How to get the output of a spawned child_process in Node.JS?
<p>First of all, I'm a complete noob and started using Node.JS yesterday (it was also my first time using Linux in years) so please be nice and explicit</p>

<p>I'm currently making a Node.JS program which has to, among other things, launch shell commands (mainly : mount an usb drive).
I'm currently using </p>

<pre><code>var spawn = require('child_process').spawnSync;

function shspawn(command) {
    spawn('sh', ['-c', command], { stdio: 'inherit' });
}

shspawn('echo Hello world');
shspawn('mkdir newdir');
</code></pre>

<p>etc. which is a really comfortable way to do it for me.
The problem is that I'd like to store the output of, for example, a "ls" command in a variable, in a way like</p>

<pre><code>var result = shspawn('ls -l')
</code></pre>

<p>I've read some examples online but they rarely use spawn and when they do, it doesn't work for me (I guess I may do something wrong, but again I'm a noob in Node)</p>

<p>If you guys have a better idea than using child_process_spawnSync I'm open to any idea, but I'd like as long as possible to keep my program package-free :)</p>

<p><strong>EDIT : I need it to work synchronously ! That's why I've started using spawnSync. I will be using some commands like dd, that takes time and needs to be fully finished before the program moves on to another command.</strong></p>