The knee pull is something that physically we can do in between to help from the tie to the actual leg attack and being in good position. So what we're going to do is I'm just going to get my arms linked away from this guy and I'm going to squat down. Now as I squat down, I want to split my body in half with his leg. So I'm going to get close enough to where I'm going to be right here. Inside hook on his knee. I'm going to have an inside hook on his knee. This is an anchor. This is a knee pull. We can knee pull to a high crotch, knee pull to a single. So all I want you to do is lock into his knee. I want him to get his feet heavy so I can pull off of it. And I just want you to kind of hop here and get light. On your single leg side, I want you to pull yourself to it. I'm going to open my hips, get my shoulder glued and open his knee up. On your high-cropped side. Again, I'm inside anchor right here. I'm just going to hop right here a little bit and I'm going to pull. I'm pulling on the back of his knee and I'm getting my hips in. This is a good transition when I get ready to shoot. Right here. It locks me into the leg and it pulls me to his thigh. It pulls me through the attack. That's all we're going to do. He's going to be in front, kind of scarecrow. I'm going to squat down. Notice it's the length of my arm. I want you to start as close to his leg. I want you to hold on. Just kind of bounce a little bit and then hop and pull. Same thing on your high-cropped side. Inside, hop and pull. Outside, step up. Bell buckle, attack the knee. Both sides, good bit. Go!


So the topic of today's lecture is going to be about the adversary method, the general adversary method. It will be the last method that we will see. But before that, I would like to finish the proof that we started last time about this recording technique. So let me go back to the last slide of last lecture. So if you remember, the goal was to obtain a lower bound on the quantum query complexity of the search problem. And for that, we defined this quantum recording framework. And at the end, we had this projector pi, which projects onto a basis state that have recorded a 1. And we wanted to bound the progress measured delta t, which was the probability of observing a 1 if we measure this state in the quantum recording model. So initially, the progress was equal to 0. And the proof that we started was about showing that it cannot increase faster than about 1 over square root n. So we already show that the increase was, at most, the norm of this particular quantity that we have to bound. So it was what we want to prove. So the claim that we still have to show is that if you take a state after t query, so psi-req-t, and if you project onto the basis state for which you haven't found a 1 yet, and if you do an extra query, then the probability of observing a 1 is going to be at most square root t over n. So this was the last missing piece. So we will actually show something stronger, which is the claim which I wrote at the bottom of the slide, which is actually a stronger claim is that for all state psi, which is in the kernel of the projector pi. So being in the kernel means you haven't recorded a 1. So for all such states, what you'll get is that if you do one extra recording query, the probability of observing a 1 is going to be at most square root t over n times the norm of psi. So if you just plug identity minus pi times psi-req-t into this claim, you get the result that you want to show. So how to prove this claim? So let's take an arbitrary state psi in the kernel. So let's take psi being in the kernel of the projector. And we'll just write down this state as being a sum over all x i b. You have some amplitude alpha x i b. Then you have x containing the record, answered with i b containing the query index and the output register. And if it is in the kernel of pi, it means that the value 1 is not in x. So this is like an arbitrary state in the kernel. And now we will further decompose this state into n plus 2 mutually orthogonal quantum state. So we decompose psi as follows. So the first state is going to be what I denote by psi id. So this just keeps the amplitude for which b is equal to 0. So it's going to be all the x i b such that b is equal to 0. This is the first one. The second one is noted psi empty. So this one is going to be all x i b such that b is not equal to 0. And x i is equal to the empty symbol. And the last n states are going to be indexed by a value y. So for each y being between 0 and n minus 1 and n, we define psi y as being the same except that x i has to be equal to y. So b is non-zero. And x i is equal to y. So the support of these joints, and if you take a summation over all of them, you just recover the state psi. So what we want to do is to bound this quantity here for each of those states. And then we just apply a triangle inequality. So let's start with the first one. So what is the norm when we start with psi i d? Apply a recording query and then project. Does someone have the answer? So psi i d, it was defined as having b equal to 0. So if you remember last time, when b is equal to 0, nothing happened if you apply this recording query. So this is just going to be equal to 0. So I can remind you how this recording query was behaving for each basis state. So when b is equal to 0, nothing happened. So second case, what happened if this is applied on psi 1? On psi 1, let's say psi 1. This is also 0 because psi 1 is equal to 0 by definition. So psi 1 has no support for the projector that we are considering. So those two cases are easy. Then third case is what happened if this is applied on psi with x psi being equal to the empty symbol. So this is an interesting case. So for that, what we will do is we'll just use the first equation, which tells us what happened if we apply error on a position where there is the empty symbol. So this is what we want to compute. So let's do the computation for that case. So what we know is for any state x i b, which is in the support of psi empty, we have the following result. So if we apply a recording query on that state, what will happen by the first equation is that all the coordinates will remain the same, except the highest input coordinate, which will be replaced by the quantity in red. So this is going to be, so let's use this notation x with an i, i b, where it means that this new input at position i, it is equal to 1. And at a position which is not i, it is unchanged. Just a single coordinate is modified in this basis state. So this was for a single basis state. So now, what if we apply that on the full state psi empty? What we'll get is, so when we apply on the full state, OK, so here what I computed is not error. It's like the projection. I just kept the coordinates for which x i i was equal to 1. And you have a 1 over a square root n. So we take a basis state. We apply the operator error defined on the top. And then we project only on the component for which there is a 1 in the support. So if you have the superposition in red, there is just a single term that will be kept. And this is the one for which you have y is equal to 1. And you will have a phase, which is going to be omega to the b.  So this is the effect of doing a recording query and then projecting. Now, if you just look at the norm of that state, what you'll get is that this is equal to 1 over a square root n times the norm of the original state. So making one query, just the effect of doing a query is that we have a new amplitude that appears, which is omega to the b over a square root n. So this is how we get this equality. And finally, the last case. So this is for those states psi y when y is not equal to 1. So I'm not going to do the computation. This is similar to what I did. You just have to use a single equation, a second line. What you will show is that this is at most 3 over square root n times the norm of psi y. So in the second case, we have a factor 3 because of this error term in blue that we have when we apply a recording query in this case. So how we conclude the proof? Well, we have all the ingredients. We just have to apply the triangle inequality. So this quantity that we wanted to bound by triangle inequality is going to be, at most, 1 over square root n times the norm of psi mt plus a summation over all y of 3 over square root n times the norm of psi y. And if you apply Cauchy-Schwarz, so this is triangle inequality, and if you apply Cauchy-Schwarz on this quantity, what you get is exactly square root 10 over n times the norm of psi. Is there any question on this proof? OK, so this is all I wanted to say about this quantum recording technique. There are still some subtleties in the proof that I didn't mention. And they will be studied during the problem session. But most of the argument are here. OK, so let's move to the next topic. This is the last method that I would like to show you. This is this generalized adversary method. So today, we'll see the lower one part. And tomorrow, we'll see how this method can give you also quantum algorithms. So this adversary method has some advantages over other method that we showed previously. The first one is that this is always optimal. In some sense, it will always give you the optimal lower bound on the query complexity that you are looking for. As we will show tomorrow, it can actually be turned into an algorithm. On the other hand, it is often harder to apply than other method that I showed you, such as the recording technique. So it is a kind of a generalization of the hybrid method. And also, it is strongly related to the recording technique. So you will see some ideas that we mentioned before to be used again in this method. I guess before describing the method, let me start with two reminders of a result that we already saw in previous lectures. The first one, which we show in the first lecture, was this distinguishing lemma, which tells you that if you want to distinguish between two quantum states produced by the algorithm on two input x and y, then in some sense, you have to have those states being orthogonal to each other, or almost orthogonal. So if the algorithm succeeds, then it means that if you look at the output state, when f of x is different from f of y, then there must be almost orthogonal. The second idea that we saw when we talk about this recording technique was the purification viewpoint, in which when we have a distribution on the input, let's say distribution px, for the recording technique, it was a uniform distribution. Then we can, as well, put this distribution into a quantum state that encoded this distribution into the amplitudes, and then control everything, control the query, unto the value contained into this purification register. And if you trace out this register, you just recover the usual framework that we studied before. So we will use those two ideas in defining the quantum adversary method in a slightly different way. OK, so let's first look at the construction, and we'll see an application at the end of the lecture. So the first step of the construction for the quantum adversary method will be to kind of generalize this purification viewpoint, where instead of having non-negative real numbers for the purification register, we can just take complex numbers in the amplitude. So what we have as input is like a quantum state of unit norm with complex vector. And as before, we just do the same thing, so controlled on the value contained into the purification register, we apply the