So I'm very pleased to introduce Quang Thanh Dang from University of Paris-St-Clay and University of Paul Sabatier who's going to talk about Ketterhainstern Metrics on log canonical varieties of general type. Okay. First, I would like to thank the organizer for inviting me to give a talk. And yeah, we hope, I really hope that we can meet each other fresh to face someday. And, but today, I will talk about my work about the Ketterhainstern Metrics on the log canonical varieties of general type. So let's get started. So, first, I'm going to outline my talk and we're going to be starting by discussing some background and some motivation to my work, my main problem. And then we are moving into the definition of the singular Ketterhainstern Metrics on the mildly singular varieties and how to make sense the notion of Ketterhainstern Metrics on the underlying space, which is no longer smooth. And then we discussed, yeah, and then we discussed about the, about the associate degenerate complex Moom Zampere equation, and then studies the continuity of the which solution to the Moom Zampere equation in big co-moluzi classes. And I list here some reference to my talk and yeah, the first one and the first one that is a reference, I think that is the first paper, which is study the singular Ketterhainstern Metrics on the mildly singular Ketterhainstern varieties. But I don't know the paper before, but and then the next one that is the paper, Burman and Ganeshya, and I will borrow their definition. And the third one that is a paper, I, yeah, that is a paper I learned some technique to my, to my paper in the last of the list. Okay. First, I fixed some notion in my talk, and we're going to let it to be a compact calamity for a complex dimension and and Omega is a is a California that is a one one positive form. And then I fixed a big co-moluzi classes. And yeah, I will give you a precise definition of the big co-moluzi class and theta is the smooth representative. And for any close the positive, yeah, I missed the positive there, the close positive one current, I did not angle bracket to be the positive to be the non-Buri polar measure of the the one one current on the manifold. And we, yeah, you can understand this measure. And in the, in the case of California, that is, it's the coincide with the usual moves and pay operator. And my work might. The word my talk today is to study the regularity of the, with your solution. The solution being the degenerate complex motion per equation and F this solution fine is, is very quick, but this have the finite energy. And I will give you some, I will give you the PSI definition of that. And on the right hand side, the density, the density F is of this form, and I, and I will explain you why we study the regularity of this solution. Okay. So first, I, I recall you are some, some notion and some no results of the gallein Stein matrix, the usual gallein Stein matrix on the smooth compact color manifold. So let's, let's, let's discuss about the chun Rishi form that is a one one form given by the minus ID diva lock of the determinant of the metric omega. And the definition of the gallein Stein matrix. Yeah, it is easy. I think it is very familiar to all the guy. That is, if a cali metric is a cali in Stein, if they exist, a real number, such as the, the Rishi form is equal to the lambda omega. Of course, this definition requires that the first chance glass of the, of the metaphor to have the device side. And this is always a case in, in a complex of dimension one.  They always exist. They exist in the metric, but not in general in a complex of dimension two. So, for instance, if you take the product up to any, to any compact reman surfaces and they exist gallein Stein metric if and only if S one and S two have the same time. And by the rescaling, we can easily to see that they are only three case to keep to consider that is where lambda is equal to minus one zero and one. We can easily to solve that we can easily solve that solving the cali in Stein metric is equivalent to solving the complex motion per equation. And we have, and this the equation is so 14, 14 or 15, 15 years ago by Obama and Joe in the case when lambda is equal to minus one. They, they was working independently. And the case when lambda is equal to zero and on the Calabi now many fraud. The East Cali Cormolo Z classes always contains a unique reticulat cali in Stein metric, but after the work of Joe and Obama, almost 40 years after or more than 40 years, the problem to the K lambda is equal to plus one is has been solved by a series, a series, a series work up to Donaldson and soon and so it's the first-gen class has the, if the first-gen class of extra is a positive and one cannot always so the cali in Stein equation. There's, they don't always exist the cali in Stein metric. And they saw that the existence of the cali in Stein metric is equivalent to the answer pro geometric condition, which is so called the key stability. And I'm gonna not explain what what it means, but let me properly say that the solution to this highly long linear PDE is equivalent to the certain and several and several geometric condition, and which is called uniform case stability. And in the center of Tian and Donaldson. Okay. And now I'm moving on the situation where the underlying, where the underlying space is no longer smooth, but rather a mildly singular Cali variety and seen a few decades ago. Sorry, since a few decades, the so called minimal model program. The MMP studies the problem of classifying classifying the algebraic many first in in dimension one, two and higher and up to a bright and soon be rational equivalence. Yeah, it's the, it's, it's, it's been sold in a complex dimension one for a few decades ago, and almost, sorry, and almost and almost finished in a complex dimension to buy from the Italian school and, and the compilation of the Japanese school. But in the high in the higher dimension, more precisely in the complex of dimension three, the situation is incredibly, incredibly more complicated. And one has to, one has to engage the picture and considers the Miley singular varieties. And, and we am at defining the corresponding the singularities and, and how to make sense, the Cali Einstein equations, and I'm going to be explaining how these can be interrupted in terms of the complex moon sample equation and that will be degenerate. And then we study these degenerate equations. And yeah, we show that the equation exists with solution and established some partial. These we are dealing with the main type of singular with singularity. We are going to consider a so called the log terminal and log canonical singularities. And I, in this talk, I'm going to considering, I'm going to be considering a normal variety. It's the means that the singular locust is, is a complex code dimension. Ah, sorry, a core dimension, at least two. And the, the variety is core key warrants time, if it's the canonical divisor exists, and exist. Yeah, is the mid send as the key live under. Okay. And, and then you take a local resolution of the normal variety. We have the assumption formula. And the AI there is core discrepancies of the why and we, we say why has the log, log canonical respectfully a log terminal singularity is the coefficient AI is greater than or equal minus one. And for the log terminal singularities that is AI is greater than it is strictly greater than minus one. And for my talk today, I'm going to focus on the log canonical singularities. Okay, and we also say that why is is a variety of general time if if the car if it's the canonical bundle case why it's big. I will, yeah, I will give you an analytic definition of the, of the big nest of the nine bundle in the secret. Okay. And, and of course, this definition is the independent independent of the choice of the local