I'll start by just recalling one or two points from last time. So last time I introduced the notions of Gower's norms. So these are norms on functions. I'm going to go over exactly the definition of those again later and I also talked about nil sequences which are the main topic of these lectures in fact. So let me just remind you what I said about what a nil sequence is. So a nil sequence is phi of p of n where p from z to g is a polynomial sequence. g is some s step or class s. What is Immanuel? What's the French term for class? I'll use class, class s, nilpotent group. The nilpotent Lie group, which I'm going to assume is simply connected. And phi is automorphic, a smooth automorphic function, gamma automorphic function for some lattice gamma in G. Now I spent a lot of time in the first lecture talking about arithmetic progressions. And I mentioned, I stated something called a generalized von Neumann theorem which provides a link between counting arithmetic progressions and the Gower's norms. And I used that to motivate the following question. So when is the Gower's norm, when is the Gower's UK norm small? Because if you can show that for a particular function that Gower's norm is small, then that function doesn't contribute to counting arithmetic progressions. So what I want to explain in detail today is at least the statement of the answer to that question. But let me state a rough form first. So theorem, this is the inverse theorem for the Gower's norms. So let, so suppose that, suppose delta is greater than zero and suppose f is a bounded function from one up to n to the complexes and suppose that its Gower's norm is, is at least delta. So suppose f in UK of n is at least delta. Then the conclusion is that f correlates with a nil sequence and then there is a nil sequence chi of n equals phi of p of n such that the average value of f of n times chi of n is at least delta primed, where here delta primed is bounded away from zero in a way that depends on delta and k. So if a Gower's norm of a function is large, then it correlates with a nil sequence. Now as I've stated it here, this result has precisely no content at all, it turns out. And the reason for that is that just every function from one up to n can be written in this form, chi of n is phi of p of n. In fact with just taking G equals r, so I'll leave that as an exercise. So to add content you need to say some additional things about chi. So here chi is, it's in fact a k minus one, a class k minus one, nil sequence and its complexity with complexity bounded in terms of just delta and k only. Well perhaps an even more trivial reason why the first statement had no content is that actually the way I stated it to begin with, I wasn't asserting any bound on chi. So I could just have multiplied k by some huge number and this would be true. So among other things complexity controls the size of k. And there's a converse to this, conversely, well if f has a large inner product with a nil sequence, then its gara's norm is large converse. If chi is a class k minus one nil sequence of complexity, well let me not say it like that. So just if chi is a k minus one, a class k minus one nil sequence that correlates with f, then f has a large gara's norm. So f in the gara's u k norm is at least delta primed, where now delta prime depends on delta k and on the complexity of chi, depends on delta k and the complexity. So one of my main aims in this lecture is going to just be to at least tell you what complexity is. And as I said, I don't think this has ever been done in a lecture by anybody. So at least we will see a rigorous statement of what the inverse theorem for the gara's norms is. But the point of this is that somehow these nil sequences are a complete list of characters, if you like, or the nil sequences of bounded complexity are a complete list of characters for this higher order Fourier analysis, which is supposed to be to do with these gara's norms, which themselves control arithmetic progressions and other related questions. Let me say a few words, though, about the proof of this theorem. So this is actually very difficult and long. It was finally finished off in a 140 page paper by Tau and Ziegler and myself, and certain special cases were done earlier. And I think the consensus is that we don't really understand why this is true yet. So we don't really understand why nil sequences are the complete list of obstructions to this gara's norm being small. The converse is much easier and I'm going to tell you, probably even sketch a proof of this. So it's relatively easy to show that if f correlates with a nil sequence, then the gara's norm is large. So any questions before I set off on trying to make all of this more precise? Good. Yeah, so the plan is I'm going to just define all of these terms properly. So let's define the gara's norms, first of all. Now, actually, it's best to define the gara's norms on a billion group, first of all, rather than on the interval 1 up to n. So let z be an abelian group, a finite abelian group. And let k greater than or equal to 2 be an integer. Then we define the gara's norm. Well, first of all, define it's 2 to the kth power, f in u to the k of z to the 2 to the k. It is defined to be this average, so the average over x and then over h1 up to hk of the product over omega. Omega ranges over the n cubed, 0, 1 to the n of, and I'll explain this in a moment, curly c to the omega f of x plus omega dot h. So here, curly c is just complex conjugation, and mod omega is just the sum omega 1 plus up to omega k. So let me remark as I did last time, it's not obvious that the quantity on the right is real and non-negative, but that actually turns out to be the case. So it turns out that the right-hand side, right-hand side, by the way, you should, I feel very embarrassed that my French is so bad that I couldn't even dream of lecturing in French, but if I say something in English that makes no sense, like yesterday I used the phrase red herring, which apparently makes no sense whatsoever in French. So if I do that again, please just tell me, okay? So the right-hand side is real and non-negative, but that's not quite obvious. It's not particularly difficult either, but it's not obvious, and so there's a unique choice of 2 to the kth root, which makes that norm real and non-negative. So define f in uk of z to be the unique real and non-negative 2 to the kth root. So depending on how much time I have in these lectures, I mean I do want to get to more substantial things, I may give some indications of the proofs of these facts, which rely on something called the Gower's Cauchy-Schwarz inequality. The main tool in all of this part of the theory is just the Cauchy-Schwarz inequality applied many times. So it also turns out that we have the triangular inequality, f plus g in uk of z is bounded by f in uk of z plus g in uk of z. And finally let me observe the, there's a nesting property of these norms. So also the u2 is less than or equal to the u3, etc. So all of these facts follow from something called the Gower's Cauchy-Schwarz inequality from Gower's Cauchy-Schwarz, which as I said is just a sort of exotic version of the Cauchy-Schwarz inequality and proven using just the Cauchy-Schwarz inequality. Is there some, sorry is there something? You didn't tell us what is f in this formula. So it's defined on z to the power k or just on z? No, that's a good question. So these, sorry, these are ranging over z.  