oracle ox. So this is the same as having sampled the input from the distribution where x is obtained probability squared of the amplitude. OK, on this side, this is a joint state of the purification register, the input, and the state of the algorithm. OK, so we can choose any AX, but you'll see that a particular choice is done in this quantum adversary method. So the second step is to look at the following gram matrix obtained by tracing out the input register. So this is a matrix which is indexed by all possible inputs. And in the entry x, y, what you have is the inner product between the state of the algorithm at time t, when the input is x or y, times the amplitude of those input under the input distribution. Because it kind of encodes all the possible inner product between all the possible state of the algorithm memory. And finally, the last step is to choose and to place some weights denoted by gamma x, y on all pairs of inputs. And those weights, you want to choose them to be important when the pairs of input that you consider, x, y, is supposed to be hard to distinguish. So the way those weights are chosen is part of the application of the method. So two conditions, which seem to be quite natural about choosing those weights. The first one is you expect them to be symmetric. So in some sense, you have the same weight on the entry x, y, under entry y, x. And secondly, when two inputs give the same output, you just take weight equal to 0. In some sense, you don't have to distinguish those input because they give the same output. So this is what we call an adversary matrix. Just saying it again, this is a real matrix, which is both symmetric. And when f of x is equal to f of y, the entry has to be equal to 0. Now, this is how we choose the adversary distribution, given a particular adversary matrix gamma, we choose a to be the principal eigenvector of gamma, normalized to be of unit norm. So this is, in some sense, our input distribution, our hard input distribution. And we will also define the following object, which will be important in the method.  There is one such matrix for each possible index i between 1 and m. And this is the same as the adversary matrix, except that you remove the inputs, the entries, for which xi is equal to yi. So imagine you are doing a query on index i. Then this matrix is only giving you information about the pairs of input for which you would observe different outcomes for the query. So those are the three important definitions that we will have to manipulate. And now this is how we define a progress measure in case of the adversary method. So it's going to behave quite similarly to the progress measure that we saw in the recording technique and the hybrid method, but slightly more complicated to bound. So this progress measure is, again, defined at time t, so after having done t quantum query. And there are two equivalent definitions. One is obtained by taking this joint state psi t of the input and the state of the algorithm. And the other one is by taking this entry-wise product between the adversary matrix gamma and the gram matrix that is displayed here. So the two definitions are equivalent. So far so good. So now we can prove some results about this framework. So those are the three most important statement about the adversary method, which tells you how the progress evolve when you make quantum queries. So as before, you will have an initial condition. So initially, the progress is equal to a certain quantity. Here it's going to be the spectral norm of the adversary matrix. Then you have a final condition, which is implied by the algorithm being correct with probability at least 2 third. Here it will be that at the end, it must be smaller than the spectral norm by a factor of, let's say, 0.95. And finally, the last lemma is how much can you decrease this progress measure by doing one query. And this will be related to the spectral norm of those gamma i matrices. Because if you have those three results together, it tells you something about how many steps, how many queries you have to do in order to solve the problem that you are considering. Okay, so let's prove each of those three results separately. So once again, it doesn't tell you how to choose the adversary matrix gamma. It just tells you that once you have chosen a particular matrix gamma, adversary matrix gamma, you can obtain such types of inequality. But of course, finding the right gamma is one important part of the problem. Like it will depend on which function you want to solve. Okay, so let's start with the first lemma. This is the easiest one. So let's just look at the definition of delta 0. So this is the initial state psi 0 that we have to compute in this inner product. So psi 0, by definition, this is the joint state of the input on the algorithm. So for the input, we have taken the adversary distribution A, which corresponds to the quantum state that encodes A into the amplitude. And the initial state of the algorithm is just the whole zero state. Okay, so delta 0 is just equal to A times 0, 0. Then we have gamma times third identity. And then again, we have A times 0, 0. Okay, so this is also A gamma A. And because A was chosen as being the principal eigenvector of gamma, this is a spectral norm of gamma. So this is why choosing A being the principal eigenvector was important. This is the choice that maximizes the initial progress. Okay, second step is about proving that at the end, delta T, the final progress, has to be sufficiently small if you want the algorithm to be able to succeed, with probability at least two-thirds. Okay, so let's define first the projector that can be used to characterize the success probability. So projector pi success. So given psi T, I want to project onto the space that characterize the success, the algorithm having succeeded. So what I do is I take a summation over all inputs, X, okay? Then I have identity, because the success does not depend on what is in the index register. And finally, in the last register, on input X, what I want to have is f of X. Okay, so you succeed if you manage to have f of X in the last register when the input is X. Okay, so the success condition. So what does it mean that an algorithm succeeds probability at least two-thirds? The success condition means that if you apply this projector on your final state, so psi T after T quantum queries, it has to be at least two-thirds, so the squared norm. Okay, so this is what we can use in doing the proof. What we will use. So, okay, so having that in mind, let's try to upper bound the final progress. So delta capital T. Okay, so first just to recall the definition, this is psi T, gamma-transferred identity psi T. Okay, so what we will do first is we will decompose this into four quantities as follows. So what we will do is we will split, we will add the projection by success and identity minus pi success in between psi T, the inner operator and psi T again. Okay, so this is what I mean by that. So we'll have psi T, pi success, then gamma identity, pi success, psi T. So this is the first term and then we just have to add all the possible other terms. So the second term is going to be the same, but here we have identity minus pi success. Okay, gamma identity, then identity minus pi success. This is the second term. And then we have the cross-terms. So the third term is going to be identity minus pi success and here I have just pi success. Okay, and then I do the same thing but the other way around. So here I have pi success and finally identity minus pi success. Okay, so I also apply the triangle inequality to do this decomposition. Is it clear to everyone why we have such an inequality? Okay, so we want to bound each of those four terms separately, so there are two easy cases which are when we have pi success on both hands or identity minus pi success. So those two terms are equal to zero because... So this is equal to zero and this is equal to zero. Okay, and this is because we have this constraint that gamma xy is equal to zero when f of x is equal to f of y. Okay, so in some sense only the cross-term will matter. Okay, so this is the result for which the first two term are equal to zero. Okay, so we just have to focus on those terms. So let's continue the proof from this step. So delta t. So by applying Cauchy-Schwarz inequality we can split each quantity into two parts. And what we'll have is two times the spectral norm of gamma and sub-identity, then the projector pi success apply on psi t times the projector identity minus pi success apply on psi t. Okay, I just use Cauchy-Schwarz inequality on each of those two quantities. And in both cases I obtain the same thing. So this is why I have a factor two and this is what I get at the end. Okay, so we are done because we can write this as follows. So the spectral norm of gamma turns out identity is just a spectral norm of gamma. So this is two times the spectral norm of gamma times this pi success apply on psi t. And then identity minus pi success, this is also one minus pi success apply on psi t. Square might take a square root. It's just writing it differently. Okay, so now we can just conclude by applying the success condition which tells us that this success probability is at least two-third. So if we apply it on this last term, it tells us that this is going to be at most two times spectral norm of gamma times square root two over three. Okay, so this is the proof of the second lemma. And finally, the last part of the proof is to show the increase condition, okay, which is that when you do one query, the increase, the decrease is at most two times the largest spectral norm over all the gamma i. Okay, so let's prove this last result. So this is the lemma three. Okay, so what we want to bound is the progress at a time t minus the progress at a time t plus one. This is what we want to upper bound. So we might as well take the absolute value of this quantity, which by definition is going to be psi t, gamma identity, psi t. So I just upper bound the difference by the absolute value of the difference. Okay, so psi t plus one, how do you obtain this state?  