results. Okay. Okay, I'm going to give you some example of the singularities. And we, you can also define. We can also do, we can also define the singularities for a general pair, why and data with the data with data being effective divisor. Okay. And for, okay, on the surface, the log terminal surface singularities are precisely the quotient singularities of this form. Okay. And in a higher dimension, we can also prove that quotient singularities are still log terminal. And, yeah, we have the beside beside beside example. Yeah, you are taking a smoother hypersurface of degree D in the in the complex projective spaces, and you take a five cone over the hypersurface. And this, and this cone has the only kind of this code has the singularities and this, and only has the kind of equal singularity if and only if D is not the exit act. And for, for Calabi yaw log pair, why and data with why being a touric variety and data being the complement of the embedded torus. Yeah, and you can, yeah, we can so that the pair is log canonical. That is an example of real 40 years of 14 or 50 years ago. Okay, now, let's discuss about the singular Caroline Stein magic and how, yeah, and in general, on the, on the Miley singular varieties is not is not easy to make sense of the some objective of some key objective like the turn richie form or, or Caroline Stein equation. And I'm going to give you the first definition constant the richie curvature of the current. And I say that a close positive one on current is admissible if is the satisfy the two following conditions. I assume the known a product of the close positive current is absolutely continuous measure on the regular locus with respect to the logic measure and I assume the log of the density is locally integrable in the in the regular locus and this definition has this definition has me to define the richie curvature of the admissible close positive one on current. And another way of thinking of this definition to interpret the positive the non-pripola positive measure of Omega on the regular locus as the singular metric on on the anti canonical life and oh, and with curvature is the richie curvature by definition above. And then I can, and after that, I can make sense of the Caroline Stein metric with negative richie curvature. Yeah. In the sequel, I will consider sorry, I will consider why to be log canonical variety of general time. So I will define the Caroline Stein defy the negatively curve Caroline Stein metric. Yeah. And I say that a positive admissible current Omega is a Caroline Stein metric. If it satisfies the two following equation. The first one. Yeah, it's more. It's like in it's more like the usual one. And the second one that this is a sufficient coalition guarantees guarantees that the Caroline Stein metric is equivalent to the degenerate complex moves and take with. Okay. And next. Can I ask a quick question about the station. Yeah, why I can't remember now why is that what you get when after you do the resolution, or is it what you have to start. Yeah, why in, in my talk, I am, I am considering why to be a normal variety. We go to Stein normal variety, which has the log canonical singularities and such as the is the canonical bundle case why it's big. Okay, got it. Okay, go ahead. Let's keep that. Ah, okay. Yeah, let's me make a few comments about the above definitions. And around 10 years ago, we can. Yeah, we have another definitions in the sense of in the sense of the French school. It's easier guest and Zegah here. They first they define the, the so called adopted the measure. And this definition is independent of the choice of the section of the non zero local section of the RKY. And then they, they saw that. And then they defy the Caroline Stein metric is a solution of the, of the following complex moves up a question. And they also saw that on the, on the local resolution, we can, we can write the, the adaptation measure of the following. And this is, this is a product of the Zi of the model of that ice to to power to AI. AI there is a discrepancy coefficient. And we can easily to see that why has the log terminal singularities if and only if every adopted measure mu has the locally finite must near the singular, near the singularity of why. And with, with that definition, yeah, they can, they could equally defy the positively curve Caroline Stein matrix on local final on local final varieties. Around, yeah, three years ago, yeah, publics on our friends, you know, okay, now we are going to, we're going to be in a decrease, we're going to be a decrease in the degenerate complex. I recall you the setting I am considering in the secret. I'm going to let why be a local canonical variety of the general time. And we, we have seen about that, the Kalein Stein, the existence of Kalein Stein matrix is equivalent to solving complex moment. And we will work, we will work on the local resolution up a wide and then we are pushed down the solution on the base. We can prove that the existence of the singular Kalein Stein matrix is equivalent to solving the complex mung zhampa equation that will be degenerate, because you see the density on the right hand side is degenerate. And I also, yeah, we also remarked that. The big less is guaranteed is preserved by by taking local resolution. Okay. And, yeah, of course, the canonical, the boom back of the canonical live under K why is still big by taking local under under local resolution. But we have to. Yeah, we have to be careful that the density F is low longer is is not integrable when some coefficient AI is minus one. Yeah. And to solve this degenerate complex mung zhampa equation, we need to, we need to give no sin, a good, a very good notion of which solutions and and this let's add the Puri potency theory. And back man and a studio guest Sega he around 10 years ago. They introduced, they introduce a new good notion of which solution and introduce the variational approach to, to solve the degenerate complex mung zhampa equation in the big co multi classes. And they, yeah, they, they use the variational approach. Yeah, the idea of the variational approach is to construct a critical point of, of an convenience functional, but I'm gonna, I'm not gonna explain what they do. But first, the, the, the main thing of my talk today is focused on the regularity of the with solution. Okay. And, okay, today, we will study the regularity of the with solution. Okay, first, we assume, we assume the solution, we assume the equation exists with solution phi with finite energy. And, and then I gonna be studying the regularity of this solution. I will show that this unique solution is continuous on the ample occurs outside the local canonical locus, the local, the local canonical locus, that is a union of the, of the exceptional divisor, the union of the support of the exceptional divisor with the coefficient ai is equal to minus one. And some no result before in the case of the Kawamata local terminal when ai is truly greater than minus one. The density, the density there is a density is a product of, of the SI, the model SI to power to AI is belongs to the LP and around 10 years ago in, yeah, around 10 years ago in 2014. The my with his collaborator collaborators, they saw that phi is continuous on the ample locus of theta. Yeah, I'm gonna give you the definition of the ample locus but you can, you can think about, you can think that the ample locus, which is open, which is the Zariski open subset. On the, on the variety one, a variety, it's sorry. And if the theta, yeah, this is if the theta, the reference from theta is additionally semi positive or is classed to be a nef. We have a result to show that phi is smooth on the Zariski open subset. And it's, and by consequence, and consequently, they exist a unique, sorry, they exist a unique singular Kalenstein metric on and suggest on the