So let f from z to the complex is be a function, yes. So let me explain actually now why I've introduced this in z. But there are many advantages of working on an abelian group. This makes many averaging arguments a lot easier and you don't ever have to worry about the range that things are averaged over. So now if, now suppose f is a function on 1 up to n, then what we do is we embed 1 up to n inside a cyclic group. So embed n inside z modulo n prime z. And it doesn't actually matter which n prime we choose, so just take it to be quite big. So with n primed bigger than 10k times n, say. And it's also convenient for technical reasons to take it to be a prime. And now we define the Gauss-Uk norm of f on n to be the norm of the same function regarded as a function on the group. This is a slight abuse of notation. f is a function on 1 up to n, but it can also be thought of as a function on this group just by setting it to be 0 outside of the image of that embedding. Normalized by the norm of the interval on that same group. So that looks very technical. Let me explain two things about it. First of all, it doesn't depend on the choice of n primed. And actually the reason for that is it's just the same thing as the average. You can also express it like this, but where the average is only over 2 to the k tuples for which all of these elements lie inside the interval 1 up to n. So same as, let's call this star, in which the average is only over x plus omega dot h lying inside 1 up to n. But that's a nasty set of x's and h's to average over. It's kind of a convex subset of z to the k plus 1. I'm not going to dwell too much on the precise distinction between the norm of functions up to n and the norm on this group. They're really the same up to a constant factor. You just slightly lose some properties. Like this monotonicity is not quite true. You have to include some extra factors of 2 and things. But more or less, they're the same. So that's some, they're of at least defined the Gauss norms. So now let me define properly what these nil sequences are. Because last time I didn't even, I mean, I think many people know, but I didn't even remind you what a nilpotent league group is in general. And actually it's good to define these in greater generality than that. So let me do that. That will come back in just a second. Can everyone see what they need to on that? Yeah. Okay, so let me talk about filtrations. And I'm trying to be consistent in my use of terminology, but I can't guarantee that this is all standard terminology. So let G be a group, a pre-filtration on G, which I will call G dot, and it's going to be a sequence of subgroups G i, i equals naught to infinity, is a nested sequence G is equal to G naught, contains G1, contains G2. This containment symbol includes the equality case, so maybe I should just make that completely clear with. So it's a nested sequence of subgroups. And we say that it has class S, I guess class at most. Class S, if all of the terms from S plus one onwards are trivial. So here E is the identity element on G. And I'll say that it's a filtration just if the first two terms are equal. So if G naught equals G1, I actually forgot the most important axiom of a pre-filtration. This is at the moment just a nested sequence of subgroups. It's supposed to satisfy, satisfying that the commutator of G i with G j is contained in G i plus j for all i and j. All i and j bigger than one, bigger than zero. So let me just remind you what the commutator of two groups is. H commutator k is the group generated by the pairwise commutators H and k, H and k, H and h, and k and k. Not the same thing as the set of commutators. So that's what a filtration is. Now there's a particular filtration, a particularly well-known filtration, is the lower central series filtration. So the lower central series is defined by G naught just to distinguish it, I won't use the brackets. So G naught equals G1 equals G and G i plus 1 is the commutator of G with G i. So it's actually the maximal filtration because any filtration G commutator G i has to be contained in G i plus 1. So it's actually the maximal. I suppose maximal, minimal, it's the, let's go with maximal. Maximal filtration on G. Any other filtration will have G i contained in G i without the brackets just by induction. So maybe I'll call it the minimal filtration. It's not absolutely immediate that the lower central series is a filtration, but that is true and that's easy to prove by induction. So this is a filtration by induction. So a group is, as is well known, a group is nilpotent if the lower central series filtration has finite class. So a group is nilpotent of class S if G sub S plus 1 is equal to the identity, i.e. if the lower central series filtration, filtration has class at most S. And because the lower central series filtration is the minimal filtration, a group will only admit a filtration of finite class if it's nilpotent. So that's what nilpotent is. So let me just give a quick example, the Heisenberg that we saw last time. So G is 1, 1, 1, R, R. So G naught equals G1 equals G. G2 is the commutator subgroup, GG, which is 1, 1, 1, 0, 0, R. And then G3 is trivial, so it's nilpotent of class. So why have I mentioned all of this? Well, it turns out that for the purposes of the theory I'm interested in, there's nothing really special about the lower central series. Very occasionally the lower central series needs to be discussed. But usually everything works just for an arbitrary filtration. And moreover, it's good to have the flexibility of arbitrary filtrations. So for example, they're closed under intersections with subgroups, whereas the lower central series need not be. So it's much nicer category, well, nice place to work. So a polynomial sequence is something that is defined relative to a filtration. Polinomial sequence, so the group definition. Let's let G bullet equals GI, I equals 0 to infinity be a filtration. The group of polynomial sequences, poly ZG dot, of polynomial sequences P from Z to G. So this definition depends on more than just G. It depends on the filtration is generated by, is the group generated by sequences of the form little GI to the PI of N. So those are sort of basic polynomial sequences where GI must always lie in a suitably high element of this filtration. So we saw this, I gave some examples in the Heisenberg group before. I'm only allowed, in the Heisenberg group, I'm only allowed quadratic terms, which sit inside the commutative subgroup G2. So EG example, 111 alpha N, beta N, gamma N squared is a polynomial is in poly ZG bullet where G bullets the lower central series filtration on the Heisenberg. That's actually not absolutely immediate, but it's an easy exercise to write this as a product of more basic sequences like this. Now again, it depends how much time I have, but there's actually a very remarkable theory of these polynomial sequences in the case where the group is nilpotent. I should say that, sorry, I only want to make this definition when G is a finite class. So G is nilpotent and the filtrations of finite class. There's just a quite remarkable theory that I want to show you some bits of, at least, due mainly to Alexander Leibman, but also to Horst and Krah. And this is the idea that there are some different characterizations of what it means to be a polynomial map in this sense. So alternative characterizations. When you say the group generated, you mean by point one product? Yes, yeah. So there are some alternative characterizations and the most remarkable, so EG, P lies in poly of ZG bullet if and only if you have this derivative property, delta H1 delta H2 to delta Hj P of n takes values in G sub J for every choice of H1 up to Hj. So for all H1 up to Hj in the integers and for all J greater than one, we're here delta sub H, well it's kind of a multiplicative notion of discrete derivative on this group. So delta sub Hf of n is f of n times f of n plus h inverse. So this is somehow, this is a very natural definition of polynomial. These are derivatives and you're saying that somehow certain derivatives lie in certain subgroups. So this is definitely a non-trivial theorem and one fact that you may immediately note about this is that with this definition here, it's completely not obvious that these P form a group. That's just not obvious at all. It's very non-obvious that it's a group with this definition. So in many ways this is the most, really this is somehow the natural definition and then it's a theorem that all polynomial sequences are of that form and that everything of that form is a polynomial sequence. G is nilpotent here. Yes. Again, this is important that G is always nilpotent. Does it follow from the user? Yes, if there's a filtration of finite class that implies that it's nilpotent because the lower central series sits beneath, sits above the filtration. Sorry, beneath the filtration and therefore if the filtration eventually terminates, so does the lower central series. So you can only have a filtration of finite class in the nilpotent case. And actually there's an example which I don't remember off the top of my head. But if G is not nilpotent, these two notions are different. So there are polynomial sequences satisfying one but not the other. So are there any questions on this before I move on? Yeah. Do you hope that the contrary enclosure, it just said you are inside? I think I meant it the other way