But ut plus one and gamma times identity commute, so you can just remove this ut plus one. And so this is equal to psi t, gamma, and solid identity psi t minus psi t. Then you apply just one query, gamma, and solid identity, a query again, and you have psi t. Okay, so if I just expand the definition of psi t and gamma, this is also equal to a summation over all x, y. Then I have gamma x, y. I have ax, ay dagger. And then I have psi x, t. Let me write it on the other board. Again, just expanding the definition of gamma and psi t. So this last term is equal to a summation over all x, y of the x, y entry of the adversary matrix times the x and y entry of the adversary distribution. And then you just have the state of the algorithm on input t, on input x, times identity minus o x, o y. So the oracle corresponding to input x and y. And then again, the state of the algorithm on input y. Okay, so a claim. So we want to understand what this operator, identity minus o x, o y is doing. So my claim is the following. So identity minus o x, o y is actually equal to a summation over all index, all query index such that xi is not equal to yi of a projection on index i, turns out identity minus the not gate. So this is kind of reminiscent to what we saw in one of the proof for the polynomial method. Okay, so this, it is just supported over indices for which the query is giving you, is giving you a different outcome. And then you have identity minus x. Okay, so, okay, I'm not gonna prove this claim. You can just do it in a case-by-case analysis. It's very simple exercise. Okay, so let's use this claim to continue the proof of the upper bound on the difference. Okay, so now I can replace this identity minus o x, o y by this summation. So it means that now I have a summation over three quantities, so x, y, but also a summation over all possible query indices i. Okay, and then, so the summation is only be supported over i such that xi is not equal to yi. Okay, because this operator otherwise is equal to zero. So equivalently, I could just take a summation over all x, yi, but instead of having the gamma matrix, I could have the gamma i matrix. So this is where the gamma i matrices appear, okay? Because gamma i is zero when xi is equal to yi. Okay, so this is why we had to introduce those gamma i matrices. So I have the same summation as before, except that gamma x, y has been replaced with punctured matrix. Okay, so then again, x, a, x, i, y, dagger, then xi, x, t, then i, i, minus x, and then xi, y, t. Okay, so we are almost done. So what we want to do is we want to apply again a Cauchy-Schwarz inequality on this term. So, okay, it's not immediately obvious how we should apply it. So let's just express this quantity in a different way, which is gonna be more convenient to manipulate. So this is equal to, or this is at most, okay? Let's put the summation over i outside the absolute value. So this is at most summation over i, here then absolute value. And then we have xi, t, so the joint state of the input and the algorithm memory. Okay, on which we apply this i, i projector, transferred a square root of the node gate. Okay, then we have gamma i, transferred identity. Okay, then I again apply i, i, square root x, psi, t. So this is for the x part, and I also have to take into account, I think I'm missing a factor two in the equation, so I think we should have a factor two. Yeah, yeah, so I have an identity missing somewhere, I guess. Let me see. Oh, I see what I'm missing. So I have that plus the same thing, but instead of x, I have identity. So I have that, plus the same thing, but instead of x, I have identity. Okay, so I just apply Cauchy-Schwarz on each term independently, so I will have two times. So the square root x will vanish in the process, so we have two times. Then summation over all i of the spectral norm of projection on i, transferred identity apply on psi, t, square. Okay, multiply by gamma i, which is inside the, okay, so I can just pull out this spectral norm of gamma i by taking a maximum. So this is two times the largest spectral norm of the gamma i, maximum over i, times summation over all i of projection on having i, i in the first index, psi, t, square. Okay, I just upper bound each individual spectral norm by the maximum to put it outside. Then it just remain a summation over all i of those projectors. And now this quantity is exactly equal to one. Okay, so this is equal to one. Okay, so what remains at the end is just two times the largest spectral norm. Okay, any question on this proof? Okay, so let's move to the next part. So if you just put those three lemma together, then you arrive immediately at the following result, which is that the quantum quick complexity is always larger than the following quantity. So you take a maximization over all the possible adversary matrices because the proof was done for any adversary matrix. And if you combine those three lemma together, you obtain that this is at least the norm of gamma over some constant time, the largest spectral norm of some puncturn matrix, gamma i. Okay, so you want to choose the best possible adversary matrix that would maximize this right-hand quantity. So of course, the natural question is how to choose this gamma matrix. So there is no general recipe, but there are some property that we can, some property that we can say about certain types of choices. So the first choice would be to only look at adversary matrices that are non-negatives, for which each entry is non-negative. So this is quite close to the hybrid method. And it has been studied, I mean, this is the first type of adversary method being studied. So one advantage of this type of choice is that it has a nice combinatorial interpretation that you will see in the problem session. But on the other hand, having non-negative entries implies some strong limitation on the type of lower bound you can show. So in particular, there are two types of barriers that you cannot break with this type of adversary matrix. One is the so-called certificate complexity barrier. So in some sense, if your function has not a nice certificate complexity, then you won't obtain a good lower bound with this method. An example of such a function is the element distinctness function. So it will not give you optimal lower bound. And the second limitation is the so-called property testing barriers, which tells you that if the input to your problem satisfies some kind of property testing properties, meaning that inputs for which output has to be different that far apart, then again, this method is not gonna give you optimal results. So if you want to kind of break those two types of barriers, you have to move to a more complicated and maybe less intuitive adversary method in which you have to choose certain entries being equal to zero. So this is called the negative weight adversary method. And with this type of choices, it's possible to break those two types of barriers. And actually, you can do even more than that because it has been shown that if you choose negative and positive entries, then there always exists a choice of gamma that will achieve the optimal quantum query complexity. Okay, so not only it is a lower bound, but it is also an upper bound. There is a matrix gamma that will exactly give you the right quantum query complexity. So we'll see some implication of this result in next lecture. And in particular, we will see a constructive proof of this result, meaning that if you give me an optimal adversary matrix, there exists a way of turning it into a quantum query algorithm that matches this complexity. Okay, so it's like a really beautiful result, I think, and this will be the topic of tomorrow's lecture. Okay, so maybe let me just take one minute to give you a very simple application of this adversary method. And you will see other application in the problem session. So this is just for the or function that we already saw in previous lecture. Again, just focusing on the hardest inputs. And in that case, this is what is an optimal choice of adversary matrix. So for the gamma matrix, it is gonna be equal to zero everywhere, except in those entries. So for instance, in the entry indexed by the all zero string on the string containing one at position one, you will have a one in the adversary matrix. Okay, so this is really the most intuitive choice of an adversary matrix. So it is symmetric, and you just put a weight equal to one when you have a pair of hard inputs to distinguish. Okay, and gamma i is represented on the right. It's almost all zero matrix. That is just two entries equal to one. And if you compute the spectral norm, you will see that you will obtain square root n and one. So the theorem implied that the query complexity is at least square root n over some constant. So just to give you a flavor of tomorrow's lecture, how to prove this optimality of the quantum adversary and how to turn it into a quantum algorithm. This will rely on using SDP duality theorem. Okay, so it turns out that this right hand quantity is an SDP. And when you have an SDP, you often want to look at its dual. And by looking at the dual of this SDP, we will be able to both prove the optimality of the method and construct an explicit quantum algorithm. Okay, with that, I conclude the lecture. Thank you.


In this video, we're going to be talking about how Vanya Hargreaves, played by the wonderful Ellen Page, ended up snapping. But we're also going to be talking about how we can deal with anger and trauma that stems from childhood. What is up everybody? This is Chris from The Rewired Soul, where we talk about the problem, but focus on the solution. And if you're new to my channel, my channel is all about mental health. And what I like to do is pull different topics from pop culture, like TV, Netflix, movies, all that kind of stuff, to try to teach you how to improve your mental and emotional well-being. So if you're into that stuff, make sure you subscribe and ring that notification bell. And like I mentioned, we're going to be talking about like towards the end, we're going to be talking about dealing with anger issues that stem from childhood. And I have a new book out, it's called Rewire Your Anger, the audio version's out. It just got released on Audible as well. The links for that will be down in the description.  I think it's only like four or five bucks over on Audible, or you can get the bundle for like $7.99. All right. But anyways, let's talk about the Umbrella Academy and specifically Vanya Hargreaves. If you haven't seen my video about Klaus, go check that out. I'm going to be doing some more character breakdowns. But anyways, for those of you who haven't seen the Umbrella Academy, there will be spoilers in this. So if you're still finishing up the series, go check it out. Come on back.  All right. So a little context for the show. These are kids who are all born on the same date, ended up having super powers. The father ended up adopting seven of them, turning them into a little superhero team. But then you have Vanya Hargreaves. She is one that they told her whole life that she doesn't have any powers. And this is what we're led to believe. So while the other six are out fighting crime and doing their thing, Vanya Hargreaves was kind of pushed to the side. And you see a lot of this, even in the beginning of the series or the season, that they ignore her, they neglect her. She's told that she's not special. She's kind of treated as this little whatever just by the rest of the kids. So they kind of neglect her and all of those things. And the first thing that we'll talk about is this. Nobody likes to be neglected.  Okay. Try to do that. Try to keep them included and all those things. Like I did a video with my mom, Dr. Randazo over on her channel about family roles, like toxic family roles and all of that. And one of the roles that I could relate to was the forgotten child. Okay. So for me personally, my sister, she was always getting in trouble, always having issues, getting kicked out of school. She had my nephew at a very young age, all these other things. All of the attention was on her. So I felt like the forgotten child, right? And it sucks because as that child, you're doing everything that you can to be good, to be on straight narrow and everything like that, but you're not getting attention. Okay. You're not getting attention. You're not getting the love. That thing that we all crave, especially from our parents, you know what I mean? And this can develop into a lot of issues, which we're going to talk about later with Vanya's relationship with Harold. All right. But here's the thing. And we saw it not only when Vanya was a child, but as she grew older as well. One of the biggest issues that people who were raised as the forgotten child, but even as they get older, we have a problem with not feeling heard. We feel like people do not hear us. All right.  