How to write loop that ends in negative number (MyProgrammingLab 11138)
<p>Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value  that is the same as the immediately preceding value  is considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7.
Write some code that uses a loop to read such a sequence of non-negative integers , terminated by a negative number. When the code exits the loop it should print the number of consecutive duplicates encountered. In the above case, that value  would be 3.</p>

<p>This is a question from MyProgrammingLab exercise 11138.  This needs to be written in C++, and we are not allowed to use any arrays yet.  Thank you so much for your help.  I really appreciate it.</p>

<p>Here is what I have so far:</p>

<pre><code>int firstNumber;
int secondNumber;
int duplicates;

secondNumber = duplicates = 0;
cin &gt;&gt; firstNumber;

while (firstNumber &gt; -1 &amp;&amp; secondNumber &gt; -1)
{
    secondNumber 
    if (firstNumber == secondNumber)
    {
        duplicates++
    }
    firstNumber = secondNumber;
}

cout &lt;&lt; duplicates;
</code></pre>