regular locus that is the satisfy, it satisfies the Kalenstein equation in the usual set. Okay, now, before going to my main result, I will give you some break ground and some, some background on the three percent, three percent theory. We still let, we still let it be, we still let it be complex complex Kalen manifold of complex dimension and a co homology class. One one co homology classes on farm is said to be big. If it contains a Kale current, which means that they exist a positive close current tea, such as the tea dominates the dominates the California. And in particular, for any live and draw L, we say that L is, we say that L is big if is the first in class is. Yeah, that is analytic analytic of the big live and draw analytic definition of the big. Okay, the next item, that is the definition of the ampoule cast. The ampoule cast of the big co homology classes. Yeah, we fixed and father is a big co homology classes. And we let the ampoule cast of unfair. That is a Zarisky open subset of all it's for which they exist. The Kale current tea is belongs to belongs to alpha with analytic singularity. We will not focus on what analytic singularity is but you can, you can understand that the Kale current tea is smooth around it. Okay. A little bit definition of the, a little bit of a brewery sub harmonic city. Yeah, we call a function of upper semi continuous function you is brewery sub harmonic. ID bar five is positive in the center currents. And we, then we have the definition of Gazi brewery sub harmonic. Did, did is locally the sum of the smooth function, the sum of smooth function and the piece of a brewery sub harmonic function. Yeah. That is a PS hat stand for. And for, for a big co homology class and far, I'm going to fix a smooth the representative theta. And we say that five is a theta PSR or theta brewery sub harmonic function, if it is a Gazi brewery sub harmonic function and theta plus the ID bar five is a positive in the center current. I think you are very similar to this definition. And I did not the envelope of the any boring function as by be theta as is a supremum or theta PSR function lying below as and I am an if as to be the constant zero. We, I will denote the V theta is, is a envelope of zero or envelope of some constant. Okay. And the factor, the fact that V theta is a theta PSR function. And which has the minimal singularities in the center of the money. It means that for any theta PSR function fine. Phi is more singular than V theta. And it means that there exists a positive constant of C and phi is is less than theta plus C. And in particular, V theta is locally bounded on the Emperor Lucas. Because the, because the for any for a big Cormolo Z class the unfound, they exist a current, which is the smooth on the Emperor Lucas by the work of books song and V theta is a is a list singular in the in the set of all theta PSR function. And so V theta is a cost less singular than the than the potential with analytics singularity. And this, and this one is locally bounded on the Emperor Lucas so V theta so is V theta. Okay. Now, I'm going to recall you the definition of the non puripura of theta PSR function, and we can extend it, which can extend this definition for any closer positive current. And, okay, first given given a theta PSR function fine. We take, because the V theta minus T is locally bounded on the Emperor Lucas. We can buy the work by the bed for Taylor Terry by the bed for Taylor Terry, we can defy the complex, we can defy the most unfair measure of theta plus the DC must find V theta minus T. On the on the sub level set the fire is greater than V theta minus T. And you see, the, and we defy the, the non puripura most unfair measure of fire to be the limit, the big, the increasing limit, the increasing limit of the of the sequences of the, of the, of the positive measures. And after that, we extend, we extend this measure trivially honest, because the, because the Emperor Lucas is a Zaris key open subset. Okay. And from now on, I did not am I fine to be the non puripura measure. The non puripura most unfair measure of a fight of a theta PSR function fine. And I defy the volume of the volume of the, the volume of the theta or the volume of the big come with the class and far is the master of the is the master of the most of no non puripura most unfair measure of V theta. And, and this the definition coincide coincide with the definition in algebraic geometry when I'm far is a first chance class of the big life and by the work of books. And we can check that the total mass of any the total mass of any theta PSR function is always less than or equal or less than or equals the volume of unfair by, by using the monotonicity of the witness. And I will let, I will let the, the class the E. Do not the, the set of theta PSR function with full most unfair must. That's mean the, the total mass of the, of the most unfair measure of fine is equal to the volume of the unfair. Okay. Now, I'm going to restate my main result. First, we assume, we assume we have a unique, we assume, we have the weakest solution. So which solution to degenerate a complex moves and pay equation. And then we study the continuity of this solution. And I, and, and this, and this theorem implies the, the theorem I introduced before, because the, when I rise density on the right hand side. I, of this form of a, I write F to be the exponent.  And, and the Z, Z belongs belongs to the LP spaces. Yeah, because the tool because the tool able. The tool able to deal with the log canonical locus. I decompose, I decompose the exceptional divisor into two parts. The first one is a log canonical locus where, where the coefficient AI is equal to minus one. And the second one is a log terminal locus, where the density j belongs to the LP for some be greater than one. And in the, in this theorem, I just proof the solution to be continuous, but I really hope to get a more higher regularity. And some idea of my proof. Firstly, I will prove five is a five have the relative zero estimate five is a greater than some data be a shop on some side minus uniform constant. And then I'm going to look for a decreasing sequences of theta pressure function, which is, which is a contrast to fight and fight chase is a continuous on the open subset. And then I will show that this the convergence above is locally uniform on you. Okay. So, for the idea of the first step, I gonna use the, the color say idea. First, I recall you the definition of the relative most ampere capacity, the capacity of E of the boring subset E to be the supremum of all the integral moons and parameters of you where you is a data piece of function between the psi minus one and psi. And I'm going to set the ST like that. Again, I extend the colors a ideas to show that the function ST is right continuous and satisfy the, the following inequality. And then by using the classical lemma, we can show that the ST is identical zero for the big enough. Yeah, that is a lemma of the day Z or three Z or Z. And I've for us is a decreasing right continuous function and satisfy the following inequality. And we can, we can find some uniform constant only depend only depends on the constancy there and suggest the ST is equal to zero for 40. greater than a infinity. Yeah, that the power of this lemma is a very basic and you can find it in some, in some reference I list above, but I let me tell you some factor of the constant a infinity. Yeah, the constant a infinity is precisely equal to two plus the T zero. And for T zero is a constant satisfy as the T zero is is very small. And of course we can control. Yeah, we can control the a infinity. Okay. And we apply this the lemma to show that we apply system lemma to solve that ST is equal to zero. And you see the formula of the ST that is the capacity. Yeah, that is a capacity of the sub level