Does that make sense? And things like that. And part of that, part of it, part of it is me trying to make sure that I'm being heard because that was one of the biggest issues that I had growing up. Now, the other reason why I say like, you know what I mean? Does that make sense and all that is because I'm used to teaching groups at a rehab center and I want to make sure that people are paying attention. So it's a little bit of both in my case. Now, one of the issues that I don't think a lot of people understand is like you've heard me talk about Dr. Daniel Siegel, who is a neuroscientist and he talks a lot about childhood brain development and all of that. Like in one of the books I read by him, it might have been parenting from the inside out, but there's actually a lot that happens in the brain when you feel like you're not being heard, when it feels like you're being misunderstood. Your brain, like your neurons, they start to just like go crazy, right? Because they freak out because part of our communication and connecting with other people is about being heard. It's about being understood. And when we feel and sometimes our perception is not the reality, but when we feel we're not being heard, it can lead to anxiety. It can lead to a lot of anger, frustration, all sorts of things. So it's important that we feel heard. That's why, by the way, you need to hang out with people who can be there and just listen to you talk, right? This is one of the reasons why therapy is such a good option for so many people. Like go see a therapist. Like therapists are trained to listen.  Talk to your doctor so you can get a referral. Talk to your insurance company, see if they can refer you to somebody. Talk to friends, family members who are in therapy, see if they can recommend anybody. If you would like, you can check down below. I have an affiliate link for BetterHelp. What that means is it helps support the channel. You get online therapy at an affordable price. I use BetterHelp, but we need somebody in our lives where we can feel heard, okay? So the next thing I want to talk about is because Vanya has been set on the outside of this family for so many years, her entire life, even as an adult, it makes her more susceptible to being a victim in an abusive relationship, which is something that you might have struggled with. Like one of the things that a lot of people don't understand is there are reasons. There are reasons why people get into abusive relationships, okay? And a lot of it stems from childhood. Like you hear that term like, oh, daddy issues and stuff like that, but it's very true.  And the thing is we ignore all of the red flags. So in Vanya's case, when she started to see Harold, she like ignored all of the red flags, but even when they became even more apparent. So even when, you know, her sister Allison was pointing out all of these things, showing her the evidence, like we have a tendency to neglect it, to neglect all those things. Because finally, finally we're getting that love, that attention, all those things that we've been craving our entire life. So our standards just slowly dropped. And this is why we have to work on our mental health. So in Vanya's case, like let's not talk for a second about how Harold was like somebody who like murdered his own father and like he was not a great guy. I hired people to like beat him up and lose an eyeball and all that. But anyways, you see what happened with how the abuse happened. So something that abusers like to do in a relationship is isolate you, right? So there were times when Vanya actually wanted to reach back out to her family and like connect with them or have a discussion with them.  I care about you. You don't need to talk to them. You need to talk to me, right? So your abuser will try to separate you from people who love and care about you. Like anybody who's been in an abusive relationship, feel free to let me know down in the comments below. Let me know, has that person separated you from other people in your life? Or if you're single and looking for someone to date, this is a huge sign of a red flag. We also had a lot of gaslighting from Harold, where Harold was constantly making, you know, Vanya question her own sanity, right? Now the thing is, is eventually Vanya ended up killing Harold, but like relationships like this, they never work out, right? Like you will see relationships that are mutually abusive, like they don't go to this extent, right? This is a fictional TV show, but they do go to this extent where somebody will stay with the other person, right? Just because they're giving them love and affection and all this attention and stuff like that. But when this person screws up, they will snap because they have a lot of unresolved issues that they haven't learned a healthy way to work through. This is again, why we need to make our mental health a major, major priority before we go jumping into relationships. Like I stayed single for over a year and a half, right? When I first started working on myself and my mental health, because I knew it wasn't fair to the other person that I wasn't even working on myself yet. Or I wasn't at a stable place where I felt like I could be in a healthy relationship. Like no matter how good the other person was to me, even if I found the best girlfriend on earth, no matter how good they were to me, I was still going to have a lot of issues and I would freak out over small things and that would be extremely selfish of me, all right? So this is one of the reasons why if you are single, make sure you are working on your mental health. So the last thing that we'll talk about is how Vanya basically brought on the apocalypse with her anger issues. Like you guys, if you're a parent, you definitely need to check out Parenting from the Inside Out by Dr. Daniel Siegel. I'll go ahead and link it down in the description below. But there are so many things that are the result of our childhood that we do not even know.  You might be treating your child in similar ways that your damaging parents treated you and you don't even realize it, all right? Like we have to gain this self-awareness so we can work on the problem. Now in Vanya's case where she lost control, blew up the moon and brought on the apocalypse, like this is why anger issues are just important for all of us to work on. This is why I wrote We Wire Your Anger. Like there's so many things that I just completely crumbled the pieces because of my anger issues and I've had to learn ways to kind of tame them. This doesn't mean that I'm never angry, but I don't bring my entire world down on top of me because of those feelings. Anger is a very normal feeling, but it's the actions that follow that typically get us in trouble, all right? So make sure, if you struggle with anger issues, check out down in the description below, all right? But anyways, let me know your thoughts on, you know, Vanya Hargreaves character, if you've watched The Umbrella Academy and all of that, or if you can relate to any of the topics that I'm talking about down in the comments below, okay? Anyways, that's all I got for this video. If you liked this video, please give it a thumbs up. If you're new, make sure you subscribe and ring that notification bell because I'm doing more character breakdowns for The Umbrella Academy. And a huge thank you to everybody supporting the channel over on Patreon. You're all amazing. And if you would like to become a patron and get some exclusive stuff, click or tap right there, all right? Thanks so much for watching. I'll see you next time.


This paper examines the effect of composition on the Auger parameter alpha in tin-based perovskites. It was found that the variation in alpha is dependent on the oxidation state, coordination, and local chemistry of the tin atom. This provides a framework for understanding the degradation of tin-based perovskites and their composition. Additionally, it allows for more accurate tracking of degradation and composition of these materials. This article was authored by Alexander Wixorek, Huaguay Lai, John Paul Pius, and others.


What now, at Chris's school in 1975, this is the first year, but you were in the first year of busing, correct? I was bused, let's say. Okay, I'm born in 65, so in 75, I'm 10. See how long it took me to realize that? Is that learning disability? I'm literally had to count it. So I'm 75 and 10, so I would say in... What's funny is that you're born in 65. Dr. King's alive. Yes, that's the thing of like how much, like the Voting Rights Act... The Voting Rights Act doesn't have until 68. So I'm born, my parents can't vote. Wow. I mean, they can, but it's... It's dicey.   But what's important about that is not that Martin Luther King was so long ago, it's that it was so recent. Yes. That wasn't that long ago. No, no. Yeah, yeah. Yes, his parents, you're the oldest? I'm the oldest of my mother's kids, yeah. So could not vote. Did they vote the first year? I have no idea. Yeah. I have no, no, you know. They didn't make a decision. I mean, they eventually voted, but yeah, I don't, you know. Fantastic, okay. Now, Chris's bus, one of the first years of busing. Now, when the... 73, 72, 73. 72, 73. When the black kid, there were how many, like 10% of the school was black? No, no, no, no, no, no. It was me from PS 277 was me and three girls, three black girls out of, I don't know, the school. 800, a thousand? Yeah, something like that, yeah. Four kids out of that. So you would get at when the bell would ring. Yeah. Everyone would, you'd... Oh, that grade school was grade school, like my first days of grade school, I remember it like, you know, there was like parents outside with like signs, no busing. Oh my God. Niggas go home, whatever, right? That was grade school.   Yeah, that's the story I'm trying to get to. Like, teachers would say... Explain the story. It feels going somewhere.  Bell would ring at three in high school or late grade school. One time, one time or a couple of times. I just remember, yeah, because we used to get out early, like they would let us out at 2.45. They let the black kids out early so they wouldn't get beat up. Yeah, you'd kind of like get that over with because you don't want to just, it's easier to watch you. So we'd get out at 2.45. Since 1700. Yeah, and that was, so I remember one of my teachers, ah, time to let the animals free or something. Time to let the animals free. Yeah. And then the janitor said something you said. Something awful. Savages or something. I don't know. Yeah, just awful. But everyone's against you.  It was like... You and four other people. It was just whatever. That were just against black people. Yeah, it was just, yeah, they weren't, they probably didn't know my name. Insane. Yeah.  I, yeah, it's weird. I've always been able to tell jokes about it. But yeah, now in therapy, I'm allowed to, you know, experience it as trauma. Yeah. You can say.  Feel like, you know, I did.  And like, I'm, I should, that's a fine thing to acknowledge that happens. It's a fine thing to acknowledge. And it's also, you know, the thing about trauma is, when you're experienced trauma, it's not that you, it's basically, whenever you think about it, like it's happening for the first time. Yeah, your body doesn't know when, it doesn't know if it's present, past or future. Right. So yeah, therapies allowed me to put it in the past. Like therapies allowed me to go, okay, I'm probably not gonna get jumped today. Yeah.


