Python Librosa : What is the default frame size used to compute the MFCC features?
<p>Using Librosa library, I generated the MFCC features of audio file 1319 seconds into a matrix <code>20 X 56829</code>. The <code>20</code> here represents the no of MFCC features (Which I can manually adjust it). But I don't know how it segmented the audio length into <code>56829</code>. What is the frame size it takes process the audio?</p>

<pre><code>import numpy as np
import matplotlib.pyplot as plt
import librosa

def getPathToGroundtruth(episode):
    """Return path to groundtruth file for episode"""
    pathToGroundtruth = "../../../season01/Audio/" \
                        + "Season01.Episode%02d.en.wav" % episode
    return pathToGroundtruth

def getduration(episode):
    pathToAudioFile = getPathToGroundtruth(episode)
    y, sr = librosa.load(pathToAudioFile)
    duration = librosa.get_duration(y=y, sr=sr)
    return duration
def getMFCC(episode):
    filename = getPathToGroundtruth(episode)
    y, sr = librosa.load(filename)  # Y gives 
    data = librosa.feature.mfcc(y=y, sr=sr)
    return data


data = getMFCC(1)
</code></pre>