around. You can have, I mean you can have really quite big, quite flabby filtrations that are just constant for a long time and then start decaying down. In fact, there's a very trivial filtration in which everything in it is just the group G. It's not a finite class. Why do you want to take G0 and C1 to be G? Why not just start at C1 equals the commutator and C and G? Well, if I label things like that then the filtration property is going to look slightly weird. It'll be something like ij and ij, i plus j minus one or some such thing. This turns out to be the neatest way to deal with things. I've done that thing with the board where I'm going to struggle to get this one down again. I think, what is it? Is this possible? So this is a very algebraic theory which I may give some hints of if I have time. It's not that easy to prove these facts and I only have six lectures. So this is valid just in the setting of nilpotent groups. But I'm exclusively going to be interested in a much more restricted setting than that. So we'll only be interested in. And I think this is, I'm not very happy with this piece of nomenclature. But let me say a proper filtration. Maybe I should call it a Lee filtration. I think that's a better term, but let's stick with proper filtration. So these are ones in which everything involved is a closed and simply connected Lee group. So simply connected Lee group in which G is a simply connected Lee group. Each GI is a closed connected subgroup. So the Heisenberg example that I showed you before is definitely of that type. So think Heisenberg example. Actually, let me give you another example. This is a pretty trivial example, but I'll mention it again later. Another example would be to take G to be R and G0 equals G1 equals Gs equals R and then Gs plus 1 and all higher terms to just be trivial. So that's what I'd call a quite a flabby sort of filtration. It's definitely not a minimal one. And an exercise, well, in fact, just follows from the definition. So with here, traditional polynomials P from Z to R of degree at most S. So EG and P of n is alpha n to the S. Those will all be polynomial sequences in the sense of my definition there, in the more general sense. So it really is a generalization of a familiar notion. So now I need to introduce, if I want to talk about nil sequences, I want to introduce a lattice. While I'm rubbing this out, maybe I should say, I mean, I think it's instructive to see the general definition of these things. But personally, I usually just think about examples on the Heisenberg group, which have a lot of the general structure already, although not all of it. So lattices and automorphic functions. So a lattice is just a discreet and co-compact subgroup. So gamma less than or equal to g is a lattice if it is discreet and co-compact. So we've seen already an example in the Heisenberg EG 111 Z Z Z in the Heisenberg. So there may not be a lattice in G. There are examples in dimension seven, I think, of class two nil-potent groups admitting no lattice. But that's totally irrelevant for me. I want to give you very much the sense that this is, even though I've used words like simply connected leagroup, I'm not doing any kind of topology here. This is really algebra. Once you think of these things as like vector spaces, they have no interesting topological content, really. I'll make that clearer because I'm going to mention the Lie algebra. So being a simply connected nil-potent leagroup means that you are, the exponential map from the Lie algebra is a homeomorphism. So they really are algebraic objects, I would say. So it's possible that G admits no lattice, but I simply won't care about such Gs in this theory. They just never come up. I'm always going to assume we say that the filtration G-bullet is rational. Well, if gamma basically forms a lattice in each element of that sequence. And we'll only ever be interested in rational filtrations. Again, there are sort of what I'd call soft results, and by soft I don't mean easy. There are statements due to Malchev along the lines of that if that any lattice will be rational with respect to the lower central series. I believe that's a theorem. But again, it's irrelevant to us. Every situation that we're given, it will somehow be clear that these things hold. So I'm not interested in pathologies. Any questions about that? So that's lattice, and now I can define automorphic function. For me, an automorphic function, a smooth automorphic function, is some phi in C infinity of G. C infinity of G is a meaningful notion. G is supposed to be a Lie group satisfying that phi of gamma G equals phi of G for all gamma in gamma. So now I can define precisely what a null sequence is. So definition, a null sequence of class S is a function chi of n is phi of p of n, where all of the objects written there are as above. So p is a polynomial with respect to some filtration for some proper filtration G bar, and which is rational, rational with respect to some lattice gamma, and phi is some smooth gamma automorphic function. So there we are. That's a formal definition of what a null sequence is. It's a bit more complicated involving this additional structure of a filtration, which must be rational with respect to a lattice. So maybe now is a good time to make some remarks about this. But I don't necessarily think that this particular definition will last forever more. And here's why I think this. I talked about null sequences being the generalizations of additive characters, which are e to the 2 pi i theta n. So those additive characters are a very special type of null sequence. And here I'm allowing any smooth function phi. And the reason for that is that we don't know which is somehow the natural subclass of smooth functions phi that we should be considering. So maybe one should take eigenfunctions of some operator on G mod gamma. I don't know. I don't know. There seems to be no persuasive reason to select one class at the moment. So this definition is potentially subject to revision in the future, but for now it's fairly workable. Now the statement of the inverse theorem for the Gauss-Norms involved a notion of complexity. And without that, it has no content because these null sequences can be just any these can take essentially arbitrary values on arbitrarily long intervals. So to make the theory useful, we have to have a notion of complexity. So I want to at least tell you the definition because I want to give a complete statement of the inverse theorem for the Gauss-Norms. But these complexity issues in this subject, they're always annoying and they're never conceptually difficult. So there's something that I always just put in to what I tell and myself we always would just put in an appendix to our papers. They kind of always work out in the end. A bit like I don't know if anybody's done linear algebra over Q where you have to keep track of the heights of the rationals that you're using and so on. These things are always tedious, but never really difficult. Well, sometimes really difficult. I guess Immanuel has done some situations where it has actually been very important to keep track of those things. But for me, they'll never be conceptually difficult. So complexity. To make the theory quantitatively useful, maybe before saying this, I should also say the notion of a null sequence first arose in work of Bergelsen-Hosten-Kra in a Gothic theory. And their notion was a little bit different to this in that they, in a Gothic theory, it's somehow natural to just use a continuous function phi. And they didn't use polynomial sequences. They used a special type of polynomial sequence, just a linear sequence. The need to use polynomial sequences arises only in this quantitative theory for reasons that I'll mention. So to make the theory quantitatively useful, we need to know, we need measures of two things really. The complexity of the filtration with respect to gamma and also how smooth the function fires. So the smoothness. So to quantify those notions, well, you have to choose a basis with respect to which you're measuring these things. And the way to do that is to pass to the Lie algebra. So we work in the Lie algebra, curly G. I'm going to run into trouble here. I need to make sure that does not look like a phi. Yeah. Well, there's a Lie algebra, G. Well, I myself am not super familiar with Lie theory. I don't want to go over huge amounts of the theory, but what I recommend, if you're