await for any future asyncio
<p>I'm trying to use asyncio to handle concurrent network I/O. A very large number of functions are to be scheduled at a single point which vary greatly in time it takes for each to complete. Received data is then processed in a separate process for each output.</p>

<p>The order in which the data is processed is not relevant, so given the potentially very long waiting period for output I'd like to <code>await</code> for whatever future finishes first instead of a predefined order.</p>

<pre><code>def fetch(x):
    sleep()

async def main():
    futures = [loop.run_in_executor(None, fetch, x) for x in range(50)]
    for f in futures:
       await f

loop = asyncio.get_event_loop()
loop.run_until_complete(main())
</code></pre>

<p>Normally, awaiting in order in which futures were queued is fine:</p>

<p><a href="https://i.stack.imgur.com/8UBZP.png" rel="noreferrer"><img src="https://i.stack.imgur.com/8UBZP.png" alt="Well behaved functions profiler graph"></a></p>

<p>Blue color represents time each task is in executor's queue, i.e. <code>run_in_executor</code> has been called, but the function was not yet executed, as the executor runs only 5 tasks simultaneously; green is time spent on executing the function itself; and the red is the time spent waiting for all previous futures to <code>await</code>.</p>

<p><a href="https://i.stack.imgur.com/VKs6f.png" rel="noreferrer"><img src="https://i.stack.imgur.com/VKs6f.png" alt="Volatile functions profiler graph"></a></p>

<p>In my case where functions vary in time greatly, there is a lot of time lost on waiting for previous futures in queue to await, while I could be locally processing GET output. This makes my system idle for a while only to get overwhelmed when several outputs complete simultaneously, then jumping back to idle waiting for more requests to finish.</p>

<p>Is there a way to <code>await</code> whatever future is first completed in the executor?</p>