Can you find the error in this equasion: 1= sqrt 1= sqrt [(-1) × (-1)] = sqrt -1 × sqrt -1= I × I= -1?
If [math]\sqrt{x} \cdot \sqrt{x} = \sqrt{x^2}[/math], then why doesn't [math]\sqrt{-1} \cdot \sqrt{-1} = i^2 = \sqrt{1} = 1[/math]?