Hey guys, it's Nate, AKA the Foot Accountant. Welcome back to the channel. I wanted to give you guys a video today about Player of the Month. You're like, dude, why are we talking about Premier League Player of the Month and it's February 5th, February 6th, and this Player of the Month trend, Alexander Arnold, still has six days left. Why are we talking about this SBC? Well, the voting has come and it's actually gone. Player of the Month for January, the voting has actually been closed already, and I think that this Player of the Month is actually gonna come out on Friday when we also have the second set of Future Stars. So I think Premier League Player of the Month is coming out on Friday, and I wanna talk a little bit about that and talk through this SBC. They have overlapped Player of the Months in the past. I believe it might have been either Ben Yetter or Timo Werner, it wasn't Timo Werner, but there was a Player of the Month SBC that they overlapped by like a day or so where both of them were out, and I think that that's gonna happen again with the Trent Alexander Arnold SBC and the SBC coming this weekend because what they do with these Player of the Months a lot of time is EA doesn't really decide when this award is given out, right? It's like up to the Premier League to give out this award. So, you know, they could just, the Premier League could have decided to give it out a little bit earlier this month instead of last month because if they would wait until next week, then we're like on the verge of Champions League stuff. So I think they're just trying to give these awards to the players that could win it while they're around. So, let's take a look at this voting and possibly how to invest in these and just kind of honestly, there's some interesting stuff with this Player of the Month. It's gonna come down to two different people that I think are gonna win this one. And as you can see, the voting is closed. It says January's Player of the Month vote will be announced soon. They announced the vote on January 31st. It's actually when they announced this vote and put it out and they closed it on Tuesdays. So what is that? Tuesday was the fourth, right? Today is Thursday. Good luck with your weekend league awards, by the way, if you're opening those this morning or today. But they closed this voting already and that is making me think that's one of the main reasons why I think that this Player of the Month is going to be on Friday. If it isn't, oh well, we wait another week and all is fine with the world and this video still applies. But I think that this Player of the Month is gonna be on Friday and that's why I wanna make this video today. So our nominees are Aguero, Ducore, Grealish, Henderson, Ayos Perez, and Stevens. And again, here's a short list right here if you couldn't see all those guys there behind my face cam. There's really only two guys that we have to worry about and two guys that are in the running for the Player of the Month this month. And that is Aguero and Allison. And you're like, wait, Allison, a goalkeeper winning Player of the Month? Yes, we're gonna talk about that in a second. But it comes down between these two guys, Aguero and Allison. Aguero in the month of January played three games, they had two wins, one draw, and of course he scored six goals and became the leading foreign goal scorer in the Premier League, getting himself this record-breaker card right here. So this record-breaker card was from earlier this month, or earlier last month in January. So Aguero seems to be like a front runner for this month's Player of the Month in my opinion. But I don't wanna leave out Allison. Here's why, when we look at Allison's stats, we obviously know how Liverpool have been on an incredible, incredible form, right? They won five games in the month of January. Allison had four clean sheets out of those five games and one assist. And if you remember that assist, it was a beautiful assist. The blazing pass everybody up the field to a running salah. As it says right here, he provided a superb assist against Manchester United to Mohamed Salah for that win. Yeah, so he had only one game that was not a clean sheet and he also made crucial saves in that one game against Wolverhampton. So I think it is possible that Allison wins Player of the Month and that will be, here's a little bit of, I talked about this way back when I thought Dean Henderson was gonna win Player of the Month, but we're gonna take you guys back to 2016 to win the last time a goalkeeper won Player of the Month. Frazier Forster won it and that was the first time since 2013. So like every three years, a goalkeeper wins Player of the Month. But I wanna show you the stats that Frazier Forster had to win Player of the Month. He had three clean sheets and then Southampton picked up seven points from their four matches and they said he had some really awesome saves. And then before that, of course, we had Tim Krule as I mentioned and he had, what do you say, four successful victories including two clean sheets and 14 saves in one game. So that was kinda like a clear breaking performance from him. But based on the stats I see from Allison, I think that Allison has a shot at this month's Player of the Month. So we're gonna talk about either Allison or Aguero winning. We're gonna talk about both of those players because I have a hunch that it's gonna be Aguero. I feel on the inside it's gonna be Aguero, but I also think Allison has a shot just because of the fact that Liverpool have been playing mental. So we'll talk about both of those today. What would those cards look like if they get Player of the Months? I obviously just showed you the Aguero card, his record breaker version, which I think it's like 400, it's like 560,000 coins. Other than that, the only other special version that Aguero has is an inform and he also has a Team of the Year nominee. Actually, he's got more special versions than I thought. He's got a Team of the Year nominee, he's got the inform, he's got the record breaker and he has the scream card. Right now the scream card is the best version. Technically it is 91 rated along with this record breaker Aguero, but the scream card has plus four paced and plus five physical on top of this record breaker. So what would Player of the Month Aguero look like? I'm guessing he would be 92 rated. He'd probably have like 86 paced, 93 shooting. He would probably get plus ones and plus twos in all of these stat categories. So it would be a little bit of an upgrade, not too much. How much would that SBC cost? Probably somewhere in the range around 600 to 700,000 in my opinion. What they've been doing with Player of the Month this year is they really, they really haven't been doing anything spectacular, right? Like, making an investing video like I'm talking about today for a Player of the Month SBC, really all it is is I'm gonna tell you to buy Premier League players that are like, if they're low enough, you know, like some SBC fodder, Premier League players and like Prem Informs, like and also the nationality related to whoever's winning. Like that's the only stuff that we can do to invest in these SBCs anymore because they don't make these Player of the Month SBCs like they used to, right? We used to have like complete this SBC because Trent Alexander Arnold had to assist in this game against whatever team. And then you would have to put in somebody from that team so I could say, okay, during the month they played against Lester City. Let's go pick up a couple Lester City rare goals and throw them in the club. But you really can't do that anymore because these SBCs are all just high rated SBCs and maybe like a Premier League player requirement, one player from Liverpool or whatever. So these SBCs are really bland and that's not as fun but they're still investable, especially because we have some cards right now in the market that are decently low. So before we go look at some investments for both of these cards, I wanna look at Allison as well. If Allison wins Player of the Month, what is this card gonna look like? He's got the 90 rated team of your nominee at the moment. I would guess that a Player of the Month Allison will be 92 rated and it would definitely not be as good as this team of the year Allison, which I think is like 400 something thousand coins-ish. Let me check on foot bin right now. Team of the year Allison is, he is 455,000 coins for a team of the year goalkeeper. So if they made a Player of the Month Allison, if they wanted anybody to do it, then it's probably gonna be a 91 rated card and they're gonna have to make it like 150K at the very most because I don't think anybody else would do it if it wasn't that cheap. So that's the move with Allison. I'm kind of hoping it's Aguero because a lot more people would, I feel like we'd do an Aguero, than they would do an Allison. But I think that we can make investments that cover both of these cards. So let's talk about the more investing side of things and what kind of stuff I could see you guys getting into in terms of buys for these cards. Now for a lot of these SBCs, if Aguero comes out and he's gonna be 700 to 800,000 coins, a good kind of barrier that we could use to compare him to a past SBC would be this Monet SBC. Player of the Month's Sadio Monet came out a couple months ago. He was Player of the Month for December. I think it was December? Yeah, it was December. This SBC was around 700 to 800K when it was out as well. You see here, 790, it jumped up big time there in December. But for the most part, it was like 800,000 coins to around 750K ish is what this SBC costed. And what did it require you to put out? I think you have like an 86, 87, and 88 rated squad. And I think these two squads here, one of them is an 86 rated squad. And the other one is, what's this other squad? So we have two 86s, an 87, and an 88, and an 85 as well. So an 85 with an inform, an 86, and then an 87, 88. 