set the fight less than a psi minus T and where when ST is equal to zero. We can show that the fight is a greater than a psi minus a almost everywhere. Yeah, we can show that fight is a greater than a psi minus a outside of the purple set and hence everywhere. Okay. And by the work of book song. I can, I can pick. I can pick a database that function, row zero, which is smooth on the apple of course. And that is, yeah, that is a success that theta plus the IDD bar row is current. And then I said, yeah, as I then I find a small a small constant a suggest the psi is equal to a fight plus the row zero is, yeah, is It's still the theta PSA function and suggest a theta plus the IDD bar psi is still a current and you will, you will, you will easily to see that psi is locally bounded on the on you, because the fight is the locally bounded and row zero of course. Okay. So for easily, I said that the new that is a ZDV and B is a to power minus one. And I have the following inequality. First, the inequalities is, is a consequence of the comparison principle. I refer you to to the paper of the book some a studio get and see a he or a series, a series paper of diverse the design loop. And on the sub level set the exponent, exponent so up B psi minus five is always is always greater than one. And we have the, the second line is very easy, but you see B phi minus B V theta is not actually a theta PSA function or Cassie PSA function in general. So the, the idea is the idea to control to control to control the interoperability of the e to power e to minus the B phi minus B V theta. That is, we take the envelope. And we show that the envelope up B theta minus the B V theta is a omega PSA function and set and we, and then we control the singularities of this, of this function. And the last line is very easy is that is, that is nothing the Honda inequality. And the fact one by the volume capacity comparison, we can show that the volume, we can show that the measure mu is always less than the constant. Time the capacity of the time the capacity to power four. Omega that is the definition of the capacity in the Coliseum paper, but that is a special key when that is special key when I think theta is equal to omega and psi is equal to zero. We can we have the definition of capacity omega. And the fact to we can control the capacity with respect to omega with the capacity with respect to theta and psi, because the function psi are certified that the theta plus the ID bar psi is a current. And we, we first we take you the, the candidate function, that is a omega PSA function between minus one and zero. We have the, this is the inequality and the function psi plus the dental zero you is a candidate function is a definition of the capacity. And this is very easy. And by fact one and fact two, we can show that the new new two power one half is less than the constant C time the capacity square. And the next one, we have to control the, the envelope of the be five minus the be V theta. And we can show that this function is a omega PSA function with the full motion by mass by using the technique of the diverse design Lou. This is the fifth one in their series, published on a current journal, and they can, we can show that the envelope of the T five minus TV data is a omega PSA function for all T, for all T greater than one. And then we have the easy, we have the classic inequality and using monotonicity of mass of the witnessium, we have the following inequality, and then we, we take a be going to plus infinity, we can so that the left hand side is a greater than the mass of the omega. So, yeah, it's, it's terrorist. This, this terrorist, the function be omega, the envelope of be five minus the be V theta is a omega PSA function with full motion by mass. And the fact for for any omega PSA function. They always, they always has the zero long numbers. That's why we can control the singularity of the envelope of be five minus be V theta. And this, this is thought is put by get in the year he 15 years ago and generalized, and then generalized by Davos, the DNA is a new 10 years after. Because the envelope of be five minus be V theta has the zero long numbers, we can, yeah, we can. So that the integral of the exponents or minus to be omega be five minus be V theta is finite. And then we can so that the constant a in the step in the step one is a uniform and depends on some quantity I list. In the step two, I gonna find a decreasing sequences, which is the continuous on the Emperor Lucas and decrease to five. That is just the consequence of the, of the two words of Burman and the money with his collaborators. For any for any as for any a smooth function as we can so that the most unfair of the envelope of us is dominated by the by a smoother by the smooth volume fall. By the work of the dummy DNF get farm Colisei and Zegahy, we can show that be theta as is a continuous in the Emperor Lucas. And back to my problem. First, I take a sh is a sequence of a soup smooth function is a Nick is a second of the negative smooth function decreasing to five. And then I take the envelope of this sequences. This this sequence they is still a decrease to five. And by the terrible bow fight chase is a continuous on the Emperor Lucas. But actually fight chase satisfy more higher regularity is the say that be theta of any smooth function is. It belongs to the class the sea one and fun. It means that the first is means that the laplacian of the P theta ash is locally bounded on the Emperor Lucas. By Burman and the money, but we have to be carefully because the dilemma one the player 12 in the in that paper is not the two, and I refer you. I refer you to the paper denies I and company last year. Okay, the step three, it just the consequence of step of step one. I fixed up size a, I fixed the lambda belongs to a zero and one, and I set the size a. Okay, and the function size a plays a symbol upside, and we do exactly the same in the step one. We, we still set the function as day and we show that this function is a right continuous and satisfy the inequality. In the lemma, and we can solve that the fries is a greater than lambda psi plus one minus lambda 5j. But I should mention that the ash J is going to zero as J tends to fit infinity because the in the in the lemma I list above we can we can control the we can control the the constant a infinity. Yeah. And then I take your J goes to plus infinity, and then, because the side is a locally bounded on the on you, and finally, we can show that the, the comparisons is uniform on in lock uniform on any compact of you. Okay, let's me. Last slide. Let me talk a little bit some further questions. Yeah, I, I can prove fire is a continuous on the MPO Lucas the outside. Outside the local record lockers outside the local record singularities, but I hope I can prove fire is harder continuous because we have the we have the result before by the domain with his collaborators. But yeah, the next question is to study the asymptotic behavior of the calenstein metric near local record lockers. And, and we have now we have now are some recent words by currency and who and data for strong, they can contract, they can contract a calenstein metric near the isolated, yeah, near the eye on the near the isolated local record singularities. And, and the last questions is coming from the work of Davos, the design new, and they, they prove they prove that they exist the unique solution, satisfy the complex moves and pay a question with the press guy singularities. And I hope, yeah, I hope when the small fine, the small fire model tire singularity and the density F, they, they are quite good enough. And we can get a more, we can get a more higher regularity of the solution. Okay, and sorry to over the time and I think I should stop my talk there and it's time for questioning. Thank you very much.


