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|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
[] | You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. | S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
| [] | SingleLineInfilling/HumanEval/119/L11 | code_infilling | S1 = lst[0] + lst[1]
| [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
| HumanEval_SingleLineInfillingLight | match_parens | python | python | [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] | You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. | return 'Yes' if check(S1) or check(S2) else 'No'
| [] | SingleLineInfilling/HumanEval/119/L12 | code_infilling | S2 = lst[1] + lst[0]
| [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
| HumanEval_SingleLineInfillingLight | match_parens | python | python | [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] | You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. | [] | SingleLineInfilling/HumanEval/119/L13 | code_infilling | return 'Yes' if check(S1) or check(S2) else 'No'
| [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
| HumanEval_SingleLineInfillingLight | match_parens | python | python | [
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
|
[] | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr. | return []
arr.sort()
ans = arr[-k:]
return ans
| [] | SingleLineInfilling/HumanEval/120/L0 | code_infilling | if k == 0:
| [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
]
] |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
"""
| HumanEval_SingleLineInfillingLight | maximum | python | python | [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
],
[
"[123, -123, 20, 0 , 1, 2, -3], 3",
"[2, 20, 123]"
],
[
"[-123, 20, 0 , 1, 2, -3], 4",
"[0, 1, 2, 20]"
],
[
"[5, 15, 0, 3, -13, -8, 0], 7",
"[-13, -8, 0, 0, 3, 5, 15]"
],
[
"[-1, 0, 2, 5, 3, -10], 2",
"[3, 5]"
],
[
"[1, 0, 5, -7], 1",
"[5]"
],
[
"[4, -4], 2",
"[-4, 4]"
],
[
"[-10, 10], 2",
"[-10, 10]"
],
[
"[1, 2, 3, -23, 243, -400, 0], 0",
"[]"
]
] |
[] | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr. | arr.sort()
ans = arr[-k:]
return ans
| [] | SingleLineInfilling/HumanEval/120/L1 | code_infilling | return []
| [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
]
] |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
"""
if k == 0:
| HumanEval_SingleLineInfillingLight | maximum | python | python | [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
],
[
"[123, -123, 20, 0 , 1, 2, -3], 3",
"[2, 20, 123]"
],
[
"[-123, 20, 0 , 1, 2, -3], 4",
"[0, 1, 2, 20]"
],
[
"[5, 15, 0, 3, -13, -8, 0], 7",
"[-13, -8, 0, 0, 3, 5, 15]"
],
[
"[-1, 0, 2, 5, 3, -10], 2",
"[3, 5]"
],
[
"[1, 0, 5, -7], 1",
"[5]"
],
[
"[4, -4], 2",
"[-4, 4]"
],
[
"[-10, 10], 2",
"[-10, 10]"
],
[
"[1, 2, 3, -23, 243, -400, 0], 0",
"[]"
]
] |
[] | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr. | ans = arr[-k:]
return ans
| [] | SingleLineInfilling/HumanEval/120/L2 | code_infilling | arr.sort()
| [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
]
] |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
"""
if k == 0:
return []
| HumanEval_SingleLineInfillingLight | maximum | python | python | [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
],
[
"[123, -123, 20, 0 , 1, 2, -3], 3",
"[2, 20, 123]"
],
[
"[-123, 20, 0 , 1, 2, -3], 4",
"[0, 1, 2, 20]"
],
[
"[5, 15, 0, 3, -13, -8, 0], 7",
"[-13, -8, 0, 0, 3, 5, 15]"
],
[
"[-1, 0, 2, 5, 3, -10], 2",
"[3, 5]"
],
[
"[1, 0, 5, -7], 1",
"[5]"
],
[
"[4, -4], 2",
"[-4, 4]"
],
[
"[-10, 10], 2",
"[-10, 10]"
],
[
"[1, 2, 3, -23, 243, -400, 0], 0",
"[]"
]
] |
[] | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr. | return ans
| [] | SingleLineInfilling/HumanEval/120/L3 | code_infilling | ans = arr[-k:]
| [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
]
] |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
"""
if k == 0:
return []
arr.sort()