86, 87, and 88. So that's around 700 to 800,000 coins. So I would expect a very, very similar type of SBC or the Aguero card. And obviously if we're investing, if Aguero is gonna be that person that comes out, what are they gonna require? They're probably going to require maybe a Manchester City player, definitely Premier League players, and then possibly an Argentine as well. It would make sense that they required an Argentine player because he broke the record for the most goal scored for a player outside of foreign nationality other than England playing in the English Premier League. So I would expect an Argentine requirement. So when we're looking at some high rated goals to invest in, I'm gonna say we wanna focus on mostly 85s and up probably 86s and 87s, to be honest, because those cards would be used in any SBC rating, ranging from 85 to 88. So that seems like a good sweet spot. Some of the guys that I like right off the bat would be any city players that you can find in this kind of cheapest zone. City players usually aren't the cheapest in terms of cheapest players by rating, but a guy like Bernardo Silva or a guy like Fernandinho, this is where you could pick up some players in Ederson as well. Ederson would be a good investment for either Allison or if Aguero comes out, because obviously he is Brazilian, but a guy like Bernardo Silva might be a big time investment, especially because of the fact that he's a right wing, and it all depends on what formation they use for this Player of the Month SBC, but a Bernardo Silva at 21,000 coins, 87s right now at 21,000 coins are not that expensive at all. These are pretty cheap, and I'm a fan of these for a club stock anyway. So if you're looking to club stock some cards in your club, high-rated, it's like you think a mid-icone SBC is coming or whatever, maybe you get on some open bids, but these cards are low again. We did a club stock earlier this week. EA has not released any more SBCs, but I do think these cards are investable in 87s, like a Bernardo Silva at 21K is fantastic. I would throw Fernandinho in that mix as well. Try to get Fernandinho for around 21,000 coins if you can. He's, again, like a double investment for if Allison or if Aguero would come out since he is Brazilian and from Manchester City in the Premier League. And that's a CDM card, so we can be used in any of the midfield positions for an SBC. And then of course, Ederson as well, 88-rated cards. You know, when you're investing in some of these right now, if you're investing for this play of the month that you think is coming out on a Friday like I do, you're also kind of investing for like a mid-icone SBC as well because if that SBC comes out in the next few days, then you're probably gonna make some coins off of this as well. So Ederson at 28, actually like 27 or 26K would be ideal for me. You can look to pick these cards up in the rewards time period as well. There's gonna be a lot of packs opened, I think. Some people might save their packs, but I'm sure there'll be a lot of people that don't. So like 27, 26,000 coins, maybe even lower on bid for some of these guys would be perfect. And then yeah, just basically any Prem, Prem high-rated that's 85 or above would be a decent shot as well. Obviously you can use this page over here on a footpin. This is, I'll put the link to this page in the description so you guys can find it. This is the easiest way to find high-rated cards on footpin.  You go down to cheapest players by rating and that takes you here. Also what you can do on this page is you can sort by informs, right? So I'm gonna click on gold inform, apply filter, and then we're gonna look at some of the cheapest informs by rating as well. Again, if we're investing for SBCs that are gonna be 85, 86, 87, or 88 rated, you're gonna wanna look for informs kind of in that 84 to 86 range because those are gonna be the most commonly used informs inside of an SBC. Any informs that jump out to me right away, stuff that is in this current team of the week, or was in last week's team of the week, like this Mollet, I don't know how to say this guy's name, but 13,000 coins for this card. If you can still snag him at 13K, that's not a bad shout. I know he has nothing to do with Premier League, but he's out of packs. He's an 84 rated center attack in mid, so that's not a bad shout right there. Premier League informs though. Where is our cheapest Premier League inform? Yeri Mina is in this week's team of the week. He is in packs though. Tarkowski at 17K for an 84, not a huge fan of that. Henderson 85 rated at 18K. I am a fan of that. I'm also a fan of the Giorginho right around 20K if you can. Maybe I'll share a bit at 19K as well. The informs are kinda harder to predict because you don't all the time need an inform, but a Henderson like this could be solid for an investment as well. 18K for the cheapest 85 rated inform, and it's a CDM from the Prem. I think that might be an undercut because it looks like he's not actually that price according to foot bin, because he was listed at 18,000, but then you have a bunch of them at 20K. So let's see if I can snag a Jordan Henderson inform under 20K really quick, because I would like to add one of those informs to my club as a possible investment for player of the month or just for later down the line, 18,500 coins, sure. I will buy one and throw it in. We will buy one of these and chuck it in the club. GG's, thank you EA Sports, there we go. There we go, two, there's two of them there, actually interesting, nice. But all right, so I've got a little high rated investment going on there and I'm feeling good about that. But again, cheapest players by rating, look at some of these guys like who else would be a possible Premier League player of the month investment. If you're feeling like maybe Allison's gonna win, then maybe you wanna look at some of the lower rated cards like Genie Wine Aldam, 84 rated Genie Wine Aldam. What is he going for right now on the market? Usually he's a little bit more expensive than 84 card just because he is a Liverpool and he's very linkable and very needed for SBCs. 4,300 for Genie Wine Aldam. Let's take a look at this right now, because I wonder how high this card gets when SBCs come out. 4.5K according to Footbin, looks like his lowest that he usually gets to is 3.8, he goes up to 6.9K though. He fluctuates a decent amount for an 84 rated card and he's down here again, 4.3K. If you can get this guy at low fours, I'm a fan of that. But again, even if you're just watching this video and you're like, I don't think Play of the Month is coming on Friday, do yourself a favor and go through here and just club stock some of these cards if you have not done it already. 86 is trying to get them below 15K if you can. Although some of the center backs you can pay a little bit more for, you can see a guy like Scrinniar who is 16,000 coins right now. He usually doesn't dip too much below this. 15,000 coins and most of the time he's above 18, 19, 20K. So this guy Scrinniar is a great one for an SBC fodder investment. I think Benucci is as well. Cause he, you know, center backs that are required for squads, right? Cause you need chemistry. He got down here to 14K, he ballooned to 20. I think it's very possible that a guy like Benucci just as an SBC fodder investment would be a pretty solid investment for this promo as well. I guess one other player that I could shout would be, if I could shout one other player as an investment, it would probably be Gunduan. Gunduan would be another one that could be solid. He rises up a lot with SBCs, but again, he's just kind of like Wijnaldum. You want to see him down in like that, 4.3 to low four range. Maybe try to get this guy at 4K or under during rewards. Look, people are mass bidding 4.5K on Gunduan and you can get him back here to 59th for 4.3, 4.4K. So this would be a card that I would be definitely looking at during rewards. I'm going to pick that one up and just chuck it in the club so that I am ready for this SBC when it comes, GGs. And yeah, of course, why wouldn't I put in this video out? It's a great time to get in on some of these high ratings because of the pack supply from Weekend League Rewards. Any other market movements that we could see because of a player of the month, you might see this aguero sold off a little bit. If there's any aguero that would get panic sold, it would probably be the record breaker since this would be the closest version to that player of the month when it comes out. You can watch the Inform as well. I think the Inform is going for somewhere around like 300K. Am I correct on that? How much is this Inform going for? Footband is telling me this Inform is 271K. 271,000 coins for the aguero Inform. So that's definitely a possibility you see this card drop as well. Just kind of depends on the price range.  But if they make it really cheap, then you might see some people selling their aguerros to go get that new version of aguero. I think it helps that we have this Sane SBC that is out here as well. So if they make that aguero SBC really cheap, you might see a few more of these Sane's come up. You might start seeing a few more of these because people would grind this SBC, especially if you're a Manchester City fan. You might get this card to link it up to the brand new version of aguero if it comes out. And let me check. I don't know if we're gonna get any Manchester City players and future stars. We don't have any from this first set, but it's possible maybe that we get.  Not too sure about that, but of course we have like a headliner sterling. We've got the Kyle Walker headliner. So there's definitely some City hype, I guess. KDB has got a team of the year. So there's definitely some special cards from City that people wanna buy and link to these cards as well. But regardless, look for some high-rated investments during rewards today. That could be a good shout for a lot of you guys. And I think it's gonna be either aguero or Allison. I'm leaning towards aguero though, with that SBC being priced somewhere in like the 650. 650 to 750,000 coin range is where I would put that SBC. And then if Allison comes out, probably like 200K at less, I hope it is at least. But I think aguero might be the move and a shout for this week's or for this month's player of the month. Again, I wanted to get this video out for you guys because it looks like it's gonna come Friday and I wanna get you guys prepared for that. Even though Trent is still gonna be here for six days. Again, EA does not decide who, when this award is given out, Premier League does. So that's my reasoning for that. If you enjoyed this video, smash the thumbs up on it. Comment down below if you have any questions and subscribe to the channel. If you are new, it's been Nate, Foot Accountant, catch you guys later. Peace out.