The Inferred Mind writings from a Zen master to a master swordsman by Takouan Soho and translated by William Wilson. What does unfettered mean? It means the release from restraint or inhibition. Takouan is a Japanese Zen Buddhist monk from the 1600s, a master in himself, a gardener, a calligrapher, a poet, author, and an advisor to samurai and shoguns. In other words, he's helping samurai become better swordsmen. While there is conflict and violence, there's peacefulness in Buddhism. His teachings were not just for them. There's a certain mentality, metaphors, wisdom, and a thunder clap type of vibration, where it's a sound wave that makes it a holistic connection. Takouan fed info to Yagyu Menonori. He's a famous samurai, as well as may influence Miyamoto Masashi. He's an advisor monk. His teachings reveal, be serious at first, then lighten up.  You will be enlightened wherever you are. If not, you won't understand, or others who aren't won't as well.  Ulysses had the siren song, and it's something you can shut out. Do not be reactive, but actively floating down a river, as Incubus sings in aqueous transmission, floating down a river. You must have a natural sense of the parallel to the great outdoors. See this true glory of water and ice. You can look at the name of this channel, Sleeping Elephant. Most people are Lincoln Park num zombies, not living life and living quiet desperation. Be in the zone. Be present moment. Holistic. No mind. Mushashi is void. The mind is like a dance. Entertainment can keep you along like a chugging engine versus relax and work. And initially this philosophy was don't stop, just like ATB. Don't stop like a deer in headlights. One sword, one spirit. The mind is in other parts of the body. Freedom by not stopping.  And if you focus on winning too much, you have not won yet because you have not emptied your mind. And also you don't want to play to avoid losing because you're just playing in a defensive tactic. Empty the mind or be at a stillness. In the beginning you should focus and really just let it go. You eventually get the mastery practice technique. It should bloom and not so much reactive, but just let out in a flow state almost mastery, putting in the 10,000 hours. And remember, you are not in the right mindedness. Right mindedness is a virtue. And the book is meant to be a relaxing book. After you read it, you should be relaxing. You should be flowing. There should be self-discipline you need to take care of, creativity, mindfulness and combine this in your personal life as well. Complete Zen and meditation, archery, game. And here's a very interesting Robert Green quote. The future belongs to those who learn more skills and combine them in creative ways. And after reading this book, I need to do further research in Japan and Zen. It's Buddhism. I've only felt a little bit of it when I went to Thailand and Cambodia. And Cambodia had more of a Buddhism slash Hinduism, so it was very interesting to see that. Next is Zen and an Alan Watts type of talks. In your personal life, you can meditate when you drive. You can enjoy the sunrise and sunset while enjoying a drink, tea, coffee, and not in your face desires like social media and porn. Anything that hits that dopamine likes. Younger males be thrown into a zombie elixir splash, infected with porn, food, drugs, news, video games and optics. And just by reading this book or even this review, you can join the club of the unfettered mind. Drug induced can work and can open other parts of the mind. There is wealth of being aware and awake, not just pursuing cash and status. And you can see in the manuscript, there's a thing called monk mode. There's much more to it and more depth to it than just not having sex or abstaining from it or satiating those passions and desires. You can just focus simply on the zone. And as you can see, I read quite a bit. I just get in the zone when I read.  Those are the enemy, especially when the ads gotcha.   Don't stop and keep those feet moving and those melodies moving. And hopefully you can use this unfettered mind and freedom into your own game. That is the end game of Zen. You're definitely on the right channel. Must definitely pick up this book and chill to its vibe.


Wisconsin authorities are scaling back their ground search for a missing 13-year-old girl whose parents were shot dead, saying their investigation is entering a new phase. Barron County Sheriff Chris Fitzgerald says the search for Jamie Kloss remains his top priority and authorities will continue to analyze leads. But incoming tips have declined, so authorities are transitioning from around the clock operation to a more methodical approach. Jamie has been missing since early on October 15th when Sheriff's deputies responding to a 911 call found the door to her family's home near Barron kicked in and her parents James and Denise Kloss shot dead inside. Investigators believe Jamie was abducted and ruled her out as a suspect in her parents' killings.


calm down calm down you'll be okay it's not the end of the world anyway that's what they say that's what I want to believe when I'm overwhelmed out of my mind and I forget to breathe and these thoughts won't go away they tell me that they're here to stay I try to listen to the voice it tells me I'll be okay but what if I'm not what if it all goes wrong it has gone wrong now the thoughts come back and I'm back to square one no I don't do this just for fun I just want to run I know I'm not the only one the only one who seems to have a mental state darker than they'd like the only one who seems to have a mental state more confused than bright I just want to see the light I just want to see the light they say believe God then you'll feel better what happens when I believe God you'd feel the same was God's mission to help me believe I can handle this on my own or give us hope amidst the pain even when I feel down even when my soul cries out even when I'm overwhelmed even when I feel left for dead I can remember the things that he said I'm with you do not fear through all this he's giving us the grace to persevere because you are near God I can persevere because you're near I don't have to let these feelings consume me because you are near life can ruin me but your life was still shine through me because you're near I don't have to be shackled anymore because you were near these shackles can be thrown to the floor because this truth can be heard I want to believe the worst that you're telling me but I'm overwhelmed as you can see God can you take this from me? Can you ease this calamity in my soul? Father I want to be whole I want to be whole


