When a U.S. Attorney files charges, does this mean it is automatically filed on behalf of the DoJ?
<h1>Background</h1>

<p>Piggy backing off the question about <a href="https://politics.stackexchange.com/questions/30719/how-would-a-trial-occur-if-two-political-bodies-investigate-the-same-crime?noredirect=1#comment112643_30719">two United State political bodies conducting an investigation</a>, someone made a comment that the a U.S. attorney is always part of the <a href="https://en.wikipedia.org/wiki/United_States_Department_of_Justice" rel="nofollow noreferrer">DoJ</a>.  I understand that in the typical case, a <a href="https://www.criminaldefenselawyer.com/resources/criminal-defense/criminal-offense/pressing-charges-a-criminal-act.htm" rel="nofollow noreferrer">lawyer (usually) represents someone who is the entity pressing charges</a>.  But I'm not sure if the same rules necessarily apply to U.S. attorneys of the Federal Government.</p>

<h1>Question</h1>

<p>When a U.S. Attorney files charges acting in his office, does this automatically mean that the DoJ itself is the party filing a charge?</p>

<p>No. The U.S. Attorney brings charges on behalf of the United States, which is the filing party, at least in criminal cases. That's why every criminal case is styled "United States v. [Whomever]."</p>

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