not familiar with it, just in the Heisenberg case, figure out what the Lie algebra is. It's a three-dimensional vector space with a bracket operation on it. So the thing is, for these simply connected, since G is nilpotent and simply connected, we have homomorphisms, homeomorphisms, not homomorphisms, homeomorphisms between the Lie algebra called the exponential map and the logarithmic map. And as I say, this really means we're doing algebra and definitely not any kind of topology. So we're doing algebra. Now, the Lie algebra is a vector space, so I can just pick a basis for it. So complexity. Complexity can only be measured with respect to a particular choice of basis. Choose a basis, curly B, for the Lie algebra, G. Now, it's convenient not to choose an arbitrary basis, but to choose one that is adapted. So we say that curly B is adapted to the filtration. So if x1 up to x sub dim, I guess I want to actually start from the other end, x sub dim g minus dim g i plus 1 up to x sub dim g is a basis for the Lie algebra of g i, which is defined to be the log of g i in the filtration. So an adapted basis is one that's good for computing with respect to filtrations. And once we've made such a choice, we can quantify those two notions above. So I can now give you the definition of both of those things. Are there any questions on that? So I should have time to just finish this before the end of the lecture. Okay, so definition. We say that the complexity, which I would write hash sub b of the filtration and gamma, because that's the things it depends on, is at most m if there is an integer. So m is supposed to be an integer if the following are true. So basically, the idea is that I want all of the interesting things about how the filtration and the lattice interact to be bounded in terms of m. And it turns out that these are the interesting things. So first of all 1, so the structure constants describe the Lie bracket in terms of this basis. So those are the aijks. They satisfy they're all at most m and they're also m rational. So mijk lies inside the integers. So somehow there is this result of Malchev that says that a Lie group only admits a lattice if all of the if and only if the structure constants are rational. So this is a quantitative version of g admitting a lattice, gamma. And I found it convenient when writing notes on this to introduce just one slightly technical extra condition. And I'll tell you why in a moment. And so this is just purely technical, but I want to give things completely. Let me just remind myself exactly what it was. Yeah, for each value of i, there are at most m values of j such that that's not zero. Not trivially zero. And I included that just because it makes these notions behave better with respect to certain functorial properties of groups like taking direct products. I found that's quite convenient. So just ignore that. And then secondly is the assertion that m times the integer lattice in the basis b is contained within log of the lattice gamma, which is contained within 1 over m times the integer lattice on the basis b. So this is another statement about how the lattice sits inside. It behaves with respect to this basis. So log gamma is just the image under the logarithm map of all the elements of the discrete group gamma. It's actually not necessarily a lattice. It's not necessarily a subgroup, actually. So you have got to be careful with these li operations. They're definitely not homomorphisms. So it's a lattice up to finite index, but it's not closed under addition necessarily. In fact, for the Heisenberg, it's not. So that's a definition of complexity. And then I have to define how smooth phi is. Well, that's fairly routine, it turns out. Let me get filtrations down again. Don't need that anymore. 10 minutes, is that OK? I think we'll make it. We'll spend the first few minutes just recalling trivial definitions anyway. Actually, maybe not. This is France, right? I think I can manage it in six minutes. So we're going to quantify the smoothness using some basically, well, essentially, sub-left derivative norms. We define the smoothness norms. Smoothness, so I write Wm curly b. This will be the supremum of basically all derivatives with respect to the basis elements. So that's an m prime of phi in L infinity. So where the supremum is overall choices of I1 up to Im prime, and overall derivatives of order at most m. So it's just the biggest any derivative can be, and derivative here is in the usual layout of a sense. So where dx phi is the derivative at 0, d by dt at t equals 0, of phi times x of xp tx. So this is a standard definition. So I don't know if there are any genuine experts in the audience, or I know this is being videoed. I don't know if people ever watch these things. But if so, I should like to remark that these notions of complexity are rather different to the ones that are used in papers by Taron myself, where we talk about Lipschitz norms on phi, which require one to put a metric on G modulo gamma. And I've come to the conclusion, and actually I think Terry came to this conclusion years ago really, that smoothness norms are the right way to proceed. And in fact, other people who work with quantitative equidistribution results, such as the papers of Einseidler, Margulis and Venkatesh, they use these smoothness norms as well. One should not be working in the Lipschitz category. Smoothness is correct. So let me finish then by just stating precisely the inverse theorem for the Gauss norms. So I basically stated it before, but so suppose that f in the Gauss norm is at least delta, then there is a nil sequence, chi of n, which is phi of g of n, where the filtration has class at most k minus 1, so where g tilde has class at most k minus 1. And with respect to a suitable basis, for a suitable basis, curly b adapted to g bullet, we have that the complexity with respect to b of the filtration is bounded only in terms of delta and k. So I'll write this as big o delta k1. And the smoothness of phi is also so bounded. So the smoothness is bounded for any m. And finally, and of course the important bit, and f correlates with chi for some delta primed greater than zero in a way that depends on delta and k only. So you can see somehow why this is not normally stated formally. It's a bit of an effort, but the gist of it is what I explained at the beginning. So you correlate with a nil sequence of finite complexity. So next time I will look at the converse of the inverse theorem for the Gauss norms, and you'll be pleased to hear that although these notions of complexity are in the background and would be important if you wanted to do everything rigorously, I shall not be mentioning them explicitly. So I'll just say that they can be bounded. So that's it for today. I guess we should go make haste.


All right, let's talk about his falcons unique run game from Sunday. Let's start here with the kids He's gonna come across in motion and what we're gonna run is just a little tall sweep now This motion is critical talk about the creativity and all this men's offense This motion is critical because it forces this DB to go outside if you go back a little bit This DB starts right at the front. He starts here So now he's contained but when you bring that motion across it forces him to widen now to play get started You got a nice tall sweep by Cordell Patterson here now watch the good blocky up front nice double team Nice job of Dalton's ceiling right here, but the guy I want you to pay attention to this offensive line It's playing some really good football to start Chris Lindstrom on the back side He's already fighting the guy at the line of scrimmage, but this is the guy he has to reach CP's gonna get a nice alley through here But if it's not for this back side effort of Chris Lindstrom cutting off this guy There's no way CP gets through this alley the play continues boom look at that Look at Lester laying out to get this block and now because he gets his block This guy could have easily made this play and he doesn't use the extra effort to get there Now it's a five-yard game, but a nice job of seal block here Nice job of finishing here and look at these guys pancake and guys right here in offensive line You got a runoff to get him out of here and now watch CP finish vision athleticism That's why CP average 8.3 yards of carry and the Falcons rush for 170 on yards again because of his effort Thank you guys for joining me. I'm DJ Shockley.  