What's good job? She bought us back again with another video. So we're gonna check out the Undertaker's funniest and worst WWE fails should be interesting. We all know the Undertaker He was the locker room leader man back in the day back in that early attitude era and pretty much any time He was around he was the The locker room leader everyone looked up to Inspired to be like the Undertaker when it came to just in-wing in-ring work and how he carried himself So it's rare that he has his little slip-ups and moments or whatnot So we're gonna check it out. And I'm pretty sure it's gonna be interesting and funny to watch appreciate all love and support I'll go to 60k and let's get right into it now. Come on Let's be fair the Undertaker is one of the greatest superstars to ever lace up a pair of wrestling boots He spent 30 years in the WWE as the phenom the dead man the lord of the darkness and in turn became one of the most successful characters of all time Although the Undertaker's been praised endlessly for his character work and match quality Even the Undertaker is prone to be involved in a fail from time to time Undertaker fails of all time Facebook for exclusive list Make sure y'all scribe to WrestleMania number 10 the Undertaker drops out Philips right on his head And the Undertaker's tombstone Paul driver finishing move was a perfect finishing move for the Undertaker It was the guy that made the move famous However, when he started doing the move there were Now we're able to still connect with our community we can still support our instructor a few times Where he would mishandled a superstar and drop right on their head a little bit too stiff with the spike This was the case in late 1991 when the Undertaker had a match with Al Philips on superstars Take it executed a tombstone Paul driver, but managed to spike Philips Oh No, so severe that Philips back appeared to have spasmed and there was deep concern for his welfare Especially from Vince McMahon on commentary who let out an audible curse word following the move Seems that Philips was okay though after the match Wrestletool Consisted of a number of notable segments, however, there was a promo exchange between In a number of hilarious mistakes the Undertaker's promo ability has never been discussed in depth over the years However, for the majority of his career he has cut promos as a dead man persona Yeah, that's naturally means he has a different promo style compared to most superstars on the roster now for this specific promo The material was quite simple when the Undertaker would stutter on a number of words was unable to save Wrestlemania Instead he said The Undertaker doesn't know what date Wrestlemania 28 is the undertaker not being able to pronounce WrestleMania wasn't the last time that it would flub up the promo segment with HPK three years later during the build to the Undertaker versus Triple H is Helena selling that was a fantastic The Undertaker would inform HPK in a promo that on April 21st that destiny will happen and on April 21st That destiny Now the problem was that the Undertaker got the date wrong for Wrestlemania In fact, Wrestlemania was set to take place on April 1st So dead man just clearly got his dates mixed up. Maybe it was in April Fools Number seven the Undertaker punches nobody During the attitude era and the ruthless aggression era It was common practice for superstars to have fun with the crowd This range from fun and engaging matches to extended promo segments which involve superstars breaking character Now without a doubt the most famous of these was the time Booker T attempted to get the Undertaker to perform a spin a rune Yeah, that was pretty cool. This was the hilarious segment which even involved Vince McMahon attempting the move and he didn't do too badly The segment also featured a fail which involved the Undertaker punching thin air The villainous group known as the un-Americans interrupted the segment before the baby faces in the ring took them out The segment were cut to the Undertaker punching an individual through the ring ropes But it actually looked like there was nobody there meaning Taker was just punching thin air Maybe he was hitting John Cena. Who knows? The Undertaker's tie-melt function and the Undertaker wore an iconic hat as part of his entrance for the majority of his rounds as the dead man However, there was a short period where the Undertaker would ditch the hat in favor of a hooded trench coat Yep, this alternative entrance and tie for the dead man would make an appearance at the Royal 1000s show It would stamp side-by-side with his brother Kane and the duo would fight a number of heels together Although the segment was a lot of fun It did feature a somewhat hilarious a time-out function for the Undertaker when Taker went to flick his hood after his entrance His hood decided to remain stuck on his head meaning he had to awkwardly mess around with the hood to try and get it off Number five, the Undertaker misses a big boot on John Cena A WrestleMania 34 would act as the redemption match for the Undertaker as the year prior He was supposed to wrestle his last match ever However, the match with Roman Reigns wasn't up to the quality that fans and Taker himself wanted This led to the Undertaker coming out of retirement for a high-profile match with John Cena The match itself was a squash match and he's known to show fans that Taker still had it in him Although the match was only three minutes in length This didn't mean that the match was absent from any fails as Taker would go for a trademark big boot on Cena He didn't come close to hitting it and miss Cena's face by a good mile Cena sold a big boot anyway and the Undertaker quickly realized that the fail could have altered the perception of the match So he quickly transitioned into the next spot. Thankfully for Taker fans quickly forgot about the aforementioned Fail as the match was pretty crap Yeah, the match wasn't that good The Undertaker's bike stools in the year 2000 I think I remember this segment Undertaker made the biggest risk of his career Decided to drop the dead man persona in favor of the American badass character This character would cut back on the darker elements of the prior persona and he would be much more accessible character for the audience Yep, the risk paid off and the character was widely popular. His American badass gimmick actually worked It legitimately worked. You still have the Undertaker feel but he talked more. He's more aggressive He let you know he come off as a badass legitimately with fans of all ages And it was so popular that Taker decided to bring the character back for his final match with AJ Styles 36 one of the things that made the character or so special was he would ride the ring on a motorcycle, but this didn't always go smoothly Take for instance the vengeance pay-per-view in 2003 Taker was set to face John Cena and unfortunately his bike stalled meaning he had to awkwardly get of his bike and walk to the ring It was hilarious, but no doubt embarrassing for Taker Number three Considered to be a dream match to many 2019 it was a long time coming The match was a complete disaster Sighted as a worst match of both superstars as respective careers There were a number of rather unfortunate mistakes in the match including Goldberg dropping the dead man right on his head following a jackhammer However, this wasn't the only time that the two men would drop right on their head When Taker went for a tombstone on Goldberg He somehow dropped the former world champion right on his head Luckily Goldberg didn't appear to be hurt from the spot, but a near 300-pound man Consequences awful match Number two the undertaker versus Roman Reigns is WrestleMania 33 main event Now as we've already mentioned in this video the undertaker's match with Roman Reigns at WrestleMania 33 was initially intended to Be Taker's last match ever Yeah, sadly the match fell apart and it featured a version of the undertaker that simply couldn't hang with Reigns Yeah As a result there were a number of notable mistakes in the match and one that fans Infamously remember when Reigns was supposed to counter a tombstone attempt from the undertaker in his own Sadly though Taker was far too exhausted to do this and he was unable to flip himself in order for Reigns to easily lift him into position After a number of attempts the spot was completely abandoned Improvised and transitioned into the next plan spot in the match and number one the undertaker's dive at WrestleMania 25 Considered by many to be the greatest WrestleMania one of the time The showdown between the fantastic match Michael's at WrestleMania 25 was epic in every sense of the word now Although the match quality was undeniable It did feature a mistake that could resulted in a serious injury for the dead man The undertaker went for a dive to the outside and the plan spot was to have him involved the cameraman Capturing him so that Taker would have a safe and secure landing However, the cameraman failed to catch the undertaker meaning he nearly landed on his head.  