Return the cube of a number in Python
<p>stuck on this exercise. </p>

<p>INSTRUCTIONS </p>

<blockquote>
  <p>First, def a function called <code>cube</code> that takes an argument called
  <code>number</code>. Don't forget the parentheses and the colon!</p>
  
  <p>Make that function return the cube of that number (i.e. that number
  multiplied by itself and multiplied by itself once again).</p>
  
  <p>Define a second function called <code>by_three</code> that takes an argument called
  <code>number</code>. if that number is divisible by 3, <code>by_three</code> should call
  <code>cube(number)</code> and return its result. Otherwise, <code>by_three</code> should return
  <code>False</code>.</p>
</blockquote>

<p>MY CODE </p>

<pre><code>def cube(number): 
    return number ** number ** number 

def by_three(number)
    if number % 3 == 0:
        return cube(number)

    else:
        return False 
</code></pre>