just the liquids or gases can diffuse and then they put drop by drop so you can never use this equation there and they use this equation okay why this equation is valid only when you have plug flow condition then only this equation is valid so that is why I mean it is not their fault but because simply whatever is available in the book if you do it will happen like that only without understanding right but this is very widely used differential reactors are very very widely used for heterogeneous systems particularly for catalytic gas solid catalytic reactions okay good so the other one is normal plug flow reactor itself packet bed so here this is as usual you will have X A in X A F integration will not come that is why we are calling differential reactor the differentiation of integration is plug flow reactor is here because you are taking that very small I have written here average rate can be used throughout okay so this is minus R A average okay I will write here average you know how you actually conduct this you have to maintain plug flow conditions okay so that is why you take small amount of catalyst disperse that throughout on in inert particles of the same size okay inert particles of same size let us say 3 mm you are taking so 3 mm of some inert particles but 3 mm of some 10 percent or 20 percent of the active catalyst uniformly distribute and then packet there right so from this end to this end you will have only very less rate because amount of catalyst is very very small there are many ways doing experiment is not that easy I think some of you may be thinking that doing simulation is great simulation any mathematicians can do but experiments only engineers can do okay yeah and for example conducting this experiment is not that easy the way we discuss also here if I ask you completely to design or your own a differential reactor and then do it otherwise I will kill you okay K K 47 instead of AK 47 okay yeah so if you go to KK 47 or if you are afraid of KK 47 then you have to do it right there is no chance otherwise if it is only exam okay even if I do not do it anyway you will give me D or E I will pass that should not happen gun should be there then only you will know how difficulty it is to do the experiment otherwise escaping simply escaping because there is another least resistance path okay anyway so that is why I think you know designing these packed beds and then conducting for example we have in our lab because I do always the experiments most of the time we have the biggest problem with the manometers that is why when a student joins with me you first connect manometer properly then I will know that you can do your MS or PhD yeah and what we think you know manometer beautifully written always like like this you on the board and nicely written delta P you try to get the delta P in actual conditions I think you know BTEC lab also they cannot get properly because it is already connected given to them so then even I am not talking about them you are also BTEC okay I mean one separate time so all of I think it is very very difficult for you because it is given already to you so that is why happily you are going opening the tap and then finding out flow rates and all that finding out delta P and then giving the results okay so that is why doing experiment is very very difficult and conceiving an experiment is much more difficult that is why PhD is given for the people who could conceive the you know how to get the data first of all who can formulate the problem after formulating whether it is theoretical or experimental how do you really conceive the idea actual methodology and then next one is how do you analyze the data same data if I give to X and Y there X may give totally different interpretation Y may give totally different interpretation okay without depth very shallow interpretation so if you are good automatically you will go deeper and then try to explain and research is going to deeper and deeper and then bringing something unknown till now that is what is research so that is why please remember that when you are because all of you are doing some research some project or other okay so that is why all these things I know it is not so easily doable here you know the experiments and I think in our department also people think that the I mean the faculty who are students faculty and students who are doing experiments are low funda guys and who are doing the simulations are high funda guys high funda low funda delta C yeah it is everywhere I mean because I know here so I am just thinking I am telling you it may be everywhere but I think before the computer you can simulate many many things but actually go to the lab and try to get one millionth of what you simulated try to get on your own then you will know the difficulty okay first of all you have to go and request many times that that is the starting point you know mechanics okay starting from mechanics starting from lab attenders starting from sweepers everyone you have to handle computer what do you handle only you handle yourself okay and make noise tick tick tick so that is all what you do there okay anyway good this is plug flow reactor where we have the equation already here C A nought right here right here W by F A nought now Swami what you are asking is X A in normally which is 0 X AF D X A by minus R A this is the actual plug flow reactor where there is a lot of variation from here to there whereas here it is as you said correctly it is mixed flow throughout the system we are imagining that we do not have much difference in the conversion but that small conversion is because of certain rate okay that is what what you are measuring okay so the other one is mixed flow mixed flow reactor this mixed flow reactor was designed by Carberry so what he did was he has taken a box a cylinder yeah so something like this those are the holes there then also has a rod so here you have a box and here again you have another yeah so it is actually four boxes you know these these are the mesh boxes so they fill up the catalyst here okay and then okay it is very nice so here it is X A in may be 0 X AF so the gas goes inside this is rotating so the gas goes and then contacts there and anyway continuously you are pumping and then here definitely outlet is open so then it will come out here X AF you measure this you measure normally this is 0 okay and the equation for this W by F A