Java stack and heap memory management
<p>I want to know how the memory is being allocated in the following program:</p>

<pre><code>public class MemoryClass {

    public static void main(final String[] args) {
        int i = 0;
        MemoryClass memoryClass = new MemoryClass();
        memoryClass.myMethod(memoryClass);
    }

    private void myMethod(final Object obj) {
        int i = 1;
        String s = "HelloWorld!";

    }

}
</code></pre>

<p>Now, as far as my understanding goes, the following diagram describes how the memory allocation takes place:<br>
<a href="https://i.stack.imgur.com/4Ttvc.png" rel="noreferrer"><img src="https://i.stack.imgur.com/4Ttvc.png" alt="Basic runtime memory allocation"></a></p>

<p><br>
In the above diagram, <strong>memory</strong>,<strong>obj</strong> and <strong>s</strong>, which are in the stack memory, are actually the references to their "<strong>actual objects</strong>" which are placed inside the heap memory.
<br>
Here is the set of questions that come to my mind:</p>

<ol>
<li>Where are the methods of <strong>s</strong> stored?</li>
<li>Had I created another object of <code>MemoryClass</code> inside <code>myMethod</code>, would JVM allocate memory for the same methods again inside the stack memory?</li>
<li>Would JVM free the memory allocated to <code>myMethod</code> as soon as it's execution is completed, if so, how would it manage the situation mentioned in question 2(<em>only applicable if JVM allocates memory multiple times to the same method</em>).</li>
<li>What would have been the case, if I had only declared <strong>s</strong> and did not initialize it, would JVM still allocate memory to all the methods of <code>java.lang.String</code> class,if so,why?</li>
</ol>