Nice job of a double team here You're gonna get a nice block on the outside and look at it They got everybody sealed up you're gonna get up to the next level and watch the wine black block here Boom here's your fullback get up on that backer who tried to come over the top and now look at all the room that CP Has on this backside to cut back on this wine black block And that's a nice good run here on first down you get six yards five six yards on first down All right Here's the exact same play you're gonna get the same action from the fullback a wine back kind of motion here And here's that same linebacker that I talked about in just the last clip now You remember the Falcons broke this off for a nice run on the backside for about six seven yards Now he's gonna be so concerned with getting to this backside He doesn't even see that this is his alley to cover now watch the the wine back motion watch this linebacker in the middle here Here's the wine bag motion full back coming across look at his eyes His eyes is looking at this fullback He should be filling this gap, but because the Falcons were such successful in this run Coming back this way He is trying so hard to get back over the top now you get an easy block by the center Nice seal here on the upside here And then you get a nice just seal block on the outside and watch the crease you get here because He sees this and then the vision of CP to go here This should this should go back this way But because this linebacker so concerned with getting over the top on this run and now you hit it And you got look here you got blocking on the outside This is the first guy he sees and you know CP with his ability to the end zone gets in the zone And they know the big-time play and this is why the Falcons were so successful running the football Because of what they did early in the ballgame.  All right. The guy I want you to watch is Caleb McGeary here watch He's gonna have a good job of sealing this guy on the edge But he also does a good job of getting up to the next level which is this guy He's gonna want to shoot this gap right through here now as the play gets started Here's the stretch zone action. Good job of getting reach block on him pits is gonna seal here You got a nice head up blocked by Parker Hesse on the back side He's got the seal in his backside as well.  This is the first guy dad's chance to get to him And he's 15 yards away. This is created by the guys up front And this is why this Falcons office has been so efficient running the football Because of all the double teams and good blocking them up front watching one more time from the back side Watch this guy shoot the gap Boom, but you see him. He's got these he's engaged now He comes off seals this guy and creates the edge that you want And now that's a nice running lane for a quarter of paterson to get through another big 15 yard game for the falcons


Ladies and gentlemen, the story you are about to hear is true. Only the names have been changed to protect the innocent. Fatima cigarettes, best of all long cigarettes, brings you drag net.  You're assigned to narcotics bureau. A vicious criminal has resumed operations in your city. His profession, dealer in narcotics. You know his name. You know he's guilty. Your job, prove it. If you want a long cigarette, smoke the best of all long cigarettes. Smoke Fatima. Fatima is the long cigarette which contains the finest Turkish and domestic tobaccos, superbly blended to make Fatima extra mild. And that's why Fatima has a much different, much better flavor and aroma than any other long cigarette. That's why Fatima has more than doubled its smokers, coast to coast. So, if you want a long cigarette, smoke the best of all long cigarettes. Smoke Fatima. The documented drama of an actual crime. For the next 30 minutes in cooperation with the Los Angeles Police Department, you will travel step by step on the side of the law through an actual case from official police files. From beginning to end, from crime to punishment, Dragnet is the story of your police force in action. It was Thursday, January 21st. It was cold in Los Angeles. We were working the night watch out of narcotics bureau. My partner's Ben Romero. The boss is Thad Brown, chief of detectives. My name's Friday. I was on the way back in to work and it was 3.49 p.m. when I got to the main lobby of the city hall. Public phone booth. Hello, ma. This is Joe. I couldn't help but, ma, they changed the schedule. I got my stuff all right. Thanks for packing it. Yeah, I got them. All right. Listen, ma, I'll call you whenever I get the chance. Now, don't worry. How long are you going to be gone? I haven't any idea. Maybe a month. All depends. You can't. Call Ben. He'll get the message to me somehow. Well, I'm not going any place, ma. I'll be right here in the city, but I just won't be able to come home for a little while. It's a special job. No, like the last time. Well, we'll rest, but then get your rest. Okay, ma. I'll be all right. Why don't you invite the neighbors over? The Newtons? That'd be good coming for you. Maybe I'll ask your hand, Elizabeth, over. Now, don't worry. If you want to get in touch with me, you deliver the message to Ben, okay? Yes, sirs. Oh, it's just another job, ma. I'll work out. I'll call you when I can. Yeah, you too. Goodbye, ma. I left the phone booth and started down the corridor. I went up a short flight of stairs and turned left. The afternoon crowd in the city hall seemed heavier than usual. I walked past the elevators and turned right down another corridor. It was 3.58 p.m. and I got to room 24, Narcotics Bureau. Captain White? Hi, Joe. You want to take these? Yeah, sure. It's my badge. Okay. It's all my identification and my gun. Right. I'll take care of them for you. These clothes, look, are they? Just a minute. Now, let's see. Yeah. I don't like that tie. Romero? Yes, Gibber? Let's see your tie. Yeah, swap with Friday, will you, Ben? Christmas tie. It's pretty loud. Mine's not. That's the idea. Here. Here's some stuff to carry in your pocket. Social Security card, ID card, all made out to Joe Kiber. Some book matches from St. Louis, a couple from Reno, Nevada. Okay. You pick up another gun? I loaned him my 25-oh-to-man. It's small. It's easy to carry. Suit yourself. I don't have to tell you to be careful. No. It's a chance we've been waiting for, Joe. A lot depends on you. Do what I can. Just one thing I want to tell you. Take your time. Take all the time you need. Don't push it. I understand. No time limit. Your time's up when they find out who you are. Captain Lynn White and I left the narcotics bureau together with Ben and Johnny Bingham. We went down the hall to the office of Chief of Detectives Thad Brown. As in most major narcotic cases, the plan involved the coordinated work of all three offices, the federal, state, and our own local bureau. The operation involved a great many men and a lot of time. When we got to the Chief of Detectives office, two men were with him. Bill Craig, the agent in charge of the Federal Bureau of Narcotics for the Southern California area, and Inspector Virgil Beckner, head of the State Narcotics Bureau for our district. All of us had one common goal, the apprehension and conviction of two men. Arthur Belmont and Ralph Costello. The first man on the list, Ralph Costello. Chief Brown outlined the overall plan. Craig, your federal men have been tracking Costello off and on for three years now. Beck's of your state agents. Same for our men. This time we can't afford to miss. You figure an undercover man working locally, right Chief? Yeah, Craig, you'll start right from the bottom, work up the line until he gets to Costello if he gets there. Beck, where are you going to start? Kevin Weiberjul laid out for Beck and Craig. Yeah, Friday here is going to handle the job. He's got his full instructions. Joe, you want to film me? All right. I'll make my first contact tonight. I'll meet in a bar down on South Pico with another one of our undercover men, Beni Arradondo. He'll introduce me as Joe Kiber to one of his informants. The informant is supposed to help get me into the Flats gang. The same bunch running on the south end of town? Yeah, small-time peddlers. Precurious little bit of everything. Go on Friday. When I get in the gang, I run with them until I find out where and how they make their buys. If you get a contact, you make buys all the way up the line and get as close as you can to the town. Yeah, that's right. You worked out your contact with us? He knows that under no conditions will he be seen around the department here. It's been set up that I have a hotel room lined up down on the east side. Romero here and Captain White will be my only contact with the office. I'll be using the name Joe Kiber. Sounds all right to me. How about you, Craig? How about that informant Friday? Can you count on him? Arradondo thinks a lot of him. He says he's a good man. He's the first rung on the ladder. He's got to be solid. If he's not, we won't have far to fall. It depends on how you look at it. You can kill yourself in the bathtub. 