Python Homework - sum of perfect squares
<p>I need help with a python homework question. </p>

<p>"Assume there is a variable , h already associated with a positive integer value. Write the code necessary to compute the sum of the perfect squares whose value is less than h, starting with 1. (A perfect square is an integer like 9, 16, 25, 36 that is equal to the square of another integer (in this case 3*3, 4*4, 5*5, 6*6 respectively).) Associate the sum you compute with the variable  q. For example, if h is 19, you would assign 30 to q because the perfect squares (starting with 1) that are less than h are: 1, 4, 9, 16 and 30==1+4+9+16."</p>

<p>So far I get really close to having it right but it always does one extra number than it needs. For example with putting in 19, instead of stopping at 1,4,9,16 it adds 25 too.</p>

<p>heres my code so far</p>

<pre><code>h_i=input()
h=int(h_i)
s=0
q=0
total=s**2
while total&lt;=h:
     s+=1
     total=s**2
     q+=total
     print(total)
print(q)
</code></pre>