How can I open a file in Perl using a wildcard in the directory name?
<p>I need to open a file called <code>OrthologousGroups.txt</code> from a directory that is named based on the date of when it is created. e.g. <code>./Results_2016-2-7</code></p>

<p>Is there a way to use a wildcard in the path name to the file I need to access?</p>

<p>I tried the following</p>

<pre><code>open(FILE, "./Results*/OrthologousGroups.txt");
</code></pre>

<p>but I get an error</p>

<blockquote>
  <p>readline() on closed filehandle</p>
</blockquote>