| HumanEval_SingleLineInfillingLight | maximum | python | python | [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
],
[
"[123, -123, 20, 0 , 1, 2, -3], 3",
"[2, 20, 123]"
],
[
"[-123, 20, 0 , 1, 2, -3], 4",
"[0, 1, 2, 20]"
],
[
"[5, 15, 0, 3, -13, -8, 0], 7",
"[-13, -8, 0, 0, 3, 5, 15]"
],
[
"[-1, 0, 2, 5, 3, -10], 2",
"[3, 5]"
],
[
"[1, 0, 5, -7], 1",
"[5]"
],
[
"[4, -4], 2",
"[-4, 4]"
],
[
"[-10, 10], 2",
"[-10, 10]"
],
[
"[1, 2, 3, -23, 243, -400, 0], 0",
"[]"
]
] |
[] | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr. | [] | SingleLineInfilling/HumanEval/120/L4 | code_infilling | return ans
| [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
]
] |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
"""
if k == 0:
return []
arr.sort()
ans = arr[-k:]
| HumanEval_SingleLineInfillingLight | maximum | python | python | [
[
"[-3, -4, 5], 3",
"[-4, -3, 5]"
],
[
"[4, -4, 4], 2",
"[4, 4]"
],
[
"[-3, 2, 1, 2, -1, -2, 1], 1",
"[2]"
],
[
"[123, -123, 20, 0 , 1, 2, -3], 3",
"[2, 20, 123]"
],
[
"[-123, 20, 0 , 1, 2, -3], 4",
"[0, 1, 2, 20]"
],
[
"[5, 15, 0, 3, -13, -8, 0], 7",
"[-13, -8, 0, 0, 3, 5, 15]"
],
[
"[-1, 0, 2, 5, 3, -10], 2",
"[3, 5]"
],
[
"[1, 0, 5, -7], 1",
"[5]"
],
[
"[4, -4], 2",
"[-4, 4]"
],
[
"[-10, 10], 2",
"[-10, 10]"
],
[
"[1, 2, 3, -23, 243, -400, 0], 0",
"[]"
]
] |
|
[] | Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions. | [] | SingleLineInfilling/HumanEval/121/L0 | code_infilling | return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
| [
[
"[5, 8, 7, 1]",
"> 12"
],
[
"[3, 3, 3, 3, 3]",
"> 9"
],
[
"[30, 13, 24, 321]",
">0"
]
] |
def solution(lst):
"""Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
"""
| HumanEval_SingleLineInfillingLight | solution | python | python | [
[
"[5, 8, 7, 1]",
"12"
],
[
"[3, 3, 3, 3, 3]",
"9"
],
[
"[30, 13, 24, 321]",
"0"
],
[
"[5, 9]",
"5"
],
[
"[2, 4, 8]",
"0"
],
[
"[30, 13, 23, 32]",
"23"
],
[
"[3, 13, 2, 9]",
"3"
]
] |
|
[] | Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr. | [] | SingleLineInfilling/HumanEval/122/L0 | code_infilling | return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
| [
[
"[111,21,3,4000,5,6,7,8,9], 4",
"24"
]
] |
def add_elements(arr, k):
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
"""
| HumanEval_SingleLineInfillingLight | add_elements | python | python | [
[
"[1,-2,-3,41,57,76,87,88,99], 3",
"-4"
],
[
"[111,121,3,4000,5,6], 2",
"0"
],
[
"[11,21,3,90,5,6,7,8,9], 4",
"125"
],
[
"[111,21,3,4000,5,6,7,8,9], 4",
"24"
],
[
"[1], 1",
"1"
]
] |
|
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L0 | code_infilling | if n%2==0:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L1 | code_infilling | odd_collatz = []
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L2 | code_infilling | else:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L3 | code_infilling | odd_collatz = [n]
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L4 | code_infilling | while n > 1:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L5 | code_infilling | if n % 2 == 0:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L6 | code_infilling | n = n/2
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L7 | code_infilling | else:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. |
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L8 | code_infilling | n = n*3 + 1
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | odd_collatz.append(int(n))
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L10 | code_infilling | if n%2 == 1:
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. |
return sorted(odd_collatz)
| [] | SingleLineInfilling/HumanEval/123/L11 | code_infilling | odd_collatz.append(int(n))
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
[] | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order. | [] | SingleLineInfilling/HumanEval/123/L13 | code_infilling | return sorted(odd_collatz)
| [
[
"5",
"[1, 5]"
]
] |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned list sorted in increasing order.