8 p.m. Thursday, January 21st. I checked in at the Casino Hotel on Terminal Street. I registered as Joe Kiber, Omaha, Nebraska. I was given the key for Room 5. The rent was $7 a week. I unpacked a few things I had in my bag and went down the hall and took a shower. I went down to the lunch room on the corner. I had an egg sandwich and a cup of coffee. It was 11.18 p.m. when I walked into Blue Wright's Bar and Grill. I ordered a beer and sat down. I watched the missing persons program on the television set above the bar. Blue somebody, Kiber? Hello, Benny. Been here long? I just got here. Where's your boy? Sitting over there with that fella in the blue suit. Name's Gene. Who is the guy in the blue suit? One of the flat's gang. Gene's lining up your introduction now. Guy's name is Ludwig. I call him Lud. He knows me as Steve. Right. What do we do? Sit tight till Gene gives us the word. Tie yours. Looks like it's on fire. Looks all right. I wouldn't wear it. Ludwig. You got an hotel, okay?  Room five. Gene wants us. Let's go. Hi, Steve. See, your boy got here. Yeah. Gene, meet Joe Kiber. Hi. This is Lud. Joe Kiber? Lud. Sit down. You like the fights, Kiber? Yeah. I got nothing out here in that line. I used to go to the garden when I was east. I got some fine cards to the legion. Where? Hollywood legion. Friday nights. Some classy-looking fighters out there. Where is that? Out in Hollywood. Nice little stadium. I'd like to go with you sometime. Tomorrow? I got a date. Maybe next week. Bring her along. A lot of women go. Not this one. Okay. Hey, you guys hungry? I could eat. Yeah. Joe? Sure. How about here?  Steamed table over there. The stuff smells pretty good. It's not as garbage if the wind's blowing the other way. Let's get a French tip sandwich. How about Galbra, serve one satelon? Okay. How about you guys? Sure. Let's go. All right. You from the east, Kiber? Omaha, Memphis. All around. Yeah. You don't talk very much. You do. You talk tough. Are you tough? Sometimes. This place we're going to go eat, sometimes a meat's tough too. Yeah.  The following week at the fights, I met some of the other members of the Flats gang. They were a typical group of hoodlums. Unlike fiction writers have portrayed them, generally gangs of this type do not operate under a gang leader. Each member considers himself the best of the lot. For all practical purposes, they didn't need a leader. But as in any group, some men are more dominant than others. Lud was one of these. Because of his tough manner, I observed that the gang members placed confidence in Lud. It was then that I decided that I had to be tougher than he was if the gang was going to accept me. Five weeks went by, March 7th. There was still no mention by any of them that they were either using or dealing in narcotics. Come on in, Kiber, sit down. Lud. Kiber, me Jerry, Phil. Hi. I picked up the tickets for the basketball game tonight. Good seats? Yeah, they look okay. Got an extra doggy? Maybe I'll tag along. Yeah, we got four. You look kind of sad, Kiber. He always looks that way. First, he was tough, now he's sad with you in that mouth. You know it all, don't you? No offense, you look a little low. I don't know about you, Kiber, but I'm a little on the par. I'm gonna have myself a pop. You interested? No, I don't use it. Why don't you try it? You might get a kick out of it. I have. It's all right going up, but it's nothing coming down. That's where you make a mistake.  Don't come down. I love it. You heard what he said, Jerry. You don't like it. How does he know? He never stayed up long enough?  You talk about Kiber trying to be tough. You think you're the big wheel around here? That's enough. You ought to quit giving orders, Lud. You know better than the rest.  I kind of talk and keep us both happy. You, you. The boss, man.  Why don't you two quit it?  Well, don't get mad at me. I only wanted to save an argument. Canada, I say. Now, look, big mouth. You can push fella around, but not me. Now you're playing the tough guy again, ain't you?  You set me down, punk. All right, now listen to me, both of you. I'm tired of being talked down to like a junior member of the firm. You either treat me equal or leave me alone.  You had it coming, Lud. Yeah. I'll put that bottle down, Lud. Well, you get the gun. We carry that thing right along. Right along. Put it down, Lud. Okay. I'm long on memory, Cabba, remember that. Yeah, and I'm real short on patience with you. Well, I still hadn't had my pup. Better hurry. I don't want to miss the game. You got good seats, eh, Cabba? They're not too low. I can't see nothing if they're too low. Don't worry. You'll be high enough. Two months went by. By playing the tough guy, I gained a great deal of prestige in the eyes of the other gang members. Jerry Fell made sure that all the members heard about that episode up in Lud's Room. Dealers and users of narcotics rarely carry guns. The members of the Flats gang were small-time peddlers and users. They're referred to as mules or small fry. When they found that I carried a gun at all times, they were impressed. They considered me one of them. Since the very beginning of my undercover work, I met weekly with Ben Romero and Captain Lynn White of the Narcotics Bureau. I would be picked up at a different location each time, making sure that I wasn't followed and would remain in the car and drive around in a remote section of the city, discussing my progress with the gang. During this first three-month period, under the pretext that I had clients to furnish, I made two small narcotics buys. One for $13 and one for $8. As soon as the purchases were made, I would mark them for identification, contact Ben, and then turn the narcotics over to him to be booked as evidence by the property clerk at Central Division. Another month went by. We had just returned from the Midget Auto races and we were sitting around in Led's room. You mentioned something out at the races, carbon. I was on your mind. I told you, Ludd, I need a half a dozen caps right away. I got people putting a bite on me. Old customers. How old can they be? You've only been out here five months, remember? When they're hooked, they get to be old customers in a month. I fixed up two buys with moors for you. Tony says he can't handle anymore. I hasn't got enough around. You got on board late, you know. Tony can get more. Who's his source? I know him. How about an officer want him? He'll deal with Tony. You said he hasn't got enough. That's right, I did. Okay. How much do you want? Are your customers worth? They'll pay. What's the guy's name? Costello's one of them. He'll have enough for you. Who's the other guy? He'll deal with Costello for now. Where can I meet him? Marshall set it up for you. I gotta meet him now, huh? Come in. Police officers. Shake it down down a hole. What's the trouble? Checking for a robbery suspect. Find anything, George? Room's clean. We don't know anything about a heist. You'll have to come downtown and answer a few questions. It's a matter with you, fellow.  