I've watched this live Oh my god Oh my god, bro He was incredibly fortunate that Taker didn't suffer some kind of serious head or neck injury According to Taker the referee was directed to call the match as a shoot meaning if Taker failed to get in the ring Following the mistake, he would have been counted out and HBK would have broken the streak by a count That's interesting. I didn't know that didn't I know that man Wow, that's crazy That was still one of the best matches of WrestleMania history of all time. Definitely one of the best matches, man But comment down below Let me know you guys enjoyed this video What other WrestleMania and other wrestling content you want me to check out link it down below in the comment section Appreciate our love support roll to CCK. Appreciate y'all kicking with me. I see y'all next week


going on everyone. Sam here with latent sports cards. We are ripping 2022 tops museum collection baseball hobby, six box half case break. Number 37 pick your team style. Let me read off the names and the teams. Adam P with the Marlins, Andrew S Cardinals, Brian F raised guardians Kazdan R Rockies, Chris B with the Blue Jays, Danny C Giants, David W Pirates, Irvin S with the Diamondbacks, Eugene L Angels, Gregory M Yankees, Phillies and Dodgers Ian B Mets, Jonathan Q Red Sox Astros, Judith G Orioles Nationals, Lawrence H with the Cubs and White Sox, Lawrence Takenbull Chicago teams, Mitch L with the Mariners, Steven S with the Athletics, Steven U Brapes, Timothy M Tigers Rangers, Troy L with the Reds and the Brewers, Tyler R Royals, William S twins and William Q with the Padres. Thank you to Tyler and William for selling us out as well as Jonathan. Thank you guys so much. Good luck. What's up Christopher? What's up Troy? Troy, how you doing buddy? Troy. It's one of the first times I feel like I've seen you in chat, man. You're always binding the breaks. We appreciate you. Appreciate you, my man. We got probably a big brewer now.  That'd be awesome. Nice framed auto. Yeah, who do we got left in the next one? We got another the second half case of this coming up right after. Three to go. What teams would those be Sean? Tigers, Padres, Cardinals. Tigers, Padres, Cardinals left. All right. First mini box of select or not select museum. Got CJ Abrams rookie. That's going to be a Don Mattingly. We've got first hits going to the Reds. 11 out of 75. Joey Vado on the quad. Nice one there. Sinti. Yeah, I know. I saw that Christopher. I appreciate you, buddy. Freddie Freeman to 99. I was telling Sean that today. I was like, I got, I got in twice on top 10 bulls this week. So I'm feeling pretty good. I own one fifth of the, all the spots on that video. So not too bad. Not too, too bad at all. Plus, I got number two, which is pretty solid. The Meryl Super got two. Mariana Royce Lewis rookie followed by an Araldis Chapman, two color, two color, 18 out of 25 for the Yankees. Congrats, New York on the Cuban missile and a Francisco Lindor copper. Let's go Dolphins. Juan Soto. There's a Francisco Lindor five out of 35, two color patch. Nice one there. Looks like from the the black jerseys. That's sweet. And a J rod rookie on the copper. Congrats on that. I appreciate you, Christopher. It's awesome, buddy. Yeah, it's pretty fun, man. I always like seeing what makes the top 10 polls of the week. There is something thick in this one. There is something huge in this one. There is a booklet. Oh, it's an Atelier. Really? It is an Atelier. Juan Soto to 150. How about all the slider boxes? Who's keeping for you? Right? This one's full. This one's almost full. We got another two cases. They're going to get another 48. All right. We got Yellich, Strasberg, Honest Wagner. We've got an Atelier autograph book card. Good luck, everybody. It's going to be Jesse Winker going to the Reds. Congrats, Reds. That is numbered 12 out of 25. Love the Atelier booklets. Pretty dope. Cincinnati is going to be where are the Reds? Of course, I can't find them. Troy. Congrats, buddy. Nice one there, Troy. Sweet Atelier, man. So awesome with the gold ink and the ballpark in the back. Congrats, man. There you go. It was a Choku's Jesse. He's pretty solid. He's a Mariner now. All right, box two. This case is already solid, man. Oh, no. There he is. Congrats, Troy. Sweet one, man. Congrats, buddy. Thanks for taking a couple of spots. Appreciate you. Got Jean Seguira, 23 out of 35. Two-color patch for the fills. Oh, nice. Thank you. And Blue, Frank Robinson to 150. Orioles. They're in the process of it right now, Collectors World. It's just like there's so many orders there, like working basically around the clock to get all the ship it. So should be in the next couple of days between now and, like, what's the day? Tuesday? Tuesday. So yeah, between now and, like, Friday would be my guess. Yeah, they knocked out a lot of it, man. They did. Hunter Green going to Troy on the rookie autograph. Nice. 103 out of 199.  Beast archival autographs and hobby bias. Yeah, reds are on fire. Troy is killing it with that spot, man. What's up? Yeah, I would say so. Yeah, no problem. No problem, Collectors World. They're going as quick as they physically can, man. There was a lot of orders. There's a Salvi Perez, I believe that is. Yep. So many of them. Royals. And another Royal, this time Whitmerefield. 379 out of 399. I would say we probably sold at least 1500 boxes. Way more than that, I think. More than that, you think? I think more than that, dude. Chris Bryant. Between both gaming games. Oh, between both. Between both, it was probably 2500, 3000. Easy. Easy, yeah. It was insane. Because, I mean, there's people that ordered, like, five or six cases of stuff. Yeah. A lot of stuff. A lot of stuff. Our entire, like, sorting and shipping area is just full of boxes right now. It's actually kind of wild. Hunter Green rookie. What's up, Joshua? Josh. Got Anthony Rendon for the Angels to 99 on the Quadgers and Anthony Rizzo. Two to go now on our next. What up, Josh? Only ordered 50 cases. Yeah, Joshua ordered 50 cases, I'm pretty sure. Andy just called me Caleb again. Time out. Time it up, Joshua, for five minutes. Yeah, you've done that, like, three times now. I love it.  