<SYSTEM_TASK:>
Given the following text description, write Python code to implement the functionality described below step by step
<END_TASK>
<USER_TASK:>
Description:
 & for multiple parameters
Step1:  2) What genres are most represented in the search results?
Edit your previous printout to also display a list of their genres in the format 
GENRE_1, GENRE_2, GENRE_3". If there are no genres, print "No genres listed".
Tip
Step2:  ANSWER
Step3:  3) Use a for loop to determine who BESIDES Lil Wayne has the highest popularity rating.
Is it the same artist who has the largest number of followers?
Step4:  ANSWER
Step5:  5) Pick two of your favorite Lils to fight it out, and use their IDs to print out their top tracks.
Step6:  Will the world explode if a musician swears? 
Get an average popularity for their explicit songs vs. their non-explicit songs. 
How many minutes of explicit songs do they have? Non-explicit?
Step7:  QUESTION
Step8:  7) Since we're talking about Lils, what about Biggies? 
How many total "Biggie" artists are there? How many total "Lil"s? 
If you made 1 request every 5 seconds, 
how long would it take to download information on all the Lils vs the Biggies?
Step9:  8) Out of the top 50 "Lil"s and the top 50 "Biggie"s, who is more popular on average?
<ASSISTANT_TASK:>
Python Code:
data = response.json()
data.keys()
artist_data = data['artists']
artist_data.keys()
lil_names = artist_data['items']
#lil_names = list of dictionaries = list of artist name, popularity, type, genres etc
Explanation: & for multiple parameters
End of explanation
for names in lil_names:
    if not names['genres']:
        print(names['name'], names['popularity'], "there are no genres listed")
    else:
        print(names['name'], names['popularity'], names["genres"])
#Join all the lists of genres in the dictionary and then count the number of elements in it
Explanation: 2) What genres are most represented in the search results?
Edit your previous printout to also display a list of their genres in the format 
GENRE_1, GENRE_2, GENRE_3". If there are no genres, print "No genres listed".
Tip: "how to join a list Python" might be a helpful search
End of explanation
#ANSWER:
all_genres = []    
    
for artist in artists:
    print("All genres we've heard of:", all_genres)
    #The conditional: None
    print("Current artist has:", artist['genres'])
    all_genres = all_genres + artist['genres']
    #genre_list = ", ".join(artist['genres'])
    #print(artist['name'], ":", genre_list)
    all_genre.count('dirty soup rap')
    all_genre.count('crunk')
#This is bad because dirty south rap shows up four times. We need a unique list of genres
    for genre in all_genres:
        genre_count = all_genres.count(genre)
        print(genre, "shows up", genre_count, "times")
#To remove duplicates. You need to turn a list into a set.
unique_genres = set(list_with_duplicates)
for genre in unique_genres:
    genre_count = all_genres.count(genre)
    print(genre, "shows up", genre_count, "times")
#There is a library that comes with Python called Collections
#Inside of it is a magic thing called Counter.
import collections # will import the whole collections
#you can also type
from collections import Counter
#all_genres is a list of strings of genrs with duplicates
#counter will count all te genres for us
counts = collections.Counter(all_genres)
counts.most_common(4) #will give you the four most common genres
#HOW TO AUTOMATE GETTING ALL THE RESULTS
response = requests.get("https://api.spotify.com/v1/search?query=lil&type=artist&market=US&limit=10")
small_data = response.json()
small_data['artists']
print(len(small_data['artists']['items'])) #We only get 10 artists
print(data['artists']['total'])
import math
page_count = math.ceil(4502/50)
#math.ceil rounds up
#math.ceil(page_count)
page_count
#First page artists 1-50: 
#https://api.spotify.com/v1/search?query=lil&type=artist&market=US&limit=50
#Second page artists 51-100: 
#https://api.spotify.com/v1/search?query=lil&type=artist&market=US&limit=50&offset=50
#Third page artists 101-150: 
#https://api.spotify.com/v1/search?query=lil&type=artist&market=US&limit=50&offset=100
#Fourth page artists 151-200: 
#https://api.spotify.com/v1/search?query=lil&type=artist&market=US&limit=50&offset=150
for page in [0, 1, 2, 3, 4]:
    offset = (page) * 50 #because page 2 is 50 and 2-1 = 1 x 50 = 50
    print("We are on page", page, "with an offset of", offset)
for page in range(91):
    #Get a page
    offset = page * 50
    print("We are on page", page, "with an offset of", offset)
    