"""
if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
| HumanEval_SingleLineInfillingLight | get_odd_collatz | python | python | [
[
"14",
"[1, 5, 7, 11, 13, 17]"
],
[
"5",
"[1, 5]"
],
[
"12",
"[1, 3, 5]"
],
[
"1",
"[1]"
]
] |
|
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L0 | code_infilling | try:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L1 | code_infilling | date = date.strip()
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L2 | code_infilling | month, day, year = date.split('-')
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L3 | code_infilling | month, day, year = int(month), int(day), int(year)
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L4 | code_infilling | if month < 1 or month > 12:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L5 | code_infilling | return False
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L6 | code_infilling | if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L7 | code_infilling | return False
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L8 | code_infilling | if month in [4,6,9,11] and day < 1 or day > 30:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L9 | code_infilling | return False
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | return False
except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L10 | code_infilling | if month == 2 and day < 1 or day > 29:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | except:
return False
return True
| [] | SingleLineInfilling/HumanEval/124/L11 | code_infilling | return False
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | return False
return True
| [] | SingleLineInfilling/HumanEval/124/L12 | code_infilling | except:
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy |
return True
| [] | SingleLineInfilling/HumanEval/124/L13 | code_infilling | return False
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
[] | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy | [] | SingleLineInfilling/HumanEval/124/L15 | code_infilling | return True
| [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'06/04/2020'",
"False"
]
] |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
"""
try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
| HumanEval_SingleLineInfillingLight | valid_date | python | python | [
[
"'03-11-2000'",
"True"
],
[
"'15-01-2012'",
"False"
],
[
"'04-0-2040'",
"False"
],
[
"'06-04-2020'",
"True"
],
[
"'01-01-2007'",
"True"
],
[
"'03-32-2011'",
"False"
],
[
"''",
"False"
],
[
"'04-31-3000'",
"False"
],
[
"'06-06-2005'",
"True"
],
[
"'21-31-2000'",
"False"
],
[
"'04-12-2003'",
"True"
],
[
"'04122003'",
"False"
],
[
"'20030412'",
"False"
],
[
"'2003-04'",
"False"
],
[
"'2003-04-12'",
"False"
],
[
"'04-2003'",
"False"
]
] |
|
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [] | SingleLineInfilling/HumanEval/125/L0 | code_infilling | if " " in txt:
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [] | SingleLineInfilling/HumanEval/125/L1 | code_infilling | return txt.split()
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
if " " in txt:
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [] | SingleLineInfilling/HumanEval/125/L2 | code_infilling | elif "," in txt:
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
if " " in txt:
return txt.split()
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [] | SingleLineInfilling/HumanEval/125/L3 | code_infilling | return txt.replace(',',' ').split()
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
if " " in txt:
return txt.split()
elif "," in txt:
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [] | SingleLineInfilling/HumanEval/125/L4 | code_infilling | else:
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
[] | Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 | [] | SingleLineInfilling/HumanEval/125/L5 | code_infilling | return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| [
[
"\"abcdef\"",
"3"
]
] |
def split_words(txt):
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
"""
if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
| HumanEval_SingleLineInfillingLight | split_words | python | python | [
[
"\"Hello world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello,world!\"",
"[\"Hello\",\"world!\"]"
],
[
"\"Hello world,!\"",
"[\"Hello\",\"world,!\"]"
],
[
"\"Hello,Hello,world !\"",
"[\"Hello,Hello,world\",\"!\"]"
],
[
"\"abcdef\"",
"3"
],
[
"\"aaabb\"",
"2"
],
[
"\"aaaBb\"",
"1"
],
[
"\"\"",
"0"
]
] |
|
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L0 | code_infilling | count_digit = dict([(i, 0) for i in lst])
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L1 | code_infilling | for i in lst:
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L2 | code_infilling | count_digit[i]+=1
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L3 | code_infilling | if any(count_digit[i] > 2 for i in lst):