Yeah, you spoiled it. You are listening to DRAG NITS. Authentic stories of your police force in action. Now, here's an authentic report from Fatima Cigarettes. In 1940, they doubled its smokers from coast to coast. In 1950, enjoy Fatima yourself. You'll find Fatima extra mild. Because Fatima is the long cigarette which contains the finest Turkish and domestic tobaccos superbly blended to make Fatima extra mild. You'll find Fatima tastes much better. Fatima's superb blend gives you a much different, much better flavor and aroma than any other long cigarette. You'll find Fatima best in cigarette quality. Fatima has always stood for the best in cigarette quality. For a new year of greater smoking enjoyment, buy Fatima in the appealing golden yellow package. You'll agree, Fatima is the best of all long cigarettes. The chance of my being picked up while working on an undercover assignment was one which all of us had considered. Since only a handful of men out of some 5,000 working police officers in the department knew anything about our narcotics investigation, we knew that such an occurrence was not impossible. It's one of the chances we had to take. In this instance, we lost and the critical meeting with one of the men we were after was forestall. How long our detention at police headquarters would delay my meeting with Ralph Costello was anybody's guess. Could mean weeks or maybe months. I was booked on suspicion of 211 PC, Robert. So was Lud. The next afternoon, I was taken from cell block 10D2 to the interrogation room. Come on in and sit down, Kiber. How are you, Friday? I was a tight squeeze. Book and numbers been canceled, Joe. Prints been stopped. Those two men from robbery who pulled me in the wind and down a hole. I thought I was in trouble for a minute. They had no idea you were in that room. Once they got up there, they had to follow through. Well, they played it right. They remembered their etiquette. If either one of them had said hello before you did, you might have been in big trouble. Well, I'm in big trouble anyway. I had a meet all set with Costello. Almost set, anyway. Just a case of bad timing in that pickup, huh? I don't think they'd get there two hours later. It might have been different. Well, how do you stand now? How close are you to Costello? I need some more money. I got to pay off Lud. He'll take you to Costello if you pay the right price? Yeah. Lud's working through a morse. You know about him. Remember, Friday, if there's any questions, when you get back to that gang, you were booked for CCW. You're out on bail. Yeah. I got you now the guns, Joe. 32 automatic, okay? Yeah, thanks. I couldn't go back with the same one. What about the federal and state men? How are they doing? Pretty good. The federal man picked up Costello and Fresno. He was connected with a sale of six cans of H. Mm-hmm.  He knows there's a shortage down here. Case isn't too strong against him.  He's out on bail. Costello's back down here now. Yeah. Seems like we get our hands on the guy, but we can't hold him. Narcotics in their possession are under their control. That's what the book says. That's the way we got to get him. We'll get him that way. It's up to you now, Friday. Stay with it and keep your chin covered. Well, if you need anything, Joe, call. My mother's been over at the house for dinner a few times. She's okay. Thanks. Tell her I'm all right, will you? Sure. She worries a lot about you, Joe. Anything happened to you and just about killed her. That makes two of us. I'll see you. Before I left the city hall, Captain White drew out some more money from the Secret Service Fund. This fund is for the sole purpose of undercover work. This latest amount was for the narcotics buy that I hoped to make with Ralph Costello. An hour before I left, Lud was released on a rift that he'd arranged for. Saturday, June 7th, 9 a.m., I checked back into my room at the Casino Hotel. During the three weeks that followed, I kept asking Lud to arrange a meeting for me with Tony Morse, the next man on the ladder, on the way up to Costello. Lud kept stalling me. Another week went by. Captain Lin White, Ben and I held our regular weekly meetings. On July 6th, Lud told me that a meeting with Morse had finally been arranged for 8 p.m. that night. I called Ben and told him I'd meet him and the captain immediately after I talked with Morse. At 8 p.m., following the instructions Lud had given me, I was in the downstairs waiting room at the subway terminal at Fifth and Hill. I was told to wait for the Apple vending machine. Excuse me, mister. Oh, yeah, sure. Khyber? Yeah, you're Morse? That's right. Want an apple? No, no thanks. Well, sit down. Now, what do you have in mind? I got a couple hundred bucks to spend. Can you handle it? Who sent you? You know who sent me. Sure I do. I just want to hear you say it. Lud. We can handle it. What do you have in mind? I said $200 worth. That's 40 caps. We got it. No, no, that Mexican junk. I want European stuff. You bought before. You'll take what we got. That last buy I made through Lud, the junk was cut to nothing. It can only use so much milk as sugar, you know? By the time it got to you, it was probably cut pretty thin. So was the price you paid for it. I'm not looking for bargains. I pushed to good people. I want good stuff. You'll do better this time. You're not dealing with Lud. Sure, we cut it. No more than anybody else. Not as much as Lud. When can I get it?  A couple. Have it for you in an hour. Where's the meat? You gotta watch? Yeah. What time you got? 12 minutes after 8. Add a minute. Make a 13 after. Okay. An hour from now. 9.13. Meet Lud at Macy and Brooklyn on the corner. He'll tell you what to do. Will Lud have it? Meet Lud at 9.13. See you later, Kyber. Wait a minute. How do I know you're leveling? How do I know you are? I went out the front of the subway terminal building. I took a cab down to 7th and Main. I got off and walked into Pop Sherman's bar. I called the office and set up a meeting with Ben and the captain. I ordered a beer, paid for it, left my change in the bar, asked the bartender to watch it, told him I'd be right back. I went out the back way, crossed the alley and got down to Los Angeles Street. I walked up to 9th and picked up a cab to take me to Fulton and Covina Avenue. I got out and walked two blocks. It was 8.41. Sir. Hi. You meet Morris? Yeah. Sure nobody killed you? I took all the precautions. What's your setup? I'm not sure and I don't have much time. I'm going to make the buy tonight. When? 9.13. You don't have much time. Kind of rushing it, aren't they? I figured I'd better play along. Who's the meet with? Morris told me to meet Lud at Macy and Brooklyn. Said that he'd carry it from there. Costello in on it? I don't know. You've got it all. All right. We'll start picking up the flats gang. Everyone but Lud. What do you think? Well, the way I got it figured. Morris is Costello's runner. I don't know if he's going to check me out as far as I could tell. He thinks I'm okay. Yeah. I got to hunt some Luds going to take me to either Morris again or Costello or possibly both. I don't know where the actual meet's going to be. That means a tail job. We'll have to pick you up at Macy and Brooklyn and stick with you until after Lud leaves if he does and follow through with you. Figure it wide, Skipper. Don't worry. I know we're close. What time you got from there, huh? 10 minutes to 9. Turn down the next block. Right. Pull up here, Ben. Here you go, Friday. Keep your chin covered. Yep. Hey. Hello, Phil. Friends of yours in the car? Why? I know them. They ain't friends of mine. I didn't say I knew them. I don't know the guy driving, but the other guy, I've seen him lots. Just about four weeks ago, we all seen him. That fuzz white, a Caddox man. Oh, yeah. Well, they've been ridin' me since they picked me up with a gun. Won't do, cop.  That was robbery, remember? They got a make on me from Nebraska. They've been on me ever since I got here. That figures. You're one of them. All right, look, Jerry. I'll argue with you later. I'm in a hurry. I gotta meet Lud. I take alone. I wanna see Lud, too. You're gonna spill the lead about what you think? Maybe. I figure I owe it to him. I know him a lot longer than you. I know he ain't no cop.  