I like combs and I just rediscovered my comb are we on oh hey hello everybody my name is Ibnar as maybe you saw on the screen Avelik Strativus and to my left is Kylie Dally and in the middle is Jamie McKinnon and our first-time guest on the show Edward Burke hello thanks for coming on Edward thank you for having me yeah really excited to have Edward show us his instruments that he makes and where do you make the instruments I make the instruments at a place called the generator down off of Pine Street on Sears Lane yeah yeah that's a new space right it is a new space we used to be in Memorial Auditorium yeah I've been in there that's fascinating so that's closed they moved everything to the Sears Lane yes I started at the generator in last year as a volunteer cool so do they still take volunteers and they do yeah and chores once in a while oh yes I've yet to get down to the new space but yeah every first Friday of the month maybe with the art hop or the first Friday gallery openings you know yeah I'd say there are practically tours given there every day so is it something that like if you if you just stop by you could get a tour or is there a schedule yeah if you stop by there's likely to be somebody at the front desk and they can show you around there's an official orientation you have to take before you become a member of the generator but come by and somebody will show you around we inevitably so that orientation that's because they have like a lot of a lot of cool equipment there to use it's like about learning to use the equipment they do yeah the generator is what's known as a maker space and others who work there would probably be more qualified and more knowledgeable to talk about it than I would be but if you live in Burlington and have an idea for a project and you need a jumpstart on getting that project off the ground whether you need the right tools or some knowledgeable info and suggestions from people who have made similar projects to what you're thinking of the generator is the place to get that jumpstart you're looking for mm-hmm so I'm I kind of want to hear you talk more about what you've been working on yes mm-hmm I make essentially musical walking sticks and these are folk percussion instruments played in various parts of the world my primary influence is the Australian logger phone L-A-G-E-R and then phone fo any logger as in logger beer that's the cap yeah bottle caps bottle caps make the fun time while you're making these things I get my caps from various sources this is an example of one I don't know if it's fully in the frame but I made this out of an old walking stick that somebody else had carved and essentially it is a stick with a bunch of caps on it a handle rubber tip at the bottom and various other fun little sound toys and you play it with specialized drumsticks and I make those homemade as well these are called ratlers so-called because they have furniture tax or you can use thumb tax to that make the logger phone rattle when you rub the rattler on the logger phone like this so you can bounce this on the ground and then hit with the stick you get a lot of interesting rhythmic variations so once you got those main elements and I hope people can hear my voice at the same time I'm playing this once you got those elements you can add in other crazy sounds like this yeah or this yeah at the top that is a sink strainer oh I love that yeah makes such a good noise too it it is and I was really surprised by the noise it made the first time I picked it up and struck it with a pencil or it might have been a pen that I had in my pocket I always test out what sounds things make before I put them on these logger phones but yeah sink strainers are strangely resonant so yeah where do people mail their sink strainers to you yeah I do have some contact info that I can give after or towards the end of the show here so that's an example of just one of the instruments I've made I've made a bunch since May this is another one it's kind of a little bit different because I've added a striking surface that's metal here so it's not bare wood and it gives kind of a different sound the rattler the rattling effect doesn't quite work here but it's a totally different feel and they basically in a musical situation can stand in for the typical drum set and you got the rubber tip down here for your bass drum and then striking surface to get a snare type sound in conjunction with the bass shake it like a tambourine little resonant piece on top for a cymbal mm-hmm yep adaptable to any musical situation right here pretty much a parade everywhere you walk say that again pretty much a parade everywhere you walk hmm if you ever bang them on the street you know going down church definitely one man parade no one's that's right mm-hmm also great for using as a walking stick or to repel bears if you're hiking grizzly country yeah yeah so once I have all those basic elements did I knock something important over I think I don't think it's a big deal oh okay so I have these basic elements and processes that I use now so I'm into making themed logger phones this one is themed for st. Patrick's day it has green spray paint swirls on it and caps up top from Guinness bottles the Ireland pride there green bells oh yeah green jingle bells mm-hmm you never know what I'll add to a logger phone bike bell right here definitely and then some ridges that I added with a Dremel a new toy that I bought with a stipend that the generator gave me I am the maker in residence for January and February and also March so I'll have my studio until the end of March yeah I encourage people to come visit me so this is what the riches sound like here yeah so I have some other things to show you here I hope I didn't bring too much no okay so I talked a bit about the Rattlers too just as I've experimented with different designs and shapes and sounds for the logger phone I'm experimenting with Rattlers too this one is a is a tree branch I stripped the bark off and I sanded it and stained it wrapped some paper tape around the end for a handle yeah paper tape by it's a product I've found around town that I have really come to enjoy using yeah and so that's just one design of Rattler this one is pretty unique this one was also a tree branch cool thing about this one the color of this wood right now I've stained this but it it's the same color that the wood was before I stained it so usually staining gives your wood a different color a different luster and you know unique look but yeah the wood that was under the bark was yellow like this I've never seen wood this color before so I call this the banana Rattler yeah and this one uses black duct tape so I'm experimenting with different types of tape different woods I really have no preference yet I'm early in this whole logger phone making career have you tried hollowing a stick out at all and seeing what kind of sound that might make no maybe a special resonance as you yeah cross that's a great idea and Ibnar is holding my favorite Rattler that is a dowel that I bought in a hardware store yeah and I decorated the top of it using a dremel this little drumstick like shape here so I call this the Jupiter Rattler actually because it has a knot in the wood that kind of looks like the red spot that swirling storm on Jupiter yeah that's what I saw in the knot and so yeah various designs and looks this one right here is made of bamboo a little piece of bamboo that I actually found here in the old north end so I took it to my studio and made it into a striking stick or Rattler I should say do you give all of your rattlers names I don't know only those two oh okay yeah oh actually yeah this is Rudolph's Rattler because I used a red and green thumbtacks on the spur of the moment and it has some green and white paper tape so this actually goes to a Christmas themed logger phone I have in my studio it is covered with jingle bells instead of the standard bottle caps so in the future I'm going to experiment with replacing the bottle caps with some other resonant objects yeah that's that that's made of reindeer horn no I wish it's a tree branch yeah yeah it's a paper tape with some mod podge painted over it okay yeah cool yeah yeah yeah do you have any questions for me about my process or anything about my work here I'll just be curious what kind of special techniques you've been developing in your space as you've been working along and working with other people and seeing what they've been doing if that's influenced you at all yeah if it's if there's one thing the generator thrives upon it's inspiration from other people working on their own stuff around you to put it more eloquently the generator's bread and butter is collaboration I personally haven't collaborated with anybody on a project there yet but and I'm trying to remember your question oh just about like what maybe you've seen someone else doing and yeah maybe I could do something like that oh yeah yeah the my use of the tremel I was inspired to get myself a tremel after seeing somebody else use one and they actually allowed me to borrow their tremel for like a few hours and so I experimented with it and I really liked the results so with the stipend I got from my residency I decided to put it towards a dremel of my own and for those of you don't know dremel is both a brand name of power tool and the name of the tool itself it allows you to engrave and also has some other attachments trying to think of the other details here dremel yeah yeah the handle of this bamboo rattler I decorated with the dremel so I definitely have used the engraving tool but it has other attachments it can sand it can cut through glass if I'm not mistaken yeah has some diamond tipped blades but I'm not a spokesperson for the tremel so this is not a product endorsement yeah what did this come from do you know these metal yeah it's a very beautiful decorative yeah I yeah these metal parts I I don't know what they they were originally but I saw them in a store and I really loved the look of them and I wanted to incorporate them into my instruments like hammered tin yeah yeah I'm wondering if maybe they were part of a door frame or something looks like something like that yeah yeah or maybe like they maybe they decorated a bookshelf yeah so I don't know I'm inspired by really anything that has an interesting look and that sounds good when I tap it yeah I'm wondering about like when you walk around town are you the way you see the world is it influenced by your work as a logger phone maker like you see something and you instantly think oh I want to know what sound that makes or yeah is has it affected you like that how I view the world isn't specifically based on making logger phones I would say it's based on my identification as a sound junkie I walk around and I'm very aware of every every little sound from the rustling of the leaves to the doppler effect from cars whizzing past you to you know the sound of children yeah life is a big symphony to me yeah that's cool yeah definitely yeah and Burlington offers us plenty of sounds yeah I bet you could write some really great poems about like the soundscapes you hear right I am having your description just now that leaves wrestling and yeah sorry to cut you off there yeah I do write poetry as well some song lyrics yeah you won't find me published anywhere yet but yeah I do do some writing that's great yeah and I brought some examples if you if you would like to hear some yeah yeah okay right