No, just keep calling Caleb. Oh, this is the Andre Blatch fan club. I am so in on Andre Blatch, dude. Wizards legend, Nets legend. Oh, Andre Blatch was the man, dude. We need Andre Blatch autographs. Anthony Rendon? There's Luis Castillo.  Troy, you are having yourself a break, buddy. Congrats, man. Nice Castillo. Reggie Jackson. Back to that. All right. Andre Blatch. Holy cow, man. Jared Durant. There's a big poppy. And Gleaver Torres, 24 out of 25. Nice one there for the inks. Two-color patch. Willie Mace. Copper. Dang, man. That's a good one, though. At least Caleb isn't a Ravens fan. Yeah, but Caleb's a Browns fan. Is that really any better, Rob? That can't physically be much better. Yeah, it's very true. George Kirby. There is Nico Horner going to the Cubs. That is seven out of 15. Nice one there. Looks like the city connectors. These Cubs is, I believe, Lawrence. Lawrence took both the Southside, or both the Chicago teams, and a blue. Blake Snell to 150. Yeah, honestly, just need to pull a bench. You got pretty much everybody on the checklist. It feels like all the big, big names, at least. Danesby Swanson on the Quad. For the, yeah, I know Joshua. It's brutal, dude. Rob's never have a lead. Also true. Bobby Whitrookie. Copper. And Shane Beiber Copper. Nice one there for the Royals. All right. Three to go here, guys. Let's see what we got. There is, is that a Wander? Nice. Wander Franco on the Campus Collection. Gorgeous card there for the Rays. Dude, the one-on-one sketch of that must be so nasty. Holy cow. That is Bryce Harper to 75. And Jose Altuve. Some guy at the Jags Ravens game. I saw I went to the Jags Ravens game, unfortunately.  And I looked at him like, Trevor Lawrence is six and 21 is the starter. And he was like, oh, yeah, we'll forget about that. Now he's seven and 21. So congrats. Congrats, Vaughn and Randy. Trevor Lawrence has a two-thirds chance to lose every time he steps on the field. There is Reese Hoskins. 12 out of 50 going to the Phillies. Nice one there, Philadelphia. The Powder Blue and the Fincher. George Brett Copper. Our defense is so bad. Our defense sold so hard on that last play. That's also true. That's also fair, fair, fair, fair. I'm a man of fairness and that is fair. Ian Anderson, one out of 50 for the Braves on the meaningful material. And Mookie Betts to 99. Trashcan Relics and Astros cards. That would be funny. Yeah, you're like a big, apparently a huge fan of the Astros. Got our framed card coming up, guys. Good luck, everybody. Piazza Alonzo. Torkelson Rookie. We've got Greg Maddox, one out of 10. Going to the Braves. Congrats, Atlanta. The Professor. Going to Stephen Yu. Congrats, buddy. Nasty Maddox right there. Loved me some Greg Maddox, man. Round of the Cunha. That's Padre's legend, Greg Maddox. That's Cubs legend, Greg Maddox. Insane Maddox right there. But golfing's the middle of baseball. Anyplace, anywhere, anytime. Maddox is sick. Who did someone say a Suzuki rookie? Ernie Banks. Canvas collection of Yachty. And there is Louis Heel, rookie to the Yankees. And Albert Pools. Scorned me on the Trashcan comment yesterday. Yeah, man. Xander Bogarts. There's Max Kepler, 38 out of 50. Going to the Twins. Raphael Devers. They're just really good. Yeah, I mean. They're tough, dude. I don't know how many, but they're really good. They're really good. And they just signed Jose Berre. Dude. That's scary, dude. I watch a thing this afternoon about their lineup. It's ridiculous, dude. It is really good.  I kind of agree with you until this year. And they won it fair and square this year. And they were bought. It was their, it was their war to lose. 100%. They were head and shoulders above every, better than everybody else. Nasty. Nice. Jose Ramirez going to the Guardians 25 out of 199. Guardians were pretty lasted for a while. Brian F. Congrats, buddy. And blue Roberto Clemente to 150. Like, I get if you are like a fan of a rival team, like someone else in the ALS. I get really hating them still, but I would say I grew with Vaughn. The ring this year validates them a little bit more. Yeah. Yeah. And they're going to keep doing that. I think the way they look. Yeah. That is one Soto Superstar showpieces. Boom. We didn't time you out, Rob. Don't worry. Nationals. Judith G. Congrats, Judith. Sweet card there. Let's go, man. What a break we had so far. We'll get that into a mag for you, Judith. Plus we have an air yard on behind that to 99. And Mickey.  Like, I still get it for sure. But I have to say, like I said, up until literally like a month ago, I was still all in on the Astros hate trend, but now that they want a series fair and square, like, a lot of those people are going to do this. That's true. Yeah. Korea is gone. What's his name? There's a pinch is gone. Beltran's gone. Some of the pitchers are gone, but Altuve's still there. Fregman. Never hear the end of it. Neither were Fregman. Yeah. Yeah. Speaking of Fregman right on top. Bobby Whitrokey, Shane Bieber, Otto, Sharon Durand, 101 out of 2.99. Is that Jonathan Q? Yes it is. Jonathan. Congrats, buddy. JQ. JQ, baby. Grats, man. Nolan are not. Trashcan relics would be pretty funny. I would agree that would, I would enjoy that. There's a Aaron Judge canvas collection followed by his Monty Grindal to 25 three color patch for the White Sox going back to Lawrence and Baber. Yeah. Do you imagine how mad the MLB would get?  Yeah, that's true. I would be, I was kind of happy for Dusty Baker. Dusty Baker deserved, deserved a ring. There's J-Rod Rookie and Eloy, the 100 for the White Sox. And Red, Joe Ryan Rookie, 12 out of 50 for the twins. Oh yeah, you weren't dumping on them constantly, Rob. No, just, I just brought up a discussion, like, of, you know, the, like the after, like the general overall feeling of the Houston Astros around the MLB at this point, you know, it's, it's just interesting. It's interesting to see how much people have changed over the past couple of years. That is, wow. Tony Gwyn, 11 out of 25, Mr. Padre. Nice one there. Congrats, San Diego. That was the last team taken. Padres, William Q. Congrats, buddy. Nice game use, Tony Gwyn, Raleigh. That is so cool. Love me some Tony Gwyn. And Clayton Kershaw. I never really watched Tony Gwyn. Did you? Oh yeah, you tell me about that. That's right. Elevator with Dylan. That's cool. All right, do a quick recap here. Ha ha ha ha, Vaughn.  Tony Gwyn, Padres, Yasmine Grindal, White Sox. That is Jordan Alvarez, Astros, Max Kepler, Twins, Ian Anderson, for the Braves, Bryce Harper, Phyllis, Dansby Swanson, Braves, Glaber Torres for the Inks, Anthony Rendo, Angels, Jean Seguira, Phyllis, Francisco Lindor, Metz, and Joey Vado for the Reds. I don't know what happened. Rob, neither of us timed you out. It must have been Eloy Jimenez for the White Sox. That is Jaren Duran, Red Sox. Jose Ramirez for the Guardians, Luis Ciel, Yankees, Rhys Hoskins, Phyllis, Nico Horner for the Cubs, Luis Castillo-Reds, Whitmerfield-Royce, and Earl Chapman-Yankees. The Cubs won 35 more games. They might add a shot. That's funny. Atelier booklet was Jesse Winker to 25 for the Reds. We've got Hunter Green to 199 for the Reds, as well for the Reds. We had a nasty one, Soto 24 out of 25 going to the Nationals, and a Greg Maddox, Framed Auto 1 out of 10 for the Braves. Gotta do it for the Braves, guys. Thanks again for the fill. Next up is the second half case. It's a good luck.