How do I find a number which when divided by 2, 3, 4, 5, 6, 7, 8, 9, 10 individually gives a remainder of 1 and when divided by 11 gives a remainder 0?
Given the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, what is the sum of the highest & lowest possible 6-digit numbers that can be formed if repetition of digits is not allowed?