    #Make the request with a changed offset ?offset [offset]
    #data = response.json()
    #add all our new artists to our list of existing artists
    #all_artists = all_artists + data['artists]['items]
    
print("Successfully retrieved", len(all_artists), "artists")
Explanation: ANSWER:
    for artist in artists:
        print(artist['name'], artist['popularity'])
        if len(artist['genres']) > 0:
            genres = ", ".join(artist['genres'])
            print("Genre list: ", genres
        else:
            print("No genres listed")
              OR
    if len(artist['name']) == 0:
              OR
    if not len(artist['genres']) == 0:
"-".join(your_list) to join lists
End of explanation
for popularity in lil_names:
    print(popularity['name'], popularity['popularity'], popularity['followers'])
print("Lil Yachty, Lil Uzi Vert, Lil Jon have the highest popularity ratings besides Lil Wayne, and they do not have the largest number of followers.")
Explanation: 3) Use a for loop to determine who BESIDES Lil Wayne has the highest popularity rating.
Is it the same artist who has the largest number of followers?
End of explanation
for kim in lil_names:
    print(kim['name'], kim['id'])
response = requests.get("https://api.spotify.com/v1/artists/5tth2a3v0sWwV1C7bApBdX/")
kim_data = response.json()
#print(kim_data)
kim_followers = kim_data['followers']
total_kim_followers = kim_followers['total']
#print(total_kim_followers)
for artists in lil_names:
    if artists["followers"]["total"] > total_kim_followers:
        print(artists['name'], artists['popularity'])
ANSWER:
    
for artist in artists:
    #print("Looking at", artist['name'])
    if artist['name'] == "Lil' Kim":
        print("Found Lil Kim")
        print(artist['popularity'])
    else:
        pass
        #print("Not Lil Kim")
lil_kim_popularity = 62
for artist in artists:
    if artist['popularity'] > lil_kim_popularity:
        print(artist['name'], "is more popular with a score of", artist['popularity'])
        more_popular_than_lil_kim.append(artist['name'])
    else:
        print(artist['name'], "is less popular with a score of", artist['popularity'])
print("#### More popular than Lil Kim ####"):
    print(artist_name)
    
