Compare a single integer against an array of integers in C?
<p>How does one compare a single integer to an array of ten integers to find if the single integer is contained within the array using C language?  My apologies if original question was unclear, while swipe is equal to any number within the array I want to output PORTD=0b10000000.  Thank you!</p>

<pre><code>short a[10]={10, 11, 12, 13, 14, 15, 16, 17, 18, 19}; //Array of accepted passwords.
short array[10];
int i;
for(i=0; i&lt;10; i++){
    array[i]=a[i];
}

srand(clock());

while(1){
int swipe=rand() % 20; /* Simulated code read from card swipe, in this
                        * instance we used a random number between
                        * 1 and 20.*/
for(i=0; i&lt;10; i++){    
    if(swipe == array[i]) {
        PORTD=0b10000000;
    } else {
        PORTD=0b00001000;
    } //If swiped code evaluates as one of the approved codes then set PORTD RD7 as high.
}

char Master=PORTDbits.RD7;
</code></pre>

<p>This seems to have solved it...thanks for all of your help!</p>

<pre><code>for(i=0; i&lt;10; i++){    
if(swipe == array[i]) {
    PORTD=0b10000000;
    break;
} else {
    PORTD=0b00001000;
    }
}
</code></pre>