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L4 | code_infilling | return False
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | return True
else:
return False
| [] | SingleLineInfilling/HumanEval/126/L5 | code_infilling | if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | else:
return False
| [] | SingleLineInfilling/HumanEval/126/L6 | code_infilling | return True
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | return False
| [] | SingleLineInfilling/HumanEval/126/L7 | code_infilling | else:
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
[] | Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers. | [] | SingleLineInfilling/HumanEval/126/L8 | code_infilling | return False
| [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
]
] |
def is_sorted(lst):
"""
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
"""
count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
| HumanEval_SingleLineInfillingLight | is_sorted | python | python | [
[
"[5]",
"True"
],
[
"[1, 2, 3, 4, 5]",
"True"
],
[
"[1, 3, 2, 4, 5]",
"False"
],
[
"[1, 2, 3, 4, 5, 6]",
"True"
],
[
"[1, 2, 3, 4, 5, 6, 7]",
"True"
],
[
"[1, 3, 2, 4, 5, 6, 7]",
"False"
],
[
"[]",
"True"
],
[
"[1]",
"True"
],
[
"[3, 2, 1]",
"False"
],
[
"[1, 2, 2, 2, 3, 4]",
"False"
],
[
"[1, 2, 3, 3, 3, 4]",
"False"
],
[
"[1, 2, 2, 3, 3, 4]",
"True"
],
[
"[1, 2, 3, 4]",
"True"
]
] |
|
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L0 | code_infilling | def is_prime(num):
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L1 | code_infilling | if num == 1 or num == 0:
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L2 | code_infilling | return False
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L3 | code_infilling | if num == 2:
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L4 | code_infilling | return True
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L5 | code_infilling | for i in range(2, num):
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L6 | code_infilling | if num%i == 0:
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L7 | code_infilling | return False
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". |
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L8 | code_infilling | return True
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L10 | code_infilling | l = max(interval1[0], interval2[0])
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L11 | code_infilling | r = min(interval1[1], interval2[1])
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | if length > 0 and is_prime(length):
return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L12 | code_infilling | length = r - l
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return "YES"
return "NO"
| [] | SingleLineInfilling/HumanEval/127/L13 | code_infilling | if length > 0 and is_prime(length):
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | return "NO"
| [] | SingleLineInfilling/HumanEval/127/L14 | code_infilling | return "YES"
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
[] | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO". | [] | SingleLineInfilling/HumanEval/127/L15 | code_infilling | return "NO"
| [
[
"(1, 2), (2, 3)",
"> \"NO\""
],
[
"(-1, 1), (0, 4)",
"> \"NO\""
],
[
"(-3, -1), (-5, 5)",
"> \"YES\""
]
] |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
"""
def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
| HumanEval_SingleLineInfillingLight | intersection | python | python | [
[
"(1, 2), (2, 3)",
"\"NO\""
],
[
"(-1, 1), (0, 4)",
"\"NO\""
],
[
"(-3, -1), (-5, 5)",
"\"YES\""
],
[
"(-2, 2), (-4, 0)",
"\"YES\""
],
[
"(-11, 2), (-1, -1)",
"\"NO\""
],
[
"(1, 2), (3, 5)",
"\"NO\""
],
[
"(1, 2), (1, 2)",
"\"NO\""
],
[
"(-2, -2), (-3, -2)",
"\"NO\""
]
] |
|
[] | You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr. | prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
return prod * sum([abs(i) for i in arr])
| [] | SingleLineInfilling/HumanEval/128/L0 | code_infilling | if not arr: return None
| [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[]",
"None"
]
] |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
"""
| HumanEval_SingleLineInfillingLight | prod_signs | python | python | [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[1, 1, 1, 2, 3, -1, 1]",
"-10"
],
[
"[]",
"None"
],
[
"[2, 4,1, 2, -1, -1, 9]",
"20"
],
[
"[-1, 1, -1, 1]",
"4"
],
[
"[-1, 1, 1, 1]",
"-4"
],
[
"[-1, 1, 1, 0]",
"0"
]
] |
[] | You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr. | return prod * sum([abs(i) for i in arr])
| [] | SingleLineInfilling/HumanEval/128/L1 | code_infilling | prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
| [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[]",
"None"
]
] |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
"""
if not arr: return None