    more_popular_string = ", ".join(more_popular_than_lil_kim)
    print("Artists mroe popular than Lil Kim are:", more_popular_string)
Explanation: ANSWER:
    #jonathansoma.com/site/lede/foundations/python-patterns/looping-problems/
second_most_popular_name = ""
second_most_popular_score = 0
for artist in artists:
    print("Looking at", artist['name]', "who has a popularity score of", artist['popularity'])
    #THE CONDITIONAL aka what you are testing
    print("Comparing", artist['popularity'], "to", most_popular_score)
    if artist['popularity'] > most_popular_score and artist['name'] != 'Lil Wayne':
                           OR
if artist['popularity'] &gt; most_popular_score:
    if artist['name'] == "Lil Wayne":
        print("Nice try, Lil Wayne, we don't care")
    else:
        print("Not Lil Wayne, updating our notebook")
    #The change, aka what you are keeping track of
    most_popular_name = artist['name']
    most_popular_score = artist['popularity']
print(most_popular_name, most_popular_score)
But what if more than one person has the highest score?
Aggregation Problem. When you're looping through a series of objects and sometimes you
want to add one of those objects to a different list.
target score = 72
initial condition
second_best_artist = []
for artist in artists:
    print("Looking at", artist['name'], "who has a popularity of", )
    #2: Conditional. When we want to add someone to our list
                               if artist['popularity'] == 72:
                               print("!!! The artist's popularity is 72")
                               #The Change
                               #Add that artist to our list
                               #.append(newthing) is how we do that in Python
                               second_best_artists.append(artist['name'])
print("Our second best artists are:")
                           for artist in second_best_artist:
                           print(artist)
Print a list of Lil's that are more popular than Lil' Kim.
End of explanation
#Let's pick Lil Wayne and Lil Mama because I don't know who most of these people are
wayne_id = "55Aa2cqylxrFIXC767Z865"
response = requests.get("https://api.spotify.com/v1/artists/" + wayne_id + "/top-tracks?country=US")
wayne_data = response.json()
top_wayne_tracks = wayne_data['tracks']
for track in top_wayne_tracks:
    print(track["name"])
mama_id = "5qK5bOC6wLtuLhG5KvU17c"
response = requests.get("https://api.spotify.com/v1/artists/" + mama_id + "/top-tracks?country=US")
mama_data = response.json()
top_mama_tracks = mama_data['tracks']
for track in top_mama_tracks:
    print(track["name"])
Explanation: 5) Pick two of your favorite Lils to fight it out, and use their IDs to print out their top tracks.
End of explanation
wayne_explicit_count = 0
wayne_exp_popularity_count = 0
wayne_ok_count = 0
wayne_ok_popularity_count = 0
wayne_explicit_len = 0
wayne_ok_len = 0
for track in top_wayne_tracks:
    print(track['name'], track['explicit'], track['popularity'], track["duration_ms"])
    if True:
        wayne_explicit_count = wayne_explicit_count + 1
        wayne_exp_popularity_count = wayne_exp_popularity_count + int(track['popularity'])
        wayne_avg_pop = wayne_exp_popularity_count / wayne_explicit_count
        wayne_explicit_len = wayne_explicit_len + int(track["duration_ms"])
    if not track['explicit']:
        wayne_ok_count = wayne_ok_count + 1
        wayne_ok_popularity_count = wayne_ok_popularity_count + track['popularity']
        wayne_ok_avg_pop = wayne_ok_popularity_count / wayne_ok_count
        wayne_ok_len = wayne_ok_len + track["duration_ms"]
if wayne_explicit_count > 0:
    print("The average popularity for Lil Wayne's explicit songs is", wayne_avg_pop)
    #1 minute is 60000 milliseconds, who knew?
    wayne_explicit_mins = int(wayne_explicit_len) / 60000
    print("Lil Wayne has", wayne_explicit_mins, "minutes of explicit songs")
if wayne_ok_count > 0:
    print("The average popularity for Lil Wayne's non-explicit songs is", wayne_ok_avg_pop)
    wayne_ok_mins = int(wayne_ok_len) / 60000
    print("Lil Wayne has", wayne_ok_mins, "minutes of explicit songs")
Explanation: Will the world explode if a musician swears? 
Get an average popularity for their explicit songs vs. their non-explicit songs. 
How many minutes of explicit songs do they have? Non-explicit?
End of explanation
mama_exp_count = 0
mama_exp_pop_count = 0
mama_ok_count = 0
mama_ok_pop_count = 0
mama_exp_len = 0
mama_ok_len = 0
for track in top_mama_tracks:
    print(track['name'], track['explicit'], track['popularity'], track["duration_ms"])
    if True:
        mama_exp_count = mama_exp_count + 1
        mama_exp_pop_count = mama_exp_pop_count + int(track['popularity'])
        mama_avg_pop = int(mama_exp_pop_count) / int(mama_exp_count)
        mama_exp_len = mama_exp_len + int(track["duration_ms"])
    if not track['explicit']:
        mama_ok_count = mama_ok_count + 1
        mama_ok_pop_count = mama_ok_pop_count + int(track['popularity'])
        mama_ok_avg_pop = int(mama_ok_pop_count) / int(mama_ok_count)
        mama_ok_len = mama_ok_len + int(track["duration_ms"])
if mama_exp_count > 0:
       #1 minute is 60000 milliseconds, who knew?
    print("The average popularity for Lil Mama's xplicit songs is", mama_avg_pop)
    mama_exp_mins = int(mama_exp_len) / 60000
    print("Lil Mama has", mama_exp_mins, "minutes of explicit songs")
if mama_ok_count > 0:
    print("The average popularity for Lil Mama's non-explicit songs is", mama_ok_avg_pop)
    mama_ok_mins = int(mama_ok_len) / 60000
    print("Lil Mama has", mama_ok_mins, "minutes of non-explicit songs")
Explanation: QUESTION: Why does this return both true and not true statements for non-explicit statements?
for track in top_mama_tracks:
    print(track['name'], track['explicit'])
    if True:
        print(track['name'], "is explicit and has a popularity of", track['popularity'])
    if not track['explicit']:
        print(track['name'], "is not explicit and has a popularity of", track['popularity'])
End of explanation
#We need to bypass the limit. And find out 
response = requests.get('https://api.spotify.com/v1/search?query=biggie&type=artist')
biggie_data = response.json()
biggie_artists = biggie_data['artists']
biggie_names = biggie_artists['items']
biggie_count= 0
for name in biggie_names:
    print(name['name'])
    biggie_count = biggie_count + 1
print("There are a total number of", biggie_count, "biggie artists")
response = requests.get('https://api.spotify.com/v1/search?query=lil&type=artist')
lil_data = response.json()
lil_x_artists = lil_data['artists']
lil_x_names = lil_x_artists['items']
lil_x_count= 0
for name in lil_x_names:
    print(name['name'])
    lil_x_count = biggie_count + 1
print("There are a total number of", lil_x_count, "lil artists")
Explanation: 7) Since we're talking about Lils, what about Biggies? 
How many total "Biggie" artists are there? How many total "Lil"s? 
If you made 1 request every 5 seconds, 
how long would it take to download information on all the Lils vs the Biggies?
End of explanation
response = requests.get('https://api.spotify.com/v1/search?query=biggie&type=artist&limit=50')
b_data = response.json()
b_artists = b_data['artists']
b_names = b_artists['items']
b_pop_count = 0
b_number = 0
for names in b_names:
    print(names['name'], names['popularity'])
    b_number = b_number + 1
    b_pop_count = b_pop_count + int(names['popularity'])
    avg_b_pop = b_pop_count / int(b_number)
print("The Biggies' average popularity is", avg_b_pop)
lil_pop_count = 0
lil_number = 0
for names in lil_names:
    print(names['name'], names['popularity'])
    lil_number = lil_number + 1
    lil_pop_count = lil_pop_count + int(names['popularity'])
    avg_lil_pop = lil_pop_count / int(lil_number)
print("The Lils average popularity is", avg_lil_pop)
print("The Lils are far more popular")
Explanation: 8) Out of the top 50 "Lil"s and the top 50 "Biggie"s, who is more popular on average?
End of explanation
<END_TASK>