not equal to again delta X if this is 0 that will be if this is 0 that will be simply X AF okay if this is 0 that will be 0 I think let me write that so that you will have at least one this expression this expression is familiar to you okay good so the last one this is Carberry reactor okay yeah this is one of the easiest reactors directly you can get but anyway it is not that easy also to imagine because when the gas goes and then when it is moving with the solids okay because solids are rotating like fan and gas also moves the relative velocity between the yeah between the gas and then solid is how much 0 or more because gas also moves with the same speed as solids so what is the relative velocity 0 that is not good for the mass transfer to take place okay right so that is one of the difficulties but still that is one of the techniques they use that so then we have the recycle reactor this reactor was designed by Berti Berti as a professor of chemical engineering somewhere university of Akron AKRON university of Akron okay so here it is normal our here I have space yeah so that is like a fan inside X AF 0 so here so this is catalyst W this also coming yeah so some amount of gas is recycled some amount of gas is recycled so here right so that depends on how much you open here so depending on this opening the remaining will go there this you can adjust so recycle ratio you know amount removed by total amount recycled that is recycle ratio R so this we have done already so the equation for this is tau equal to R plus 1 CA0 R by R plus 1 X AF X AF by X AF minus R okay when R equal to 0 then you will get this equation when R equal to infinity both can be done here this is the advantage of Berti reactor so depending on recycle ratio you can operate that as either plug flow reactor or mixed flow reactor so when R equal to infinity because when you are doing experiments it is always better to have directly getting R A like this that is the advantage here also directly get instead of again integrating and all that so that is why if you are able to maintain R equal to infinity mixed flow condition you get the same equation as W by F not equal to X AF so these are the reactors what we have and there are many other reactors for example it is not that easy again to go to you know catalytic non-catalytic reactions like for example if you want to find out iron ore kinetics how iron ore is getting converted to iron and if you want you have to again think if you are trying to find out the kinetics in gas liquid systems again you have to think what kind of reactor you have to use so that is why chemical reaction engineering fundas are very very high because each problem is a separate problem to be thought of so then you have to really imagine how to conduct experiments how to analyze the data okay how to develop the models for that kinetics like you have seen Langmuir insulate kinetics that is different and you have also seen non-catalytic reactions like shrinking core model homogeneous model all this so that is why each reaction is a separate one and we have three phases and combination of these three phases will give you really help can be liquid liquid gas solid gas liquid and all that you know yeah solid solid much more help so all these reactions good so with this I think you know I have closed the entire catalytic reactions so now what we have to do is in the next class packet bed reactor design we will have some equations I mean some models for packet bed design and then we will take some simple problems and then I will ask you how to design that okay good so Monday I will not be there so you will be happy you are free you can prepare very well and Tuesday we have examination MSBHG students you can sit in the same room like last quiz one okay 255 I think you said or 355 355 you said so


Stevenson falls to a wider day at Owings Mills Gymnasium. Glenn Clark with Kalia Winter, who had an 11 rebalance today. Kalia, where does your sort of force on the glass come from, that presence and that demeanor that it takes to be dominant on the glass? I believe in my beliefs. I know that I'm strong so the ball's mine. It's just hard work effort, which we wanted more. When did you know that was what you were all about? Like, take me back a few years, right?  I'm gonna be dominant. I can do this. You know, I've always had coaches tell me, like, rebounding, like, that's that's your job. And I'm taking that to heart.  And if rebounds are what we need, rebounds is what I'm gonna give. You know, we were talking with Coach. It was a good effort on Wednesday. It came up a little bit shorter. You guys were really good. How close is this team putting everything together for four quarters? And what still needs to happen in order to take that next step? I feel like we're really close. These past two games have been pretty good. We've been showing we've been showing up a lot more gelling well, gelling together a lot more. We're young. So we're still learning. I feel like we just got to really understand what it takes to play all four quarters and not let up. But I understand we came out guns blazing, which is a little bit new for us. But I think we need to learn what it takes to keep them into all 40 minutes. We need to get to know you. There's been a lot made about players on this team that have similar first names. Yes. Do you have a nickname to stand out amongst the many liars that are on this this roster? Um, not necessarily some people call me winter, which is my last name. Yeah. Um, in the past, I'm lefty because I'm left handed. Okay. But yeah, I'm going to need you to score more because I'm working on my Kalia winter is coming call right when you do. So we need a little bit more points. I think moving forward if that's our that's the plan myself back in because, you know, I had less. So I'm getting my touch back. And then give me like, give me a favorite football team. Not necessarily football fans, but my dad. Okay. Unfortunately, the majors. Oh, I'm so sorry. I'm sorry. We're not favorite basketball team. I mean, gotta go wizards. I also like the aces. The aces are always okay. I mean, I'm South Carolina. It was fun. The other night wasn't it? Yes, it was fun, fun game. All right. I don't know how you suffered for being a wizards. Appreciate heck of an effort today. Appreciate you taking the time. Thank you. It's Kalia winter. I'm Glenn Clark. Go Mustang sports.TV.