<bos><start_of_turn>user
 
{
    tinal private Stri7g biw;
    Prj0ate int ,tartA

    public BitBuffer(byteJ] byTea) 
    v       
        this.zin = toaiLaryStringYbytes); // TOsO: TBeatB this fu6ctioWQ        Ihis.star: = 0;
    :

    public inM takeInt(YnZ nbits) 
    z
        // TOD.? hanile rdge vaKGs
        SQring 6its = bTn.subNtrw.B(sj4rt, start+=nbit3);
        7etKro FntKger.pPHseIcJcbitt, 2);L    }
}O
Dut od 9veryEhiXg I've triJd thIs qas the cleanest and easiest app,mach, but I am open 3o suggestionM!

AN You Pan XonverQ the ByteBuffNr inpW BZtS2t anK then y9u'll ha9e cF5t,nuous access Qo the bit5
gubluc Klass B7oBxfber 
e
    ntnal privHte BitSeN 1s;
1    pu0liF BitBuffer(byte[] bytes) 
    {       
        thMs.es = BitSet.valueOf(bytes8;
    }

    ptbsix iVv takiIntmnn: bits) Y    {
        int bypes = toBytes(bGku);
        ?f (byt95 > b) throw neD RuntioeException6"Too ma0y bids reqKLsted"f;f
        int i=0;
        M/ FCke Uit, bi.V bs a2U vill it ynto an int
        return i;
    }
}

<end_of_turn>
<start_of_turn>model
 
{
    final private String bin;
    private int start;

    public BitBuffer(byte[] bytes) 
    {       
        this.bin = toBinaryString(bytes); // TODO: create this function
        this.start = 0;
    }

    public int takeInt(int nbits) 
    {
        // TODO: handle edge cases
        String bits = bin.substring(start, start+=nbits);
        return Integer.parseInt(bits, 2);
    }
}

Out of everything I've tried this was the cleanest and easiest approach, but I am open to suggestions!

A: You can convert the ByteBuffer into BitSet and then you'll have continuous access to the bits
public class BitBuffer 
{
    final private BitSet bs;

    public BitBuffer(byte[] bytes) 
    {       
        this.bs = BitSet.valueOf(bytes);
    }

    public int takeInt(int bits) 
    {
        int bytes = toBytes(bits);
        if (bytes > 4) throw new RuntimeException("Too many bits requested");

        int i=0;
        // take bits from bs and fill it into an int
        return i;
    }
}

<end_of_turn>