now sure okay it is a poetry show yeah all right I wouldn't call these real refined poems they're just a little snippets I write down when it wherever the whenever the mood strikes me sounds like poetry yeah so let's see here sometimes I find I write when I'm out enjoying a drink at the bar and I've nobody else to talk to go inside my head so this is an example of one of those let's see it's untitled but here it goes taste of fermented wheat so sweet so many feet on the floor in this bar noise crowds my head no thoughts to be fed I wonder where I'm being led what are all these people talking about what are these people talking about I hear noise not conversation the moisture on my coaster condensation the dim light glistening through the beer the popping bubbles whispers of my ancestors do I hear remember us remember us we laid your foundations paved the roads for your bus we toiled and we fought of the comforts you enjoy today we thought we enjoyed a cold one after a day's work when it really meant something remember your ancestors from even longer ago who first procured the golden liquid the witch we whisper yeah I like that I have two more if we have time for them yeah okay so this is a poem that I or like just an assemblage of words I wrote down last year and it paints a moment sitting and thinking lingering fingers exploring the buns of my cell the evening breeze is swell I'm on no one's time no one's dime I wish I had a rum and coke with lime no drama no crime just a few moments of my time on this bench outside of this south and deli my legs like jelly feet sinking into concrete I feel complete why must I go home yeah and then the last one I planned for today is a poem with that I'll say it's a poem that's very timely timely here and this one is not titled either but I could entitle it I watch the wasp there we go I wrote this last year during summer I watch the wasp climb up the bus stop window a tough guy reaching high yet falling down at random moments how many of us fall due to our swagger our false pride how many of us over exert and try yet fail the people at the top have further to fall yeah it's very timely I feel yeah yeah I can picture when I see like wasp or a hornet or a little flying creature like that that's it's seemingly trying to find its way back outside I got behind a glass and so it's crawling up the side yeah and it's must be exhausted because every once in a while it tumbles down and it's the seal and has to fly back up some very vivid image mm-hmm yeah yeah I am I want to make sure I read one poem by local poet who has recently passed Marilyn Grigas and I have I did meet Marilyn and I enjoyed a few conversations with her and so let me let me read one this is her book called shift that okay well anyway it's a gorgeous cover that's called shift so let me I love Marilyn's poetry so I want to share one here I could read I could just pick just about anything out here so I will read this one though this happened to be where I opened up it's called package and sad sad wrapped in anxious anxious wrapped in a slew of questions shrink wrapped in a warped frame still wishing for connections even with weather mild and kind even with new romantic dreams and oops and dimly lit rooms my mind recoils not anchors not answers not icons or echoes but just a thin strap would do stars above burn in their constellations dog star wrapped with a white dwarf white dwarf bound in gravity dog star the axis of it all even as every sad and limping thing collapses and radiates nice yeah could maybe one one more okay and then you brought some poems to read to Jamie Kylie yeah okay yeah Jamie's been writing like crazy okay yeah okay well this okay about muscle if there's no need for movement then no need for a brain I've learned a fact demonstrated by the sea squirt a small creature that swims freely in its youth until it settles on a rock then it devours its own brain and spinal cord it simply doesn't require them any longer God don't let me settle parentheses need for movement leads to need for muscle the the brain evolves in order to plan and execute reaching grasping turning according to the expert on Charlie Rose which I watch on my iPad while walking on the treadmill to rebuild my strength plenty of species thrive without brains he says it could be different on another planet I suppose but here evolution of the brain is about muscle just ask Arnold Schwarzenegger or an evolutionary biologist yet the brainless sea squirt still gets upset still squirts maybe it's innate like a horse is hide shuddering to dislodge a fly maybe that's why I started moving and arranging boulders last fall I thought I was making a terrace but afterward it looked more like a grave Marilyn Griegus powerful beautiful actually yeah thank you to Marilyn some new poems there's something like that bus went out sure they're we're working on a new thing here with some photographs of flowers that were all taken down south and either Tennessee North Carolina or Virginia and alongside that is a little story kind of like a poem kind of more like a run-on sense however you'd call it so do the first one then maybe we'll do another one later that's later on set out from north VT across the Great Lake Champlain down near Ticonderoga and straight soaring over suspension bridge past battle battlements in age old fortress well all of New York being an age old fortress either cities or trees through all that Roland Calcune on Delaware a hundred feet across to Damascus PA great rocks and river and orange sand for dirt kill the engine and stop first great rushes over now enjoy eating with family and beautiful abode on quite still stilts and for one that's lit a little later on in the journey here swarm to the sunny south in the springtime in search of pollen and just watch us do our dance it's what the honey does sweet nectar and my god proviscusing about and slurping from sugar streams and buzzing with furry legs jittering about on flower stocks and buzzing up a talk insect droning on and on in UV ray spectrum fragmented through a million faceted eyes and loop-to-loop flight paper wings and starlight folding and flapping iridescent and burning among soft sepals and pedals these are all the photos you haven't written poems about yet but so all the so the one that that one's inspired by is at home but that one it's it's this like yellow tree flower that is just like yellow and bursting in every direction looks like a little firework like this that's a trout really actually yeah but the the other one it looked I don't know it makes sense that Jamie wrote the bumblebee poem for me for my part I really liked the part about the proboscis we can keep talking but I think we might have wrapped up is that it okay yeah probiscus the other yeah yeah your use of language in that passage I mean I'm not much of a poet so yeah I liked the part about the proboscis and like soaring from flower to flower I can't remember exactly what you wrote there but that that was a good passage mm-hmm maybe we'll do one more here yeah this one is the smokies coming in from Asheville to Cherokee after eating biscuits with herb gravy and bacon in the city which is quiet on this city on this sunny morning but loud the way out weaving through industrial lots of all conditions finally to a mega highway caped in trees and mountains and only the constant roar and rush of ocean road and metal waves propelled by gasoline wind to remind you of your troops surroundings anyways made up to move on from road to path and thus in the backcountry office obtaining a pass to camp river sites up into the big valley below the high peaks and fabled Appalachian trail here we are dirty but well-fed in a parking lot full of window peepers and AC Seasters kiosk layers and photo nannies never leave the road and there we go backpacks bobbing into rhododendron would you call AC Sears AC Seasters AC Seasters I just been like right writing as fast as possible kind of and just seeing what comes out yeah yeah I'd say that's the kind of writing I do too yeah it's good for your mind you know I feel really liberated are we done here? are we done? oh one more? okay yeah one more? don't read another one from there sure Kylie did you want to read something? yeah could I read I was reading a couple of poem books today oh these are sketches I made from my same track these ones I think I want to read the Mary Oliver I've read Mary Oliver on here before probably but this one was like it was the first one I opened up to today and it was just perfect for the moment I needed the cricket doesn't wonder if there's a heaven or if there is if there's room for him it's fall romance is over still he sings if he can he enters a house through the tiniest crack under the door then the house grows colder he sings slower and slower than nothing this must mean something I don't know what but certainly it doesn't mean he hasn't been an excellent cricket all his life I like that one yeah oh glad you read that and you brought one of your paintings yeah Jamie brought that along but I painted it this summer offering rocks and this is your latest I think right? yeah I would say still in progress I'll still add some stuff to it but the glitter effects nice I like getting into that and this it looks can I look at this yeah it looks like like tissue paper stained like glued on but it's actually transparent brush strokes or something maybe yeah and then the texture is actually if you ever heard of silly string like the string that sprays out of a can of course it's not really string at all it's I don't know weird foamy material but I sprayed the whole thing with that first to like build up an interesting texture that is very creative I like that yeah you can see like in that bottom corner there that texture is like the silly string oh yeah more thick in the right side you can see some of that pink and blue there yeah I always wondered what silly strings made out of I'm in a kick these days of using my the voice recognition software on my phone to ask a question like that like what is silly string made out of yeah yeah or like what's the origin of twizzlers you know yeah growing a tree yeah I'm a really big trivia nerd nice yeah everything nice painting right there putting glitter on your logger phones yeah they kind of have their own shine already it's likely that I will use glitter at some point I would totally recommend glitter glue it's like mm-hmm that has both glitter glue and just like shake it on glitter yeah the glitter glue like won't fall off you won't you don't have to worry about it like flaking off at all mm-hmm so that's really nice about it and speaking of the gender speaking of logger phones I made them at the generator space 40 Sears Lane off of Pine Street mm-hmm so I definitely encourage all of you to come out and visit us if you are down in the south end come by my studio until the end of the month and you can visit me and yeah I encourage you to find out more about us generatorvt.org excellent mm-hmm thanks for coming yeah thank you Edward thank you yeah I've enjoyed myself mm-hmm we had some jams in the studio before we came up too oh excellent under a quarter in the free pile and Edward was like a master at it I had beginner's luck that's all I'll say that sounded pretty good to me luck of the Irish so those are going to be a big logger phone parade on St. Paddy's Day you think yeah it could be fun if you have like a few I don't have that much past experience in organizing things