Uncaught Error: Call to undefined function mysql_select_db()
<p>I'm trying to fetch data from the database using Xamp Server but am getting this error.</p>

<blockquote>
  <p>Fatal error: Uncaught Error: Call to undefined function
  mysql_select_db() in E:\xamp\htdocs\PoliceApp\News\fetch.php:10 Stack
  trace: #0 {main} thrown in E:\xamp\htdocs\PoliceApp\News\fetch.php on
  line 10</p>
</blockquote>

<p>Below is my <strong>php</strong> script , am still new in <strong>php</strong> please help me out on this.
But i read all the other Posts here but it seems it's confusing to me,how can I make it right please.</p>

<pre><code>&lt;?php  
$username="root";  
$password="namungoona";  
$hostname = "localhost";  
//connection string with database  
$dbhandle = mysqli_connect($hostname, $username, $password)  
or die("Unable to connect to MySQL");  
echo "";  
// connect with database  
$selected = mysql_select_db("police",$dbhandle)  
or die("Could not select examples");  
//query fire  
$result = mysql_query("select * from News;");  
$json_response = array();  
// fetch data in array format  
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {  
// Fetch data of Fname Column and store in array of row_array
$row_array['Headlines'] = $row['Headlines'];  
$row_array['Details'] = $row['Details']; 
$row_array['NewsPhoto'] = $row['NewsPhoto']; 

//push the values in the array  
array_push($json_response,$row_array);  
}  
//  
echo json_encode($json_response);  
?&gt;  
</code></pre>