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Two plates are connected by a lap joint using four bolts of 20 mm diameter. If the joint is subjected to a tensile force of 100 kN, the shear stress in the bolt is

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  1. 25 N/mm2

  2. 31.4 N/mm2

  3. 79.6 N/mm2

  4. 50 N/mm2

Correct Answer: Option 3 (Solution Below)

This question was previously asked in

TN TRB Civil 2012 Paper


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Shear stress (τ) may be defined as the shear force per unit area.

\({\rm{\tau }} = \frac{{{\rm{Force}}}}{{{\rm{Area}}}}\)


Force acting on each bolt, \({\rm{F}} = \frac{{100}}{4} = 25{\rm{\;kN}}\)

Shear stress, \({\rm{\tau }} = \frac{{\rm{F}}}{{\rm{A}}} = \frac{{25}}{{\frac{{\rm{\pi }}}{4} \times {{20}^2}}} = 79.6{\rm{\;N}}/{\rm{m}}{{\rm{m}}^2}\)
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