Output / echo string without quotation marks
<p>Is there any way I can echo a string without using single or double quotation marks. Here's my issue.</p>

<p>If I have a bash script with the following contents it works as expected.</p>

<pre><code>./node_modules/.bin/json -I -f ./test.json -e 'console.log("thomas")'
</code></pre>

<p>I'm trying to use that exact code, I cant alter it in any way. And I'm trying to execute it as a string within one command.</p>

<p>I tried wrapping the string-to-echo in single and double quotes and it doesn't execute right because the code has both single and double quotes.</p>

<pre><code>echo './node_modules/.bin/json -I -f ./test.json -e 'console.log("thomas")'' | sh

echo "./node_modules/.bin/json -I -f ./test.json -e 'console.log("thomas")'" | sh
</code></pre>

<p>Is there any way I can execute the code above in one line and pipe it to <code>sh</code>?</p>