In how many ways can you divide 20 chocolates between 4 people such that A always gets more chocolates that B? X1 + x2 + x3 + x4 = 20 & x1 > x2 , a person might get no chocolates at all. (Question on Permutation and Combination).
In how many ways 20 chocolates can be distributed among 4 boys such that each boy gets at least one chocolate and no one get the same number of chocolates?