| HumanEval_SingleLineInfillingLight | prod_signs | python | python | [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[1, 1, 1, 2, 3, -1, 1]",
"-10"
],
[
"[]",
"None"
],
[
"[2, 4,1, 2, -1, -1, 9]",
"20"
],
[
"[-1, 1, -1, 1]",
"4"
],
[
"[-1, 1, 1, 1]",
"-4"
],
[
"[-1, 1, 1, 0]",
"0"
]
] |
[] | You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr. | [] | SingleLineInfilling/HumanEval/128/L2 | code_infilling | return prod * sum([abs(i) for i in arr])
| [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[]",
"None"
]
] |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
"""
if not arr: return None
prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
| HumanEval_SingleLineInfillingLight | prod_signs | python | python | [
[
"[1, 2, 2, -4]",
"-9"
],
[
"[0, 1]",
"0"
],
[
"[1, 1, 1, 2, 3, -1, 1]",
"-10"
],
[
"[]",
"None"
],
[
"[2, 4,1, 2, -1, -1, 9]",
"20"
],
[
"[-1, 1, -1, 1]",
"4"
],
[
"[-1, 1, 1, 1]",
"-4"
],
[
"[-1, 1, 1, 0]",
"0"
]
] |
|
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L0 | code_infilling | n = len(grid)
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L1 | code_infilling | val = n * n + 1
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L2 | code_infilling | for i in range(n):
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L3 | code_infilling | for j in range(n):
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L4 | code_infilling | if grid[i][j] == 1:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L5 | code_infilling | temp = []
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L6 | code_infilling | if i != 0:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. |
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L7 | code_infilling | temp.append(grid[i - 1][j])
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L9 | code_infilling | if j != 0:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. |
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L10 | code_infilling | temp.append(grid[i][j - 1])
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L12 | code_infilling | if i != n - 1:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. |
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L13 | code_infilling | temp.append(grid[i + 1][j])
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L15 | code_infilling | if j != n - 1:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. |
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L16 | code_infilling | temp.append(grid[i][j + 1])
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. |
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L18 | code_infilling | val = min(temp)
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L20 | code_infilling | ans = []
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L21 | code_infilling | for i in range(k):
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | ans.append(1)
else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L22 | code_infilling | if i % 2 == 0:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | else:
ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L23 | code_infilling | ans.append(1)
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | ans.append(val)
return ans
| [] | SingleLineInfilling/HumanEval/129/L24 | code_infilling | else:
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | return ans
| [] | SingleLineInfilling/HumanEval/129/L25 | code_infilling | ans.append(val)
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through. | [] | SingleLineInfilling/HumanEval/129/L26 | code_infilling | return ans
| [
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
| HumanEval_SingleLineInfillingLight | minPath | python | python | [
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
|
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L0 | code_infilling | if n == 0:
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L1 | code_infilling | return [1]
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L2 | code_infilling | my_tri = [1, 3]
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L3 | code_infilling | for i in range(2, n + 1):
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L4 | code_infilling | if i % 2 == 0:
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L5 | code_infilling | my_tri.append(i / 2 + 1)
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| [] | SingleLineInfilling/HumanEval/130/L6 | code_infilling | else:
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. | return my_tri
| [] | SingleLineInfilling/HumanEval/130/L7 | code_infilling | my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
| [
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
| HumanEval_SingleLineInfillingLight | tri | python | python | [
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
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