Beginning with the left hand period, we find the greatest cube
in 12 is 8, the root of which is 2. Place the 2 on the right of
the gi\Ln number for the first part of the root, and also in Col. L
on the left of the number. Multiplying the 2 into itself, write the
product 4 in Col. II, ; and multiplying 4 by 2, subtract its product
from tlip period, nnd to the right of the remiiinder bring down the
nt!xt [H'riiKl for a dividend. 'J'lien Hclding 2, the first figure of the
root, to the first term of Col. 1., and multiplying the sum by 2,
we add the product 8 to the 1st term of Col. II , and to this sum







Ojierriiioit.
Col. I.
C..1.II.
1216'7(23


1st term


2


4X'2 =


8


2d


it


4
63


1200 (livisoi


r,)416'7


Sd


1389X3 =


: 4167



Quest.— 586. What 13 it to extr&ct tho cube root 1



Arts. 585-587.] cube root. 375

annex two ciphers, for a divisor ; also add 2, the first figure of
the root, to the 2d teim of Col. I. Finding the divisor°is con-
tained in the dividend 3 times, we place the 3 in the root, also on
the right of the 3d term of Col. I. Then multiply the 3d term
thus increased, hy 3, the figure last placed in the root, and add
the product to the divisor. Finally, we multiply this sum hy 3
and subtract the product from the dividend. Ans. 23.
587. Hence, we derive the following general

RULE FOR EXIKACTING THE CUBE ROOT.