I know you are. Let's see what Lud thinks. Yeah. All right, come on. On your feet. Get out. I looked at my watch. It was two minutes to nine. In 15 minutes, I had to meet Lud. I had to hit Jerry Fell. I couldn't take the chance of him getting to Lud before I did. I couldn't leave him. I couldn't take him with me. I pulled him to his feet and half dragged and half carried him two blocks before I spotted a patrolman. Hey, officer. Officer, over here. Yeah, what's the trouble? I'm Friday, Central Narcotics. Yeah. Take this man and get him downtown. Contact Chief Brown. He'll identify me. Serial number 2288. Friday, Narcotics. Suspect's name here is Jerry Fell. You got it? Yeah, you got some kind of identification? No, I haven't. Not a thing. It's a special duty. I'm sorry. I don't know you. You have to hold you until I call in. All right, but hurry, huh? Call box right here. This is Carlson box 117. Check on a matter with the Chief of Detective Brown, will you? Yeah, that's right. I have a man here who identifies himself as Friday. What's your first name? Joe, Joe Friday. Tell him to hurry. Yeah. Joe Friday, Central Narcotics. Serial number 2288. Says he's in a hurry. Holding a suspect, Jerry Fell. I'll hold on. You might watch this five after nine. What time you got? I got six minutes after. Might be a little fast. Any cab stands around here? Four blocks up the street. Which way? That way. Yeah. Okay, I will. Thank you. Okay, Sergeant. Sorry to hold you up. Need any help? No, you just hang on to this guy. Don't let him go. I started to run. Macy in Brooklyn. Six blocks away and I had eight minutes to make it. A narcotics buy is one date you're not late for. Either you're there at the specified time or there's no deal. The veteran narcotics peddler knows that that's the only safe way for him to operate. A minute, one way or the other, could mean an arrest. I ran. You're out of breath, Kiber. Anything wrong? No, the cab broke down. I didn't want to be late. All right, you got 40 seconds. That's cutting it pretty thin, but it'll do. Come on. Right here. By this lamppost. I had said right in front of it, don't move to the left or right. Stay put. They'll handle the rest so long. 200. Here's your package. Okay. That's it. Hi, Kiber. Meet Ralph Costello. Hi. Out this side, Kiber. Okay. I'll see you. Did you make the buy Friday? Yeah, take them. All right, Joe. Ben. Thought you were with the captain. They don't need me. That intersection's blocked off up there. They're pulling them over right now. Yeah. They got them. Costello in the car? Yeah. And that's half of the team. Now what? We'll go after the big man, Arthur Belmont. Took us seven months and four days to get to Costello. That's time. Yeah. It always seems to work out that way, doesn't it? What's that? They always run out of time before we do. The story you have just heard was true. Only the names were changed to protect the innocent. On July 6th at 10.45 p.m., Ralph Costello was taken to the Narcotics Bureau, the interrogation room. In a moment, the results of that interrogation. It's amazing how many long cigarette smokers are changing to Fatima. Here is the actual report. From coast to coast, Fatima has more than doubled its smokers. Yes, more and more smokers every day are discovering that Fatima is the best of all long cigarettes. Smokers find Fatima has a much different, much better flavor and aroma than any other long cigarette. They find that Fatima is extra mild because it's the long cigarette which contains the finest Turkish and domestic tobaccos superbly blended to make it extra mild.  Best of all long cigarettes. With the promise of the United States District Attorney that his prison terms for the possession and sale of narcotics would run concurrently rather than consecutively, Ralph Costello agreed to furnish us vital information concerning the number one narcotics dealer on the Pacific Coast, Arthur Belmont. Next week, The Big Man. Arthur Belmont. You have just heard Dragnet, a new series of authentic cases from official files. Technical advice for Dragnet comes from the Office of Chief of Police W.A. Wharton, Los Angeles Police Department. Fatima Cigarettes. Best of all long cigarettes has brought you Dragnet from Los Angeles. Here, Mr. and Mrs. Ronald Coleman in the halls of Ivy. Tomorrow evening on NBC.


If you go back and watch my videos over the last few months, you're going to hear me saying over and over again that the Democrats and the media are going to incite violence with their hyperbolic rhetoric over immigration. All these comparisons to Germany during World War II and concentration camps are obviously going to incite somebody to take action. Why wouldn't you? I mean, if you truly believe that Nazis have risen up and are putting people in camps, you have to take action. That's a question that I have for the Democrats and their media. If they truly believe all of their rhetoric about concentration camps in Nazis, why haven't they raised an army and stopped it? Why haven't they taken action themselves? I think the answer is pretty obvious that they don't actually believe this and they are trying to incite groups like Antifa to do their dirty work for them. I think ultimately they want people on our side to fight back and defend themselves and then suddenly the media will take an interest and cast our side as the aggressors. This attack occurred over the weekend during protests that took place in ICE facilities, one of which where they took down an American flag and raised a Mexican flag in its place. Antifa was at these rallies and one of their members decided that it would be cool to get an AR-15 rifle and some fire bombs and attack an ICE facility. It didn't go well for him and he was shot dead. If you look at the guy's manifesto, you're going to find lots of words and phrases that come straight from AOC, her cohorts and the media.  That's a talking point from AOC and her defenders in the media. But keep in mind just for context that this is taking place just a couple of weeks after a journalist was attacked and violently beaten by Antifa members and then subsequently defended by members of the media. Which is another story that the media largely ignored and the journalist that did cover it actually defended Antifa and attacked the journalist for being critical of the domestic terrorist organization. Checking on Twitter, you'll notice that none of the media organizations are covering this story at all. If you search Google for any reporting on this Antifa terrorist attack, what you're going to find is that all the mainstream networks mention it on their internet sites, but don't mention Antifa. If you refine the search to include Antifa, you'll find all the people that are mentioning that's Antifa are all alternative news sites. Curiously, this story involves an attacker that used an AR-15 and when does the media ever pass up a chance to fearmonger about the AR-15? The answer is when they're the ones who incited the attack. One thing I did find while browsing Twitter was a domestic terrorist promotional piece by CNN's Kamal Bell, who I've exposed on more than one occasion promoting Antifa. Did you happen to catch that familiar face?   And they're talking about Antifa or Antifa, however you want to pronounce it, calling them the alt-left. Well that group protests fascism. So maybe their tactics weren't exactly right. All groups like that, political groups, rights groups, protest groups. It's messy. Antifa or whomever anarchist or malcontent or misguided, they are all so wrong to hit, but fighting hate is right. And Tifa is widely perceived as an African American organization and this is just part of the same story. This is about black versus white. With media outlets and the Democrat Party openly defending and promoting this violent domestic terrorist organization, it shouldn't be a big surprise that we're seeing this escalation in violence from them. They appear to be above the law in places like Portland, Oregon where the mayor has told police to stand down while Antifa carries out their attacks. And make no mistake, there are more attacks coming. Especially with these extremists in the media saying things like Trump is terrorizing citizens with his ICE raids. Certainly protecting their fellow human beings and their fellow citizens, but I thought that was just so despicable and I just, it was cruel because he was terrorizing people. But it's what he does. Sonny Hostin is a big Obama supporter, so it's curious that she would take this hardline position when these ICE raids were occurring under Obama's administration. Obama separated tens of thousands of families with these ICE raids and subsequent deportations. With folks in the media pumping out this hyperbolic rhetoric, anyone who actually believes in it will feel a duty to take action. I think this puts us all in danger because anybody that sides with Antifa will see anybody that opposes them as a Nazi or fascist and thus a justifiable target. And for this, you can thank the ideological subversion being carried out by the likes of CNN, MSNBC and ABC. Hey, thanks for watching everybody. Make sure to hit that like button, it really helps the channel. If you enjoy my content and you want to help support this channel, please consider subscribing to me on Patreon or Subscribestar. You can also send me a donation on Paypal. Thanks a lot.