how to open xlsx file with python 3
<p>I have an xlsx file with 1 sheet.
I am trying to open it using python 3 (xlrd lib), but I get an empty file!</p>

<p>I use this code:</p>

<pre><code>file_errors_location = "C:\\Users\\atheelm\\Documents\\python excel mission\\errors1.xlsx"
workbook_errors = xlrd.open_workbook(file_errors_location)
</code></pre>

<p>and I have no errors, but when I type:</p>

<pre><code>workbook_errors.nsheets
</code></pre>

<p>I get "0", even the file has some sheets... when I type:</p>

<pre><code>workbook_errors 
</code></pre>

<p>I get:</p>

<pre><code>xlrd.book.Book object at 0x2..
</code></pre>

<p>any help? thanks</p>