59. A farmer has. oats which are worth 20 cts. a bushel, rye
55 cts., and barley 60 cts., of Tvhich he wishes to make a mixture
worth 50 cts. per bushel : what part of each must the mixture
contain ?

Analysis. — The prices of the rye and barley must each be com-
pared with the price of the oats. If 1 bu. oats gains 30 cts. in
the mixture, it will take as many bu. of rye to balance it, as 5 cts.
(the loss per bu.) are contained times in 30 cts., viz : 6 bu. Again,
since 1 lu. oats gains 30 cts., it -vvfll take as many bushels of bar-
lev to balance it, as 10 cts. (the loss per bu.) are contained times
In 30 cts., viz : 3 bu. Hence, the mixture must contain 2 parts
»f oats, 6 parts rye, and 3 parts barley.
